cven2302 final exam 2010
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Final Exam 2010 for Cven2302TRANSCRIPT
THE UNIVERSITY OFNEW SOUTH WALES
SCHOOL OF ClVIL AND ENVIRONMENTAL E GINEERING
CVEN 2302 MATERIALS AND STRUCTURES
FINAL EXAMINATION
NOVEMBER 2010
Time Allowed - 3 Hours
All Questions to be answered
ANSWER QUESTION 1 IN ONE BOOKLETANSWER QUESTIO S 2-4 IN A SEPARATE BOOKLET
Questions are NOT of equal value
Closed Book Examination
This paper may be retained by the candidate
Electronic calculators anddrawing instruments may be used
All answers to be legibly written in ink
Pencil may be used for drawings, sketches and graphs.
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SECTION A MATERIALS
Answer this Section in a separate booklet
QUESTION 1 (34 Marks)
(a) Discuss the contribution of C3S and C3A (of General Purpose Portland cement) on heat ofhydration. (3 marks)
(b) Describe Slump Test and Compacting Factor method for the measurement of workability ofconcrete. (8 marks)
(c) What are the advantages of testing cylinders to obtain the compressive strength of concretewhen compared with cubes? (3 marks)
(d) Determine the modulus of rupture of the prism having a cross-section of 102 x 102 mm, span of300 mm and a failure load of 20 kN. (3 marks)
(e) Describe the causes of corrosion of steel reinforcement. What remedial actions can be taken tominimise corrosion of reinforcement. (8 marks)
(f) What is alkali-silica reaction? What are the possible preventive measures? (9 marks)
SECTIONB STRUCTURES
Answer this Section in a separate booklet
QUESTION 2 (18 Marks)
A splice is made in an I-section tension member by bolting it to 2 - 400 x 20 mm plates of Grade 300
steel, one to each flange. The 18 mm bolts in 20 mm holes are arranged as shown with a gauge of 60
mm and a staggered pitch of 50 mm. (Grade 300 steel: h = 320 MPa,fu = 440 MPa)
(I) Calculate the gross and net cross-sectional area without stagger (Ag and A,,) for plates.
(2) Calculate the net cross-sectional area with stagger (A,,) for plates. (Hint: s~ Xg )(3) Determine the maximum design force N* that can be transmitted through the plates.
, , , , ,sp , -' '- '- ,, -, - ,- ,- ,-=
, , , , ,,50: 50 :50 :50 :50,
50 : : , ,
~5g=60--- -----o--~--o--~-_o-+-O-
- - - - - - - - +- - -(4)- -}- - -cD - -:- - Q - -i --
60_1_ ·····················+·········t··········f···········~···········l···········!··········+······· .
................. ,....•..........., -..,. ,. , , ..
- --- - ~ - -0- -:--0 -~--6-- ~------{!--~-~--~-\>-~--CF-i ....................-.-..........-.
(a) Plate Cb) I-section tension member
Figure 2
QUESTION 3 (24 Marks)
The floor shown in the figure below with an overall depth of 250 mm (reinforced concrete slab) is to be
designed to carry an imposed load of 4 kPa. Assume that the beam weight is 50 kN/m. The unit weight
of reinforced concrete is 20 kN/m] (Note: Generally strength limit state is used to calculate design
actions and beams are on the same level unless otherwise specified)
(1) Draw the tributary areas and calculate the design loads acting on beams BI-B3, Cl-C2 and CI-Dl.
(2) Determine the design shear force and bending moment for the strength limit state for beams B I-B3.
-03m
-03m
IB------a-----e---~-0I<::(:-_--'4--'.m"----_---7)I<::(__----"4:-<m'-'---_----;:»I"'(__4"--'.!m-'----__-3»I
(;) 0 (0 CVFigure 3
QUSTIO 4 (24 Marks)
The pin-joined truss with design loads are shown in Figure 4.
(1) Calculate the force in member DE.
(2) Check if a 125 x 75 x 5.0 RHS (Rectangular Hollow Section) is sufficient for member DE. Use
Grade 300 steel.
80kN !160kN 1c
1_4B_3_m__~1_4_3_m_-+l~1
3m
Figure 4
Notes:
I. All joints are laterally braced. Ignore the members' self-weight. Grade 300 steel: h = 320 MPa,fu =
440MPa.
2. Yield slenderness limit for all plates of RHS: 2,y = 45. Rectangular Hollow Sections:
125 mm
15
3. 2 =!:~ i y 1= bh 3
r = TT 2 = fk(L)~ i y
, t 250' 12' fA" v"" f r 250 .
a - {1-~I-(90J'1 _(2/90)'+1+17 2-2 +a.a a _ 2100(2.-13.5)4. c -~ ~2''; - 2(2/90)' , -. ba, a - 2~ -15.32. +2050 '
ab =-1.0, 17=0.00326(2-13.5»0.