day 4 10-22 solve: 1.5e24 molecules of so 2 = ____ grams of so 2 ? s 2 + 2o 2 2so 2 and how many...

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Day 4 10-22 SOLVE: 1.5e24 molecules of SO 2 = ____ grams of SO 2 ? S 2 + 2O 2 2SO 2 And how many moles of S 2 ?

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Page 1: Day 4 10-22 SOLVE: 1.5e24 molecules of SO 2 = ____ grams of SO 2 ? S 2 + 2O 2  2SO 2 And how many moles of S 2 ?

Day 4 10-22

SOLVE: 1.5e24 molecules of SO2 = ____ grams of SO2?

S2 + 2O2 2SO2

And how many moles of S2?

Page 2: Day 4 10-22 SOLVE: 1.5e24 molecules of SO 2 = ____ grams of SO 2 ? S 2 + 2O 2  2SO 2 And how many moles of S 2 ?
Page 3: Day 4 10-22 SOLVE: 1.5e24 molecules of SO 2 = ____ grams of SO 2 ? S 2 + 2O 2  2SO 2 And how many moles of S 2 ?

Limiting Reactant – the reactant that limits the amounts of the other reactants that can combine and the amount of product that can form in a chemical reaction – the one you will run out of

Excess Reactant – any substance that is not used up completely in a reaction – left over

Limiting Reactants

Page 4: Day 4 10-22 SOLVE: 1.5e24 molecules of SO 2 = ____ grams of SO 2 ? S 2 + 2O 2  2SO 2 And how many moles of S 2 ?

Limiting Reactants

To determine the Limiting Reactant – use either reactant to calculate the amounts necessary for reaction

Example:

4NH3(g) + 6NO(g) 5N2(g) + 6H2O(l)

Given the following, determine the limiting reactant:

40 g NH3

41 g NO

Page 5: Day 4 10-22 SOLVE: 1.5e24 molecules of SO 2 = ____ grams of SO 2 ? S 2 + 2O 2  2SO 2 And how many moles of S 2 ?

Limiting ReactantsExample:

4NH3(g) + 6NO(g) 5N2(g) + 6H2O(l)

Given the following, determine the limiting reactant:

40 g NH3

41 g NO

Page 6: Day 4 10-22 SOLVE: 1.5e24 molecules of SO 2 = ____ grams of SO 2 ? S 2 + 2O 2  2SO 2 And how many moles of S 2 ?

2Na + Cl2 → 2NaCl

Limiting Reactants

Start with 4 moles of Na and 3 moles of Cl2:

limiting = ?

excess = ?

Page 7: Day 4 10-22 SOLVE: 1.5e24 molecules of SO 2 = ____ grams of SO 2 ? S 2 + 2O 2  2SO 2 And how many moles of S 2 ?

2Na + Cl2 → 2NaCl

Limiting Reactants

Start with 26 grams of Na and 35.5 grams of Cl2:

limiting = ?

excess = ?

Page 8: Day 4 10-22 SOLVE: 1.5e24 molecules of SO 2 = ____ grams of SO 2 ? S 2 + 2O 2  2SO 2 And how many moles of S 2 ?

Day 5 10-23

1. If you start with 2.5 moles of solid aluminum and allow it to react with 2.5 moles of CuCl2 which reactant will be left over at the end?

2. Why is today Mole Day?

Page 9: Day 4 10-22 SOLVE: 1.5e24 molecules of SO 2 = ____ grams of SO 2 ? S 2 + 2O 2  2SO 2 And how many moles of S 2 ?

Day 6 10-24

1. Which reactant determines your theoretical yield?

Page 10: Day 4 10-22 SOLVE: 1.5e24 molecules of SO 2 = ____ grams of SO 2 ? S 2 + 2O 2  2SO 2 And how many moles of S 2 ?

Percent Yield =

Percent Yield

Actual Yield Theoretical Yield

X 100

the percent yield is a measure of the efficiency of a reaction carried out in the lab. - a perfect percent yield would

be a 100%

Page 11: Day 4 10-22 SOLVE: 1.5e24 molecules of SO 2 = ____ grams of SO 2 ? S 2 + 2O 2  2SO 2 And how many moles of S 2 ?

Example # 1:Calcium carbonate, which is found in seashells, is decomposed by heating. The reaction is below:

CaCO3(s) CaO(s) + CO2(g)

What is the theoretical yield of CaO if 24.8 grams of CaCO3 is heated?

If only 12 grams of CaO are recovered, what is the percent yield?

What could be the cause?

Percent Yield = Actual Yield Theoretical Yield

X 100

Page 12: Day 4 10-22 SOLVE: 1.5e24 molecules of SO 2 = ____ grams of SO 2 ? S 2 + 2O 2  2SO 2 And how many moles of S 2 ?

12

Quarterly PracticeA solution containing 3.50 g sodium

phosphate is mixed with a solution containing 6.40 g barium nitrate. After the reaction is complete, 4.85 g barium phosphate are collected.

1. What is the limiting reagent?2. What is the theoretical yield of barium

phosphate?3. What is the percent yield of barium

phosphate?

2Na3PO4(aq) + 3Ba(NO3)2(aq) 6NaNO3(aq) + Ba3(PO4)2(s)

molar masses:Na3PO4 = 163.9Ba(NO3)2 = 261.3Ba3(PO4)2 = 601.9

Page 13: Day 4 10-22 SOLVE: 1.5e24 molecules of SO 2 = ____ grams of SO 2 ? S 2 + 2O 2  2SO 2 And how many moles of S 2 ?

13

Quarterly PracticeA solution containing 3.50 g sodium

phosphate is mixed with a solution containing 6.40 g barium nitrate. After the reaction is complete, 4.85 g barium phosphate are collected.

1. What is the limiting reagent?2. What is the theoretical yield of barium

phosphate?3. What is the percent yield of barium

phosphate?

2Na3PO4(aq) + 3Ba(NO3)2(aq) 6NaNO3(aq) + Ba3(PO4)2(s)

If you start with 3.50 g Na3PO4 you NEED 8.37 g Ba(NO3)2

So Barium nitrate is limiting and you start your theoretical with 6.40 g barium nitrateTheoretical yield = 4.91% yield = 98.8 %

Page 14: Day 4 10-22 SOLVE: 1.5e24 molecules of SO 2 = ____ grams of SO 2 ? S 2 + 2O 2  2SO 2 And how many moles of S 2 ?

Review sections 12.1 and 12.2 and complete # 8 on page 389, # 11 on page 391, # 13 on page 393, and # 23 on page 398 – due tomorrow

Assignment

Page 15: Day 4 10-22 SOLVE: 1.5e24 molecules of SO 2 = ____ grams of SO 2 ? S 2 + 2O 2  2SO 2 And how many moles of S 2 ?
Page 16: Day 4 10-22 SOLVE: 1.5e24 molecules of SO 2 = ____ grams of SO 2 ? S 2 + 2O 2  2SO 2 And how many moles of S 2 ?

Get to # 11

Hand in assignment from Friday

Page 17: Day 4 10-22 SOLVE: 1.5e24 molecules of SO 2 = ____ grams of SO 2 ? S 2 + 2O 2  2SO 2 And how many moles of S 2 ?

Review sections 12.1 and 12.2 and complete #s 5, 6, 8, 9, and 10 on page 389, #s 11 and 12 on page 391, and #s 13 and 14 on page 393 – due beginning of class Tuesday 10-29

Complete #s 21-25 on page 398 – due Wednesday 10-30

Assignment