1. Sec 4.9 – Circles & Volume Volume of Pyramids & Cones Name:
UsingCavalieri’sPrinciplewecanshowthatthevolumeofapyramidisexactly⅓thevolumeofaprismwiththesameBaseandheight.
Considerasquarebasedpyramidinscribedincube.
Next, translatethepeakofthepyramid.Cavalieri’sPrinciplewouldsuggestthatthevolumeoftheobliquepyramidisthesameas
theoriginalpyramid.
Next,wecancreate2moreobliquepyramidswiththesamevolumeoftheoriginalwiththeremaining
spaceinthecube.
Inthisdiagram,wecanseethe3obliquepyramidsofequalvolumepulledoutfromthecube.So,thisdemonstratesapyramidinscribedinacubehasexactly⅓thevolumethecube.
Thisideacanbeextendedtoanypyramidorcone.
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1. FindtheVolumeofthefollowingsolids(figuresmaynotbedrawntoscale).
Volume:
Volume:
Volume: Volume:
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2. FindtheVolumeofthefollowingsolids(figuresmaynotbedrawntoscale).
Volume:
Volume:
Volume: Volume:
Findthevolumeoftheregularoctahedron. Findthevolumeoftheirregularsolid.Thebasehasanareaof80cm2andaheightof9cm.
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3. FindtheVolumeofthefollowingsolids(figuresmaynotbedrawntoscale).
Volume:
Volume:
ConsidertriangleABCwithverticesatA(0,0),B(4,6),andC(0,6)plottedandacoordinategrid.Determinethevolumeofthesolidcreatedbyrotatingthetrianglearoundthey‐axis.
Volume:
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UsingCavalieri’sPrinciplewecanshowthatthevolumeofaspherecanbefoundby ∙
First,considerahemispherewitharadiusofR.CreateacylinderthathasabasewiththesameradiusRandaheightequaltotheradiusR.Then,removeaconefromthecylinderthathasthesamebaseandheight.
Next,consideracrosssectionthatisparalleltothebaseandcutsthroughbothsolidsusingthesameplane.
Cavalieri’sPrinciplesuggestsifthe2crosssectionshavethesameareathenthe2solidsmusthavethesamevolume.
Theareaofthecrosssectionofthesphereis:∙
UsingthePythagoreantheoremweknow: or
So,withsimplesubstitution:∙
Theareaofthecrosssectionofthesecondsolid is:∙ ∙
Usingsimilartrianglesweknowthath=bandthen,usingsimplesubstitution
∙ ∙
VolumeofHemisphere=VolumeofCylinder–VolumeofCone= ∙ ∙
WealsoknowthatR=b=h.So,VolumeofHemisphere= ∙ ∙ ∙ ∙ ∙
Tofindthevolumeofacompletesphere,wecanjustdoublethehemisphere:VolumeofSphere= ∙
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