cs codes wit problems

PROBLEM STATEMENT 1/* PROBLEM STATEMENT 1:Design and create a program that will prompt the user to enter the number of hours required to install a hardwood floor. Display the number of complete eight-hour work days required for the job, as well as the remaining hours needed in the last day. Compute and display the total cost of the job at Php 350 per day plus Php 50 per hour for any partial day. */

#include <iostream>using namespace std;

int main (){ int TOTALcost, pay_350, pay_50, COMPLETEDhr, REMAININGhr, hrs;

cout << " This program will able to enter the number of hours required to install a hardwood floor" << endl;

cout << "Please enter the number of hours:";cin >> hrs;

//FORMULASCOMPLETEDhr = hours / 8;REMAININGhr = hours % 8;pay_350 = 350 * COMPLETEDhr;pay_50 = 50 * REMAININGhr;TOTALcost = pay_350 + pay_50;

cout << "Number of complete eight-hour work day/s: " << COMPLETEDhr << " hour/s" << endl;

cout << "Number of remaining hour/s: "<< REMAININGhr << " hour/s" << endl;

cout << "Total cost of the job is Php " << TOTALcost;cout << endl;cin.get ();return 0;}

PROBLEM STATEMENT 2/* PROBLEM STATEMENT 2:Design and create a program for a bank that allows the user to enteran amount of money in cents. Display the number of whole peso the bankwill give the customer in exchange. */


int main (){ int cent, peso;cout << "BANK SERVICE" << endl;

cout << " Please enter the amount of money in cents: ";cin >> cent;

cout << "You entered an amount of " << cent << " centavos." << endl;

//CENTAVOS TO PESOS FORMULApeso = cent/100;

// Conversion of centavos to pesos (OUTPUT)cout << "The number of whole peso the bank will give in exchange is " << peso << " peso/s" << endl;

return 0;}

PROBLEM STATEMENT 3/* PROBLEM STATEMENT 3:All years that are evenly divisible by 400 or are evenly divisible by four and not evenly divisible by 100 are leap years. For example, since 1600 is evenly divisible by 400, the year 1600 was a leap year. Similarly, since 1988 is evenly divisible by four but not by 100, the year 1988 was also a leap year. Using this information, write a C++ program that accepts the year as user input, determine if the year is a leap year, and displays an appropriate message that tells the user if the entered year is or not a leap year. */

#include <iostream>using namespace std;int main(){ int year;

cout << "IS IT A LEAP YEAR OR NOT? " << endl;cout << "Please enter a year: ";cin >> year;

/* Conditions to satisfy a leap year:1. Years that are divisible by 4.2. If it's divisible by 100, it isn't. BUT if its divisible by 400, it is. */

if (year%4==0 && year&100!=0 || year&400==0)cout << "The year, " << year << ", is a leap year!"<< endl;

elsecout << "The year, " << year << ", is NOT a leap year!" << endl;

return 0;}

PROBLEM STATEMENT 4

/* PROBLEM STATEMENT 4:Based on an automobile's model year and weight the state of New Jersey determines the car's weight class and registration fee using the following schedule:Using this information, write C++ program that accepts the year and weight of an automobile and determine and displays the weight class and registration fee for the car. */


int main (){ int year, lbs;// This program will let you know the weight class and registration for the automobile carcout << "AUTOMOBILE's WEIGHT CLASS & REGISTRATION FEE" << endl;

if (year <= 1970){ if (lbs < 2700)cout << "The weight class is 1 and the registration fee is $16.50" << endl;

else if (lbs >= 2700 && lbs <= 3800)cout << "The weight class is 2 and the registration fee is $25.50" << endl;

else cout << "The weight class is 3 and the registration fee is $46.50" << endl; }

else if (year >= 1971 && year <=1979){ if (lbs < 2700)cout << "The weight class is 4 and the registration fee is $27.00" << endl;

else if (lbs >= 2700 && lbs <= 3800)cout << "The weight class is 5 and the

cout << "Please enter the automobile's model year: ";cin >> year;

cout << "Please enter the automobile's weight in lbs: ";cin >> lbs;cout << endl;

registration fee is $30.50" << endl;

else cout << "The weight class is 6 and the registration fee is $52.50" << endl; }

else { if (lbs < 3500)cout << "The weight class is 7 and the registration fee is $19.50" << endl;else cout << "The weight class is 8 and the registration fee is $52.50" << endl; }

cin.get ();cin.get ();return 0;}

PROBLEM STATEMENT 5/* PROBLEM STATEMENT 5:The program will ask for a number. Then will display the odd numbers on that number. Then on the next line will show the even numbers from the number we have input. Then add up all even numbers and multiply all the odd numbers.

Input Validation:Input an integer:

Sample Run:Input a number 15Odd Number: 1 3 5 7 9 11 13 15Even Number: 4 6 8 10 12 14Sum of Even numbers: 56Product of Odd Numbers: 2027025 */


int main (){ int number sum_even=0,product_odd=1;

cout << “INPUT VALIDATION: “ << endl;cout << " Input a Number: ";cin >> number;

cout<<"Even Number: ";for (int i=1; i<=number; i++)

{ if (i%2==0){ cout<< i <<" ";sum_even+=i; } }cout << endl;

cout<<"Odd Numbers :";for (i=1; i<=number; i++){if (i%2!=0){ cout<< I <<" ";product_odd*=i; } }cout << endl;

cout<< " Sum of Even Numbers: "<< sum_even << endl;

cout<< " Product of Odd Numbers: " << product_odd << endl;

return 0;}

PROBLEM STATEMENT 6/* PROBLEM STATEMENT 6:The Fibonacci Sequence is a sequence of numbers that are obtained by adding the last two numbers in the sequence to get the next one. Usually, the first two numbers in the sequence are 0 and 1. This leads to the sequence: 0, 1, 1, 2, 3, 5, 8, 13, 21, 24, 35, 55. As you can see, each term in the sequence is equal to the sum of the two terms before it. Your task is to create a program that will generate a Fibonacci Type Sequence of length N, given the two first numbers in the sequence A and B.

Input:N, an integer, the length of the output sequence required (0 <= N <= 100), A and B, both integers, the first and second items in the sequence (0<=A<=100; 0<=B<=100)

Output:N, integers, separated by spaces of the Fibonacci Type Sequence beginning with A and B */


int main (){ int N, c, first = 0, second = 1, next;

cout << "FIBONACCI SEQUENCE" << endl;cout << " Input length: ";cin >> N; // N, an integer, the length

cout << "A: " << first << endl;cout << "B: " << second << endl;

/* PROBLEM STATEMENT 6:Using loop, write a program that will ask the user to enter a character for left or right. Then, the user will enter a number. The program should generate a ladder of x wherein the level depends on the number entered and the character should dictate whether it faces right or left.SAMPLE:

Character is rNumber is 3

XXXXXX

Character is rNumber is 4

XXXXXXXXXX

Character is lNumber is 5

XXX

XXXXXXX

XXXXX*/

#include <iostream>#include <string>using namespace std;

int main( ){ char c;int number, n, i, j, k;

cout << "Character is ";cin >> c;

cout << "Number is ";cin >> number;

n = number - 1;for (i = 0; i < num; ++i) { if (toupper(c) == 'L')

{ for (k = 0; k < n; ++k) { cout << " "; }--n; }

if (toupper(c) == 'L' || toupper(c) == 'R')

cout << "First " << N << " terms of Fibonacci Series are: " << endl;for (c = 0; c < N; c++){ if (c <= 1)next = c;else { next = first + second;first = second;second = next; }cout << " " << next; }

return 0;}

{ for (j = 0; j < i + 1; ++j) { cout << "X"; }cout << endl; } }

return 0; }

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