clicker chapter 22 physics

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Chapter 22: The Electric Field II: Continuous Charge Distributions Section 22-1: Calculating E from Coulomb’s Law

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Physics 2 question and examples for electrostatic field, electric force etc..

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Page 1: Clicker Chapter 22 physics

Chapter 22: The Electric Field II: Continuous Charge Distributions

Section 22-1: Calculating E from Coulomb’s Law

Page 2: Clicker Chapter 22 physics

A conducting circular disk has a uniform positive surface charge density. Which of the following diagrams best represents the electric field lines from the disk? (The disk is drawn as a cross–section.)

A. 1

B. 2

C. 3

D. 4

E. None of the diagrams.

1 2 3 4

Page 3: Clicker Chapter 22 physics

A conducting circular disk has a uniform positive surface charge density. Which of the following diagrams best represents the electric field lines from the disk? (The disk is drawn as a cross–section.)

A. 1

B. 2

C. 3D. 4

E. None of the diagrams.

1 2 3 4

Page 4: Clicker Chapter 22 physics

An infinite plane lies in the yzplane and it has a uniform surface charge density. The electric field at a distance x from the plane

A. decreases linearly with x.

B. decreases as 1/x2.

C. is constant and does not depend on x.

D. increases linearly with x.

E. is undetermined.

Page 5: Clicker Chapter 22 physics

An infinite plane lies in the yzplane and it has a uniform surface charge density. The electric field at a distance x from the plane

A. decreases linearly with x.

B. decreases as 1/x2.

C. is constant and does not depend on x.D. increases linearly with x.

E. is undetermined.

Page 6: Clicker Chapter 22 physics

A uniform circular ring has charge Q and radius r. A uniformly charged disk also has charge Q and radius r. Calculate the electric field due to the ring at a distance of r along the axis of the ring divided by the electric field due to the disk at a distance of r along the axis of the disk.

A. 1.0

B. 0.60

C. 1.7

D. 0.50

E. 0.85

Page 7: Clicker Chapter 22 physics

A uniform circular ring has charge Q and radius r. A uniformly charged disk also has charge Q and radius r. Calculate the electric field due to the ring at a distance of r along the axis of the ring divided by the electric field due to the disk at a distance of r along the axis of the disk.

A. 1.0

B. 0.60 C. 1.7

D. 0.50

E. 0.85

Page 8: Clicker Chapter 22 physics

Chapter 22: The Electric Field II: Continuous Charge Distributions

Section 22-2: Gauss’s Law

Page 9: Clicker Chapter 22 physics

A cubical surface with no charge enclosed and with sides 2.0 m long is oriented with right and left faces perpendicular to a uniform electric field E of (1.6 105 N/C) in the +x direction. The net electric flux E through this surface is approximately

A. zero

B. 6.4 105 N · m2/C

C. 13 105 N · m2/C

D. 25 105 N · m2/C

E. 38 105 N · m2/C

Page 10: Clicker Chapter 22 physics

A cubical surface with no charge enclosed and with sides 2.0 m long is oriented with right and left faces perpendicular to a uniform electric field E of (1.6 105 N/C) in the +x direction. The net electric flux E through this surface is approximately

A. zero

B. 6.4 105 N · m2/C

C. 13 105 N · m2/C

D. 25 105 N · m2/C

E. 38 105 N · m2/C

Page 11: Clicker Chapter 22 physics

A surface is so constructed that, at all points on the surface, the E vector points inward. Therefore, it can be said that

A. the surface encloses a net positive charge.

B. the surface encloses a net negative charge.

C. the surface encloses no net charge.

Page 12: Clicker Chapter 22 physics

A surface is so constructed that, at all points on the surface, the E vector points inward. Therefore, it can be said that

A. the surface encloses a net positive charge.

B. the surface encloses a net negative charge.

C. the surface encloses no net charge.

Page 13: Clicker Chapter 22 physics

A surface is so constructed that, at all points on the surface, the E vector points outward. Therefore, it can be said that

A. the surface encloses a net positive charge.

B. the surface encloses a net negative charge.

C. the surface encloses no net charge.

Page 14: Clicker Chapter 22 physics

A surface is so constructed that, at all points on the surface, the E vector points outward. Therefore, it can be said that

A. the surface encloses a net positive charge.

B. the surface encloses a net negative charge.

C. the surface encloses no net charge.

Page 15: Clicker Chapter 22 physics

The figure shows a surface enclosing the charges q and –q. The net flux through the surface surrounding the two charges is

A. q/0

B. 2q/0

C. –q/0

D. zero

E. –2q/0

Page 16: Clicker Chapter 22 physics

The figure shows a surface enclosing the charges q and –q. The net flux through the surface surrounding the two charges is

A. q/0

B. 2q/0

C. –q/0

D. zero E. –2q/0

Page 17: Clicker Chapter 22 physics

The figure shows a surface enclosing the charges 2q and –q. The net flux through the surface surrounding the two charges is

3 E.

zero D.

C.

2 B.

A.

0

0

0

0

q

qεq

q

Page 18: Clicker Chapter 22 physics

The figure shows a surface enclosing the charges 2q and –q. The net flux through the surface surrounding the two charges is

3 E.

zero D.

C.

2 B.

A.

0

0

0

0

q

qεq

q

Page 19: Clicker Chapter 22 physics

+q 2q

s

The figure shows a surface, S, with two charges q and –2q. The net flux through the surface is

0

0

0

0

3 E.

zero D.

C.

2 B.

A.

q

qεq

q

Page 20: Clicker Chapter 22 physics

+q 2q

s

The figure shows a surface, S, with two charges q and –2q. The net flux through the surface is

0

0

0

0

3 E.

zero D.

C.

2 B.

A.

q

qεq

q

Page 21: Clicker Chapter 22 physics

A hollow spherical shell of radius 5.36 cm has a charge of 1.91 C placed at its center. Calculate the electric flux through a portion of the shell with an area of 1.20 10–2 m2.

A. 6.48 105 N.m2/C

B. 2.16 105 N.m2/C

C. 7.20 104 N.m2/C

D. 2.16 101 N.m2/C

E. None of the above.

Page 22: Clicker Chapter 22 physics

A hollow spherical shell of radius 5.36 cm has a charge of 1.91 C placed at its center. Calculate the electric flux through a portion of the shell with an area of 1.20 10–2 m2.

A. 6.48 105 N.m2/C

B. 2.16 105 N.m2/C

C. 7.20 104 N.m2/C D. 2.16 101 N.m2/C

E. None of the above.

Page 23: Clicker Chapter 22 physics

A horizontal surface of area 0.321 m2 has an electric flux of 123 N.m2/C passing through it at an angle of 25° to the horizontal. If the flux is due to a uniform electric field, calculate the magnitude of the electric field.

A. 907 N/C

B. 423 N/C

C. 1.10 10–3 N/C

D. 2.36 10–3 N/C

E. 383 N/C

Page 24: Clicker Chapter 22 physics

A horizontal surface of area 0.321 m2 has an electric flux of 123 N.m2/C passing through it at an angle of 25° to the horizontal. If the flux is due to a uniform electric field, calculate the magnitude of the electric field.

A. 907 N/C B. 423 N/C

C. 1.10 10–3 N/C

D. 2.36 10–3 N/C

E. 383 N/C

Page 25: Clicker Chapter 22 physics

Chapter 22: The Electric Field II: Continuous Charge Distributions

Section 22-3: Using Symmetry to Calculate E with Guass’s Law, and

Concept Check 22-1

Page 26: Clicker Chapter 22 physics

The electric field E in Gauss’s Law is

a. only that part of the electric field due to the charges inside the surface.

b. only that part of the electric field due to the charges outside the surface.

c. the total electric field due to all the charges both inside and outside the surface.

Page 27: Clicker Chapter 22 physics

The electric field E in Gauss’s Law is

A. only that part of the electric field due to the charges inside the surface.

B. only that part of the electric field due to the charges outside the surface.

C. the total electric field due to all the charges both inside and outside the surface.

Page 28: Clicker Chapter 22 physics

zero E.

2 D.

4 C.

B.

A. 2

rkrkrkrk

A rod of infinite length has a charge per unit length of l (= q/l). Gauss's Law makes it easy to determine that the electric field strength at a perpendicular distance r from the rod is, in terms of k = (40)–1,

Page 29: Clicker Chapter 22 physics

zero E.

2 D.

4 C.

B.

A. 2

rkrkrkrk

A rod of infinite length has a charge per unit length of l (= q/l). Gauss's Law makes it easy to determine that the electric field strength at a perpendicular distance r from the rod is, in terms of k = (40)–1,

Page 30: Clicker Chapter 22 physics

A solid sphere of radius a is concentric with a hollow sphere of radius b, where b > a. If the solid sphere has a uniform charge distribution totaling +Q and the hollow sphere a charge of –Q, the electric field magnitude at radius r, where r < a, is which of the following, in terms of k = (40)–1?

zero E.

D.

C.

B.

A.

2

2

3

2

bkQakQakQrrkQ

Page 31: Clicker Chapter 22 physics

A solid sphere of radius a is concentric with a hollow sphere of radius b, where b > a. If the solid sphere has a uniform charge distribution totaling +Q and the hollow sphere a charge of –Q, the electric field magnitude at radius r, where r < a, is which of the following, in terms of k = (40)–1?

zero E.

D.

C.

B.

A.

2

2

3

2

bkQakQakQrrkQ

Page 32: Clicker Chapter 22 physics

A solid sphere of radius a is concentric with a hollow sphere of radius b, where b > a. If the solid sphere has a uniform charge distribution totaling +Q and the hollow sphere a charge of –Q, the electric field magnitude at radius r, where a < r < b, is which of the following, in terms of k = (40)–1?

2

2

2

2

2

)( E.

D.

C.

2 B.

A.

abkQbkQakQrkQrkQ

Page 33: Clicker Chapter 22 physics

A solid sphere of radius a is concentric with a hollow sphere of radius b, where b > a. If the solid sphere has a uniform charge distribution totaling +Q and the hollow sphere a charge of –Q, the electric field magnitude at radius r, where a < r < b, is which of the following, in terms of k = (40)–1?

2

2

2

2

2

)( E.

D.

C.

2 B.

A.

abkQbkQakQrkQrkQ

Page 34: Clicker Chapter 22 physics

A solid sphere of radius a is concentric with a hollow sphere of radius b, where b > a. If the solid sphere has a uniform charge distribution totaling +Q and the hollow sphere a charge of –Q, the electric field magnitude at radius r, where r > b, is which of the following, in terms of k = (40)–1?

zero E.

D.

C.

2 B.

A.

2

2

2

2

bkQakQrkQrkQ

Page 35: Clicker Chapter 22 physics

A solid sphere of radius a is concentric with a hollow sphere of radius b, where b > a. If the solid sphere has a uniform charge distribution totaling +Q and the hollow sphere a charge of –Q, the electric field magnitude at radius r, where r > b, is which of the following, in terms of k = (40)–1?

zero E.

D.

C.

2 B.

A.

2

2

2

2

bkQakQrkQrkQ

Page 36: Clicker Chapter 22 physics

A sphere of radius 8.0 cm carries a uniform volume charge density = 500 nC/m3. What is the electric field magnitude at r = 8.1 cm?

A. 0.12 kN/C

B. 1.5 kN/C

C. 0.74 kN/C

D. 2.3 kN/C

E. 12 kN/C

Page 37: Clicker Chapter 22 physics

A sphere of radius 8.0 cm carries a uniform volume charge density = 500 nC/m3. What is the electric field magnitude at r = 8.1 cm?

A. 0.12 kN/C

B. 1.5 kN/CC. 0.74 kN/C

D. 2.3 kN/C

E. 12 kN/C

Page 38: Clicker Chapter 22 physics

A spherical shell of radius 9.0 cm carries a uniform surface charge density = 9.0 nC/m2. The electric field magnitude at r = 4.0 cm is approximately

A. 0.13 kN/C

B. 1.0 kN/C

C. 0.32 kN/C

D. 0.75 kN/C

E. zero

Page 39: Clicker Chapter 22 physics

A spherical shell of radius 9.0 cm carries a uniform surface charge density = 9.0 nC/m2. The electric field magnitude at r = 4.0 cm is approximately

A. 0.13 kN/C

B. 1.0 kN/C

C. 0.32 kN/C

D. 0.75 kN/C

E. zero

Page 40: Clicker Chapter 22 physics

A spherical shell of radius 9.0 cm carries a uniform surface charge density = 9.0 nC/m2. The electric field magnitude at r = 9.1 cm is approximately

A. zero

B. 1.0 kN/C

C. 0.65 kN/C

D. 0.32 kN/C

E. 0.13 kN/C

Page 41: Clicker Chapter 22 physics

A spherical shell of radius 9.0 cm carries a uniform surface charge density = 9.0 nC/m2. The electric field magnitude at r = 9.1 cm is approximately

A. zero

B. 1.0 kN/C C. 0.65 kN/C

D. 0.32 kN/C

E. 0.13 kN/C

Page 42: Clicker Chapter 22 physics

An infinite plane of surface charge density = +8.00 nC/m2 lies in the yz plane at the origin, and a second infinite plane of surface charge density = –8.00 nC/m2 lies in a plane parallel to the yz plane at x = 4.00 m. The electric field magnitude at x = 3.50 m is approximately

A. 226 N/C

B. 339 N/C

C. 904 N/C

D. 452 N/C

E. zero

Page 43: Clicker Chapter 22 physics

An infinite plane of surface charge density = +8.00 nC/m2 lies in the yz plane at the origin, and a second infinite plane of surface charge density = –8.00 nC/m2 lies in a plane parallel to the yz plane at x = 4.00 m. The electric field magnitude at x = 3.50 m is approximately

A. 226 N/C

B. 339 N/C

C. 904 N/C D. 452 N/C

E. zero

Page 44: Clicker Chapter 22 physics

An infinite plane of surface charge density = +8.00 nC/m2 lies in the yz plane at the origin, and a second infinite plane of surface charge density = –8.00 nC/m2 lies in a plane parallel to the yz plane at x =4.00 m. The electric field magnitude at x = 5.00 m is approximately

A. 226 N/C

B. 339 N/C

C. 904 N/C

D. 452 N/C

E. zero

Page 45: Clicker Chapter 22 physics

An infinite plane of surface charge density = +8.00 nC/m2 lies in the yz plane at the origin, and a second infinite plane of surface charge density = –8.00 nC/m2 lies in a plane parallel to the yz plane at x =4.00 m. The electric field magnitude at x = 5.00 m is approximately

A. 226 N/C

B. 339 N/C

C. 904 N/C

D. 452 N/C

E. zero

Page 46: Clicker Chapter 22 physics

An infinite slab of thickness 2d lies in the xz–plane. The slab has a uniform volume charge density r. The electric field magnitude at y = b where 0 < b < d is

x

y

z

d d

2

4 E.

2 D.

4 C.

2 B.4 A.

bπkρbπkρbπkρπkρbπkρb

Page 47: Clicker Chapter 22 physics

An infinite slab of thickness 2d lies in the xz–plane. The slab has a uniform volume charge density r. The electric field magnitude at y = b where 0 < b < d is

x

y

z

d d

2

4 E.

2 D.

4 C.

2 B.4 A.

bπkρbπkρbπkρπkρbπkρb

Page 48: Clicker Chapter 22 physics

An infinite slab of thickness 2d lies in the xz–plane. The slab has a uniform volume charge density r. The electric field magnitude at y = b where b > d is

x

y

z

d d

dkdkdk

dkbk

4 E.

2 D.4 C.

4 B.

4 A.

2

Page 49: Clicker Chapter 22 physics

An infinite slab of thickness 2d lies in the xz–plane. The slab has a uniform volume charge density r. The electric field magnitude at y = b where b > d is

x

y

z

d d

dkdkdk

dkbk

4 E.

2 D.4 C.

4 B.

4 A.

2

Page 50: Clicker Chapter 22 physics

An infinite slab of thickness 2d lies in the xz–plane. The slab has a uniform volume charge density . Which diagram best represents the electric field along the y–axis?

E. None of the diagrams.

x

y

z

d d

Page 51: Clicker Chapter 22 physics

An infinite slab of thickness 2d lies in the xz–plane. The slab has a uniform volume charge density . Which diagram best represents the electric field along the y–axis?

E. None of the diagrams.

x

y

z

d d

Page 52: Clicker Chapter 22 physics

Chapter 22: The Electric Field II: Continuous Charge Distributions

Section 22-4: Discontinuity of En

Page 53: Clicker Chapter 22 physics

A thin conducting plane with surface charge density is exposed to an external electric Eext. The difference in the electric field between one surface of the plane to the other surface is

A. /0

B. /0 Eext

C. /0 Eext

D. 2/0 Eext

E. /20 Eext

Eext

Page 54: Clicker Chapter 22 physics

A thin conducting plane with surface charge density is exposed to an external electric Eext. The difference in the electric field between one surface of the plane to the other surface is

A. /0

B. /0 Eext

C. /0 Eext

D. 2/0 Eext

E. /20 Eext

Eext

Page 55: Clicker Chapter 22 physics

Chapter 22: The Electric Field II: Continuous Charge Distributions

Section 22-5: Charge and Field at Conductor Surfaces

Page 56: Clicker Chapter 22 physics

Electrical conductors contain

A. only free electrons.

B. only bound electrons.

C. both free and bound electrons.

D. neither bound nor free electrons.

E. only protons and neutrons.

Page 57: Clicker Chapter 22 physics

Electrical conductors contain

A. only free electrons.

B. only bound electrons.

C. both free and bound electrons. D. neither bound nor free electrons.

E. only protons and neutrons.

Page 58: Clicker Chapter 22 physics

The electric field at the surface of a conductor

A. is parallel to the surface.

B. depends only on the total charge on the conductor.

C. depends only on the area of the conductor.

D. depends only on the curvature of the surface.

E. depends on the area and curvature of the conductor and on its total charge.

Page 59: Clicker Chapter 22 physics

The electric field at the surface of a conductor

A. is parallel to the surface.

B. depends only on the total charge on the conductor.

C. depends only on the area of the conductor.

D. depends only on the curvature of the surface.

E. depends on the area and curvature of the conductor and on its total charge.

Page 60: Clicker Chapter 22 physics

Qra

rb1

rb2

A solid conducting sphere of radius ra is placed concentrically inside a conducting spherical shell of inner radius rb1 and outer radius rb2. The inner sphere carries a charge Q while the outer sphere does not carry any net charge. The electric field for ra r rb1 is

ero E.

ˆ2 D.

ˆ2 C.

ˆ B.

ˆ A.

2

2

z

rrkQ

rrkQ

rrkQ

rrkQ

Page 61: Clicker Chapter 22 physics

Qra

rb1

rb2

A solid conducting sphere of radius ra is placed concentrically inside a conducting spherical shell of inner radius rb1 and outer radius rb2. The inner sphere carries a charge Q while the outer sphere does not carry any net charge. The electric field for ra r rb1 is

ero E.

ˆ2 D.

ˆ2 C.

ˆ B.

ˆ A.

2

2

z

rrkQ

rrkQ

rrkQ

rrkQ

Page 62: Clicker Chapter 22 physics

A solid conducting sphere of radius ra is placed concentrically inside a conducting spherical shell of inner radius rb1 and outer radius rb2. The inner sphere carries a charge Q while the outer sphere does not carry any net charge. The electric field for rb1 r rb2 is

Qra

rb1

rb2ero E.

ˆ2 D.

ˆ2 C.

ˆ B.

ˆ A.

2

2

z

rrkQ

rrkQ

rrkQ

rrkQ

Page 63: Clicker Chapter 22 physics

A solid conducting sphere of radius ra is placed concentrically inside a conducting spherical shell of inner radius rb1 and outer radius rb2. The inner sphere carries a charge Q while the outer sphere does not carry any net charge. The electric field for rb1 r rb2 is

Qra

rb1

rb2ero E.

ˆ2 D.

ˆ2 C.

ˆ B.

ˆ A.

2

2

z

rrkQ

rrkQ

rrkQ

rrkQ

Page 64: Clicker Chapter 22 physics

A solid conducting sphere of radius ra is placed concentrically inside a conducting spherical shell of inner radius rb1 and outer radius rb2. The inner sphere carries a charge Q while the outer sphere does not carry any net charge. The electric field for r rb1 is

Qra

rb1

rb2

ero E.

ˆ2 D.

ˆ2 C.

ˆ B.

ˆ A.

2

2

z

rrkQ

rrkQ

rrkQ

rrkQ

Page 65: Clicker Chapter 22 physics

A solid conducting sphere of radius ra is placed concentrically inside a conducting spherical shell of inner radius rb1 and outer radius rb2. The inner sphere carries a charge Q while the outer sphere does not carry any net charge. The electric field for r rb1 is

Qra

rb1

rb2

ero E.

ˆ2 D.

ˆ2 C.

ˆ B.

ˆ A.

2

2

z

rrkQ

rrkQ

rrkQ

rrkQ

Page 66: Clicker Chapter 22 physics

The charge on an originally uncharged insulated conductor is separated by induction from a positively charged rod brought near the conductor. For which of the various Gaussian surfaces represented by the dashed lines does ?

A. S1

B. S2

C. S3

D. S4

E. S5

0sdE

Page 67: Clicker Chapter 22 physics

The charge on an originally uncharged insulated conductor is separated by induction from a positively charged rod brought near the conductor. For which of the various Gaussian surfaces represented by the dashed lines does ?

A. S1

B. S2

C. S3

D. S4

E. S5

0sdE