Download - Problem exercises on aerodynamics
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FLIGHT MECHANICS Exercise Problems
CHAPTER 4
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Problem 4.1
• Consider the incompressible flow of water through a divergent duct. The inlet velocity and area are 5 ft/s and 10 ft2, respectively. If the exit area is 4 times the inlet area, calculate the water flow velocity at the exit.
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Solution 4.1
sftA
AVV
VAVAm
/25.14
15
2
112
222111
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Problem 4.2
• 4.2 In the above problem calculate the pressure difference between the exit and the inlet. The density of water is 62.4 Ibm/ft3.
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Solution 4.2
222
12
3
22
21
12
/7.222
25.1594.1
/94.12.32
4.62
2
02
1
2
1
ftlbpp
ftslug
VVpp
VdVdpv
v
p
p
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Problem 4.3
• Consider an airplane flying with a velocity of 60 m/s at a standard altitude of 3 km. At a point on the wing, the airflow velocity is 70 m/s. Calculate the pressure at this point. Assume incompressible flow.
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Solution 4.3
H.W.
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Problem 4.4
• An instrument used to measure the airspeed on many early low-speed airplanes, principally during 1919 to 1930, was the venturi tube. This simple device is a convergent - divergent duct (The front section's cross-sectional area A decreases in the flow direction, and the back section's cross-sectional area increases in the flow direction. Somewhere in between the inlet and exit of the duct, there is a minimum area, called the throat.) Let A1 and A2 denote the inlet and throat areas, respectively. Let p1 and p2 be the pressures at the inlet and throat, respectively.
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The venturi tube is mounted at a specific location on the airplane (generally on the wing or near the front of the fuselage), where the inlet velocity V, is essentially the same as the freestream velocity that is, the velocity of the airplane through the air. With a knowledge of the area ratio A2/A1 (a fixed design feature) and a measurement of the pressure difference p1- p2 the airplane's velocity can be determined. For example, assume A2/A1 =1/4 and p1- p2 = 80 Ib/ft2. If the airplane is flying at standard sea level, what is its velocity?
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Solution 4.4
H.W.
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Problem 4.5
Consider the flow of air through a convergent-divergent duct, such as the venturi described in Prob. 4.4. The inlet, throat, and exit areas are 3, 1.5, and 2 m2 respectively. The inlet and exit pressures are 1.02 x 105 and 1.00 x 105 N/m2, respectively. Calculate the flow velocity at the throat. Assume incompressible flow with standard sea-level density.
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Solution 4.5
smV
A
AV
AA
ppV
A
AVV
Vp
Vp
/22.102
123
225.1
10)00.102.1(2
5.1
3
1
)(2
22
2
5
12
12
2
3
1
311
3
113
23
3
21
1
Note that only a pressure change of 0.02 atm produce this high speed
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Problem 4.6
An airplane is flying at a velocity of 130 mi/h at a standard altitude of 5000 ft. At a point on the wing, the pressure is 1750.0 Ib/ft2. Calculate the velocity at that point assuming incompressible flow.
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Solution 4.6
sftV
Vpp
V
VpVp
sftmphV
/8.216
7.1900020482.0
17509.176022
/7.19760
88130130
2
421
2122
222
211
1
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Problem 4.7
Imagine that you have designed a low-speed airplane with a maximum velocity at sea level of 90 m/s. For your airspeed instrument, you plan to use a venturi tube with a 1.3 : 1 area ratio. Inside the cockpit is an airspeed indicator—a dial that is connected to a pressure gauge sensing the venturi tube pressure difference p1-
p2 and properly calibrated in terms of velocity. What is the maximum pressure difference you would expect the gauge to experience?
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Solution 4.7
222
21
2
2
12
121
2
112
22
2
21
1
/342313.12
90225.1
12
22
mNpp
A
AVpp
A
AVV
Vp
Vp
Maximum when maximum velocity 90 m/s and sea level density; however better design for over speed during diving
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Problem 4.8
A supersonic nozzle is also a convergent-divergent duct, which is fed by a large reservoir at the inlet to the nozzle. In the reservoir of the nozzle, the pressure and temperature are 10 atm and 300 K, respectively. At the nozzle exit, the pressure is 1 atm. Calculate the temperature and density of the flow at the exit. Assume the flow is isentropic and, of course, compressible.
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Solution 4.8
H.W.
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Problem 4.9
Derive an expression for the exit velocity of a supersonic nozzle in terms of the pressure ratio between the reservoir and exit po/pe and the reservoir temperature To.
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Solution 4.9
1
0
e0
1
0
e
0
e
0
2
220
12
)(2
2
12
1
2
1
p
pTcV
p
p
T
T
TTcV
Vhh
VTcVTc
pe
epe
eeo
eepop
Note that the velocity increases as To goes up or pressure ratio goes down; used for rocket engine performance analysis
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Problem 4.10
Consider an airplane flying at a standard altitude of 5 km with a velocity of 270 m/s. At a point on the wing of the airplane, the velocity is 330 m/s. Calculate the pressure at this point.
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Solution 4.10
H.W.
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Problem 4.11
The mass flow of air through a supersonic nozzle is 1.5 Ibm/s. The exit velocity is 1500 ft/s, and the reservoir temperature and pressure are 1000°R and 7 atm, respectively. Calculate the area of the nozzle exit. For air, Cp = 6000 ft • lb/(slug)(°R).
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Solution 4.11
2
14.1
11
1
o
e0
0
00
22
0
20
0061.015000051.02.32
5.12.32
5.1
0051.01000
5.8120086.0
0086.010001716
21167
5.81260002
15001000
2
2
1
ftV
mA
VAm
T
T
RT
p
Rc
VTT
VTcTc
eee
eee
e
p
ee
eepp
Energy eq.
Continuity eq.
No shock wave, isentropic relationship
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Problem 4.12
A supersonic transport is flying at a velocity of 1500 mi/h at a standard altitude of 50,000 ft. The temperature at a point in the flow over the wing is 793.32°R. Calculate the flow velocity at that point.
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Solution 4.12
sftV
V
sftsfthmiV
VTTcV
VTcVTc
p
pp
/3.6
220032.799399.38960002
/2200/60
881500/1500
2
2
1
2
1
2
222
1
2121
22
222
211
Very low value, almost a stagnant point
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Problem 4.13
For the airplane in Prob. 4.12, the total cross-sectional area of the inlet to the jet engines is 20 ft2. Assume that the flow properties of the air entering the inlet are those of the freestream ahead of the airplane. Fuel is injected inside the engine at a rate of 0.05 Ib of fuel for every pound of air flowing through the engine (i.e., the fuel-air ratio by mass is 0.05). Calculate the mass flow (in slugs/per second) that comes out the exit of the engine.
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Solution 4.13
H.W.
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Problem 4.14
Calculate the Mach number at the exit of the nozzle in Prob. 4.11.
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Solution 4.14
07.11397
1500
/13975.81217164.1
5.812
/1500
e
e
a
VM
sftRTa
RT
sftV
e
ee
e
e
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Problem 4.15
A Boeing 747 is cruising at a velocity of 250 m/s at a standard altitude of 13 km. What is its Mach number?
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Solution 4.15
H.W.
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Problem 4.16
A high-speed missile is traveling at Mach 3 at standard sea level. What is its velocity in miles per hour?
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Solution 4.16
H.W.
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Problem 4.17
Calculate the flight Mach number for the supersonic transport in Prob. 4.12.
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Solution 4.17
27.294.967
2200
/94.96799.38917164.1
/2200
a
VM
sftRTa
sftV
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Problem 4.18
Consider a low-speed subsonic wind tunnel with a nozzle contraction ratio of 1 : 20. One side of a mercury manometer is connected to the settling chamber, and the other side to the test section. The pressure and temperature in the test section are 1 atm and 300 K, respectively. What is the height difference between the two columns of mercury when the test section velocity is 80 m/s?
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Solution 4.18
cmm
A
AVh
hhpp
A
AVpp
mkgRT
p
8.2028.0
20
11
2
80
10*33.1
173.11
2
10*33.1
12
/173.1300287
10*01.1
22
5
2
1
22
2
521
2
1
22
221
35
Manometer reading
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Problem 4.19
We wish to operate a low-speed subsonic wind tunnel so that the flow in the test section has a velocity of 200 mi/h at standard sea-level conditions. Consider two different types of wind tunnels: (a) a nozzle and a constant-area test section, where the flow at the exit of the test section simply dumps out to the surrounding atmosphere, that is, there is no diffuser, and (b) a conventional arrangement of nozzle, test section, and diffuser, where the flow at the exit of the diffuser dumps out to the surrounding atmosphere. For both wind tunnels (a) and (b) calculate the pressure differences across the entire wind tunnel required to operate them so as to have the given flow conditions in the test section.
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For tunnel (a) the cross-sectional area of the entrance is 20 ft2, and the cross-sectional area of the test section is 4 ft2. For tunnel (b) a diffuser is added to (a) with a diffuser area of 18 ft2. After completing your calculations, examine and compare your answers for tunnels (a) and (b). Which requires the smaller overall pressure difference? What does this say about the value of a diffuser on a subsonic wind tunnel?
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Solution 4.19 (a)
222
21
2
1
22
221
1
221
22
2
21
1
/15.9820
41
2
3.293002377.0
12
22
ftlbpp
A
AVpp
A
AVV
Vp
Vp
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Solution 4.19 (b)
2222
21
2
1
2
2
3
22
231
3
223
1
221
23
3
21
1
/959.020
4
18
4
2
3.293002377.0
2
,
22
ftlbpp
A
A
A
AVpp
A
AVV
A
AVV
Vp
Vp
Economical to use diffuser (running compressor or vacuum pump)
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Problem 4.20
A Pitot tube is mounted in the test section of a low-speed subsonic wind tunnel. The flow in the test section has a velocity, static pressure, and temperature of 150 mi/h, 1 atm, and 70°F, respectively. Calculate the pressure measured by the Pitot tube.
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Solution 4.20
220
2
0
2
0
3
/21722202
00233.02116
60
88*150
2
00233.02116
2
/00233.0460701716
2116
ftlbp
p
Vpp
ftslugRT
p
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Problem 4.21
The altimeter on a low-speed Piper Aztec reads 8000 ft. A Pitot tube mounted on the wing tip measures a pressure of 1650 Ib/ft2. If the outside air temperature is 500°R, what is the true velocity of the airplane? What is the equivalent airspeed?
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Solution 4.21
H.W.
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Problem 4.22
The altimeter on a low-speed airplane reads 2 km. The airspeed indicator reads 50 m/s. If the outside air temperature is 280 K, what is the true velocity of the airplane?
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smV
V
V
mkgRT
p
true
eq
true
/56989.0
225.150
/989.0280287
10*95.7
0
34
Solution 4.22
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Problem 4.23
A Pitot tube is mounted in the test section of a high-speed subsonic wind tunnel. The pressure and temperature of the airflow are 1 atm and 270 K, respectively. If the flow velocity is 250 m/s, what is the pressure measured by the Pitot tube?
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Solution 4.23
550
14.1
4.12
120
10*48.110*01.1*47.147.1
47.12
76.0)14.1(1
2
)1(1
76.0329
250
/329270*287*4.1
pp
M
p
p
a
VM
smRTa
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Problem 4.24
A high-speed subsonic Boeing 777 airliner is flying at a pressure altitude of 12 km. A Pitot tube on the vertical tail measures a pressure of 2.96 x 104 N/m2. At what Mach number is the airplane flying?
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Solution 4.24
801.0
N/m 10*94.1p km, 12 altitudeat note;
110*94.1
10*96.2
14.1
2
11
2
10*94.1
1
24
4.1
14.1
4
4
1
1
021
4
M
p
pM
p
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Problem 4.25
A high-speed subsonic airplane is flying at Mach 0.65. A Pitot tube on the wing tip measures a pressure of 2339 Ib/ft2. What is the altitude reading on the altimeter?
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Solution 4.25
1761328.1
2339
328.1
328.12
65.0)14.1(1
2
)1(1
0
14.1
4.12
120
pp
M
p
p
Appendix B, pressure altitude reads 5000 ft
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Problem 4.26
A high-performance F-16 fighter is flying at Mach 0.96 at sea level. What is the air temperature at the stagnation point at the leading edge of the wing?
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Solution 4.26
H.W.
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Problem 4.27
An airplane is flying at a pressure altitude of 10 km with a velocity of 596 m/s. The outside air temperature is 220 K. What is the pressure measured by a Pitot tube mounted on the nose of the airplane?
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Solution 4.27
25402
41
214.1
4.1
2
22
21
1
21
21
2
1
02
1
11
1
/10*49.110*65.2*64.5
10*65.2
64.514.1
2*4.1*24.11
)14.1(22*4.1*4
2)14.1(
1
21
)1(24
)1(
0.2297
596
/297220*287*4.1
mNp
pas
M
M
M
p
p
a
VM
smRTa
Use Rayleigh Pitot tube formula
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Problem 4.28
The dynamic pressure is defined as q = 0.5V2. For high-speed flows, where Mach number is used frequently, it is convenient to express q in terms of pressure p and Mach number M rather than and V. Derive an equation for q = q(p,M).
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Solution 4.28
22
22
12
222
222
22
1
2
1
Mp
a
VpV
p
pq
pc
d
cd
d
dpa
Vp
pV
p
pVq
so
as
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Problem 4.29
After completing its mission in orbit around the earth, the Space Shuttle enters the earth's atmosphere at very high Mach number and, under the influence of aerodynamic drag, slows as it penetrates more deeply into the atmosphere. (These matters are discussed in Chap. 8.) During its atmospheric entry, assume that the shuttle is flying at Mach number M corresponding to the altitudes h:
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Calculate the corresponding values of the freestream dynamic pressure at each one of these flight path points. Suggestion: Use the result from Prob. 4.28. Examine and comment on the variation of q∞ as the shuttle enters the atmosphere.
h, km
60 50 40 30 20
M 17 9.5 5.5 3 1
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Solution 4.29
2
2 M
pq
h, km 60 50 40 30 20
p∞25.6 87.9 299.8 1.19*103 5.53*103
M 17 9.5 5.5 3 1
q∞5.2*103 5.6*103 6.3*103 7.5*103 3.9*103
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Problem 4.30
Consider a Mach 2 airstream at standard sea-level conditions. Calculate the total pressure of this flow. Compare this result with (a) the stagnation pressure that would exist at the nose of a blunt body in the flow and (b) the erroneous result given by Bernoulli's equation, which of course does not apply here.
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Solution 4.30
165602116824.7824.7
824.72
2)14.1(1
2
)1(1
0
14.1
4.1212
0
pp
M
p
p
Total pressure when the flow is isentropically stopped (true for supersonic and subsonic)
2402
214.1
4.1
2
22
21
1
21
21
2
1
02
/10*193.1116.2*64.5
64.514.1
2*4.1*24.11
)14.1(22*4.1*4
2)14.1(
1
21
)1(24
)1(
ftlbp
M
M
M
p
p
But there must be a shockwave at the nose (at the stagnation point)
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2420
22
0
/10*804.02*116.2*2
4.1116.2
22
ftlbp
Mpp
Vpp
If Bernoulli’s equation is used accidentally
51% error
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Problem 4.31
Consider the flow of air through a supersonic nozzle. The reservoir pressure and temperature are 5 atm and 500 K, respectively. If the Mach number at the nozzle exit is 3, calculate the exit pressure, temperature, and density.
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Solution 4.31
3
4
0
00
12
0
414.1
4.12
512
0
/267.06.178287
10*37.1
6.178357.0*5002
)1(1
10*37.12
3)14.1(110*01.1*5
2
)1(1
mkgRT
p
KM
TT
Mpp
ee
ee
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Problem 4.32
• Consider a supersonic nozzle across which the pressure ratio is pe/po = 0.2. Calculate the ratio of exit area to throat area.
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Solution 4.32
35.171.12
14.11
14.1
2
71.1
1
2
11
1
21
71.1
92.212.051)1(
2
2
)1(1
14.1
14.1
22
1
1
2
2
286.0
1
0
2
12
0
e
et
e
e
ee
ee
MMA
A
M
p
pM
M
p
p
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Problem 4.33
• Consider the expansion of air through a convergent-divergent supersonic nozzle. The Mach number varies from essentially zero in the reservoir to Mach 2.0 at the exit. Plot on graph paper the variation of the ratio of dynamic pressure to total pressure as a function of Mach number; that is, plot q/ po versus M from M = 0 to M = 2.0.
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Solution 4.33
5.322
12
22
22
22
2.017.0
2
11
22
222
1
MMp
q
MM
p
pM
p
q
Mp
a
VpVq
The graph shows that the local dynamic pressure has a peak value at M=1.4
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Problem 4.34
The wing of the Fairchild Republic A-10A twin-jet close-support airplane is approximately rectangular with a wingspan (the length perpendicular to the flow direction) of 17.5 m and a chord (the length parallel to the flow direction) of 3 m. The airplane is flying at standard sea level with a velocity of 200 m/s. If the flow is considered to be completely laminar, calculate the boundary layer thickness at the trailing edge and the total skin friction drag. Assume the wing is approximated by a flat plate. Assume incompressible flow.
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Solution 4.34
H.W.
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Problem 4.35
In Prob. 4.34, assume the flow is completely turbulent. Calculate the boundary layer thickness at the trailing edge and the total skin friction drag. Compare these turbulent results with the above laminar results.
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Solution 4.35
NND
bottomand top
NSCqD
C
cmmL
f
ff
L
f
lar
turb
L
56602830*2
28300022.0*5.17*3*10*45.2
0022.010*10.4
0074.0
Re
0074.0
75.1324.0
3.3
3.3033.010*10.4
3*37.0
Re
37.0
4
2.072.0
2.072.0
10.5 times larger than laminar flow assumption
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Problem 4.36
• If the critical Reynolds number for transition is 106, calculate the skin friction drag for the wing in Prob. 4.34.
Laminar Flow A
Turbulent Flow B
Xcr
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Solution 4.36
ND
mmS
mNVq
SqSqSCqD
mV
x
xV
turbf
cr
fturbf
crcr
crcr
146
5.17*10*3.7
/10*45.2200*225.12
1
2
1
10
074.0
Re
074.0
10*3.7200*225.1
10*7894.1*10Re
Re
2
2422
2.062.0
256
Drag of one side
Calculate drag force if the laminar flow portion A were turbulent flow
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NNND
N
SqSCqD
NDDD
ND
f
cr
fAf
AftotalfBf
turbulenttotalf
turb
5452268442
425.17*10*3.710*45.210
135
Re
1328
26841462830
2830
242.06
5.0
laminar
On the wing, it is mostly turbulent flow
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Problem 4.37
Let us reflect back to the fundamental equations of fluid motion discussed in the early sections of this chapter. Sometimes these equations were expressed in terms of differential equations, but for the most pan we obtained algebraic relations by integrating the differential equations. However, it is useful to think of the differential forms as relations that govern the change in flowfield variables in an infinitesimally small region around a point in the flow.
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(a) Consider a point in an inviscid flow, where the local density is 1.1 kg/m3. As a fluid element sweeps through this point, it is experiencing a spatial change in velocity of two percent per millimeter. Calculate the corresponding spatial change in pressure per millimeter at this point if the velocity at the point is 100 m/sec. (b) Repeat the calculation for the case when the velocity at the point is 1000 m/sec. What can you conclude by comparing your results for the low-speed flow in part (a) with the results for the high-speed flow part (b).
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Solution 4.37
mmmNds
dp
mmmNds
dp
mmdsVdV
dsVdV
Vds
dVV
ds
dp
VdVdp
./2200002.010001.1
./22002.01001.1
/02.0
22
22
2
It requires a much larger pressure gradient in a high-speed flow
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Problem 4.38
The type of calculation in Problem 4.3 is a classic one for low-speed, incompressible flow, i.e., given the freestream pressure and velocity, and the velocity at some other point in the flow, calculate the pressure at that point. In a high-speed compressible flow, Mach number is more fundamental than velocity. Consider an airplane flying at Mach 0.7 at a standard altitude of 3 km. At a point on the wing, the airflow Mach number is 1.1. Calculate the pressure at this point. Assume an isentropic flow.
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Solution 4.38
44
0
0
14.1
4.1212
0
14.1
4.1212
0
10*555.410*0121.7*65.0135.2
387.1
135.22
1.1)14.1(1
2
)1(1
387.12
7.0)14.1(1
2
)1(1
pp
p
p
p
p
p
M
p
p
M
p
p
Pressure at 3 km altitude
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Problem 4.39
• Consider an airplane flying at a standard altitude of 25,000 ft at a velocity of 800 ft/sec. To experience the same dynamic pressure at sea level, how fast must the airplane be flying?
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Solution 4.39
sftV
V
V
e
e
/8.53510*3769.2
10*0663.1800
3
3
0
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Problem 4.40
In Section 4.9, we defined hypersonic flow as that flow where the Mach number is five or greater. Wind tunnels with a test section Mach number of five or greater are called hypersonic wind tunnels. From Eq. (4.88), the exit-to-throat area ratio for supersonic exit Mach numbers increases as the exit Mach number increases. For hypersonic Mach numbers, the exit-to-throat ratio becomes extremely large, so hypersonic wind tunnels are designed with long, high-expansion ratio nozzles.
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In this and the following problems, let us examine some special characteristics of hypersonic wind tunnels. Assume we wish to design a Mach 10 hypersonic wind tunnel using air as the test medium. We want the static pressure and temperature in the test stream to be that for a standard altitude of 55 km. Calculate: (a) the exit-to-throat area ratio, (b) the required reservoir pressure (in atm), and (c) the required reservoir temperature. Examine these results. What do they tell you about the special (and sometimes severe) operating requirements for a hypersonic wind tunnel.
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Solution 4.40
KM
TT
atmp
M
p
p
MMA
A
eeo
o
e
e
o
e
et
e
57912
10)1(178.275
2
)1(1
\3.2010*053.2373.4810*224.4
10*224.42
10)14.1(1
2
)1(1
9.535102
14.11
14.1
2
10
1
2
11
1
21
22
64
4
5.3212
14.1
14.1
22
1
1
2
2
The surface of the sun is about 6000k; sacrifice accuracy because of temperature
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Problem 4.41
• Calculate the exit velocity of the hypersonic tunnel in Problem 4.40.
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Solution 4.41
smaMV
smRTa
eee
ee
/33299.33210
/9.33278.2752874.1
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Problem 4.42
Let us double the exit Mach number of the tunnel in Problem 4.40 simply by adding a longer nozzle section with the requisite expansion ratio. Keep the reservoir properties the same as those in Problem 4.40. Then we have a Mach 20 wind tunnel, with test section pressure and temperature considerably lower than in Problem 4.40, i.e., the test section flow no longer corresponds to conditions at a standard altitude of 55 km. Be that as it may, we have at least doubled the Mach number of the tunnel.
![Page 93: Problem exercises on aerodynamics](https://reader037.vdocument.in/reader037/viewer/2022102418/55cf9d96550346d033ae48f0/html5/thumbnails/93.jpg)
• Calculate: (a) the exit-to-throat area ratio of the Mach 20 nozzle, (b) the exit velocity. Compare these values with those for the Mach 10 tunnel in Problems 4.40 and 4.41. What can you say about the differences? In particular, note the exit velocities for the Mach 10 and Mach 20 tunnels. You will see that they are not much different. What is then giving the big increase in exit Mach number?
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Solution 4.42
smRTMaMV
KM
TT
MMA
A
eeeee
ee
e
et
e
/33905.712874.120
5.712
20)1(15791
2
)1(1
15377202
14.11
14.1
2
20
1
2
11
1
21
1212
0
14.1
14.1
22
1
1
2
2
Not much increase in velocity
28.7 times increase of exit area