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E. coli = E. lephant ?
F. JacobJ. MonodA. Pardee
D. HawthorneH. DouglasY. Oshima
1965 1966
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Analogy and homology as tools in genetic investigation
AnimalMandibular Arch (ventral)
Mandibular Arch (dorsal)
Hyoid Arch(dorsal)
Shark Meckel's cartilagePalatoquadrate cartilage
Hyomandibular cartiliage
Amphibian Articular (bone) Quadrate (bone) Stapes
Mammal Malleus Incus Stapes
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a cells produce a pheromone and receptor
cells produce pheromone and a receptor
diploid (a/) cells produce none of the above
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ShmooAl Capp (1948) – Li’l Abner
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Marsh and Rose diagram
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The phenotype of a haploid yeast cell with respect to mating is determined by
transcription factors
An cell produces two transcription factors, Mat1p and Mat2p, that ensure expression of specific genes, including the pheromone and receptor, and repress expression of a specific genes.
In an a cell, Mat1p and Mat2p are not expressed, and a different transcription factor is expressed, Mata1p. The genes are off, and the a genes (pheromone and receptor) are on.
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A.9
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Amazing but true
A wild-type haploid yeast cell contains THREE copies of mating type-determining genes:
• Copy #1: the 1 and 2 genes (silent).• Copy #2: the a1 and a2 genes (also silent).• Copy #3: An additional copy of genes in item 1,
or of the genes in item 2, but active.
Whichever genes are contained in copy #3 determines the mating type.
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A.11
A.12
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“An easily understood, workable falsehood is more useful than an incomprehensible truth.”
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cen MATHML HMRa
a1a2
cell
active silentsilent
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Loss of silencing at the silent mating type cassettes creates a “nonmater” – a haploid
that is a/ and that thinks it’s a diploid.
cen MATHML HMRa
a1a2
cell
active activeactive
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Screen for silencing mutants
A sample “screen”:
1. Take haploid cells.2. Mutate them.3. Screen for those that don’t mate.
Problem: mating is so much more than proper silencing of mating type loci!!
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The mating pheromone response
Jeremy Thorner
Thorner diagramAlso see Fig. A.13.
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How to screen for silencing mutants
cen MATHML HMRa
a1a2
a cell
a1a2
active silentsilent
Jasper Rine and Ira Herskowitz (1987) Genetics 116: 9-22.
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How to screen for silencing mutants
cen mata1-1HML
a1a2
active silentsilent
Jasper Rine and Ira Herskowitz (1987) Genetics 116: 9-22.
HML
Note: mata1-1 is a special allele of the a gene – it is recessive to
18MCB 140 11/27/06Jasper Rine and Ira Herskowitz (1987) Genetics 116: 9-22.
Rine schematic
mate to a cells
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The data
• Colonies screened: 675,000
• Colonies that mated to a: 295
• Major complementation groups: 4
silent information regulators:
SIR1, SIR2, SIR3, SIR4
Jasper Rine and Ira Herskowitz (1987) Genetics 116: 9-22.
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Question
What molecular mechanisms are responsible for silencing at the mating type loci?
heterochromatin formation in metazoaprostate cancer breast cancer ageing “normal” gene regulation in mammals
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Homework
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How can one explain the evolution of two distinct mating
types in budding yeast?Surely a pathway could have just
evolved for the fusion of two identical haploid cells?
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Two mating types have evolved under selective pressure to avoid inbreeding
M
D1
D2
D1
D2
One evolutionary advantage of mating is the production of novel genotypic combinations via the fusion of two
genomes with different life histories.
x
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Granddaughters of any given mother can switch mating type
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cen MATHML HMRa
a1a2
cell
cen MATHML HMRa
a1a2
a cell
a1a2
active silentsilent
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Epigenetic inheritance
• In an strain, the genetic information at MAT and at HML is identical.
• The one at MAT is expressed, but the one at HML is not – it is epigenetically silenced.
Epigenetic: mitotically stable (persists through cell division) change in gene expression state that is not associated with a change in DNA sequence.
Examples: X chromosome inactivation; imprinted genes; transgene silencing in gene therapy.
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> 1 metre< 10-5 metres
15,000x compaction
Compaction into chromatin brings the eukaryotic genome to life
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“Beads on a string”
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The Nucleosome Core Particle:8 histones, 146 bp of DNA
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Histones: Conserved and Charged
H.s. = Lycopersicon esculentum
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“Extremely conserved histone H4 N terminus is dispensable for growth but essential for repressing
the silent mating loci in yeast” (M. Grunstein)
Kayne et al. (1988) Cell 55: 27-39.
Fig. 3 kayne
35MCB 140 11/27/06Kayne et al. (1988) Cell 55: 27-39.
Fig. 6 and 7 of Kayne.
36MCB 140 11/27/06Kayne et al. (1988) Cell 55: 27-39.
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Acetylation of lysine in histone tail neutralizes its charge (1964)
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“Genetic evidence for an interaction between SIR3 and histone H4 in the repression of the silent
mating loci in Saccharomyces cerevisiae”
Johnson et al. (1990) PNAS 87: 6286-6290.
Reverse genetics: introduce point mutations in H4 tail!!
39MCB 140 11/27/06Johnson et al. (1990) PNAS 87: 6286-6290.
Table 2
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And 5 years later …
Sir3p and Sir4p bind H3 and H4 tails
Hecht et al. (1995) Cell 80: 583.
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Houston, we have a …
Every nucleosome in the cell has an H3 and H4 tail (two of each, actually).
Why do the SIRs bind only where they bind?
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The silencers
“Hawthorne deletion” (1963) and onwards:
two silencers flank the mating type loci:
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The key question
How do the SIRs spread from the silencer and over the mating type loci genes?
= how do the SIRs actually silence txn?
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Roy Frye (Pitt)
“Characterization of five human cDNAs with homology to the yeast SIR2 gene: Sir2-like proteins (sirtuins) metabolize NAD and may have protein ADP-ribosyltransferase activity” BBRC 260: 273 (1999).
1. Bacteria have proteins homologous to Sir2.
2. So do humans (>5).
3. The bacterial proteins are enzymes, and use NAD to ADP-ribosylate other proteins.
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J. Denu: Sir2p is a NAD-dependenthistone deacetylase (HDAC)
Tanner et al., PNAS 97: 14178 (2000)
Sir2p
47MCB 140 11/27/06Rusche L, Kirchmaier A, Rine J (2002) Mol. Biol. Cell 13: 2207.
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acetylation
Histone tail acetylation promotes chromatin unfolding (somehow)
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Next time: the genetics of heterochromatin
in metazoa