Disscussion

1. UV rays found in sunlight . These UV rays work to break the covalent bonds between atoms of bromine. This fragmentation is also known as "homolytic cleavage". As a result of this created a homolytic cleavage of the unstable species is very reactive and we know as free radicals.

2. Solubility

Alkane : C6H14 + H2O C6H10 + H2O

Alkene : C6H10 + H2O C6H10+ H2O

Combustion

Alkane : 2C6H14 + 19O2 12CO2 + 14H2O

Alkene : 2C6H10+ 17O2 12CO2 + 10H2O

Bromine water

Alkane :Hexane C6H14 + bromine Br2 1,1-dibromohexane + hygrogen gas H2.

# cyclohexane, only the Br2 will react, but even it will require the addition ultraviolet light. 

Alkene : cyclohexene C6H10 + bromine Br2 1,2-dibromocyclohexane

Iodine

Alkane : C6H14 +I2 C6H12 + I2 

Alkene : cyclohexene C6H10 + Iodine I2 1,2-diiodocyclohexane

Baeyer test

Alkane : C6H14+ KMnO4  C6H12 + KMnO4

Alkene : cyclohexene C6H10 + KMnO4  1,2-cyclohexadiol 

3. Cyclohexene, C6H10 is the most reactive hydrocarbon with bromine water and the easiest hydrocarbon oxidized by potassium permanganate solution in this experiment.