Ch 7 Continued
Substrings
Returns substrings
Format:
Substr(stringvalue, m, n)
Where m is the starting value and n is the length of characters (count)
Assume orders have the format:”
Abc1234
cdf2345etc..
Get the first and last part of the order
Select substr (order_numb, 1,3),substr (order_numb,4,4)
From order;
INSTR function
Allows searching for a string of characters, gives the position of the string but does Not cut off anything
Format:
Instr(string, set, start,occurrence)
Start is the start of the search set in the string
Occurrence is the position of occurrence that you want to search
Search for first “/” in p_code
SQL> select p_code, instr(p_code,'/') from product;;
• P_CODE INSTR(P_CODE,'/')• -------- -----------------• 11QER/31 6• 13-Q2/P2 6• 14-Q1/L3 6• 1546-QQ2 0• 1558-QW1 0• 2232/QTY 5• 2232/QWE 5• 2238/QPD 5• 23109-HB 0• 23114-AA 0• 54778-2T 0
• P_CODE INSTR(P_CODE,'/')• -------- -----------------• 89-WRE-Q 0• PVC23DRT 0• SM-18277 0• SW-23116 0• WR3/TT3 4
• 16 rows selected.
JOINING TABLES
when information needed is in more than one table, we need to join tables;
WHERE clause in the select SQL statement creates a join. Note some queries can also be answered using sub query
Rules FOR joining
WHERE attribute1 condition attribute2
Ex: where employee.ssn=student.ssn
Value(s) from one table are matched value(s) from other tables all matching values are attached
allows joining of tables based on common attribute domains
without the WHERE clause it will produce a Cartesian product also
Give the names of salesperson and their customers in maryland
SQL>Select cust_name, Sales_name from Customer C, salesperson Swherec.sales_numb= s. sales_numb’AndUpper(c.cust_st) =‘MD’;
C & S are aliases for tables Customer and Salesperson respectively
Types of joins (see page 294)
• Outer join– Left– Right– Full
Format:– Select From table1 LEFT [outer] join table 2
ON Joint condition– Select from table1 RIGHT join table2 ON join-
condition
Give the customer order information of all customers also
include customers that do not have orders Select *
From customer left join order on customer.cust_numb=order.cust_numb;
Give the salesperson’s information of all that have customers also include salesperson’s that do not have orders
Select *From customer right join salesperson on
salesperson.sales_numb=.customer.salse_numb;
Correlated subqueries
• It executes once for each row in the outer query
• Like a nested loop
Normal subqueryFor X = 1 TO 2PRINT “X = “XEND
Normal sub queryFor X = 1 TO 2PRINT “X = “XENDCORRELATED SUB QUERY:FOR X = 1 TO 2
FOR Y = 1 TO 3PRINT “X= ‘, “Y= ‘YEND
END
Get the names of salespeople that have earned more commission than average commission of all salespeople
Select sales_name
From salesperson
Where commission >(select avg (commission) from salesperson);
Get the names of salespeople that have earned more commission than average commission of all salespeople from that state
Select sales_name
From salesperson sa
Where commission > (select avg (commission) from
Salesperson where ????? = ?????));
INDEX (p 181..B&F)
An index creates a separate file, that has two columns
• 1st col contains the value and• 2nd col contain primary key or record#
index are used to optimize query access– unique vs non-unique– take space
• automatically updated every time some changes are made to affected data.
Format:• CREATE [UNIQUE] INDEX index-name ON
table-name(col name)
Ex:
Create index sales_name_index on slaesperson (sales_name)
• DROP INDEX index-name• Drop index sales_name_index;
Security
two ways to control access internally:
• VIEWS
• GRANT
• VIEWS.. already discussed (session 4)
GRANT/REVOKE
Privileges:System User
User Privileges:• A user can grant privileges to anything that is in
their account or they ownFormat:• GRANT object privilege [cols,] ON object to user
[WITH GRANT OPTION];• Table name MUST be preceded by the owner's
user name
Student XYZ (ordb022)grants access to student YYZ (acct: ordb021)
• GRANT SELECT, UPDATE ON STUDENT TO ORDB021;
This will allow ORDB021 TO ACCESS STUDENT table of ORDB022. Privilege is granted by ORDB022 from his/her account.
• However, when ORDB021 attempts to access it from his/her account as:
• SELECT * FROM STUDENT; (assuming no STUDENT table in his/her account) will give an error message.
• Why?
Problem is table is not on user ordb021 account
Must qualify it like in the trial exercise.
Easier to create synonyms
Create synonym STU FOR ORDB022.STUDENT;
Revoke
• REVOKE object privileges ON object FROM user;
REVOKE select on STUDENT from ORDB021;
• Will take select privileges from ORDB021 related to table STUDENT of ORDB222
Procedural SQL
SQL does NOT support IF – THEN –ELSEorDO WHILE – END
Use persistent Stored module (PSM)• A block of code that has sql and extension • This can be shared by multiple users• Like a module
ORACLE implementation
Through PL/SQLCan be invoked by users
Format:Declare
<dec section>BEGIN
<execuable section>END; Declare: defines/initialize variablesExecutable commands: IF_THEN_ELSE, LOOPS
example:DECLARE
pi constant NUMBER (9,7) :=3.1415926;//declares a variable pi of constant value of size (9,7)radius INTEGER (5); //variable radius of integer typearea NUMBER (14,2);
BEGINradius :=3 //assigns an initial value to variable radiusarea = :=pi*power(radius,2); Insert into AREAS values (radius, area);//inserts value in table AREAS
END; /
Cursor can be used for multiple entries (get data from another table)BF(ch 21) & An Introduction to PL/SQL by Loney & koch)
DECLARE pi constant NUMBER (9,7) :=3.1415926;//declares a variable pi of area NUMBER (14,2);
Cursor rad_cursor isselect * from RADIUS_VAL;
Rad_val rad_cursor%ROWTYPE;
BEGINOpen rad_cursor;
Fetch rad_cursor into rad-valradius :=3
area = :=pi*power(radval.radius,2);
Insert into AREAS values (radval.radius, area);
Close rad_cursor;END; /
triggers
Like an alarm clock
It is automatically invoked by an event, i.e.
Add
Delete
Modify
Can be used to enforce rules that can not be enforced in design, generate derived columns
Format:(SEE PAGE 330-333)
Create or replace trigger trigger_name[before/after] [delete/insert/update of col_name] on
table_name[for each rwo][declare]
[var name data type etc..]BEGINPL/SQL INTERFACEEND;
Ch 9: DBD
SDLC
Plan
Analysis
Design
Implement
maintenance
DBLC (page 365)
• Initial studyDefine objectives/scope
• Database design..
Data Analysis & Requirements:
Develop conceptual model (ERD)..DBMS independent
Create logical (translate ERD into tables,views etc)..DBMS dependent
Physical design (storage structure, access method, optimization..)
Hardware dependent (page 383)
ImplementationCreate DBMSLoad dataSecurityBack ups and recoverystandards
• Test & evaluationrobust
• OperationIs it doing what it is supposed to do?
Maintenance
• Audits
• Back ups
• disaster planning
• Usage statistics
design
• Top down vs bottom up
• Centralized vs decentralized