Dilution CalculationsExample 5

Concentrated hydrochoric acid, HCl, is shipped in bottles of 36% HCl, in which the [HCl] = 11.65 M.

Concentrated hydrochoric acid, HCl, is shipped in bottles of 36% HCl, in which the [HCl] = 11.65 M.A chemistry teacher needs to prepare 2.00 L of 3.00 M HCl for a lab.

Concentrated hydrochoric acid, HCl, is shipped in bottles of 36% HCl, in which the [HCl] = 11.65 M.A chemistry teacher needs to prepare 2.00 L of 3.00 M HCl for a lab.What volume of 11.65 M HCl does she need to use?

To prepare 2.00 L of 3.00 M HClWhat volume of 11.65 M HCl is needed?

c1 =V1 =

c2 =V2 =

To prepare 2.00 L of 3.00 M HClWhat volume of 11.65 M HCl is needed?

c1 =V1 =

c2 = 3.00 MV2 =

To prepare 2.00 L of 3.00 M HClWhat volume of 11.65 M HCl is needed?

c1 =V1 =

c2 = 3.00 MV2 = 2.00 L

To prepare 2.00 L of 3.00 M HClWhat volume of 11.65 M HCl is needed?

c1 =V1 =

c2 = 3.00 MV2 = 2.00 L

To prepare 2.00 L of 3.00 M HClWhat volume of 11.65 M HCl is needed?

c1 = 11.65 MV1 =

c2 = 3.00 MV2 = 2.00 L

To prepare 2.00 L of 3.00 M HClWhat volume of 11.65 M HCl is needed?

c1 = 11.65 MV1 = ?

c2 = 3.00 MV2 = 2.00 L

To prepare 2.00 L of 3.00 M HClWhat volume of 11.65 M HCl is needed?

c1 = 11.65 MV1 = ?

c2 = 3.00 MV2 = 2.00 L

The dilution formula

To prepare 2.00 L of 3.00 M HClWhat volume of 11.65 M HCl is needed?

c1 = 11.65 MV1 = ?

c2 = 3.00 MV2 = 2.00 L

c1V1 = c2V2

The dilution formula

To prepare 2.00 L of 3.00 M HClWhat volume of 11.65 M HCl is needed?

c1 = 11.65 MV1 = ?

c2 = 3.00 MV2 = 2.00 L

c1V1 = c2V2

The dilution formula

To prepare 2.00 L of 3.00 M HClWhat volume of 11.65 M HCl is needed?

c1 = 11.65 MV1 = ?

c2 = 3.00 MV2 = 2.00 L

c1V1 = c2V2

The dilution formula

2 21

1

3.00 M 2.00 L

11.65 M1000 mL

0.515 L 515 m L

L1

c VV

c

To prepare 2.00 L of 3.00 M HClWhat volume of 11.65 M HCl is needed?

c1 = 11.65 MV1 = ?

c2 = 3.00 MV2 = 2.00 L

c1V1 = c2V2

The dilution formula

2 21

1

3.00 M 2.00 L

11.65 M1000 mL

0.515 L 515 m L

L1

c VV

c

To prepare 2.00 L of 3.00 M HClWhat volume of 11.65 M HCl is needed?

c1 = 11.65 MV1 = ?

c2 = 3.00 MV2 = 2.00 L

2 21

1

2.00 L

11.65 M1000 mL

0.515

3.00 M

L1

5 mLL

15

VV

c

c

To prepare 2.00 L of 3.00 M HClWhat volume of 11.65 M HCl is needed?

c1 = 11.65 MV1 = ?

c2 = 3.00 MV2 = 2.00 L

221

1

3.00 M

11.65 M1000 mL

0.515

2.00 L

515 mLL1 L

VcV

c

To prepare 2.00 L of 3.00 M HClWhat volume of 11.65 M HCl is needed?

c1 = 11.65 MV1 = ?

c2 = 3.00 MV2 = 2.00 L

21

1

2

11.65

3.00 M 2.00 L

1000 mL0.5

M

5115 LL1

5 mL

c VV

c

To prepare 2.00 L of 3.00 M HClWhat volume of 11.65 M HCl is needed?

c1 = 11.65 MV1 = ?

c2 = 3.00 MV2 = 2.00 L

2 21

1

3.00 M 2.00 L

11.65 1000 mL

0.515

M

515 mLL1 L

c VV

c

To prepare 2.00 L of 3.00 M HClWhat volume of 11.65 M HCl is needed?

c1 = 11.65 MV1 = ?

c2 = 3.00 MV2 = 2.00 L

2 21

1

3.00 M 2.00 L

11.65 1000 mL

0.515

M

515 mLL1 L

c VV

c

To prepare 2.00 L of 3.00 M HClWhat volume of 11.65 M HCl is needed?

c1 = 11.65 MV1 = ?

c2 = 3.00 MV2 = 2.00 L

2 21

1

M L

M1000 mL

0.515 L1

3.00 2.00

11

L

.65

515 mL

c VV

c

To prepare 2.00 L of 3.00 M HClWhat volume of 11.65 M HCl is needed?

c1 = 11.65 MV1 = ?

c2 = 3.00 MV2 = 2.00 L

2 21

1

3.00 M 2.00 L

11.65 M10

0.515 L 515 00

m1 L

L mL

c VV

c

To prepare 2.00 L of 3.00 M HClWhat volume of 11.65 M HCl is needed?

c1 = 11.65 MV1 = ?

c2 = 3.00 MV2 = 2.00 L

2 21

1

3.00 M 2.00 L

11.65 M10

0.515 L 515 00

m1 L

L mL

c VV

c

To prepare 2.00 L of 3.00 M HClWhat volume of 11.65 M HCl is needed?

c1 = 11.65 MV1 = ?

c2 = 3.00 MV2 = 2.00 L

2 21

1

3.00 M 2.00 L

11.65 1M

0.515 L000 mL

515 mL1 L

c VV

c

To prepare 2.00 L of 3.00 M HClWhat volume of 11.65 M HCl is needed?

c1 = 11.65 MV1 = ?

c2 = 3.00 MV2 = 2.00 L

2 21

1

3.00 M 2.00 L

11.65 1000 mL

0.515 L 515 mL1

M

L

c VV

c

To prepare 2.00 L of 3.00 M HClWhat volume of 11.65 M HCl is needed?

c1 = 11.65 MV1 = ?

c2 = 3.00 MV2 = 2.00 L

2 21

1

3.00 M 2.00 L

11.65 M1000 mL

0.515 L 515 m L

L1

c VV

c

To prepare 2.00 L of 3.00 M HClWhat volume of 11.65 M HCl is needed?

c1 = 11.65 MV1 = ?

c2 = 3.00 MV2 = 2.00 L

To prepare 2.00 L of 3.00 M HCl, 515 mL of concentrated11.65 M HCl is needed.

It is important to note here that water should never be added to concentrated acid. The large amount of heat generated could cause the acid to splash.

It is important to note here that water should never be added to concentrated acid. The large amount of heat generated could cause the acid to splash. Remember—Always add acid to water, not the other way around!And it must be done slowly!

Also, any work with concentrated acids must be done in a fume hood, and the person must wear a lab apron, chemical resistant gloves, and approved eye protection!