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The Hypothesis ProcessEXPLAINING THE HYPOTHESIS TEST PROCESS
PRESENTED BY TEAM A: ROGER GOMEZ, CHRISTIAN GLORIA, AND DUSTIN BUJANDA
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The Problem
The claim by a weight loss company is that, on average, the client will lose 10
pounds over the first two weeks. 50 people who joined the program were
sampled. Their weight loss is 9 pounds with a standard deviation of 2.8
pounds. Can we conclude, at the .05 level (95% confident), that a person will
lose less than 10 pounds.
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List Important Data = Mean from Claim, Prediction, Null Hypothesis = Sample Mean (Actual findings from study, research, analysis. = Level of Significance (.05, .01, .10); /2 S = Standard Deviation (Find the Variance, take the
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Draw “Comparison Distribution”
100
0.05 95%
Cutoff Z-score = -1.65 Z-Table
.05/1= .05
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Calculate or Pick a Critical Value1. Level of Significance Chosen by Researcher or Client.
2. Most Common Are: .05 (95% Confident), .01, .10
3. The Formula for Critical Value is: Zα/2
4. Will appear in problem as …a. Can we conclude, at the .05 level, that…
b. At the 5% level of significance is the mean …
c. At the .10 level of significance, has the selling…
.05/2= .025
95%
Z-Table
Used for finding Confidence Interval: Zα/2 X
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Calculate Null & Alternate Hypothesis
Always begin by solving the Alternate Hypothesis first simply by asking “What is the Alternate Hypothesis asking?” In our example case, “Is the mean
So,
Alternate Hypothesis: The true or actual mean of the population under analysis.
H1: 10
Null Hypothesis: the hypothesized mean of the population under analysis.
Ho:
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Decision Rule & Calculate Sample Z Score
Reject Ho if Z < -1 .645
Calculate Z:
Yes, -2.53 is less than -1.65 T-Score Exa
mple
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Write Report Conclusion: We reject the Null Hypothesis (Ho) and conclude the mean weight loss is less than 10 lbs.
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Questions
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References
Statistics for Psychology, Fifth Edition, by Arthur Aron, Elaine N. Aron, and Elliot J. Coups. Published by Prentice Hall. Copyright © 2009 by Pearson Education, Inc.
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Z-Table
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Z-Table for Problem
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Confidence Interval
.781.9695% 9.788.22
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T-Score
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5