classical genetics. humans have a long history of animal and plant breeding… but without an...
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Humans have a long history of animal and plant breeding…
but without an understanding of the underlying process
Humans have a long history of animal and plant breeding…
but without an understanding of the underlying process
Classical Mendelian Genetics has a limitation: The requirement for observable phenotypic differences in different genotypes
Mendel chose single gene mutants with extreme phenotypesto study.
This made different genotypes recognizable and countable.
Terminology
• Genes and alleles
• Genotype and Phenotype
• Homozygote, Heterozygote, Hemizygote
• Dominance
• Meiosis and Syngamy (Fertilization)
• Parents, Gametes, Offspring
Genes and Alleles
• A gene is a nucleotide sequence of a DNA molecule that codes for the primary structure of a protein or RNA molecule
• Alleles are gene variants. They differ in their nucleotide sequences.
Genotype and Phenotype
• Genotype: An individual’s genetic constitution
AA, Aa, aa are diploid genotypes
• Phenotype: An organism’s appearance, reflecting genotypic and environmental influences
blue yellow white
Dominance
• Many alleles are mutations whose gene products (proteins) work poorly or not at all (e.g., allele a). These alleles are recessive to normal alleles in the sense that they affect the phenotype only when there are no functional alleles present, i.e., in the homozygous recessive genotype aa.
• Both homozygotes (e.g., AA) for the normal allele and heterozygotes (e.g., Aa) share the functional allele (A) and exhibit the normal phenotype. However, aa individuals are unable to perform the function that this gene is responsible for and they will have a different phenotype.
• Operationally, one allele is said to be dominant over another if the heterozygote has the same phenotype as a homozygote (e.g., Aa and AA look alike).
Homozygous fortwo normal alleles
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Homozygous fortwo non-functional alleles
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Heterozygous fora normal and a non-functional allele
Dominance
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Siamese Cats:
An enzyme that catalyzes pigment synthesis is denatured under warmer physiological conditions, like warmer parts of the cat’s body. Only cooler extremities reveal intense pigmentation.
Similarly, the enzyme can be deactivated not only under conditions that are too warm (below), but also under conditions that are cooler (above).
A Mendelian Research ProgramAA x aa
all Aa
1/4 AA, 2/4 Aa, 1/4 aa
P generation
F1 generation
F2 generation
Mendel figured out how to start a breeding experiment:
A Classical Mendelian Research Program
1/2 Aa, 1/2 aa
monohybrid crossbackcross used as a test cross
backcross used as a test cross
true breeding line “A”
true breeding line “a”
Classical genetic analysis involves 3 stepsbased on the structure of a eukaryotic life cycle
Syngamy(fertilization)
Meiosis
multicellular body(parents and offspring)
gametes
Classical genetic analysis involves 3 stepsbased on the structure of a eukaryotic life cycle
Syngamy(fertilization)
Meiosis
1. Parental Genotypes
gametes
Offspring
Classical genetic analysis involves 3 stepsbased on the structure of a eukaryotic life cycle
Syngamy(fertilization)
Meiosis
1. Parental Genotypes
2. Meiotic products = gametes
Offspring
Rules for step 2:Diploid parents making haploid gamete genotypes
AA parents produce all A gametes
aa parents produce all a gametes
but
Aa parents produce 1/2 A and 1/2 a gametes
MENDEL’S FIRST LAW
Classical genetic analysis involves 3 stepsbased on the structure of a eukaryotic life cycle
Syngamy(fertilization)
Meiosis
1. Parental Genotypes = start
2. Meiotic products = gametes
3. Fertilization products = Offspring
Predicting products of fertilization
Step 1 parental genotypes
Steps 2-3 predict gametes and combine them randomly
haploid gametes
haploid gametes
diploidoffspring
Predicting products of fertilization:
AA x AA
Step 1 AA x AA
Steps 2-3 predict gametes and combine them randomly
All A gametes
All A gametes
All AAdiploid
offspring
Genotypic ratio: all AA
Phenotypic ratio: all “A”
Predicting products of fertilization:
AA x Aa
Step 1 AA x Aa
Steps 2-3 predict gametes and combine them randomly
1/2 A 1/2 a
All A1/2 AA
Genotypic ratio: 1/2 AA and 1/2 Aa; 1:1
Phenotypic ratio: all “A”
1/2 Aa
Predicting products of fertilization:
aa x aa
Step 1 aa x aa
Steps 2-3 predict gametes and combine them randomly
All a gametes
All a gametes
All aadiploid
offspring
Genotypic ratio: all aa
Phenotypic ratio: all “a”
Predicting products of fertilization:
AA x aa
Step 1 AA x aa
Steps 2-3 predict gametes and combine them randomly
All A gametes
All a gametes
All Aadiploid
offspring
Genotypic ratio: all Aa
Phenotypic ratio: all “A”
Predicting products of fertilization:
Aa x aa
Step 1 Aa x aa
Steps 2-3 predict gametes and combine them randomly
1/2 A 1/2 a
All a gametes
Genotypic ratio: 1/2 Aa 1/2 aa
Phenotypic ratio: 1/2 “A” 1/2 “a”
1/2 Aa
1/2 aa
Test
Cross
Predicting products of fertilization:
Aa x Aa
Step 1 Aa x Aa
Steps 2-3 predict gametes and combine them randomly
1/2 A 1/2 a
Genotypic ratio: 1/4 AA 2/4 Aa 1/4 aa
Phenotypic ratio: 3/4 “A” 1/4 “a”
1/4 AA 1/4 Aa1/2 A
1/2 a 1/4 Aa 1/4 aa
Monohybrid
Cross
A Mendelian Research ProgramAA x aa
all Aa
1/4 AA, 2/4 Aa, 1/4 aa
P generation
F1 generation
F2 generation
A Classical Mendelian Research Program
1/2 Aa, 1/2 aa
monohybrid crossbackcross used as a test cross
backcross used as a test cross
true breeding line “A”
true breeding line “a”
Only monohybrid and test crosses produce patterns in the progeny
red bluex red redx
1/2 red 1/2 blue 3/4 red 1/4 blue
Only monohybrid and test crosses produce patterns in the progeny
Aared
aablue
xAared
Aared
x
1/2 Aa red 1/2 aa blue 3/4 A_ red 1/4 aa blue
Brain Teasers
• Mother and father both find the taste of phenylthiourea very bitter, but three of their four children find it tasteless. Assuming that this difference is caused by a single gene with two alleles, is the non-taster phenotype dominant or recessive (circle the correct answer)? What kind of cross is this? Be prepared to explain with a diagram of the cross that identifies phenotypes and their genotypes.
• Mother finds the taste of phenylthiourea very bitter, but father and three of their four children find it tasteless. Assuming that this difference is caused by a single gene with two alleles, is the non-taster phenotype dominant or recessive (circle the correct answer) )? What kind of cross is this? Be prepared to explain with a diagram of the cross that identifies phenotypes and their genotypes.
Remember
Monohybrid crosses provide the most information:
Informing about both dominance and the number of genes
...and the parents in monohybrid crosses look alike
Test crosses also produce different progeny phenotypes, but
...whereas the parents in test crosses look different
Hints:
• Each family produced both phenotypes in their children, so the matings must be either test crosses or monohybrid crosses.
• Parents look alike in monohybrid crosses, but not in test crosses.
Brain Teasers
• Mother and father both find the taste of phenylthiourea very bitter, but three of their four children find it tasteless. Assuming that this difference is caused by a single gene with two alleles, is the non-taster phenotype dominant or recessive (circle the correct answer)? What kind of cross is this? Be prepared to explain with a diagram of the cross that identifies phenotypes and their genotypes.
Two progeny phenotypes, parents alike:
Therefore a monohybrid cross, taster dominant:
Taster(Aa) x Taster(Aa)
3 Non-taster (aa) and Taster (AA, Aa)
Brain Teasers
• Mother finds the taste of phenylthiourea very bitter, but father and three of their four children find it tasteless. Assuming that this difference is caused by a single gene with two alleles, is the non-taster phenotype dominant or recessive (circle the correct answer) )? What kind of cross is this? Be prepared to explain with a diagram of the cross that identifies phenotypes and their genotypes.
Two progeny phenotypes, parents not alike:
Therefore a test cross, but can’t resolve dominance relationships:
Aa x aa
1/2 Aa and 1/2 aa
No Dominance
• Some heterozygotes have phenotypes unlike either homozygote. The alleles of these heterozygotes are said not to exhibit dominance.
• In this case, each genotype has a unique phenotype.
Classical genetic analysis involves 3 stepsbased on the structure of a eukaryotic life cycle
Syngamy(fertilization)
Meiosis
1. Parental Genotypes = start
2. Meiotic products = gametes
3. Fertilization products = Offspring
Homogametic and Heterogametic Genotypes XX XY
In our speciesXX = female, XY = male
Other speciesXY = female, XX = male
Sex Linkage
centromere
pairing region
differential regions
A B
Ccentromere
X chromosome
Y chromosome
Figure 1. Sex Linkage
Y Linkage
X Linkage
pseudo-autosomal