component vectors
DESCRIPTION
Component Vectors. Vectors have two parts (components) X component – along the x axis Y component – along the y axis. Finding components. X component – follow from the tail of the vector along the x axis until you reach the point where the tip would be if it fell straight down. - PowerPoint PPT PresentationTRANSCRIPT
Component Vectors•Vectors have two parts (components)–X component – along the x axis
–Y component – along the y axis
Finding components
•X component – follow from the tail of the vector along the x axis until you reach the point where the tip would be if it fell straight down
•Y component – follow from where you stopped on the x axis straight up to the tip
•You should now have formed a right triangle with the original vector as the hypotenuse
To find components• To find components, you must use
trigonometric functions
Hypotenuse
Adjacent
Opposite
ø
Trig functions• Θ is the angle between
the vector and the x axis• sin Θ = _opposite_
hypotenuse• cos Θ = _adjacent_
hypotenuse• tan Θ = _opposite_
adjacent
Steps for finding the components
1) Draw a picture (arrowheads, original vector & components)
2) Choose a trig function3) Use algebra to solve for the
desired variable & plug in4) Calculator in degrees!5) Check with Pythagorean theorem
Example
•
X component
•cos Θ = _adjacent_ hypotenuse
•cos 35 = _adjacent_ 316
•316 cos 35 = adjacent•259 N = adjacent
Y component
• sin Θ = _opposite_ hypotenuse
• sin 35 = _opposite_ 316
• 316 sin 35 = opposite• 181 N = opposite
How to find components when you add two vectors
1)Find the x and y component for both vectors
2)Add up the x components 3)Add up the y components4)Draw a new set of vectors5)Use Pythagorean theorem to get the
magnitude of the resultant vector6)Use arctangent to get the angle of the new
vector
Vector d1
X component
adj = hyp cos Θ
adj = 36 cos34º
adj = + 29.8 m
Y component
opp = hyp sin Θ
opp = 36 sin34º
opp = +20.1 m
X component
opp = hyp sin Ø
opp = 23 sin64º
opp = - 20.7 m
Y component
adj = hyp cos Θ
adj = 23 cos64º
adj = +10.1 m
Vector d2
Total X displacement – add d1 and d2
dtotal = d1 + d2
dtotal = 29.8 m + (-20.7m)
dtotal = +9.1m
Total Y displacement – add d1 and d2
dtotal = d1 + d2
dtotal = 20.1 m + 10.1m
dtotal = +30.2m
To get the magnitude of the resultant vector
• Use Pythagorean Theorem
dTotal = (dX)2 + (dy)2
dTotal = (9.1)2 + (30.2)2
dTotal = 82.81 + 912.04
dTotal = 994.85 = 31.5 m
To find the angle of the resultant vector
•Use arctangent function: Θ = tan-1 (opp/adj) Θ = tan-1 (30.2/9.1) Θ = tan-1 (3.3) Θ = 73.1°
Formulas• a2 + b2 = c2
• R2 = a2 + b2 - 2ab(cosθ)
• SOH• CAH• TOA