day 35 ppt batfink on the rocks

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Page 1: Day 35 Ppt Batfink On The Rocks
Page 2: Day 35 Ppt Batfink On The Rocks

#1 All students must perform all of the work of the activity in their science journals.

#2 When you are sure of your answer, transfer the information onto a mini whiteboard.

#3 The whiteboard work is to remain on the white board until it is approved.

#4 After your work is approved you are to become a student teacher and assist someone in the room who is having difficulty.

Page 3: Day 35 Ppt Batfink On The Rocks
Page 4: Day 35 Ppt Batfink On The Rocks

The evil Hugo A-Go-Go has stolen all of the water on the planet and is threatening to push Batfink, who is trapped in a barrel, off of the 52 meter high Canadian

Horseshoe Falls into the dried up Maid of the Mist Pool.

Batfink is 50 kg. He and the 25 kg. barrel are pushed with a 100N force over a distance of 10 m before leaving

the cliff. The force of friction is 8N.

How much time will Batfink have to escape from the barrel once it leaves the cliff? Karate is padding the

place where the barrel will land in case Batfink cannot free himself. How far away from the cliff should Karate

place the barrel catching device made of super foam?

Page 5: Day 35 Ppt Batfink On The Rocks
Page 6: Day 35 Ppt Batfink On The Rocks
Page 7: Day 35 Ppt Batfink On The Rocks

What is the Fg on Batfinkand the barrel?

Show all of your work.

Page 8: Day 35 Ppt Batfink On The Rocks

KNOWN WANT

m of Batfink = 50 kg. Fg

m of barrel = 25 kg.

Total mass = 75 kg.

GENERAL FORMULA

kg. x N/kg. = N

75 kg. x 9.8N/kg = 735N

Page 9: Day 35 Ppt Batfink On The Rocks

What is the Fs acting on Batfink and the Barrel?

Show all of your work.

Page 10: Day 35 Ppt Batfink On The Rocks

KNOWN WANT

mass = 75 kg. Fs

Fg = 735N

g = 9.8 m/s2

GENERAL FORMULA

Fs = W and since no acceleration, Fs = Fg = mg

Fs = (75 kg.)(9.8 m/s2)

Fs = 735N

Page 11: Day 35 Ppt Batfink On The Rocks

Draw a force diagram of Batfink and the barrel while rolling on top of the cliff.

Page 12: Day 35 Ppt Batfink On The Rocks

y

Fs 735N

Ff 8N F 100N x

Fg 735N

Page 13: Day 35 Ppt Batfink On The Rocks

Calculate the acceleration of the barrel in the “x” direction.

Page 14: Day 35 Ppt Batfink On The Rocks

KNOWN WANT

mass = 75 kg. a

F = 100N

Ff = 8N

GENERAL FORMULA

Fx net = ma

F - Ff = ma

100N - 8N = (75 kg.)(a)

92N/75 kg = 1.23 m/s2

Page 15: Day 35 Ppt Batfink On The Rocks

What is the Vf of the barrel just before it falls off the cliff?

Page 16: Day 35 Ppt Batfink On The Rocks

KNOWN WANT

a = 1.23 m/s2 Vf

d = 10 m

Vo = 0 m/s

GENERAL FORMULA

Xf = Xo + Vo t + ½ at2 then V = at

10 m = (0 m/s)(t) + ½ (1.23 m/s2 )(t2)

10 m/.615 m/s2 = (t2)

16.26 s = t2

t = 4.03 s Vf = 4.96 m/s

Page 17: Day 35 Ppt Batfink On The Rocks

How much time will Batfink have to escape from the barrel once it leaves the cliff?

Page 18: Day 35 Ppt Batfink On The Rocks

KNOWN WANT

g = 9.8. m/s2 td = 52 mVo = 0 m/sGENERAL FORMULA

Yf = Yo + Vo t + ½ at2

52 m = (0 m/s)(t) + ½ (9.8 m/s2 )(t2) 52 m/4.9 m/s2 = t2

10.61 s = t2

3.26 s = t

Page 19: Day 35 Ppt Batfink On The Rocks

How far away from the cliff should Karate place the barrel catching device made of super foam?

Page 20: Day 35 Ppt Batfink On The Rocks

KNOWN WANT

a = 1.23 m/s2 Xf

d = 52 m

Vo = 0 m/s

t = 3.26 s

GENERAL FORMULA

Xf = Xo + Vo t + ½ at2

Xf = 0 m + (4.95 m/s)(3.26 s)

Xf = 16.14 m

Page 21: Day 35 Ppt Batfink On The Rocks