copyright © 2011 pearson education, inc. slide 2.5-1 2.5 piecewise-defined functions the absolute...
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Copyright © 2011 Pearson Education, Inc. Slide 2.5-1
2.5 Piecewise-Defined Functions
• The absolute value function is a simple example of a function defined by different rules over different subsets of its domain. Such a function is called a piecewise-defined function. – Domain of is with one rule on
and the other rule on
• Example Find each function value given the piecewise-defined function
Solution
(a)
(b)
(c)
xxf )( ),,( xxf )( ),0,(xxf )( ).,0[
.0 if2
1
0 if2)(
2 xx
xxxf
. ofgraph Sketch the (d) )3( (c) )0( (b) )3( (a) ffff
.123)3( thus,2)( rule theuse ,03 Since fxxf
.220)0( thus,2)( rule theuse ,00 Since fxxf
.5.4)9()3()3( thus,)( rule theuse ,03 Since21
21
21 22 fxxf
. ofgraph on the are )5.4,3( and (0,2), ),1,3( points The f:Note
Copyright © 2011 Pearson Education, Inc. Slide 2.5-2
2.5 The Graph of a Piecewise-Defined Function
(d) The graph of
Graph the ray choosing x so that with a solid endpoint (filled in circle) at (0,2). The ray has slope 1 and
y-intercept 2. Then, graph for This graph will be
half of a parabola with an open endpoint (open circle) at (0,0).
time.aat piece onedrawn is 0 if
2
1
0 if2)(
2
xx
xxxf
,2xy ,0x
221 xy .0x
Figure 51 pg 2-117
Copyright © 2011 Pearson Education, Inc. Slide 2.5-3
2.5 Graphing a Piecewise-Defined Function with a Graphing Calculator
• Use the test feature– Returns 1 if true, 0 if false when plotting the value of x
• In general, it is best to graph piecewise-defined functions in dot mode, especially when the graph exhibits discontinuities. Otherwise, the calculator may attempt to connect portions of the graph that are actually separate from one another.
Copyright © 2011 Pearson Education, Inc. Slide 2.5-4
2.5 Graphing a Piecewise-Defined Function
Sketch the graph of
Solution
For graph the part of the line to the left of, and including, the point (2,3). For graph the part of the line to the right of the point (2,3).
.2 if722 if1 )(
xxxxxf
1xy
72 xy
,2x,2x
Copyright © 2011 Pearson Education, Inc. Slide 2.5-5
2.5 The Greatest Integer (Step) Function
Example Evaluate for (a) –5, (b) 2.46, and (c) –6.5
Solution (a)
(b)
(c)
Using the Graphing Calculator
The command “int” is used by many graphing calculators for the greatest integer function.
integeran not is if than lessinteger greatest the
integeran is if xx
xx
52
7
( )f x x
x
Copyright © 2011 Pearson Education, Inc. Slide 2.5-6
2.5 The Graph of the Greatest Integer Function
– Domain:
– Range:
• If using a graphing calculator, put the calculator in dot mode.
||)( xxf ),(
},3,2,1,0,1,2,3,{}integeran is { xx
Figure 58 pg 2-124
Copyright © 2011 Pearson Education, Inc. Slide 2.5-7
2.5 Graphing a Step Function
• Graph the function defined by Give the domain and range.
Solution
Try some values of x.
. 121
xy
x -3 -2 -1 0 .5 1 2 3 4
y -1 0 0 1 1 1 2 2 3
}.,2,1,0,1,{ is range theand ),( isdomain The on. so
and ,2 ,42For .1 then ,20 if that Notice
yxyx
Copyright © 2011 Pearson Education, Inc. Slide 2.5-8
2.5 Application of a Piecewise-Defined Function
Downtown Parking charges a $5 base fee for parking through 1 hour, and $1 for each additional hour or fraction thereof. The maximum fee for 24 hours is $15. Sketch a graph of the function that describes this pricing scheme.
SolutionSample of ordered pairs (hours,price): (0.25,5), (0.75,5), (1,5), (1.5,6), (1.75,6).
During the 1st hour: price = $5During the 2nd hour: price = $6During the 3rd hour: price = $7
During the 11th hour: price = $15
It remains at $15 for the rest of the 24-hour period.
Graph on the interval (0,24].Figure 62 pg 2-127
Copyright © 2011 Pearson Education, Inc. Slide 2.5-9
2.5 Using a Piecewise-Defined Function to Analyze Data
Due to acid rain, the percentage of lakes in Scandinavia that had lost their population of brown trout increased dramatically between 1940 and 1975. Based on a sample of 2850 lakes, this percentage can be approximated bythe piecewise-defined function f .
Determine the percent of lakes that had lost brown trout (a) by 1950 and (b) by 1972. Interpret your results.
19759601 if18)1960(15
32
19609401 if7)1940(20
11
)(
xx
xxxf
Copyright © 2011 Pearson Education, Inc. Slide 2.5-10
2.5 Using a Piecewise-Defined Function to Analyze Data
(a) Use the first rule with x = 1950.
(b) Use the second rule with x = 1972.
(percent) 6.4318)19601972(15
32)1972( f
By 1972, about 44% of the lakes had lost their population of brown trout.
11(1950) (1950 1940) 7 12.5
20f
By 1950, about 12.5% of the lakes had lost their population of brown trout.