damped and forced shm
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Damped and Forced SHM. Physics 202 Professor Lee Carkner Lecture 5. If the amplitude of a linear oscillator is doubled, what happens to the period?. Quartered Halved Stays the same Doubled Quadrupled. - PowerPoint PPT PresentationTRANSCRIPT
If the amplitude of a linear oscillator is doubled, what happens to the period?
a) Quarteredb) Halvedc) Stays the samed) Doublede) Quadrupled
If the amplitude of a linear oscillator is doubled, what happens to the spring constant?
a) Quarteredb) Halvedc) Stays the samed) Doublede) Quadrupled
If the amplitude of a linear oscillator is doubled, what happens to the total energy?
a) Quarteredb) Halvedc) Stays the samed) Doublede) Quadrupled
If the amplitude of a linear oscillator is doubled, what happens to the maximum velocity?
a) Quarteredb) Halvedc) Stays the samed) Doublede) Quadrupled
If the amplitude of a linear oscillator is doubled, what happens to the maximum acceleration?
a) Quarteredb) Halvedc) Stays the samed) Doublede) Quadrupled
If you have a pendulum of fixed mass and length and you increase the length of the path the mass travels, what happens to the period?
a) Increaseb) Decreasec) Stays the same
If you have a pendulum of fixed mass and length and you increase the length of the path the mass travels, what happens to the maximum velocity?
a) Increaseb) Decreasec) Stays the same
If you have a pendulum of fixed mass and length and you increase the length of the path the mass travels, what happens to the maximum acceleration?
a) Increaseb) Decreasec) Stays the same
The pendulum for a clock has a weight that can be adjusted up or down on the pendulum shaft. If your clock runs slow, what should you do?
a) Move weight upb) Move weight downc) You can’t fix the clock by moving
the weight
PAL #4 Pendulums The initial kinetic energy is just the kinetic
energy of the bullet ½mv2 = (0.5)(0.01 kg)(500 m/s)2 =
The initial velocity of the block comes from the kinetic energy KE = ½mv2
v = (2KE/m)½ = ([(2)(1250)]/(5))½ = Amplitude =xm, can get from total energy
Initial KE = max KE = total E = ½kxm
xm =(2E/k)½ = ([(2)(1250)]/(5000))½ = Equation of motion = x(t) = xmcos(t)
k = m2
= (k/m)½ = [(5000/(5)]½ = 31.6 rad/s
Uniform Circular Motion
Simple harmonic motion is uniform circular motion seen edge on
Consider a particle moving in a circle with the origin at the center
The projection of the displacement, velocity and acceleration onto the edge-on circle are described by the SMH equations
Uniform Circular Motion and SHM
x-axis
y-axis
xm angle =t+
Particle movingin circle of radius xm
viewed edge-on:
cos (t+)=x/xm
x=xm cos (t+) x(t)=xm cos (t+)
Particle at time t
Observing the Moons of Jupiter
He discovered the 4 inner moons of Jupiter
He (and we) saw the orbit edge-on
Application: Planet Detection
The planet cannot be seen directly, but the velocity of the star can be measured
The plot of velocity versus time is a sine curve (v=-xmsin(t+)) from which we can get the period
Damped SHM Consider a system of SHM where friction is
present
The damping force is usually proportional to the velocity
If the damping force is represented byFd = -bv
Then,
x = xmcos(t+) e(-bt/2m)
e(-bt/2m) is called the damping factor and tells you by what factor the amplitude has dropped for a given time or:
x’m = xm e(-bt/2m)
Energy and Frequency The energy of the system is:
E = ½kxm2 e(-bt/m)
The period will change as well:’ = [(k/m) - (b2/4m2)]½
Damped Systems
Most damping comes from 2 sources: Air resistance
Example:
Energy dissipation Example:
Lost energy usually goes into heat
Forced Oscillations If you apply an additional force to a
SHM system you create forced oscillations
If this force is applied periodically then you have 2 frequencies for the system
d = the frequency of the driving force The amplitude of the motion will
increase the fastest when =d
Resonance
Resonance occurs when you apply maximum driving force at the point where the system is experiencing maximum natural force Example: pushing a swing when it is all the
way up All structures have natural frequencies
Summary: Simple Harmonic Motion
x=xmcos(t+)
v=-xmsin(t+)
a=-2xmcos(t+)
=2/T=2fF=-kx
=(k/m)½ T=2(m/k)½
U=½kx2 K=½mv2 E=U+K=½kxm2
Summary: Types of SHM
Mass-springT=2(m/k)½
Simple PendulumT=2(L/g)½
Physical PendulumT=2(I/mgh)½
Torsion PendulumT=2(I/)½