Scat

ter

P

lots

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Course 3

Course 3

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NAME DATE PERIOD SCORE

8.NS.1

8.EE.7, 8.EE.7a

8.NS.2

Cop

yrig

ht ©

McG

raw

-Hill

Edu

catio

n. P

erm

issi

on is

gra

nted

to r

epro

duce

for

clas

sroo

m u

se.

Course 3 • Countdown • 19 Weeks 15

Program: SBAC Component: Count Down 19

PDF PassVendor: MPS Grade: Course 3

Countdown: 19 Weeks1. A company sells only items that are in the shape of cubes.

Select all of the volumes of cubes with rational number side lengths.

8 in3

33 cm3

1.5 ft3

9 ft3

1,000 m3

(4.12 yd)3

2. Sherron is writing a computer program that solves linear equations and displays a numerical answer for the solution.

Part A: When Sherron inputs the equation 4x + 3 = 4(1 + x) + 1, she gets an error message. Explain why.

Part B: Sherron inputs the equation 5 + 6y = 9y + 2 + 3(1 – y). What is the result and why?

3. A square picture frame encloses an area of 29 square inches. Its owner claims that the frame sides are between 5.25 and 5.35 inches long. Is the owner correct? Why or why not?

Think Smart for SBAC On the actual test, you might be asked to click all of the correct answer choices. In this book, you will be asked to shade a box next to each correct answer choice.

015-016_SBAC_A_C3_CD19_793945.indd 15015-016_SBAC_A_C3_CD19_793945.indd 15 11/23/14 5:17 PM11/23/14 5:17 PM

8.EE.2

8.NS.2

Copyright ©

McG

raw-H

ill Education. Permission is granted to reproduce for classroom

use.

16 Course 3 • Countdown • 19 Weeks

Program: SBAC Component: Count Down 19

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4. A cargo ship has a stack of shipping containers. The stack is x containers wide, x containers long, and x containers tall. Circle all of the equations that could represent the total number of containers on the ship.

x3 = 64 x3 = 16 100 = x3

x3 = 9 27 = x3 x3 = 0.125

0.343 = x3 x3 = 8 216 = x3

5. A ball rolls in a straight line roughly 3π yards before stopping. Then someone kicks it backward 0.5π yards.

Part A: On the number line, plot a point to represent the distance from the ball’s initial location at 0 to its final location. Each increment on the number line represents 1 yard.

210 9 10876543

Part B: Explain why you cannot illustrate the distance exactly. Then give the distance rounded to the nearest hundredth.

Think Smart for SBAC On the actual test, you might be asked to click the button to plot a point on the number line. In this book, you will be asked to draw the point on the number line.

015-016_SBAC_A_C3_CD19_793945.indd 16015-016_SBAC_A_C3_CD19_793945.indd 16 11/23/14 5:17 PM11/23/14 5:17 PM

Copyright ©

The McG

raw-H

ill Com

panies, Inc. Permission is granted to reproduce for classroom

8.EE

.2

8.N

S.2

16

Cou

rse

3 •

Cou

ntdo

wn

• 19

Wee

ks

4.

A c

argo

shi

p ha

s a

stac

k of

shi

ppin

g co

ntai

ners

. The

sta

ck is

x c

onta

iner

s w

ide,

x c

onta

iner

s lo

ng, a

nd x

con

tain

ers

tall.

Circ

le a

ll of

the

equa

tions

th

at c

ould

rep

rese

nt th

e to

tal n

umbe

r of

con

tain

ers

on th

e sh

ip.

x3 =

64

x3 =

16

100

= x

3

x3 =

9

27 =

x3

x3 =

0.12

5

0.34

3 =

x3 x3

= 8

216

= x

3

5.

A b

all r

olls

in a

str

aigh

t lin

e ro

ughl

y 3π

yar

ds b

efor

e st

oppi

ng.

Then

som

eone

kic

ks it

bac

kwar

d 0.

5π

yard

s.

Par

t A

: O

n th

e nu

mbe

r lin

e, p

lot a

poi

nt to

rep

rese

nt th

e di

stan

ce

from

the

ball’

s in

itial

loca

tion

at 0

to it

s fin

al lo

catio

n. E

ach

incr

emen

t on

the

num

ber

line

repr

esen

ts 1

yar

d.

21

09

108

76

54

3

Par

t B

: Ex

plai

n w

hy y

ou c

anno

t illu

stra

te th

e di

stan

ce e

xact

ly. T

hen

give

th

e di

stan

ce r

ound

ed to

the

near

est h

undr

edth

.

Th

ink

Sm

art

fo

r S

BA

C

On

the

actu

al te

st, y

ou m

ight

be

ask

ed to

clic

k th

e bu

tton

to p

lot a

poi

nt o

n th

e nu

mbe

r lin

e. In

this

boo

k, y

ou w

ill b

e as

ked

to d

raw

the

poin

t on

the

num

ber l

ine.

Sam

ple

answ

er: B

ecau

se π

is ir

ratio

nal,

any

mul

tiple

of

π is

als

o ir

ratio

nal.

So,

2.5

π is

irra

tiona

l. Ir

ratio

nal

num

bers

nev

er t

erm

inat

e or

rep

eat,

so t

hey

cann

ot b

e ill

ustr

ated

exa

ctly

. The

dis

tanc

e fr

om t

he in

itial

lo

catio

n to

the

fin

al lo

catio

n is

2.5

π y

d ≈

7.8

5 y

d.

015-

016_

SB

AC

_A_C

3_C

D19

_793

945.

indd

16

11/2

3/14

5:

17 P

M

NA

ME

D

ATE

P

ERIO

D

SC

OR

E

8.N

S.1

8.EE

.7, 8

.EE.

7a

8.N

S.2

Copyright © McGraw-Hill Education. Permission is granted to reproduce for classroom use.

Cou

rse

3 •

Cou

ntdo

wn

• 19

Wee

ks

15

Cou

ntdo

wn:

19

Wee

ks1.

A

com

pany

sel

ls o

nly

item

s th

at a

re in

the

shap

e of

cub

es.

Sele

ct a

ll of

the

volu

mes

of c

ubes

with

rat

iona

l num

ber

side

leng

ths.

8 in

3

33 c

m3

1.5 ft

3

9 ft

3

1,00

0 m

3

(4.12

yd)

3

2.

Sher

ron

is w

ritin

g a

com

pute

r pr

ogra

m th

at s

olve

s lin

ear

equa

tions

and

di

spla

ys a

num

eric

al a

nsw

er fo

r th

e so

lutio

n.

Par

t A

: W

hen

Sher

ron

inpu

ts th

e eq

uatio

n 4x

+ 3

= 4

(1 +

x) +

1, s

he g

ets

an

erro

r m

essa

ge. E

xpla

in w

hy.

Par

t B

: Sh

erro

n in

puts

the

equa

tion

5 +

6y

= 9

y +

2 +

3(1

– y

). W

hat i

s th

e re

sult

and

why

?

3.

A s

quar

e pi

ctur

e fr

ame

encl

oses

an

area

of 2

9 s

quar

e in

ches

. Its

ow

ner

clai

ms

that

the

fram

e si

des

are

betw

een

5.2

5 a

nd 5

.35

inch

es lo

ng. I

s th

e ow

ner

corr

ect?

Why

or

why

not

?

Th

ink

Sm

art

fo

r S

BA

C

On

the

actu

al te

st, y

ou m

ight

be

ask

ed to

clic

k al

l of t

he

corr

ect a

nsw

er c

hoic

es. I

n th

is b

ook,

you

will

be

aske

d to

sha

de a

box

nex

t to

each

co

rrec

t ans

wer

cho

ice.

The

equa

tion

sim

plifi

es t

o 5

+ 6

y =

5 +

6y,

or

5 =

5,

whi

ch h

as a

n in

finite

num

ber

of s

olut

ions

. So,

She

rron

w

ould

get

an

erro

r m

essa

ge.

No;

Bec

ause

the

fra

me

is a

squ

are,

the

sid

es m

ust

be

the

sam

e le

ngth

. The

are

a A

= s

2 =

29.

So,

the

sid

e le

ngth

mus

t eq

ual √

___

29

≈ 5

.38

5 in

ches

. Thi

s do

es n

ot

fall

betw

een

5.2

5 a

nd 5

.35

, so

the

owne

r is

inco

rrec

t.

The

equa

tion

sim

plifi

es t

o 4x

+ 3

= 4

x +

5, o

r 3

= 5

, w

hich

has

no

solu

tion.

So,

She

rron

get

s an

err

or.

015-

016_

SB

AC

_A_C

3_C

D19

_793

945.

indd

15

11/2

3/14

5:

17 P

M

Program: SBAC Component: CD 19

PDF PassVendor: MPS Grade: Course 3

172 Course 3 • Countdown

Countdown: 19 Weeks

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