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Page 1: Section 5-4 Applying Trig Functions Objective: Students will be able to use trigonometry to find the measures of the sides of right triangles

Section 5-4

Applying Trig Functions

Objective: Students will be able to use trigonometry to find the measures of the sides of right triangles.

Page 2: Section 5-4 Applying Trig Functions Objective: Students will be able to use trigonometry to find the measures of the sides of right triangles

Example 1:

If B = 42Β° and a = 12, find c, b, and A.

You know the measure of the side adjacent the angle.

The cosine function relates the side adjacent to the angle and the hypotenuse.

cosπœƒ=π‘ π‘–π‘‘π‘’π‘Žπ‘‘π‘—π‘Žπ‘π‘’π‘›π‘‘hπ‘¦π‘π‘œπ‘‘π‘’π‘›π‘’π‘ π‘’

cos 42 Β°=12𝑐𝑐 cos 42Β°=12𝑐=

12cos 42 Β°

C = 16.1476

C

tanπœƒ=π‘ π‘–π‘‘π‘’π‘œπ‘π‘π‘œπ‘ π‘–π‘‘π‘’π‘ π‘–π‘‘π‘’π‘Žπ‘‘π‘—π‘Žπ‘π‘’π‘›π‘‘

tan 42 Β°= 𝑏12

12 tan 42Β°=𝑏10.8048=π‘π‘β‰ˆ10.8

A + B + C = 180

A + 42 + 90 = 180

A = 48

Page 3: Section 5-4 Applying Trig Functions Objective: Students will be able to use trigonometry to find the measures of the sides of right triangles

Example 2:RECREATION A child holding on to the string of a kite gets tired and decides to put the

string on the ground and secure it with a brick. The length of the string from the brick to the kite is 240 feet.

A) If the angle formed by the string and the ground is 50.275Β°, how high is

the kite?

We know the angle and the hypotenuse. We want to findthe height of the kite (h).

sin πœƒ=π‘ π‘–π‘‘π‘’π‘œπ‘π‘π‘œπ‘ π‘–π‘‘π‘’hπ‘¦π‘π‘œπ‘‘π‘’π‘›π‘’π‘ π‘’

sin 50.275= h240

240sin 50.275=h

h = 184.589The height of the kite is about 184.6 feet.

Page 4: Section 5-4 Applying Trig Functions Objective: Students will be able to use trigonometry to find the measures of the sides of right triangles

B) What is the horizontal distance between the kite and the brick?

Her we want to know the side adjacent the angle. So we will use the cosine function.

cosπœƒ=π‘ π‘–π‘‘π‘’π‘Žπ‘‘π‘—π‘Žπ‘π‘’π‘›π‘‘hπ‘¦π‘π‘œπ‘‘π‘’π‘›π‘’π‘ π‘’

cos 50.275= 𝑑240

240 cos 50.275 = d

D = 153.3848

The horizontal distance between the brick and the kite is about 153.4 feet.


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