continue on warm up page 9/9convert the following: 6.3 days to seconds 7.10,095 m/sec to miles/sec...

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Continue on Warm Up page… 9/9 Convert the following: 6. 3 days to seconds 7. 10,095 m/sec to miles/sec 8. 57 km/hr to m/sec

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An object is in motion if its position changes. So how do we know an object is moving? The mathematical description of motion is kinematics. The simplest kind of motion an object can experience is uniform motion in a straight line or linear motion.

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Page 1: Continue on Warm Up page 9/9Convert the following: 6.3 days to seconds 7.10,095 m/sec to miles/sec 8.57 km/hr to m/sec

Continue on Warm Up page…

9/9 Convert the following:6. 3 days to seconds

7. 10,095 m/sec to miles/sec

8. 57 km/hr to m/sec

Page 2: Continue on Warm Up page 9/9Convert the following: 6.3 days to seconds 7.10,095 m/sec to miles/sec 8.57 km/hr to m/sec

The Equations…

Page 3: Continue on Warm Up page 9/9Convert the following: 6.3 days to seconds 7.10,095 m/sec to miles/sec 8.57 km/hr to m/sec

An object is in motion if its position changes.

So how do we know an object is moving?

The mathematical description of motion is kinematics. The simplest kind of motion an object can experience is uniform motion in a straight line or linear motion.

Page 4: Continue on Warm Up page 9/9Convert the following: 6.3 days to seconds 7.10,095 m/sec to miles/sec 8.57 km/hr to m/sec

As the car moves, it often undergoes changes in speed. For example, during an average trip to school, there are many changes in speed. Rather than the speedometer maintaining a steady reading, the needle constantly moves up and down to reflect the stopping and starting and the accelerating and decelerating.

Page 5: Continue on Warm Up page 9/9Convert the following: 6.3 days to seconds 7.10,095 m/sec to miles/sec 8.57 km/hr to m/sec

Distance: How far something travels (scalar quantity)

What is the difference between distance and displacement?

Displacement: How far something travels in a given direction, the straight line distance from my start point to end point (vector quantity)

Page 6: Continue on Warm Up page 9/9Convert the following: 6.3 days to seconds 7.10,095 m/sec to miles/sec 8.57 km/hr to m/sec

What is the distance of the biker?

What is the displacement of the biker?

DISTANCE

DISPLA

CEMEN

T

Page 7: Continue on Warm Up page 9/9Convert the following: 6.3 days to seconds 7.10,095 m/sec to miles/sec 8.57 km/hr to m/sec

A skier travels from A to B then to C then to D.

What is her displacement at D?

What distance does she travel? 420 m

140 m right of A

Page 8: Continue on Warm Up page 9/9Convert the following: 6.3 days to seconds 7.10,095 m/sec to miles/sec 8.57 km/hr to m/sec

SCALAR vs VECTOR QuantitiesScalars are quantities which are fully described by a magnitude (measurement) alone.

Ex. Distance, speed, and time Vectors are quantities which are fully described by both a magnitude (measurement) and a direction.

Ex. Displacement and velocity

Distance traveledDisplacement

= AC + CB + BC = 400 m.= 200 m right of A

If she jogs from A to B to C

Page 9: Continue on Warm Up page 9/9Convert the following: 6.3 days to seconds 7.10,095 m/sec to miles/sec 8.57 km/hr to m/sec

Scalar vs. Vector

Quantity Scalar or Vector

10 m/s East

10 N to the right

35 mi/hr

13 sec.

67 yds North

25 meters

VectorVector

Vector

ScalarScalar

Scalar

Page 10: Continue on Warm Up page 9/9Convert the following: 6.3 days to seconds 7.10,095 m/sec to miles/sec 8.57 km/hr to m/sec

Frame of reference

• Based on your perception…describing something that is moving and comparing it to something stationary – Independent and dependent variable

relationship– What is frame of reference dependent on?

Page 11: Continue on Warm Up page 9/9Convert the following: 6.3 days to seconds 7.10,095 m/sec to miles/sec 8.57 km/hr to m/sec

AVERAGE SPEED (scalar)If an object takes a time interval t to travel a distance d, then the average speed of the object is given by:

s

dist

t

Page 12: Continue on Warm Up page 9/9Convert the following: 6.3 days to seconds 7.10,095 m/sec to miles/sec 8.57 km/hr to m/sec

PROBLEM SOLVING GUIDELINES• Make a list of given quantities (Data)• Convert units if needed• Make a sketch if necessary• Identify what is to be determined• Always solve the equation for the unknown• Be consistent with units• Check that the answer seems reasonable• Physics problems take practice –

the more you do the easier it will be!

Page 13: Continue on Warm Up page 9/9Convert the following: 6.3 days to seconds 7.10,095 m/sec to miles/sec 8.57 km/hr to m/sec

Givens: Base formula/rule: Answer:

Work:

Diagrams:

Example 1: A runner makes one lap around a 200 m track in a time of 25 s. What is the runner's average speed?

d = 200 mt = 25 s

Unknown: S

Duncan Phillips AMCHS ‘07‘O6 State Gold Medal 1600 m

S = d t

S = d t

20025

= 8 m/s

8 m/s

ms

Page 14: Continue on Warm Up page 9/9Convert the following: 6.3 days to seconds 7.10,095 m/sec to miles/sec 8.57 km/hr to m/sec

Example 2: According to the World Disk Federation, on April 8,2000, Jennifer Griffin threw a Frisbee for a distance of 138.56 m to capture the woman’s record. If the Frisbee was thrown horizontally with a speed of 13.0 m/s, how long did the Frisbee remain aloft? Givens: Base formula/rule: Answer:

 

Work:

Diagrams:

S = 13.0 m/sd = 138.56 mt = ?

S = d t

t = d S

= 138.56 m 13.0 m/s

= 10.658

= 10.7 s

Page 15: Continue on Warm Up page 9/9Convert the following: 6.3 days to seconds 7.10,095 m/sec to miles/sec 8.57 km/hr to m/sec

Example 3: A snail can move approximately 0.30 meters per minute. How many meters can the snail cover in 15 minutes?

Givens: Base formula/rule: Answer: 

Work:

Diagrams:

S = 0.30 m/mint = 15 mind = ?

S = d t

d = st =(15 min) (0.30m/min)= 50

= 50 m

Page 16: Continue on Warm Up page 9/9Convert the following: 6.3 days to seconds 7.10,095 m/sec to miles/sec 8.57 km/hr to m/sec

AVERAGE VELOCITY (vector) Average velocity is the displacement divided by the amount of time it took to undergo that displacement. The difference between average speed and average velocity is that average speed relates to the distance traveled while average velocity relates to the displacement.V = displacement = x elapsed time t

v

x t

x=xf-xi (found by finding the difference)

-xf means final (you may also see Xf)-xi means initial (you may also see Xi)-Need to have an origin/reference point

Page 17: Continue on Warm Up page 9/9Convert the following: 6.3 days to seconds 7.10,095 m/sec to miles/sec 8.57 km/hr to m/sec

Example 1: A vehicle travels 2345m in 315 sec toward the evening sun. What was its velocity?

Page 18: Continue on Warm Up page 9/9Convert the following: 6.3 days to seconds 7.10,095 m/sec to miles/sec 8.57 km/hr to m/sec

Example 2: What is a vehicles displacement if it is traveling 120 km/hr north for 30 min?

Page 19: Continue on Warm Up page 9/9Convert the following: 6.3 days to seconds 7.10,095 m/sec to miles/sec 8.57 km/hr to m/sec

Example 3: Houston is 200km away, how long will it take a southbound bicyclist traveling at 100 m/s?

Page 20: Continue on Warm Up page 9/9Convert the following: 6.3 days to seconds 7.10,095 m/sec to miles/sec 8.57 km/hr to m/sec

Observe the animation of the three cars below. How would you describe the motion of the red car?

the blue car?

the green car?

The rate at which velocity changes is ACCELERATION

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ACCELERATION Acceleration is the rate of change of velocity. The change in velocity ΔV is the final velocity Vf minus the initial velocity Vo.

av vt

f o

Units: m/s2

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A positive acceleration means an increase in velocity; a negative acceleration usually means a decrease in velocity (deceleration).

Note that negative acceleration is in OPPOSITE direction of the velocity

Page 23: Continue on Warm Up page 9/9Convert the following: 6.3 days to seconds 7.10,095 m/sec to miles/sec 8.57 km/hr to m/sec

Example 3: An object starts from rest with a constant acceleration of 8 m/s2 along a straight line. Find the speed at the end of 5 s

Givens: Base formula/rule: Answer: 

Work:

Diagrams:

Vo = 0 m/sa = 8 m/s2

t = 5 s

v v atf o

v v atf o Vf = ?

Vf = 0m/s + (8m/s2)(5s)

Vf = 40 m/s

Vf = 40 m/s

Page 24: Continue on Warm Up page 9/9Convert the following: 6.3 days to seconds 7.10,095 m/sec to miles/sec 8.57 km/hr to m/sec

Example 4: A truck's speed increases uniformly from15 km/h to 60 km/h in 20 s. Determine the acceleration.Givens: Base

formula/rule:Answer:

 

Work:

Diagrams:

vo = 15 km/h = 4.17 m/svf = 60 km/h = 16.7 m/st = 20 sa = ?

av vt

f o

av vt

f o

16 7 4 1720

. . m/ss

= 0.6265 m/s2

= 0.63 m/s2

Page 25: Continue on Warm Up page 9/9Convert the following: 6.3 days to seconds 7.10,095 m/sec to miles/sec 8.57 km/hr to m/sec

Example 5: A bus moving at a speed of 20 m/s begins to slow at a constant rate of 3.0 m/s2. How long before it stops?

Givens: Base formula/rule: Answer: 

Work:

Diagrams:

Vo = 20 m/sVf = 0 m/s

a = - 3 m/s/s t =?

v v atf o

t = Vf – Vo

a

t = 0 – 20 m/s -3 m/s2

t = 6.6667 s

t = 6.67 s