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Chemistry Jeopardy Unit 6Solutions &
SolubilityI’m
ConcentratingColligative Properties
Equal What? Special K’s
10 10 10 10 10
20 20 20 20 20
30 30 30 30 30
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50 50 50 50 50
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The ingredient of a solution present in the greatest
amount.
A. IonsB. LiquidC. SoluteD. Solvent
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This factor has the largest effect
of the solubility of solid
compounds.
A. Pressure
B. Temperature
C. Rate of Stirring
D. Amount of solvent
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A solution that contains the maximum amount of solute
possible.
A. Unsaturated B. SaturatedC. Supersaturated D. Megasaturated
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To maximize the solubility of gases in solutions a student
should.
A. Increase the temperatureB. Decrease the temperatureC. Decrease the pressure D. Increase the amount of solvent
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What saying allows us to predict if a solvent will dissolve a solute?
A. Likes dissolve likesB. Polar dissolves nonpolarC. Nonpolar dissolves polarD. All solvents dissolve all solutes
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Molarity has units of
A. grams/moleB. moles/kilogramC. liters/moleD. moles/liter
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What is the concentration of a solution made by dissolving 1.5 mol of NaCl
to a volume of 500. mL
A. 1.5 M B. 0.0030 M C. 3.0 MD. 2.0 M
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The product of concentration times volume.
A. MolesB. MolarityC. KeqD. Dilution
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Proper solution preparation requires what piece of equipment.
A. BeakerB. Erlenmeyer FlaskC. Graduated CylinderD. Volumetric Flask
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What is the resulting concentration when 20. mL of a 2.0M solution
is diluted to 40. mL?
A. 1.0 MB. 0.50 MC. 2.0 MD. 4.0 M
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Colligative Properties depend on the number of
A. Chemists WorkingB. Particles in solutionC. Beakers usedD. Readings taken
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A liquid reaches its boiling point when
A. It feels like itB. When bubbles start formC. The vapor pressure of the
liquid equals the pressure of the atmosphere
D. Cannot be determined
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Adding a solute to a solvent
A. Raises the freezing pointB. Lowers the boiling pointC. Lowers the freezing pointD. Does not change the boiling point
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What is the advantage of using AlCl3 to melt ice on sidewalks as opposed to
NaCl
A. The freezing point change will be 2x largerB. The freezing point change will be 4x largerC. The freezing point change will be 10x largerD. There is no advantage
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When ΔTf = 3.4 ºC for an aqueous solution of NaCl the new freezing
point of the solution is
A. 3.4 ºCB. -3.4 ºCC. 103.4 ºCD. 96.6 ºC
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When a reaction reaches equilibrium the forward and reverse reactions
A. Occur at different ratesB. Occur at the same rateC. Stop D. Make the same amount of chemical
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The only stress that can change the equilibrium constant is
A.ConcentrationB.TemperatureC.PressureD.Final Exams
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A large equilibrium constant mean the reaction is
A.Product favoredB.Reactant favoredC.NeutralD.Happens very fast
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Ksp expressions are written for
A. Chemical equilibriumB. Force equilibriumC. Solubility equilibriumD. Balance Equilibrium
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When a common ion is added to an equilibrium the equilibrium shifts
A. Toward the added ionB. Away from the added ionC. Toward the heat in the reactionD. Toward the higher pressure
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What is the equilibrium expression for the following equation?3A(g) + 2B(g) A3B2(g)
A. Keq = [A3B2] / ([A]3[B]2)B. Keq = [A]3 [B]2 / [A3B2] C. Keq = [A] [B] / [A3B2]D. Keq = [A3] [B2] / [A3B2]
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How can the following reaction bemade to favor the product side
of the reaction?3A(g) + 2B(g) A3B2(g) + heat
A. Add more productB. Increase the pressureC. Increase the temperatureD. Add a catalyst
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What is the Ksp expression for the following reaction
BaSO4(s) Ba+2 + SO4-2
A. Ksp = [BaSO4] / ([Ba+2] [SO4-2])
B. Ksp = [Ba+2] [SO4-2] / [BaSO4]
C. Ksp = [BaSO4] / [Ba]2 [SO4] -2
D. Ksp = [Ba+2] [SO4-2]
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Which of the following will have no effect on the reaction?
A (g) + B (g) AB (g) + heat
A. Increasing the amount of AB. Decreasing the temperature C. Increasing the amount of A2B2
D. Increasing the pressure
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How could you lower the concentration of Ba+2 for the following reaction?
BaSO4(s) Ba+2 + SO4-2
A. Add solid Na2SO4
B. Increase the pressureC. Add solid Ba(NO3)2
D. The concentration cannot be changed