dickson octagon hay feeder designing an octagon hay feeder

Dickson Octagon Hay Feeder

Designing an Octagon

Hay Feeder


Objectives

The student will

• Translate word phrases & sentences into expressions and equations

• Solve linear equations (determine angle and degree of cut)

• Draw and analyze dimensional figures

• Use tools to construct figures


Definitions

• Polygon – A simple closed curve made

up of segments (each called a “side”)

• Complimentary angles – Two angles whose sum is 90

degrees

• Perpendicular – Two lines intersecting in a 90

degree angle


Definitions (cont.)

• Proportion– A statement that ratios are

equal

• Unit of measure– Linear feet or inches

• Octagon– Eight sided polygon

• Pentagon (5 sides) and Hexagon (6 sides)


Formula for Interior Angle

of a Polygon

Angle = (N-2) • 180° N

(number of sides minus two,multiplied by 180 degrees, then divided by the number of sides)N = number of sides


Formula for “cut of angle”

• Divide the degree of angle by 2

• Subtract the degree from 90

Ex. Degree of cut = 135°÷ 2

67.5° =

90° - 67.5° = 22.5°


Optional Formula for “cut of angle”

• Shortcut for finding the “cut of angle” is to use 180º divided by the number of sides (180º N)

• Example: “cut of angle” for a pentagon

• 180º 5 = 36º


Finding the Length of Side

• To find the length of the sides of an octagon feeder is to use the formula 2rTan(180º/N) or dTan(180º/N), where r is radius and d is diameter.

• Ex.: 7’ diameter feeder7Tan(180º/8) =

7Tan(22.5º) = 7(.4142) = 2.9” or 2’ 11”

dickson octagon hay feeder designing an octagon hay feeder

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