I will Measure You: It Matters not , how Tall are You
Prepared by: Rolando Jaca Amy Caballero Lea Buligao
Brief Description of Thales
The Greek philosopher, Thales was born around 624BC, the son of Examyes and Cleobuline. He came from a distinguished family. He was an engineer, scientist, mathematician, and philosopher, the first natural philosopher in the Milesian School..
His contribution to math
Thales was known for his innovative use of geometry. His understanding was theoretical as well as practical. For example, he said:
“Space is the greatest thing, as it contains all things”. Thales understood similar triangles and right triangles, and what is more, used that knowledge in practical ways.
How Thales found the height of the pyramid? The story is told that he measured the
height of the pyramids by their shadows at the moment when his own shadow was equal to his height. A right triangle with two equal legs is a 45-degree right triangle, all of which are similar. The length of the pyramid’s shadow measured from the center of the pyramid at that moment must have been equal to its height.
The modeled situation
It is about the height of the pyramid with the help of the pyramid shadow and a stick.
The pyramid
The pyramid base, a parallelogram, is designed using the center property with central symmetry.
The pyramid height is designed to have a perpendicular direction to the front side of the base. The stick is parallel to the pyramid height. Dashed segments are used to represent the hidden sides of the pyramid. An arc is used to represent the sun position.
The shadow
The sun is modelized as a point on the arc.
The pyramid shadow is constructed semi-arbitrary with the ray going from the sun position to the pyramid summit. An arbitrary point in this ray is chosen as the shadow of the pyramid summit. The shadow of the pyramid height is constructed from this point and the pyramid base center.
Definition of similar triangles
Triangles are similar if they have the same shape, but can be different sizes.
Two triangles are similar iff:
all the corresponding angles are equal, or
all the corresponding sides are proportional.
angle A = angle Dangle B = angle Eangle C = angle F
AB/DE = BC/EF = AC/DF
Shadow Method
Using shadows is a quick way to estimate the heights of trees, flagpoles, buildings, and other tall objects. To begin, pick an object whose height may be impractical to measure, and then measure the length of the shadow your object casts. Also measure the shadow cast at the same time of day by a yardstick (or some other object of known height) standing straight up on the ground.
Shadow MethodTIME CAPTURED:
Wednesday, February24, 2010
12:30 pm in front of CED Bldg. (MSU-IIT)
TIME CAPTURED: Wednesday,
February24, 201012:30 pm in front of CED Bldg. (MSU-IIT)
DIAGRAMDIAGRAM
hh
109 in.
64 in64 in
34 in.
Tree’s shadow
Jaca’s shadow
TIME CAPTURED: Wednesday,
February24, 201012:30 pm in front of CED Bldg. (MSU-IIT)
TIME CAPTURED: Wednesday,
February24, 201012:30 pm in front of CED Bldg. (MSU-IIT)
Solving for h Using triangle similarity by ratio and proportion
and let h be the height of the tree then we have:
64 in h
34 in 109 in
34 in(h) = 64 in (109in)
34 in(h) = 6976 in2
34 in(h) 6976 in2
34 in 34 in
Therefore the height of the tree is 205.18 in
h = 205.18 in. h = 205.18 in.
Mirror Method
Choose a tall object with a height that would be difficult to measure directly, such as a football goalpost, a basketball hoop, a flagpole.
Steps:Step 1 Mark crosshairs on your mirror. Use tape or a soluble pen.
Call the intersection
point X. Place the mirror on the ground several meters from your object.
Step 2 An observer should move to a point P in line with the object and the mirror in
order to see the reflection of an identifiable point F at the top of the object at
point X on the mirror. Make a sketch of your setup, like this one.
Step 3 Measure the distance PX and the distance from X to a point B at the base of
the object directly below F. Measure the distance from P to the observer’s eye
level, E.
Step 4 Think of FXas a light ray that bounces back to the observer’s eye along XE .
Why is B P? Name two similar triangles. Tell why they are similar.
Step 5 Set up a proportion using corresponding sides of similar triangles. Use it to
calculate FB, the approximate height of the tall object.
Step 6 Write a summary of what you and your group did in this investigation. Discuss
possible causes for error.
Solving for y
Using triangle similarity by ratio and proportion and let y be the height of the post then we have:
y 62.5 in.
89 in. 41 in
41in.(y) = 3.062 in2
41in.(y) 3.062 in2
41in. 41in.
Therefore the height of the post is 74.61 in.
y= 74.61 in.
Clinometers
The method of measurement requires a protractor (clinometer), a straw and a measuring tape. This method does not use the shadows but uses accurate visual senses of the measurer. The protractor preferably must be as big as possible for accurate angle observation and for further calculation.
Procedure
Step 1 Get a protractor with one straight edge (a 180 degree protractor).
Step 2 Tape a straw along the straight edge of the protractor.
Step 3.Tie a string through the small hole on the straight edge that is directly across from the 0 degree mark on the protractor. This may also be labelled as 90 degrees. If your protractor does not have a small hole here, or if the hole is not situated correctly (this is a common problem with some cheap protractors), tape or glue the string to the protractor at this mark. Make sure the string dangles a few inches below the protractor.
Step 4Attach a washer or fishing weight to the dangling end of the string.
Step 5 Sight the top of a tall object through the straw.
Step 6Note the number where the string crosses. Subtract this number from 90 to determine the angle of elevation between your eye and the top of the object you are sighting
Reminders
It is necessary to add our height to the calculated height of the object as our reference point (eye level) is above the ground. It is not necessary to add our height if, we measure the angle keeping our eye at ground level (on which the building stands).
ClinometersTime captured:
Wednesday, February24, 2010
4:12 pm in front of Asnie boarding house
(Tibanga I.C.)
Time captured: Wednesday,
February24, 20104:12 pm in front of
Asnie boarding house(Tibanga I.C.)
Aha!!!!!! The string crosses at 350 ,so I should subtract it from 900 according to the rule to get the angle of elevation between my eye and the top of the electric post. Then, I have:900-350 = 550 . Therefore the angle of elevation is 550 .
Aha!!!!!! The string crosses at 350 ,so I should subtract it from 900 according to the rule to get the angle of elevation between my eye and the top of the electric post. Then, I have:900-350 = 550 . Therefore the angle of elevation is 550 .
550550
zz
157 in.157 in.
Electricpost
roland
Time captured: Wednesday,
February24, 20104:12 pm in front of
Asnie boarding house(Tibanga I.C.)
Time captured: Wednesday,
February24, 20104:12 pm in front of
Asnie boarding house(Tibanga I.C.)
DIAGRAM
157 in.157 in.
Angle of elevation
64 in.
Solving for z
Using tangent function we have:
tan 550 = z /157 in.
z = tan 550 (157 in.
z = 1.43 (157 in.)
z = 224.22 in.
To find the height of the electric post:
As the reminders remind me. I should add my height which is 64 in. from the value of z which is 224.22 because my eye is sighting not on the level ground. So the height of the electric post is: Z + 64 in. = 224.22 in + 64 in. = 288.22 in.
Still on the ground but still can’t out of reach
Time captured: Wednesday, February24, 2010
4:12 pm in front of Gym Building (MSU-IIT)
CherieCherie
LeahLeahAmy
JessieJessie
AsnieAsnie
111 in.111 in.
xx
25 in.25 in.
202 in.202 in.
DIAGRAM
Solving for xUsing triangle similarity by ratio and proportion and let x be
the length across the rotunda then we have:
202 in. X+111 in.
25 in. 111 in.
(25 in.)(x+111 in.) = (111 in.)(202 in.)
25 in. (x )+ 2775 in2. = 22422 in2.
25 in. (x ) = 22422 in2. - 2775 in2.
25 in. (x ) = 19647 in2.
25 in. (x ) 19647 in2.
25 in. 25 in.
Therefore the length across the rotunda is 785.88 in.
x = 785.88 in.
x = 785.88 in.