classification of metals, conductors and semiconductors...classification of metals, conductors and...
TRANSCRIPT
Classification of Metals, Conductors and Semiconductors
Solids can be classified as metals, semiconductors or insulators based
on conductivity or resistivity and energy bands in electronics. This
helps us understand the band theory and the importance of valence and
conduction bands in solids. Let us also study the types of
semiconductor.
Classification Based on Conductivity
The relative values of electrical conductivity (σ) and resistivity
(ρ=1/σ) help classify solids as:
● Metals – These are solids which have very low resistivity or
very high conductivity). Hence,
σ ~ 102 – 108 S/m
ρ ~ 10-2 – 10-8 Ωm
● Insulators – These are solids which have very high resistivity or
very low conductivity. Hence,
σ ~ 10-11 – 10-19 S/m
ρ ~ 1011 – 1019 Ωm
● Semiconductors – These are solids which have resistivity or
conductivity values between those of metals and insulators.
Hence,
σ ~ 105 – 10-6 S/m
ρ ~ 10-5 – 106 Ωm
It is important to note that these values are indicative and could go
outside the range as well. Let’s shift our focus to semiconductors.
These can be of the following types:
Types of Semiconductor
1. Elemental semiconductors – available naturally like Silicon
(Si) and Germanium (Ge)
2. Compound semiconductors – made by compounding two or
more metals together. They are sub-divided into these
categories:
a. Inorganic; like CdS, GaAs, CdSe, etc.
b. Organic; like anthracene, doped phthalocyanine, etc.
c. Organic polymers; like polypyrrole, polyaniline,
polythiophene, etc.
Most semiconductor devices available are based on elemental and
compound inorganic semiconductors. Eventually, organic
semiconductors were used and semiconducting polymers were
developed.
Classification Based on Energy Bands
Bohr’s model of the atom states that the energy of an electron is
determined by the orbit in which it revolves. This is true for an
isolated atom. In a solid, atoms are close together. Therefore, electrons
from neighbouring atoms come very close even overlap at times.
Hence, the motion of an electron is different in a solid as compared to
an isolated atom.
In an atom, electrons in the innermost orbits, which are filled are
called Valence electrons. On the other hand, electrons in the outer
orbits that do not fill the shell completely are called Conduction
electrons.
In a crystal, every electron has a unique position and different pattern
of surrounding charges. Hence, each electron has a different energy
level. These energy levels with a continuous variation of energy form
the Energy bands. The energy band which includes the energy levels
of the valence electrons is called Valence band. Also, the energy band
above it is called Conduction band. If there is no external energy
supplied, then the valence electrons stay in the valence band.
Now, electrons move from the valence band to the conduction band
when the lowest level in the conduction band is lower than the highest
level in the valence band. Usually, the conduction band is empty.
Classification of Metals, Semiconductors, and Insulators
● In case of metallic conductors, conduction band overlaps on the
electrons in the valence band.
● In insulators, there is a large gap between both these bands.
Hence, the electrons in the valence band remain bound and no
free electrons are available in the conduction band.
● Semiconductors have a small gap between both these bands.
Some valence electrons gain energy from external sources and
cross the gap between the valence and conduction bands. By
this movement, they create a free electron in the conduction
band and a vacant energy level in the valence band for other
valence electrons to move. This creates the possibility of
conduction.
Let’s understand this better with the following diagrams and
explanations:
Case 1.
Ec denotes the lowest energy level of the conduction band and Ev
denotes the highest energy level of the valence band. The above
diagram describes a solid where the valence band is partially empty.
Hence, electrons from the lower energy levels can move to the higher
levels making conduction possible. Also, the resistivity of such solids
is low or the conductivity is high.
Case 2.
Ec and Ev are the same as case 1 and Eg is the energy gap. This
diagram describes a solid where the conduction and valence bands
overlap each other. Hence, electrons can easily move from the valence
to the conduction band. This makes a large number of electrons
available for conduction. Also, the resistivity of such solids is low or
the conductivity is high.
Case 3.
This diagram describes a solid where the energy gap (Eg) is very large
(>3 eV). Due to this large gap, electrons cannot be excited to move
from the valence to the conduction band by thermal excitation. Hence,
there are no free electrons in the conduction band and no conductivity.
These are insulators.
Case 4.
This diagram describes a solid where the energy gap is small (< 3 eV).
Since the gap is small, some electrons acquire enough energy even at
room temperature and enter the conduction band. These electrons can
move in the conduction band increasing the conductivity of the solid.
These are semiconductors. The resistivity of semiconductors is lower
than that of insulators but higher than that of metals.
Solved Examples for You
Question: Name the different types of semiconductors with examples.
Solution: Semiconductors are of the following types:
● The ones available naturally like Silicon and Germanium –
Elemental Semiconductors. Also, the ones made by
compounding two or more metals together – Compound
Semiconductors.
● Further, compound semiconductors are of three types –
inorganic (CdS, GaAs, etc.), organic (anthracene, etc.) and
organic polymers (polypyrrole, polyaniline, etc.).
Question: What are valence and conduction bands?
Solution: In a crystal, every electron has a different energy level.
These different energy levels along with the continuous variation of
energy are called Energy bands. The energy band which includes the
energy levels of the valence electrons is called the valence band. And
the band above it is called the conduction band.
Intrinsic Semiconductor
An Intrinsic Semiconductor is the purest form of a semiconductor,
elemental, without any impurities. Naturally available elements like
silicon and germanium are best examples of an Intrinsic
Semiconductor. Let’s know them in further more detail.
The Lattice Structure of Elements
They are also called diamond-like structures. In such structures, every
atom is surrounded by four neighbouring atoms. Now, both Si and Ge
have four valence electrons and in the crystalline structure, each atom
shares one of its valence electrons with each of its four neighbours.
Also, it takes one electron from each of its neighbours. This shared
pair of electron is called a Covalent bond or a Valence bond. This is
how the Si or Ge structure looks in two-dimensions with emphasis on
the covalent bond:
Also, the above image shows the structure with all bonds intact. This
is possible only at low temperatures. As the temperature increases and
more energy becomes available to the valence electrons, they break
away leading to an increase in conductivity of the element.
Now, the thermal energy ionizes only a few atoms. This ionization
creates a vacancy in the bond. When an electron, having charge –q,
gets excited due to the thermal energy, it breaks free from the bond.
This leaves a vacancy there with effective charge +q. This vacancy
with an effective positive electronic charge is a hole.
The hole also behaves like a free particle but with a positive charge. In
intrinsic semiconductors, the number of free electrons is equal to the
number of holes and is called the intrinsic carrier concentration.
Intrinsic Semiconductor – The Movement of Holes
Another interesting property of semiconductors is that like the
electrons, the holes move too. Consider the following image:
In the image above, you can see that an electron, after being excited
due to thermal energy breaks itself away from the bond, generating a
free electron. (Site1) A vacancy is created at the site from where the
electron releases itself. Now, imagine that an electron from Site 2, as
shown in the image, jumps to the hole or vacancy created in Site 1.
The hole will now have moved from Site1 to Site2 as shown in the
image below:
It is important to observe that the electron freed from Site 1 is not
involved in the movement of the hole. It moves independently like a
conduction electron contributing to electron current (Ie) under an
applied electric field. Also, movement of the hole is actually a
movement of bound electrons.
Under an electric field, these holes move towards the negative
potential generating hole current (Ih). Hence, the total current (I) is:
I = Ie + Ih
Another important thing to remember is that apart from the process of
the generation of free electrons and holes, a process of recombination
takes place simultaneously. In this process, the electrons recombine
with the holes. In the state of equilibrium, the rate of generation is
equal to the rate of recombination.
Intrinsic Semiconductor at T = 0K
At T = 0K, an intrinsic semiconductor will behave like an insulator.
Structurally, there is a small energy gap between the valence and
conduction bands in a semiconductor. When the temperature is low,
the electrons are not excited enough to jump to a higher energy state.
The image below explains how at T = 0K, the electrons stay in the
valence band and there is no movement to the conduction band.
When the temperature increases, at T > 0K, some electrons get
excited. These electrons jump from the valence to the conduction
band. Here is how it will look:
Solved Examples for You
Question: How many valence electrons does silicon have?
A. 1
B. 2
C. 3
D. 4
Solution: Option (D) Silicon has 4 valence electrons.
Question: If we add an impurity to a metal those atoms also deflect electrons.
Therefore,
A. Electrical and thermal conductivities both increase
B. Electrical and thermal conductivities both decrease
C. Thermal conductivity increases but electrical conductivity
decreases
D. Electrical conductivity increases but thermal conductivity
decreases
Solution: Option (B).
If the number of electrons increases, collisions between them also
increase thus increasing the thermal and electrical resistance. So,
electrical and thermal conductivities both decrease.
Extrinsic semiconductors
Semiconductors can be broadly classified into Intrinsic and Extrinsic
Semiconductors. Intrinsic Semiconductors start conducting at
temperatures above the room temperature, developing important
electronic devices using these can pose a problem. This led to a need
for improving the conductivity of intrinsic semiconductors. Let’s find
out more.
Extrinsic Semiconductors
After some experiments, scientists observed an increase in the
conductivity of a Semiconductor when a small amount of impurity
was added to it. These materials are Extrinsic Semiconductors or
impurity Semiconductors. Another term for these materials is ‘Doped
Semiconductor’. The impurities are dopants and the process – Doping.
An important condition to doping is that the amount of impurity added
should not change the lattice structure of the Semiconductor. To
achieve this the size of the dopant and Semiconductor atoms should be
the same.
Types of Dopants in Extrinsic Semiconductors
Crystals of Silicon and Germanium are doped using two types of
dopants:
1. Pentavalent (valency 5); like Arsenic (As), Antimony (Sb),
Phosphorous (P), etc.
2. Trivalent (valency 3); like Indium (In), Boron (B), Aluminium
(Al), etc.
The reason behind using these dopants is to have similarly sized atoms
as the pure semiconductor. Both Si and Ge belong to the fourth group
in the periodic table. Hence, the choice of dopants is from the third
and fifth group. This ensures that size of the atoms is not much
different from the fourth group. Hence, the trivalent and pentavalent
choices. These dopants give rise to two types of semiconductors:
1. n-type
2. p-type
n-type semiconductor
An n-type semiconductor is created when pure semiconductors, like Si
and Ge, are doped with pentavalent elements.
As can be seen in the image above, when a pentavalent atom takes the
place of a Si atom, four of its electrons bond with four neighbouring
Si atoms. However, the fifth electron remains loosely bound to the
parent atom. Hence, the ionization energy required to set this electron
free is very small. Thereby, this electron can move in the lattice even
at room temperature.
To give you a better perspective, the ionization energy required for
silicon at room temperature is around 1.1 eV. On the other hand, by
adding a pentavalent impurity, this energy drops to around 0.05 eV.
It is important to remember that the number of electrons made
available by the dopant atoms is independent of the ambient
temperature and primarily depends on the doping level. Also, as the
temperature rises, the Si atoms free some electrons and generate some
holes. But, the number of these holes is very small. Hence, at any
given point in time, the number of free electrons is much higher than
the number of holes. Also, due to recombination, the number of holes
reduce further.
In a nutshell, when a semiconductor is doped with a pentavalent atom,
electrons are the majority charge carriers. On the other hand, the holes
are the minority charge carriers. Therefore, such extrinsic
semiconductors are called n-type semiconductors. In an n-type
semiconductor,
Number of free electrons (ne) >> Number of holes (nh)
p-type semiconductor
A p-type semiconductor is created when trivalent elements are used to
dope pure semiconductors, like Si and Ge. As can be seen in the image
above, when a trivalent atom takes the place of a Si atom, three of its
electrons bond with three neighbouring Si atoms. However, there is no
electron to bond with the fourth Si atom.
This leads to a hole or a vacancy between the trivalent and the fourth
silicon atom. This hole initiates a jump of an electron from the outer
orbit of the atom in the neighbourhood to fill the vacancy. This creates
a hole at the site from where the electron jumps. In simple words, a
hole is now available for conduction.
It is important to remember that the number of holes made available
by the dopant atoms is independent of the ambient temperature and
primarily depends on the doping level. Also, as the temperature rises,
the Si atoms free some electrons and generate some holes. But, the
number of these electrons is very small. Hence, at any given point in
time, the number of holes is much higher than the number of free
electrons. Also, due to recombination, the number of free electrons
reduce further.
In a nutshell, when a semiconductor is doped with a trivalent atom,
holes are the majority charge carriers. On the other hand, the free
electrons are the minority charge carriers. Therefore, such extrinsic
semiconductors are called p-type semiconductors. In a p-type
semiconductor,
Number of holes (nh) >> Number of free electrons (ne)
Important note: The crystal maintains an overall charge neutrality. The
charge of additional charge carries is equal and opposite to that of the
ionized cores in the lattice.
Energy Bands of Extrinsic Semiconductors
In extrinsic semiconductors, a change in the ambient temperature
leads to the production of minority charge carriers. Also, the dopant
atoms produce the majority carriers. During recombination, the
majority carriers destroy most of these minority carriers. This leads to
a decrease in the concentration of the minority carriers.
Therefore, this affects the energy band structure of the semiconductor.
In such semiconductors, additional energy states exist:
● Energy state due to donor impurity (ED)
● Energy state due to acceptor impurity (EA)
The above energy band diagram is of n-type Si semiconductor. Here
you can see that the energy level of the donor (ED) is lower than that
of the conduction band (EC). Hence, electrons can move into the
conduction band with minimal energy (~0.01 eV). Also, at room
temperature, most donor atoms and very few Si atoms get ionized.
Hence, the conduction band has most electrons from the donor
impurities.
The above energy band diagram is of p-type Si semiconductor. Here
you can see that the energy level of the acceptor (EA) is higher than
that of the valence band (EV). Hence, electrons can move from the
valence band to the level Ea, with minimal energy. Also, at room
temperature, most acceptor atoms are ionized.
This leaves holes in the valence band. Hence, the valence band has
most holes from the impurities. The electron and hole concentration in
a semiconductor in thermal equilibrium is:
ne × nh = ni2
Do you know what is p-n Junction ?
Solved Examples for You
Question: What are Extrinsic Semiconductors?
Solution: Extrinsic Semiconductors are pure semiconductors which
conduct even at room temperature. This is achieved by adding
impurities to the pure semiconductor.
Question: Who are the major charge carriers in n-type and p-type
semiconductors?
Solution: In n-type semiconductors, electrons are the major charge
carriers. In p-type semiconductors, holes are the major charge carriers.
p-n Junction
Understanding the formation and functioning of a p-n Junction is
paramount to analyzing the working of semiconductor devices. Let’s
look at how a p-n Junction is formed and how it behaves under a bias
(or an externally applied voltage).
Formation of a p-n Junction
Let’s imagine a thin p-type silicon (p-Si) semiconductor wafer. Now,
we add a pentavalent impurity to it. Due to this, a small part of the
p-Si wafer is converted into an n-Si. Now, the wafer contains a
p-region and an n-region with a metallurgical junction between the
two. Two important processes take place during the formation of a p-n
Junction:
1. Diffusion
2. Drift
In an n-type semiconductor, the concentration of electrons is more
than that of holes. On the other hand, in a p-type semiconductor, the
concentration of holes is more than that of electrons.
When a p-n junction is being formed, holes diffuse from the p-side to
the n-side (p→n) while electrons diffuse from the n-side to the p-side
(n→p). This happens due to the concentration gradient across p and n
sides. This gives rise to a diffusion current across the junction. Let’s
look at both the scenarios:
Electron Diffuses from n→p
This diffusion leaves an ionized donor (or a positive charge) on the
n-side. This donor is bonded to the surrounding atoms and is
immobile. As more and more electrons start diffusing to the p-side, a
layer of positive charge (or positive space-charge region) in the n-side
of the junction is formed.
Learn Junction Transistor here in detail.
Hole Diffuses from p→n
This diffusion leaves an ionized acceptor (or a negative charge) on the
p-side. As more and more holes start diffusing to the n-side, a layer of
negative charge (or negative space-charge region) on the p-side of the
junction is formed.
Since the diffusion of electrons and holes across the junction depletes
the region of its free charges, these space charge regions together are
called the depletion region.
This process is depicted in the image above. The thickness of the
depletion region is merely around one-tenth of a micrometre. Also, an
electric field develops, directed from the p-side to the n-side of the
junction. This is because of the positive space-charge region on the
n-side and the negative space-charge region on the p-side of the
junction.
This electric field is responsible for the movement of electrons from
the p-side to the n-side and holes from the n-side to the p-side. This
motion of charged carriers due to the electric field is called drift.
Hence, a drift current starts which is opposite in direction to the
diffusion current. This is also seen in the image above.
Study Semiconductor Diode here in detail.
The Last Stages of Formation of a p-n Junction
When the diffusion starts, the diffusion current is large and the drift
current is very small. As diffusion continues, the space-charge regions
on either side of the junction start extending. This strengthens the
electric field and eventually the drift current. The process continues
till diffusion current = drift current. This is how a p-n junction is
formed.
Barrier Potential
In the state of equilibrium, there is no current in a p-n junction. A
difference of potential develops across the junction of the two regions
due to the loss of electrons by the n-region and the subsequent gain by
the p-region. The polarity of the potential opposes the further flow of
carriers to maintain the state of equilibrium. This is the Barrier
Potential.
Solved Examples for You
Question: Why is a photodiode is used in reverse bias?
A. Photocurrent flows only in reverse bias
B. Thermally generated current is large in reverse biased as
compared to the photocurrent
C. Photocurrent is large in forward bias as compared to the
forward bias current
D. Photocurrent is significant in reverse bias as compared to the
reverse bias current
Solution: Option (D)
When a photo-diode is reverse biased, the width of depletion layer
increases as compared to forward biased and a small reverse current
(dark current) flows through the diode. Now, when the light is incident
on the junction, electron-hole pairs are generated in depletion layer in
a big amount (due to broad depletion layer) and these charge carriers
can easily cross the barrier, hence contribute to current across the
diode. We can say that in reverse bias, diode changes the incident light
to current, more significantly due to broad depletion layer i.e.
photocurrent is significant in reverse bias as compared to the forward
bias current.
Question: The curve represents the I−V characteristics of which
optoelectronic device?
A. Solar Cell
B. Photo-diode
C. LED( Light Emitting Diode)
D. None of these
Solution: Option (A) Solar Cell
Question: From the adjacent circuit, the output voltage is
A. 10 V
B. 100 V
C. 90 V
D. 0 V
Solution: Here, Zener diode is connected parallel to the input voltage
source. Zener diode is known as a voltage regulating diode hence, the
output voltage will be equal to the voltage across Zener diode i.e. 10V
Special Purpose p-n Junction Diode
Let’s look at some p-n junction diodes, developed for specific
applications. We will cover Zener diode and Opto-electronic junction
devices including photodiodes, light emitting diode, and solar cells.
Zener Diode
C. Zener designed a p-n junction diode in reverse bias to operate in the
breakdown region. It is used as a voltage regulator. The symbol for a
Zener diode is:
It is made by doping both p and n sides of the junction heavily. This
leads to the formation of a very thin depletion region and an extremely
high electric field across the junction even for a small reverse bias
voltage (~5 V). Here is a quick look at the V-I characteristics of a
Zener diode:
In the above graph, you can see that as the reverse bias voltage (V)
reaches the breakdown voltage of the Zener diode (Vz), there is a large
change in current. Also, note that for a negligible change in the
reverse bias voltage, a large change in current is produced. Hence, in a
Zener diode, the voltage remains nearly constant even when there is a
large change in current. This property is used to regulate supply
voltages.
Why does the current increase suddenly?
This is really interesting. We know that the reverse current is created
due to the movement of the minority charge carriers. The electrons
from the p-side move to the n-side and the holes from the n-side move
to the p-side. As we increase the reverse bias voltage, the electric field
at the junction becomes stronger.
At V=Vz, the electric field is strong enough to pull valence electrons
from the host atoms on the p-side which are accelerated to n-side. This
explains the sudden increase in current. This process of emission of
electrons from the host atoms due to a high electric field is known as
Internal Field Emission or Field Ionization.
Zener Diode as a Voltage Regulator
By now we know that even if we use a rectifier to convert AC input
voltage, the output fluctuates too. A Zener diode is used to get
constant DC voltage from a DC unregulated output of a rectifier.
This is a circuit diagram of a Zener diode used as a voltage regulator.
Here the unregulated DC output of a rectifier is connected to it
through a series of resistance (Rs). Also, it is in reverse bias. Here is
how it works:
● An increase in input voltage increases the current through Rs
and the diode
● The voltage drop across Rs increases
● The voltage across the Zener diode does not change
This happens because, in the breakdown region, Zener voltage
remains constant despite the change in current.
● A decrease in the input voltage decreases the current through
Rs and the diode
● The voltage drop across Rs decreases
● The voltage across the Zener diode does not change
Hence, an increase/decrease of the voltage drop across the Rs does not
change the voltage across the Zener diode. Hence, it acts as a voltage
regulator.
Optoelectronic Junction Devices
Till now, you have read about how semiconductor diodes behave
under electrical inputs. Now, let’s look at how they react to
photo-excitation. These are optoelectronic devices or devices in which
carriers are generated by photons. Let’s look at three such devices:
1. Photodiodes to detect optical signals
2. Light Emitting Diodes (LEDs)
3. Solar cells
Photodiodes
This is a special p-n junction diode operated in reverse bias and
designed with a transparent window to allow light to fall on it. When
photons with energy (hv) greater than the energy gap of the
semiconductor fall on it, electron-hole pairs are generated. The diode
is designed in a manner that these electron-hole pairs are generated in
or near the depletion region.
Also, the electric field at the junction ensures that the electrons and
holes are separated before they recombine. Further, the direction of
the electric current is to ensure that the electrons reach the n-side and
holes reach the p-side. This gives rise to an EMF.
Current flows on connecting an external load. Also, the magnitude of
this photocurrent depends on the intensity of the incident light. The
direct correlation between the two is easily observed on application of
a reverse bias. Hence, a photodiode can detect optical signals. Here is
a circuit diagram of a photodiode:
Light emitting diode (LED)
A LED is a heavily doped p-n junction which emits spontaneous
radiation under forward bias. It is covered in a capsule with a
transparent cover allowing the emitted light to come out. Being
forward biased, electrons move from n to p-side and holes move from
p to n-side.
Also, the concentration of the minority carriers is higher near the
junction as compared to the equilibrium concentration. Hence, at the
junction, on either side, excess minority carriers recombine with the
majority carriers. This releases energy in the form of photons. The
photons emitted have energies equal to or less than the band gap.
Another thing to note here is that the intensity of the emitted light is
small when the forward current is small. The intensity of the emitted
light increases as this current increases and reached a maximum value.
Post this, an increase in forward current leads to a decrease in light
intensity.
Commercially available LEDs can emit red, yellow, orange, green and
blue light. LEDs are used extensively in remote controls, optical
communication, etc. Here are some advantages of LEDs over
incandescent low power lamps:
● Low operational voltage and less power.
● Fast action and no warm-up time required.
● The bandwidth of emitted light is 100 Å to 500 Å or in other
words, it is nearly (but not exactly) monochromatic.
● Long life and ruggedness.
● Fast on-off switching capability.
Solar Cell
A solar cell is a p-n junction which generates EMF when solar
radiation falls on it. The working principle is similar to the photodiode
except that no external bias is applied and the junction area is much
larger to enable solar radiation incidence. This is how a simple p-n
junction solar cell looks:
When sunlight falls on a solar cell, the EMF is generated due to these
three processes:
● Generation of electron-hole pairs due to light (with hν > Eg)
close to the junction
● Separation of electrons and holes due to the electric field of the
depletion region. Electrons are swept to n-side and holes to
p-side.
● Collection – the electrons reaching the n-side are collected by
the front contact and holes reaching p-side are collected by the
back contact. Thus p-side becomes positive and n-side becomes
negative giving rise to photo-voltage.
The above diagram shows an external load connected to a solar cell
leading to a flow of photocurrent. The V-I characteristics can be
graphically shown as follows:
The correlation is shown in the fourth quadrant because the solar cell
does not draw current but supplies it to the load. Also, remember that
sunlight is not always required for a solar cell. A light having a
frequency greater than the band gap suffices.
Solved Examples for You
Question: How does a Voltage regulator using Zener diode work?
Solution: The unregulated DC output of a rectifier is connected to a
Zener diode through a series of resistance (Rs). Also, it is in reverse
bias. Here is how it works:
● An increase in input voltage increases the current through Rs
and the diode
● The voltage drop across Rs increases
● The voltage across the Zener diode does not change
This happens because, in the breakdown region, Zener voltage
remains constant despite the change in current.
● A decrease in the input voltage decreases the current through
Rs and the diode
● The voltage drop across Rs decreases
● The voltage across the Zener diode does not change
Hence, an increase/decrease of the voltage drop across the Rs does not
change the voltage across the Zener diode. Hence, it acts as a voltage
regulator.
Semiconductor Diode
Imagine a p-n junction with metallic contacts at both the ends for
application of external voltage. This is a semiconductor diode.
This is the symbolical representation of a semiconductor diode:
In the image above, the arrow indicates the direction of current when
the diode is under forward bias. It is also important to note here that
the equilibrium barrier potential can be altered. This is achieved by
applying an external voltage across the diode. Depending on how this
voltage is applied, a semiconductor diode is a forward-bias or a
reverse-bias diode.
Semiconductor Diode under Forward Bias
In the image above, you can see that an external voltage is applied
across the semiconductor diode where the p-side of the diode is
connected to the positive terminal and the n-side is connected to the
negative terminal of the battery. This diode is forward biased.
Formation of a Forward Bias Diode
Since the resistance of the depletion region (the region where there are
no charges) is very high, the applied voltage drops primarily across
this region. The drop in voltage across the p and n side of the junction
is relatively negligible. Also, the direction of the applied voltage (V)
being opposite to that of the built-in potential (V0), the depletion
layer’s width decreases and the barrier height reduce.
If the applied voltage is small, then the barrier potential is reduced
marginally below the equilibrium value. This results in a small
number of carriers crossing the junction. Hence, the current is small.
On the other hand, for a significantly high value of voltage, more
carriers have the energy to cross the junction. This leads to a higher
current.
Another thing to note is that when the voltage is applied, some
electrons crossover to the p-side and some holes cross to the n-side.
Under forward bias, this process is the minority charge injection
process (refer to image below). Hence, the minority charge
concentration (electrons on the p-side are a minority and holes on the
n-side are a minority) is significantly higher at the junction boundary.
This concentration gradient, the injected electron diffuse from the
junction-end to the far-end of the p-side. Similarly, injected holes
diffuse to the far end of the n-side. This gives rise to current too.
The total diode forward current = Hole diffusion current + Electron
diffusion current (usually in mA)
Semiconductor Diode under Reverse Bias
In the image above, you can see that an external voltage is applied
across the semiconductor diode. The n-side of the diode connects to
the positive terminal and the p-side connects to the negative terminal
of the battery. This diode is a reverse-bias diode.
Formation of a Reverse Bias Diode
Since the resistance of the depletion region (the region where there are
no charges) is very high, the applied voltage drops primarily across
this region. The drop in voltage across the p and n side of the junction
is relatively negligible.
Also, the direction of the applied voltage (V) being the same as that of
the built-in potential (V0), the depletion layer’s width widens and the
barrier height increases. This leads to a suppression of the flow of
electron to the p-side and holes to the n-side. Hence, the diffusion
current decreases to a great extent.
Due to the direction of the electric field, the electrons in the p-side and
holes in the n-side are swept to their majority zones, if they come
close to the junction. This causes drift current. The drift current is
usually of a few μA. This current is very low even in the
forward-biased diode as compared to the current due to the injected
carriers.
Critical Value of Reverse Bias Voltage
Also, a small amount of voltage applied to the diode is sufficient to
sweep the minority charge carrier to the far side of the junction. This
diode reverses current is not dependent on the voltage but on the
concentration of the minority charge carriers on both sides of the
junction.
However, the current is independent up to a critical value of reverse
bias voltage – the Breakdown Voltage (Vbr). When the voltage applied
crosses Vbr, even a small change in the bias voltage causes a huge
change in current. There is also an upper limit of current for every
diode, beyond which it gets destroyed due to overheating. This is the
rated value of current.
Experimental Study of the V-I characteristics of a Semiconductor Diode
The above diagram shows a diode connected in forward bias. The
battery connects to the diode through a potentiometer enabling us to
change the voltage for the sake of the experiment. A milliammeter
measures the current.
This diagram shows a diode connected in reverse bias. The battery
connects to the diode through a potentiometer enabling us to change
the voltage for the sake of the experiment. A microammeter (since the
expected current is low) measures the current. Here is what we
observe:
As can be seen in the graph above, in the forward biased diode,
initially the current increases almost negligibly till a certain value is
reached. Post that, the current increases exponentially even for a small
increase in diode bias voltage. This voltage is the threshold voltage.
(~0.7 V for silicon diode and ~ 0.2 V for germanium diode)
In the reverse biased diode, the current is very small and almost
remains constant with a change in bias voltage. It is the Reverse
saturation current. In some cases, beyond the breakdown voltage, the
current increases suddenly.
Hence, from this experiment, we can conclude that the p-n junction
diode allows the flow of current only in one direction, i.e.
forward-bias. Also, the forward bias resistance is lower than the
reverse bias resistance.
Solved Examples for You
Question: Define a forward-bias diode
Solution: When you apply an external voltage across a p-n junction
diode such that:
● the positive terminal of the battery connects to the p-side and
● the negative terminal to the n-side
It is a forward-bias diode.
Question: Define a reverse-bias diode
Solution When you apply an external voltage across a p-n junction
diode such that:
● the positive terminal of the battery connects to the n-side and
● the negative terminal to the p-side
It is a reverse-bias diode.
Digital Electronics and Logic Gates
We live in a digital world. Understanding digital electronics is
necessary to make the most of digitization. In this article, we will try
to understand Logic gates which are the building blocks of digital
electronics.
Continuous or Analogue Signals
If you look at amplifiers or oscillators, the input signal used is a
continuous, time-varying current or voltage. These signals are
Continuous or Analogue Signals. They look like:
Now, it is possible to have an input signal with discrete values of
voltage. Or in simple words, an input signal which provides Level 0 or
Level 1 voltage. These signals are Digital Signals; refer to the diagram
below:
Binary numbers (0 and 1) are used to represent such signals. Only
these two levels of voltage are used in digital electronics. Both input
and output are either Level 0 or Level 1.
A classic example of digital signals: When you switch on a light in
your house, the output value is Level 1 which turns the light ON.
When you switch it off, the output value drops to Level 0, switching
the light OFF.
Logic Gates process digital signals in a specific manner and are used
in calculators, digital watches, etc. Let’s understand them better.
Logic Gates
For digital devices to function the way they do, a logic needs to be
established between the input and output voltages. This is achieved by
using a gate or a digital circuit that follows the logical relationship.
Since the control the flow of information based on a certain logic, they
are called logic gates.
Each logic gate is indicated by a symbol and has a truth table which
displays all possible input-output combinations. In short, the truth
tables help understand the behaviour of the logic gates. These gates
are made using semiconductor devices. The five most commonly used
logic gates are:
● NOT
● AND
● OR
● NAND
● NOR
Let’s study each one of them in detail.
1. NOT gate
A simple gate with one input and one output, a NOT gate simply
inverts the input signal. So, the output is ‘0’ when the input is ‘1’ and
vice-versa. Due to this property, a NOT gate is also known as an
inverter. Here is the commonly used symbol for a NOT gate:
And, the truth table for a NOT gate is as follows:
Input (A) Output (Y)
0 1
1 0
2. OR Gate
An OR gate has two or more inputs and one output. The logic of this
gate is that the output would be 1 when at least one of the inputs is 1.
Simply put, the output is high when any of the input is high. The
commonly used symbol for an OR gate is as follows:
And, the truth table for an OR gate is as follows:
Input Output
A B Y
0 0 0
0 1 1
1 0 1
1 1 1
3. AND gate
An AND gate also has two or more inputs and a single output. In this
gate, the output is 1 when all the inputs are 1. In other words, the
output is high when all the inputs are high. The most commonly used
symbol for an AND gate is as follows:
And the truth table for the AND gate is as follows:
Input Output
A B Y
0 0 0
0 1 0
1 0 0
1 1 1
4. NAND gate
A NAND gate is simply an AND gate followed by a NOT gate.
Confused? It’s simple. The output is 1 only when all inputs are NOT
1. Or the output is high when all the inputs are NOT high and at least
one of them is low. These are also called Universal gates since the
earlier three gates can be realized, y using the NAND gate. The
commonly used symbol for a NAND gate is as follows:
And, the truth table for a NAND gate is as follows:
Input Output
A B Y
0 0 1
0 1 1
1 0 1
1 1 0
As can be seen above, it is the opposite of an AND gate –
(NOT+AND = NAND).
5. NOR gate
A NOR gate is simply an OR gate followed by a NOT gate. The
output is 1 only when all inputs are 0. Or the output is high when all
the inputs are low. These are also called Universal gates since the
earlier three gates can be realized by using the NOR gate. The
commonly used symbol for a NOR gate is as follows:
And the truth table for a NOR gate is as follows:
Input Output
A B Y
0 0 1
0 1 0
1 0 0
1 1 0
As can be seen above, it is the opposite of an OR gate – (NOT+OR =
NOR).
Solved Examples for You
Question: Write the truth table for the NAND gate connected as given
below:
Solution: A NAND gate has two or more inputs and one output. In the
image above, the inputs are connected together. This means that when
‘A’ is low, all inputs for the NAND gate will be low and vice-versa.
Now, the original NAND truth table is as follows:
Input Output
A B Y
0 0 1
0 1 1
1 0 1
1 1 0
Since, inputs A and B are connected together, when A=0, both A, and
B are 0. Also, when A=1, both A and B are 1. Hence the truth table
will be as follows:
Input (A) Output (Y)
0 1
1 0
This is exactly the truth table for a NOT gate. Hence, a NAND gate
connected as shown in the example above works like a NOT gate.
Question:
Write the truth table for circuit given in the figure below consisting of
NOR gates and identify the logic operation (OR, AND, NOT) which
this circuit is performing.
Solution: The above image is a combination of two NOR gates. The
first gate functions like a normal NOR gate following the below
mentioned truth table:
Input Output
A B Y
0 0 1
0 1 0
1 0 0
1 1 0
In the second gate, the A and B inputs are connected together. So,
when A=0, both A and B are 0 and vice-versa. Hence the truth table
for this gate will be as follows:
Input (A) Output (Y)
0 1
1 0
This is the truth table for a NOT gate. Combining the two together, we
get a NOR gate followed by a NOT gate. So, the truth table for the
example cited above becomes:
Input Output
A B Y
0 0 0
0 1 1
1 0 1
1 1 1
This is the truth table for an OR gate. Hence, the diagram above uses
NOR gate to function like an OR gate.
Junction Transistor – Structure and Action
In 1951, William Schockley invented the first junction transistor with
two back to back p-n junctions. Over the years, different types of
transistors were invented and to differentiate the junction transistor
from the new ones it is now called Bipolar Junction Transistor (BJT).
In this chapter, since we are not talking about any other transistors we
will use the words ‘transistor’, ‘junction transistor’ and ‘Bipolar
Junction Transistor’ interchangeably.
Introduction to a Junction Transistor
A junction transistor has three doped regions – emitter, base, and
collector. These regions form two p-n junctions between them.
Depending on the number of n and p-type semiconductors in the
transistor, they are of two types:
● n-p-n transistor: A p-type semiconductor (base) separates two
segments of the n-type semiconductor (emitter and collector).
● p-n-p transistor: An n-type semiconductor (base) separates two
segments of the p-type semiconductor (emitter and collector.
As can be seen in both the figures above, all three segments have
different thickness and doping levels. The schematic symbols of both
these transistors are as follows:
The arrowhead shows the direction of the conventional current in the
transistor. Let’s understand the three segments in detail:
Emitter This segment is on one side of the transistor. It has a moderate size and is heavily doped causing it to supply a large number of carriers for the flow of current.
Base This segment is at the centre of the transistor. It is thin and lightly doped.
Collector This segment is also on one side of the transistor. It is larger than the emitter and is moderately doped. Hence, it collects most of the majority carriers supplied by the emitter.
Also, in the case of a junction transistor, the depletion regions are
formed at the emitter-base junction and the base-collector junction. To
understand the action of the transistor, it is important to consider the
nature of depletion regions formed at these junctions.
It is also important to note here that junction transistor was invented to
produce an enlarged copy of a signal – an amplifier. Eventually, it
became equally popular as a switch.
The Amplifying Capabilities of a Junction Transistor
A junction transistor works as an amplifier when,
1. The emitter-base junction is forward biased and
2. The base-collector junction is reverse biased.
The circuit diagram for the same is as shown below:
As can be seen above, the base is the common terminal for two power
supplies whose other terminals are connected to the emitter and
collector.
Some Terminologies
● The voltage between emitter and base = VEB
● The voltage between collector and base = VCB
● VEE = Power supply connected between the emitter and base
● VCC = Power supply connected between the collector and base
Let us now study the path of the current carriers in the junction
transistor where –
● The emitter-base junction is forward biased and
● The Base-collector junction is reverse biased
The emitter is heavily doped and has a large concentration of the
majority carriers. These majority carriers enter the base in large
numbers. Since the base is very thin and lightly doped, it has very few
majority carriers. Let’s look at the path of current in a p-n-p transistor:
p-n-p Transistor
The emitter has a large concentration of holes. The base, being an
n-type semiconductor will have electrons as its majority charge
carriers. When the majority carriers (holes) enter the base from the
emitter, they swamp the majority charge carriers of the base
(electrons). The base-collector junction is reverse biased.
Hence, these holes appear as minority carriers at the junction. Hence,
they can easily enter the collector (which is a p-type semiconductor).
The holes in the base can either:
● Move towards the base terminal to combine with the electrons
entering from outside or
● Cross the junction and enter the collector.
Since the base is very thin, most of the holes find themselves near the
base-collector junction (reverse biased). Hence, they cross over to the
collector rather than move to the base terminal.
Observations
The forward bias leads to a large current entering the emitter-base
junction. However, most of it diverts to the adjacent base-collector
junction. Hence, the current coming out of the base is a small fraction
of that entering the junction. The total current in a forward biased
diode is Ih + Ie … where Ih is the hole current and Ie is the electron
current.
The emitter current IE = Ih + Ie. However, the base current IB << Ih +
Ie. This is because a big part of IE goes to the collector instead of the
base terminal. Now, current enters the emitter from outside. Applying
Kirchhoff’s law:
IE = IC + IB
where IC is the current emerging from the collector terminal. Also, IC
is nearly equal to IE since IB is very small.
n-p-n Transistor
In an n-p-n transistor, current enters from the base to the emitter. The
description of the paths followed by the majority and minority charge
carriers is similar to that of the p-n-p transistor. However, the current
paths are exactly the opposite.
In an n-p-n transistor, electrons are the majority charge carriers,
supplied by the n-type emitter region. They cross the thin p-type base
region and are able to reach the collector to give the collector current,
IC.
Solved Examples for You
Question: Name and describe the three regions of a junction transistor
Solution: A junction transistor comprises three regions – emitter, base,
and collector. The emitter is on one side of the transistor. It is
moderate in size and heavily doped. Also, it supplies a large number
of majority charge carriers. The base lies at the centre of the transistor.
It is very thin and lightly doped. The collector is on the other side of
the transistor. It is large in size and moderately doped. Also, it collects
most of the majority carriers supplied by the emitter.
Junction Transistor – Circuit Configurations and Characteristics
In a junction transistor, the Emitter (E), Base (B) and Collector (C) are
the only three terminals available. Hence, in any circuit, one of these
terminals has to be common to both input and output connections.
Therefore, the junction transistor can be connected in either of these
configurations:
● CE or Common Emitter
● CB or Common Base
● CC or Common Collector
Among these, the junction transistor is most widely used in the
Common Emitter configuration. Also, the n-p-n Silicon transistors are
used more commonly than the p-n-p transistors. Hence, we will look
at the characteristics and configurations of an n-p-n Silicon Junction
Transistor in a CE configuration.
Characteristics of a CE Junction Transistor
In Common Emitter (CE) configuration, the emitter is the common
terminal. Hence, the input is between the base and the emitter while
the output is between the collector and the emitter. Two terms that you
must remember:
● Input characteristic – the variation of the base current (IB) with
the base-emitter voltage (VBE)
● Output characteristic – the variation of the collector current (IC)
with the collector-emitter voltage (VCE)
It is observed that the output characteristics are controlled by the input
characteristics. Hence, the collector current changes with the base
current. Let’s study them with the help of a circuit diagram shown
below:
Studying the Input Characteristics
Also, a curve is plotted between the base current (IB) and the
base-emitter voltage (VBE) to study the input characteristics of the
junction transistor in CE configuration. The collector-emitter voltage
(VCE) is kept at a fixed value to study the relation between IB and
VBE.
Since we intend to study the input characteristics when the transistor is
in an active state, VCE is maintained at a large value. The value chosen
is large enough to ensure reverse biasing of the base-collector
junction. For a Silicon transistor, VCE = 0.6-0.7 V. Also,
VCE = VCB + VBE
Hence, VCE has to be maintained at a value much larger than 0.7 V.
The approximate range of voltage is between 3 and 20 V. An increase
in the value of VCE appears as an increase in the value of VCB. Hence,
we get almost identical curves for various values of VCE. Also,
determining one input characteristic is sufficient to understand curve
as shown below:
Studying the Output Characteristics
To study the output characteristics, let’s plot a curve is between the
Collector current (IC) and the collector-emitter voltage (VCE). Also,
keep the base current (IB) at a steady value.
Now, if the base-emitter current (VBE) is increased by a small amount,
you can observe an increase in hole current from the emitter and
electron current from the base regions. Hence, IB and IC increase
proportionally. Or, if IB increases, IC increases too. So, keeping IB
constant and plotting IC against VCE, you can make the following
observations:
For every value of IB, the plot of IC versus VCE displays one output
characteristic.
Calculation of Important AC Parameters of Junction Transistors
Now, let’s calculate some important ac parameters of transistors using
the linear segments of the input and output characteristics.
Input Resistance (ri)
Input resistance (ri) is the ratio of change in the base-emitter voltage
(ΔVBE) to the subsequent change in base current (ΔIB) when the
collector-emitter voltage (VCE) is kept constant.
ri = (ΔVBE/ ΔIB)VCE
This is ac resistance or dynamic resistance and which is obvious in the
input characteristics since its value varies with the operating current in
the transistor.
Output Resistance (ro)
Output resistance (ro) is the ratio of change in the collector-emitter
voltage (ΔVCE) to the change in the collector current (ΔIC) when the
base current (IB) is kept constant.
ro = (ΔVCE/ ΔIC)IB
A close look at the output characteristics reveals that initially, IC
increases linearly for every small change in the value of VCE. The
reason is simple – the base-collector junction is not reverse biased and
the transistor is not active. On the contrary, the transistor is in a
saturation state.
Hence, the current is controlled by the supply voltage (VCC) in this
part of the characteristic. In this state VCC = VCE. As VCE increases
and reaches a value which is higher than that required to reverse bias
the junction, IC increases marginally with increasing VCE. This
reciprocal of the slope of the linear part of the output characteristics
offers the value of ro.
The bias of the base-collector junction primarily controls the output
resistance of the transistor. Also, the output resistance (ro) is very
high. This is because of the reverse-bias state of the diode. Hence, you
observe that initially, the resistance is very low when the transistor is
in a saturation state.
Current Amplification Factor (β)
Current Amplification Factor (β) is the ratio of change in the collector
current (IC) to the change in base current (IB) when the
collector-emitter voltage (VCE) is kept constant. Also, the transistor is
in an active state. Now, the small signal current gain is
βac = (ΔIC/ ΔIB)VCE
This has a large value. On the other hand, if we take a simple ratio of
IC and IB, we get βdc of the junction transistor.
βdc = IC/IB
It is important to note that IC and IB increase almost linearly. In simple
words, if IB=0, then IC=0. Hence, the values of βac and βdc are nearly
equal.
Solved Examples for You
Question: What are the input and output characteristics of a CE
Junction Transistor?
Solution: In a Common Emitter configuration of a Junction Transistor,
the emitter is the common terminal. Input is between the base and
emitter. The output is between the collector and emitter. Input
characteristics are the variation of base current (IB) with the
base-emitter voltage (VBE). Output characteristics are the variation of
collector current (IC) with the collector-emitter voltage (VCE).
Junction Transistor as a Device
A junction transistor can be used as a device application like a switch,
amplifier etc. depending on many parameters.
● The configuration used – CB (Common Base), CC (Common
Collector) or CE (Common Emitter)
● Reverse/Forward biasing of the E-B and B-C junctions
● Operation region – Cutoff, active or saturation
Our focus is the CE configuration and we will concentrate on the
biasing and operation region to understand how the device works.
Junction Transistor as a Switch
When a junction transistor is used in the cutoff or saturation state, it
acts as a switch. Let’s look at a base-biased transistor, as shown in the
figure below, in the CE configuration and analyze its behaviour to
understand the operation of a transistor as a switch.
Now, let’s apply Kirchhoff’s voltage rule to the input and output sides
of this circuit. It is easy to understand that
VBB = IBRB + VBE … (1) &
VCE = VCC – ICRC … (2)
Now, we will treat VBB as the input voltage (Vi) and VCE as the dc
output voltage (Vo). Therefore, we get,
Vi = IBRB + VBE
Vo = VCC – ICRC
Next, let’s observe the change in Vo as Vi increases from zero
A Silicon junction transistor remains in a state of Cutoff as long as Vi
is less than 0.6 V. Also, IC = 0. Hence, Vo = VCC. When Vi goes
beyond 0.6 V, the transistor moves into an active state. Also, IC > 0
and Vo decreases (since ICRC increases). Initially, IC increases almost
linearly with increasing Vi.
Also, Vo decreases linearly till its value falls below 1 V. Post this, the
change becomes non-linear and the transistor moves into the
saturation state. On increasing Vi further, Vo decreases but never
becomes zero. Here is a plot of Vo vs. Vi (also called the transfer
characteristics of a base-biased transistor):
In the above graph, we can see that the transition from Cutoff to
Active state and Active to Saturation state is not sharply defined. You
can see non-linear regions in these areas.
How to operate a junction transistor as a switch?
Two things to remember here:
1. If Vi is low and unable to forward-bias the transistor, then Vo is
high (=VCC).
2. If Vi is high enough to move the transistor into saturation, then
Vo is very low (~0).
Also, when a transistor is not conducting, it is switched off. On the
other hand, when it is in the saturation state, it is switched on. Putting
these elements together, imagine a transistor where the low and high
states are defined below and above certain voltage levels.
These levels correspond to the cutoff and saturation of the transistor.
In such a scenario, we can say that a low input switches the transistor
off and a high input switches it on. These circuits are designed so that
the transistor does not remain in an active state. This is how it can
operate as a switch.
Junction Transistor as an Amplifier
To use a junction transistor as an amplifier we will focus on the active
region of the Vo vs. Vi curve shown above. If you observe this region,
the linear part of the curve is the change of the output with the input.
However, the output decreases as input increases because,
Vo = VCC-ICRC AND NOT ICRC.
Now, if we consider ΔVo and ΔVi as small changes in the output and
input voltages, then the small signal gain of the amplifier (AV) is
Av = ΔVo/ ΔVi
If the VBB voltage has a fixed value corresponding to the mid-point of
the active region, then the circuit will behave like a CE amplifier
having a voltage gain of ΔV o/ ΔVi.
The voltage gain is expressed as follows:
We know that Vo = VCC – ICRC; hence, ΔVo = 0 – RCΔIC
Also, Vi = IBRB + VBE; hence ΔVi = RBΔIB + ΔVBE
However, ΔVBE is negligibly small as compared to RBΔIB in this
circuit. Hence, the voltage gain of this CE amplifier is
Av = – RCΔIC/RBΔIB = – βac(RC/RB) … since βac = ΔIC/ΔIB
The Configuration of a Junction Transistor as an Amplifier
It is important to fix the operating point of a junction transistor in the
middle of its active region to enable it to function as an amplifier. This
will ensure that the dc base current (IB) and collector current (IC) are
constant. Also, the dc voltage (VCC) remains constant. And, the
operating values of VCE and IB determine the operating point of the
amplifier.
Imagine a sinusoidal voltage (having amplitude vs) superimposed on a
dc base bias. If the sinusoidal source of the signal is connected in
series with the VBB supply, the base current will have sinusoidal
variations superimposed on IB. Hence, the collector current will also
have sinusoidal variations superimposed on IC.
Eventually, these will lead to a change in the value of Vo. AC
variations can be measured by blocking the dc voltages by using large
capacitors. Up until now, we have not spoken about ac signals. And
the fact is, amplifiers are used to amplify alternating signals. So, let’s
superimpose an ac input signal (vi) on the dc bias (VBB) as shown
below.
The output is measured between the collector and ground.
Let’s look at how the amplifier works.
Initially, let’s assume that vi = 0. Applying Kirchhoff’s law, for the
output loop we get
VCC = VCE + ICRL
And, for the input loop, we get,
VBB = VBE + IBRB
If vi is not zero, then
VBE + vi = VBE + IBRB + ΔIB (RB + ri)
Now, a change in VBE can be related to the input resistance ri and a
change in IB. Hence,
Vi = ΔIB (RB + ri) = rΔIB
A change in IB causes a change in IC. We define a parameter βac,
which is similar to the βdc defined earlier, as
βac = ΔIC/ΔIB = IC/IB
also known as ac current gain Ai. In the linear region of the output
characteristics, βac is nearly equal to βdc. Also, a change in IC (due to a
change in IB) affects a change in VCE. This causes the voltage to drop
across resistor RL since VCC is constant. So,
ΔVCC = ΔVCE + RLΔIC = 0 OR
ΔVCE = –RLΔIC
We also know that the change in VCE is the output voltage Vo. Hence,
we get
Vo = ΔVCE = – βacRLΔIB
And the voltage gain of the amplifier is
Av = Vo/Vi = ΔVCE/rΔIB = – βacRL/r
Please note that the negative sign means that the output voltage has an
opposite phase as of the input voltage. From the above calculations,
we can find the power gain Ap as follows:
Ap = βac × Av
Remember, a transistor is not a power generating device. The energy
for the higher ac power at the output is supplied by the battery.
Solved Examples for You
Question: What are the parameters based on which a junction
transistor is used as a device?
Solution: A junction transistor is used as a device based on the
configuration used, biasing of the junctions, and the operation region.
Configurations are Common Base, Collector, and Emitter. Biasing can
be forward or reverse. Operation region includes cutoff, active and
saturation regions.
Junction Transistor as a Feedback Amplifier and Transistor Oscillator
While using a junction transistor as an amplifier we give a sinusoidal
input to get an amplified signal at the output. In other words, in an
amplifier, it is important to provide an ‘ac input’ to sustain an ‘ac
output’. However, in an oscillator, you can get an ‘ac output’ without
the need for any external input signal. Or, the oscillator is
self-sustained.
Junction transistor as a Feedback Amplifier
Take an amplifier and return a portion of the output back to the input
in phase with the starting power as shown below.
Fig.1
This process is called ‘Positive Feedback’. To achieve this, you can
use inductive coupling (via mutual induction) or LC or RC networks.
There are different types of oscillators which use different coupling
methods to feedback the output to the input. Also, they use a resonant
circuit to get oscillation at a particular frequency.
Understanding the Oscillator Action
In the circuit given below, the feedback is given by inductive coupling
from one coil winding (T1) to another coil winding (T2).
Fig.2
Observe that both T1 and T2 are wound on the same core. This means
that they are inductively coupled through their mutual inductance.
Also, the base-emitter junction is forward biased and the
base-collector junction is reverse biased.
Now, assuming that the switch S1 is put on to apply a proper bias for
the first time, a surge of current flows through the transistor. This
current flows through the coil T2 (terminals number 3 and 4 in the
diagram above). Also, the current increases slowly and does not reach
full amplitude instantly as can be seen in the figure below. (Current
increases from X to Y)
Fig.3
Now, the inductive coupling between coils T2 and T1 causes a current
to flow in the emitter circuit.
Note: this is the FEEDBACK from input to output.
This positive feedback causes the emitter current (current in T1) to
increase too (from X to Y as can be seen in the figure below).
Fig.4
Now, the collector current (current in T2) acquires a value ‘Y’ when
the transistor is saturated. In simpler words, the maximum collector
current is flowing and it cannot increase any further. This causes the
magnetic field around T2 to stop increasing.
Since the magnetic field becomes static, feedback from T2 to T1 stops.
This eventually causes the emitter current to fall which results in a
decrease of the collector current from Y to Z. (Fig 3).
Now, a decreasing collector current results in a decaying magnetic
field around T2. Hence, T1 observes a decaying field in T2 which
results in a decrease in the emitter current until it reaches the value Z.
If it decreases further, the transistor is cut-off or IE and IC stop
flowing. Hence, the transistor reverts back to the starting point.
Summing up
This process keeps repeating itself. The transistor is first driven to
saturation, cut-off and then back to saturation. The time taken depends
on the constants of the tank or tuned circuit (inductance L of the coil
T2 and C connected parallel to it). The frequency of oscillation of the
oscillator depends on the resonance frequency (v) of the tuned circuit.
The circuit shown in Fig.2 has the tank or tuned circuit connected on
the collector side of the junction transistor. This device is called
Tuned Collector Oscillator. If it is connected to the base side, it will be
called Tuned Base Oscillator.
Solved Examples for You
Question: What is a positive feedback amplifier?
Solution: In an amplifier, when a part of the output is returned back to
the input, in phase with the starting power, then the amplifier is called
Positive Feedback Amplifier.
Application of a Junction Diode as a Rectifier
The concept of Direct Current and Alternating Current is not alien to
many. Devices, invariably have clear instructions about using AC/DC
current. However, there are times when you might have an AC power
point but need to connect a device that requires a DC. This is when a
Rectifier steps in. In simple words, a Rectifier converts Alternating
Current into Direct Current.
The Volt-Ampere characteristics of a junction diode explain how
current is passed through the diode only when it is ‘forward biased’.
Hence, if an alternating voltage is applied across a junction diode, then
the current will flow only in the part where it is forward biased. This
property of a junction diode can be used to rectify alternating voltage/
current. The circuit used for this purpose is a Rectifier.
A junction diode can be used as a rectifier in two ways:
Half-wave Rectifier
Look at the following diagram:
Source: Wikipedia
In the above circuit, an alternating voltage is applied across a junction
diode connected to a load in a series connection. In this case, a voltage
will appear across the load only during those half cycles of the AC
input when the diode is forward biased. This circuit, which rectifies
only one half of the input current is a Half-wave Rectifier.
The alternating current is supplied at points A and B. During the
alternating cycle, the diode is forward biased when the voltage at point
A is positive. This is when the diode conducts. On the other hand,
when the voltage at point A is negative, the diode is reverse biased
and it doesn’t conduct. For all practical purposes, the reverse
saturation current can be considered zero since it is negligible.
Hence, an output voltage is available only through one half of the
input cycle. Also, no current is available in the other half. Hence, the
output still varies between positive and zero but the negative cycle is
cut off and the output voltage is said to be rectified.
Full-wave Rectifier
Look at the following diagram:
Source: Wikipedia
In the above circuit, two junction diodes are connected to a load. This
circuit gives out in both positive and negative halves of the AC cycle.
Hence, it is a Full-wave Rectifier. In this circuit, the p-sides of both
the diodes are connected to the input. And, the n-sides are connected
together and connected to the load.
Also, the mid-point of the transformer is connected to the load to
complete the circuit. This mid-point of connection is also called
Center tap and hence, the transformer is called Center tap transformer.
The reason two diodes are connected is very simple. One diode
rectifies the voltage for one half of the cycle while the other diode
rectifies it for the other half. Therefore, the output between their
common terminals and the centre-tap of the transformer becomes a
full-wave rectifier output. Let’s see how this works-
If the voltage at point A is positive, then that at point B is negative. In
such a scenario, the diode D1 is forward biased while D2 is negatively
biased. Hence, D1 conducts while D2 blocks the current. Hence,
during the positive half of the input AC cycle, we get output current.
Subsequently, the voltage at point A becomes negative and that at
point B becomes positive. In such a scenario, D2 conducts while D1
blocks the current. Hence, we get an output current in the negative
half of the input AC cycle too.
Since the circuit rectifies both the halves of the input voltage, it is
called Full-wave Rectifier. But, the output is pulsating and not steady.
To derive a steady DC output, a capacitor is connected across the
output terminals (parallel to the load).
Role of a Capacitor
A capacitor filters out the AC ripple and provides pure DC output.
Here is how it works:
As can be seen in the circuit above, a capacitor is connected parallel to
the load. When the voltage across the capacitor rises, it gets charged.
It discharges only when a load is connected to it. On discharge, the
voltage across it falls.
As the AC cycle changes and the second diode kicks in, the capacitor
charges again to its peak value. This is again discharged due to the
presence of the load.
It is important to note here that the rate of discharge depends on the
inverse product of Capacitor and Resistance (or load). To increase the
discharge time and get a steady DC output, large capacitors are
connected. The idea is to obtain an output voltage close to the peak
voltage of the rectified current. You can find such filters in most
power supplies.
Solved Examples for You
Q1. What is a half-wave rectifier?
Ans. A half wave rectifier is a circuit which converts one half of the
alternating input voltage into direct voltage. This is achieved by using
a junction diode in series with a load. During the positive cycle of the
input alternating voltage, the diode is forward biased and conducts
current. Whereas during the negative cycle it shuts off and no current
is passed.
Q2. What is a full-wave rectifier?
Ans. A full wave rectifier is a circuit which converts the entire
alternating input voltage into direct voltage. This is achieved by using
two junction diodes. The p-sides of the diode are connected to the
input while the n-sides are connected together and along with the
centre, tap form the output.
During the positive cycle of the alternating voltage, one diode
conducts while the other doesn’t. This is reversed during the negative
cycle. Hence, both positive and negative cycles are converted into a
direct voltage.