Transcript
Page 1: Solving Quadratic Inequalities October 9, 2015 SWBAT: Solve Quadratic Inequalities

Solving Quadratic

Inequalities October 9,

2015

SWBAT: Solve Quadratic Inequalities

Page 2: Solving Quadratic Inequalities October 9, 2015 SWBAT: Solve Quadratic Inequalities

SWBAT: Solve Quadratic Inequalities

8x - 4 20 or 8x - 4 -20 +4 +4

8x 24 +4 +4

8x -16 8 8 8 8

x -2 or x 3

x 2 or x 3

𝒙𝒙

Eliminate 3&4, bc

those are for less than’s!

Page 3: Solving Quadratic Inequalities October 9, 2015 SWBAT: Solve Quadratic Inequalities

SWBAT: Solve Quadratic Inequalities

Less ThAND

greatOR

Page 4: Solving Quadratic Inequalities October 9, 2015 SWBAT: Solve Quadratic Inequalities

SWBAT: Solve Quadratic Inequalities

Page 5: Solving Quadratic Inequalities October 9, 2015 SWBAT: Solve Quadratic Inequalities

SWBAT: Solve Quadratic Inequalities

π’šπ’†π’” !

-15

-2-53

(π’™βˆ’πŸ“ )=𝟎

𝒙=βˆ’πŸ‘ 𝒙=πŸ“

Less thAND

Ans:βˆ’πŸ‘

AND

Page 6: Solving Quadratic Inequalities October 9, 2015 SWBAT: Solve Quadratic Inequalities

SWBAT: Solve Quadratic Inequalities

π’“πŸ

8 6

24

(𝒙+𝟐 )=𝟎

𝒙=βˆ’πŸ’ 𝒙=βˆ’πŸ

βˆ’πŸ’

Answer:

Page 7: Solving Quadratic Inequalities October 9, 2015 SWBAT: Solve Quadratic Inequalities

SWBAT: Solve Quadratic Inequalities

𝑡𝑢 ! greatOR

-24

-2-64

(π’™βˆ’πŸ” )=𝟎

𝒙=βˆ’πŸ’ 𝒙=πŸ”OR

βˆ’πŸ’

𝒙<βˆ’πŸ’π’π’“ 𝒙>πŸ”

Page 8: Solving Quadratic Inequalities October 9, 2015 SWBAT: Solve Quadratic Inequalities

SWBAT: Solve Quadratic Inequalities

π’“πŸ (π’™βˆ’πŸ“ ) (𝒙+𝟐 )=𝟎

(π’™βˆ’πŸ“ )=𝟎 𝒙=βˆ’πŸ

(𝒙+𝟐 )=𝟎-10 -3

2-5

βˆ’πŸ

Answer:

Page 9: Solving Quadratic Inequalities October 9, 2015 SWBAT: Solve Quadratic Inequalities

SWBAT: Solve Quadratic Inequalities

𝑡𝑢 ! greatOR

6 7

61 (𝟐 𝒙+𝟏)(𝟐 𝒙+πŸ”)(𝟐 𝒙+𝟏)(𝒙+πŸ‘)

reduce binomials

(𝒙+πŸ‘ )=𝟎

𝒙=βˆ’πŸπŸ 𝒙=βˆ’πŸ‘

OR

βˆ’πŸ‘

𝒙<βˆ’πŸ‘π’π’“ 𝒙>βˆ’πŸπŸ

Page 10: Solving Quadratic Inequalities October 9, 2015 SWBAT: Solve Quadratic Inequalities

SWBAT: Solve Quadratic Inequalities

π’“πŸ β€œRainbow method”

3 4

1 3

(𝒙+𝟏 )=πŸŽπ’™=βˆ’πŸ

(πŸ‘ 𝒙+𝟏 )=𝟎

- βˆ’πŸ

Answer:

Γ·πŸ‘

Page 11: Solving Quadratic Inequalities October 9, 2015 SWBAT: Solve Quadratic Inequalities

SWBAT: Solve Quadratic Inequalities

-5 4

5-1(π’™βˆ’πŸ )=𝟎

𝒙=βˆ’πŸ“(𝒙+πŸ“ )=𝟎

-3 -2

1-3(π’™βˆ’πŸ‘ )=𝟎 𝒙=βˆ’πŸ

(𝒙+𝟏 )=𝟎

Page 12: Solving Quadratic Inequalities October 9, 2015 SWBAT: Solve Quadratic Inequalities

SWBAT: Solve Quadratic Inequalities


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