clicker question 1 suppose y = (x 2 – 3x + 2) / x. then y could be: – a. 2x – 3 – b. ½ x 2...

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Clicker Question 1 Suppose y = (x 2 – 3x + 2) / x . Then y could be: A. 2x – 3 B. ½ x 2 – 3x + 2 C. ½ x 2 – 3x + 2 ln(x) + 7 D. ½ x 2 – 3 + 2 ln(x) E. (1/3 x 3 – 3/2 x 2 + 2 x) / (1/2 x 2 )

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Page 1: Clicker Question 1 Suppose y = (x 2 – 3x + 2) / x. Then y could be: – A. 2x – 3 – B. ½ x 2 – 3x + 2 – C. ½ x 2 – 3x + 2 ln(x) + 7 – D. ½ x 2 – 3 + 2 ln(x)

Clicker Question 1

Suppose y = (x2 – 3x + 2) / x . Then y could be:– A. 2x – 3– B. ½ x2 – 3x + 2– C. ½ x2 – 3x + 2 ln(x) + 7– D. ½ x2 – 3 + 2 ln(x)– E. (1/3 x3 – 3/2 x2 + 2 x) / (1/2 x2)

Page 2: Clicker Question 1 Suppose y = (x 2 – 3x + 2) / x. Then y could be: – A. 2x – 3 – B. ½ x 2 – 3x + 2 – C. ½ x 2 – 3x + 2 ln(x) + 7 – D. ½ x 2 – 3 + 2 ln(x)

Clicker Question 2

If f (t) = tan(t), then f (t) could be:– A. sec2(t)– B. sec(t2)– C. ln(sec(t))– D. ln(tan(t))– E. ln(cos(t))

Page 3: Clicker Question 1 Suppose y = (x 2 – 3x + 2) / x. Then y could be: – A. 2x – 3 – B. ½ x 2 – 3x + 2 – C. ½ x 2 – 3x + 2 ln(x) + 7 – D. ½ x 2 – 3 + 2 ln(x)

Clicker Question 3

Suppose dy / dx = 1 / (1 – x2), then y could be:– A. arcsin(x) + 12– B. arctan(x) - 5– C. sin(x) + 43– D. tan(x) – 3.5– E. (1 – x2)-3/2 + e2

Page 4: Clicker Question 1 Suppose y = (x 2 – 3x + 2) / x. Then y could be: – A. 2x – 3 – B. ½ x 2 – 3x + 2 – C. ½ x 2 – 3x + 2 ln(x) + 7 – D. ½ x 2 – 3 + 2 ln(x)

Differential Equations (3/17/14)

A differential equation is an equation which contains derivatives within it.

More specifically, it is an equation which may contain an independent variable x (or t) and/or a dependent variable y (or some other variable name), but definitely contains a derivative y ' = dy/dx (or dy/dt).

It may also contain second derivatives y '' , etc.

Page 5: Clicker Question 1 Suppose y = (x 2 – 3x + 2) / x. Then y could be: – A. 2x – 3 – B. ½ x 2 – 3x + 2 – C. ½ x 2 – 3x + 2 ln(x) + 7 – D. ½ x 2 – 3 + 2 ln(x)

Examples of DE’s

Every anti-derivative (i.e., indefinite integral) you have solved (or tried to solve) this semester is a differential equation!

What is y if y ' = x2 – 3x + 5 ? What is y if y ' = x / (x2 + 4) What is y if dy/dt = e0.67t

Note that you also get a “constant of integration” in the solution.

Page 6: Clicker Question 1 Suppose y = (x 2 – 3x + 2) / x. Then y could be: – A. 2x – 3 – B. ½ x 2 – 3x + 2 – C. ½ x 2 – 3x + 2 ln(x) + 7 – D. ½ x 2 – 3 + 2 ln(x)

New types of examples

The following is a DE of a different type since it contains the dependent variable:

y ' = .08y Say in words what this says! Note that we don’t see the independent

variable at all – let’s call it t . What is a solution to this equation? And how

can we find it?

Page 7: Clicker Question 1 Suppose y = (x 2 – 3x + 2) / x. Then y could be: – A. 2x – 3 – B. ½ x 2 – 3x + 2 – C. ½ x 2 – 3x + 2 ln(x) + 7 – D. ½ x 2 – 3 + 2 ln(x)

The solutions to a DE

A solution of a given differential equation is a function y which makes the equation work.

Show that y = Ae0.08t is a solution to the DE on the previous slide, where A is a constant.

Note that we are using the old tried and true method for solving equations here called “guess and check”.

Page 8: Clicker Question 1 Suppose y = (x 2 – 3x + 2) / x. Then y could be: – A. 2x – 3 – B. ½ x 2 – 3x + 2 – C. ½ x 2 – 3x + 2 ln(x) + 7 – D. ½ x 2 – 3 + 2 ln(x)

Examples of guess and check for DE’s

Show that y = 100 – A e –t satisfies the DE y ' = 100 - y

Show that y = sin(2t) satisfies the DEd2y / dt 2 = -4y

Show that y = x ln(x) – x satisfies the DE y ' = ln(x)

Of course one hopes for better methods to solve equations, but DE’s can be very hard.

Page 9: Clicker Question 1 Suppose y = (x 2 – 3x + 2) / x. Then y could be: – A. 2x – 3 – B. ½ x 2 – 3x + 2 – C. ½ x 2 – 3x + 2 ln(x) + 7 – D. ½ x 2 – 3 + 2 ln(x)

Assignment for Wednesday

Read over these slides (and try to solve the problems on them), and read Section 9.1.

On page 584, do # 1 – 7 odd.