8/17/2019 DISCUSSION AND CONCLUSION part 1(4).pdf

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7.0 DISCUSSION AND CONCLUSION

PART 1

1. Derive equation 1

Sc = W (La – a) …………. Equation 1 L

The solution:W

R A R B

+

ε A = !

"R B (L) + Wa = !

R B = " Wa L

+ + ε #$ = ! % #& = ! #& = ! R A + R B – W = ! R A = W – R B = W – Wa L = WL – Wa L R A = W (L – a) L

8/17/2019 DISCUSSION AND CONCLUSION part 1(4).pdf

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! ' $ ' a

!

= Wa ( La – a ) L

$

+

ε #& = ! :

– RA = ! – W (L – a) = ! L

= W (L – a) ER* E

L

8/17/2019 DISCUSSION AND CONCLUSION part 1(4).pdf

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(ue to an in#rea'e( loa(

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,elation ith loa4 that i3 ose4 an4 4istance at oint loa4.

Sc = W (La – a) …………. Equation 1 L