combinational logic part 2: karnaugh maps (quick)
TRANSCRIPT
Combinational LogicPart 2:
Karnaugh maps (quick)
Sum of Minterms Implementation
• OR all of the minterms of truth table for which the functionvalue is 1
F = m0 + m2 + m5 + m7
F = X’Y’Z’ + X’YZ’+XY’Z + XYZ
2
Sum of Products Implementation
• Simplifying sum-of-minterms can yield a sum of products
• Difference is that each term need not have all variables
• Resulting gates • ANDs and one OR
F = Y’ + X’YZ’ + XY
3
Two-Level Implementation
• Sum of products has 2 levels of gates
Fig 2-6
4
More Levels of Gates?
• What’s best?♦ Hard to answer♦ More gate delays (more on this later)♦ But maybe we only have 2-input gates
5
Product of Maxterms Implementation
• Can express F as AND of Maxterms for all rows that should evaluate to 0
6431 MMMMF
))(( ZYXZYXF ))(( ZYXZYX
or
This makes one Maxterm fail each time F should be 0
6
Product of Sums Implementation
• ORs followed by AND
))(( ZYXZYXF
7
Karnaugh Map
• Graphical depiction of truth table
• A box for each minterm♦ So 2 variables, 4 boxes♦ 3 variable, 8 boxes♦ And so on
• Useful for simplification♦ by inspection♦ Algebraic manipulation harder
8
K-Map from Truth TableExamples
• There are implied 0s in empty boxes
9
Function from K-Map
• Can generate function from K-map
XYF XYYXYXF Simplifies to X + Y (in a moment)
10
In Practice:
• Karnaugh maps were mildly useful when people did simplification
• Computers now do it!• We’ll cover Karnaugh maps as a
way for you to gain insight, ♦ not as real tool
11
Three-Variable Map
• Eight minterms• Look at encoding of columns
and rows
12
Simplification
• Adjacent squares (horizontally or vertically) are minterms that vary by single variable
• Draw rectangles on map to simplify function
• Illustration next
13
Example
instead ofYXYXF
ZYXZYXZYXZYXF 14
Adjacency is cylindrical
• Note that wraps from left edge to right edge.
Z
15
Covering 4 Squares
is
ZXYZYXZYXZYXF ZXZXF ZF
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Another Example
• Help me solve this one
17
In General
• One box -> 3 literals• Rectangle of 2 boxes -> 2
literals• Rectangle of 4 boxes -> 1 literal• Rectangle of 8 boxes -> Logic 1
(on 3-variable map)♦ Covers all minterms
18
Slight Variation
• Overlap is OK.
• No need to use full m5-- waste of input
19
4-variable map
• At limit of K-map
20
Also Wraps (toroidal topology)
21
Systematic Simplification
A Prime Implicant is a product term obtained by combining the maximum possible number of adjacent squares in the map into a rectangle with the number of squares a power of 2.
A prime implicant is called an Essential Prime Implicant if it is the only prime implicant that covers (includes) one or more minterms.
Prime Implicants and Essential Prime Implicants can be determined by inspection of a K-Map.
A set of prime implicants "covers all minterms" if, for each minterm of the function, at least one prime implicant in the set of prime implicants includes the minterm.
Chapter 2 - Part 2 22
DB
CB
1 1
1 1
1 1
B
D
A
1 1
1 1
1
Example of Prime Implicants
Find ALL Prime ImplicantsB’D’ and BD are ESSENTIAL Prime Implicants
C
BD
CD
BD
Minterms covered by single prime implicant
DB
1 1
1 1
1 1
B
C
D
A
1 1
1 1
1
AD
BA
Chapter 2 - Part 2 23
Prime Implicant Practice
Find all prime implicants for:13,14,15),10,11,12,(0,2,3,8,9 D)C,B,F(A, m
Chapter 2 - Part 2 24
Prime Implicant Practice
Find all prime implicants for:13,14,15),10,11,12,(0,2,3,8,9 D)C,B,F(A, m
1 1
1 1
1 1
B
D
A1 1
1
C
1 1
ACB
DB
Chapter 2 - Part 2 25
Algorithm to Find An Optimal Expression for A Function
Find all prime implicants. Include all essential prime implicants in the
solution Select a minimum cost set of non-essential
prime implicants to cover all minterms not yet covered.
The solution consists of all essential prime and the selected minimum cost set of non-essential prime implicants
minimum cost
selected minimum cost
Chapter 2 - Part 2 26
The Selection Rule
Obtaining a good simplified solution: Use the Selection Rule
Chapter 2 - Part 2 27
Prime Implicant Selection Rule
Minimize the overlap among prime implicants as much as possible.
In the solution, make sure that each prime implicant selected includes at least one minterm not included in any other prime implicant selected.
Chapter 2 - Part 2 28
Selection Rule Example
Simplify F(A, B, C, D) given on the K-map.
1
1
1
1 1
1
1
B
D
A
C
1
1
1
1
1
1 1
1
1
B
D
A
C
1
1
Essential
Minterms covered by essential prime implicants
Selected
Chapter 2 - Part 2 29
Don’t Care
• So far have dealt with functions that were always either 0 or 1
• Sometimes we have some conditions where we don’t care what result is
• Example: dealing with BCD♦ Only care about first 10
30
Mark With an X
• In a K-map, mark don’t care with X
• Simpler implementations• Can select an X either as 1 or 0
31
Example
or
What would we have if Xs were 0? 32
Selection Rule Example with Don't Cares
Simplify F(A, B, C, D) given on the K-map. Selected
Minterms covered by essential prime implicants
1
1
x
x
x x
x
1
B
D
A
C
1
1 1
1
x
x
x x
x
1
B
D
A
C
1
1
Essential
Chapter 2 - Part 2 33
Product of Sums Example
Find the optimum POS solution:
• Hint: Use and complement it to get the result.
,13,14,15)(3,9,11,12 D)C,B,F(A, m (1,4,6) d
F
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