differential and multistage amplifierskttang/course/slides/ee2260/week11.pdf · amplifier •the...
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Differential and MultistageAmplifiers
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Outline
•The MOS Differential Pair•Small-Signal Operation of the MOS Differential Pair•The BJT Differential Pair•Other Nonideal Characteristics of the Differential
Amplifier•The Differential Amplifier with Active Load•Frequency Response of the Differential Amplifier•Multistage Amplifiers
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A Bipolar Op Amp
Diff-inDiff-out
Diff-inSingle-endedoutput
DC level ShiftingVoltage gain
Output
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Example 7.4Connecting the two input terminals to ground.(a) Assume >>1, |VBE|=0.7V, neglect Early effect
(b) The quiescent powerdissipation
(c) Input bias current for=100
(d) Input common-moderange
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Example 7.5(a) Input resistance
(b) Output resistance
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Example 7.5 (con’t)(c) Voltage gain
Input stage Second stage
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Example 7.5 (con’t)(c) Voltage gain
Third stage Output stage
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Analysis Using Current Gains
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c
c
b
b
c
c
b
b
c
c
b
b
e
i
e
ii
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ii
ii
ii
ii
ii
ii 2
2
5
5
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7
7
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88
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Frequency Response
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Feedback
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Outline
•The General Feedback Structure•Some properties of Negative Feedback•The Four Basic Feedback Topologies•The Series-Shunt Feedback Amplifier•The Series-Series Feedback Amplifier•The Shunt-Shunt and Shunt-Series Feedback Amplifier•Determining the Loop Gain•The Stability Problem•Effect of Feedback on the Amplifier Poles•Stability Study Using Bode Plots•Frequency Compensation
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Feedback
•Most physical systems incorporate someform of feedback–Negative –Degenerative–Positive –Regenerative
•Negative feedback in amplifier design–Desensitize the gain–Reduce nonlinear distortion–Reduce the effect of noise–Control the input and output impedances–Extend the bandwidth of the amplifier
•Everything good is at the expense of areduction of gain. Gain-reduction factor –theamount of feedback
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General Feedback Structure
fsi xxx
sf xA
Ax
1
si xA
x
1
1
io Axx A : Open-loop gain
of xx : Feedback factor
AA
xx
As
of
1
A: Loop gain1+A: Amount of feedbackAf : Closed-loop gain
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Exercise 8.1
(a) Assume that the op amp has infinite Rinand zero Rout, find
(b) If the open-loop voltage gain A=104, findR2/R1 to obtain closed-loop voltage gain Af=10
(c) What is the amount of feedbackIn decibels?
(d) If Vs=1V, find Vo, Vf, and Vi
(e) If A decreases 20%, what is theCorresponding decrease in Af?
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Outline
•The General Feedback Structure•Some properties of Negative Feedback•The Four Basic Feedback Topologies•The Series-Shunt Feedback Amplifier•The Series-Series Feedback Amplifier•The Shunt-Shunt and Shunt-Series Feedback Amplifier•Determining the Loop Gain•The Stability Problem•Effect of Feedback on the Amplifier Poles•Stability Study Using Bode Plots•Frequency Compensation
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Gain and Bandwidth
AA
Af
1
21 AdA
dAf
AdA
AA
dA
f
f
11
Gain Desensitivity
H
M
sA
sA
1
sA
sAsAf
1
MH
MMf As
AAsA
11
1
MHHf A 1
M
LLf A
1
1+A: desensitivity factor
Bandwidth Extension
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Noise Reduction
2AVV
NS
n
s
n
s
VV
NS
21
1
21
21
11 AAA
VAA
AAVV nso
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Reduction in Nonlinear Distortion
Gain = 0
Gain = 100
Gain = 1000
9.9001.010001
1000
5001.01001
100
1
2
f
f
A
A
What does negative feedback do to amplifier saturation?
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Outline
•The General Feedback Structure•Some properties of Negative Feedback•The Four Basic Feedback Topologies•The Series-Shunt Feedback Amplifier•The Series-Series Feedback Amplifier•The Shunt-Shunt and Shunt-Series Feedback Amplifier•Determining the Loop Gain•The Stability Problem•Effect of Feedback on the Amplifier Poles•Stability Study Using Bode Plots•Frequency Compensation
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Voltage Amplifiers
Input signal: voltageOutput signal: voltage
Voltage-mixing Voltage-sampling
Series –Shunt feedback topology
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Current Amplifiers
Input signal: currentOutput signal: current
Current-mixing Current-sampling
Shunt –Series feedback topology
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Transconductance Amplifiers
Input signal: voltageOutput signal: current
Voltage-mixing Current-sampling
Series –Series feedback topology
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Transresistance Amplifiers
Input signal: currentOutput signal: voltage
Current-mixing Voltage-sampling
Shunt –Shunt feedback topology
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Outline
•The General Feedback Structure•Some properties of Negative Feedback•The Four Basic Feedback Topologies•The Series-Shunt Feedback Amplifier•The Series-Series Feedback Amplifier•The Shunt-Shunt and Shunt-Series Feedback Amplifier•Determining the Loop Gain•The Stability Problem•Effect of Feedback on the Amplifier Poles•Stability Study Using Bode Plots•Frequency Compensation
![Page 25: Differential and Multistage Amplifierskttang/Course/Slides/EE2260/Week11.pdf · Amplifier •The Differential Amplifier with Active Load •Frequency Response of the Differential](https://reader031.vdocument.in/reader031/viewer/2022021711/5cb754e488c99379328bfb5a/html5/thumbnails/25.jpg)
The Ideal Situation
Af =
Rif =
ssAsZsZ iif 1
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The Ideal Situation (con’t)
Rof =
ssA
sZsZ o
of
1
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The Practical Situation
Problems:
1) Feedback network is not an idealvoltage-controlled voltage source
2) The source and load resistances A, Ri, and Ro will be affected!!
Given an amplifier, find the A circuit and thecircuit as the ideal structure
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Two-Port Network Parameters
Four variables: V1, I1, V2, I2Two can be excitation, and the other two as response
3) h parameters: I1, V2 excitation, V1, I2 response
4) g parameters: V1, I2 excitation, I1, V2 response
1) y parameters: V1, V2 excitation, I1, I2 response
2) z parameters: I1, I2 excitation, V1, V2 response
Equivalent-Circuit Representation
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h Parameters
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The Practical Situation (con’t)
|h21|feedback << |h21|forward
Lof
out
sifin
RR
R
RRR
11
1
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The Practical Situation (con’t)|h12|forward << |h12|feedback
The loading effect of the feedback network on the basic amplifier isrepresented by the components h11 and h22
02
112
1
I
VV
h
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Summary
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Example 8.1Find A, , Vo/Vs, Rin, and Rout
= 104, Rid = 100k, ro = 1k, RL = 2kR1 = 1k, R2 = 1M, Rs =10k
Op amp has f3dB = 1kHz, what is f3dBof the closed-loop gain?
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Example 8.1 (con’t)