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  • 8/11/2019 DPPS___3__Atomic_Structure-1__03-6-14

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    CAREER POINT

    PRACTICE PROBLEM SHEET

    PHYSICS

    Topic Atomic Structure-3

    Question based on Spectrum and spectrum lines

    Q.1 If the series limit wavelength of the Lyman series for hydrogen atom is 912 , then the series limitwavelength for the Balmer series for the hydrogen atom is -

    (1) 912 (2) 912 2 (3) 912 ()2

    912

    Q.2 In hydrogen s!e"tr#m, the shortest wavelength in Balmer series is $ %he shortest wavelength in Bra"&ett

    series will 'e -

    (1) 2 (2) (3) 9 () 1

    Q.3 If the wave n#m'er of a s!e"tral line of Bra"&ett series of hydrogen is))

    9times the *yd'erg "onstant$

    +hat is the state from whi"h the transition has ta&en !la"e

    (1) n (2) n . (3) n () n /

    Q.4 0or the first mem'er of Balmer series of -s!e"tr#m, the wavelength is $ +hat is the wavelength of these"ond mem'er

    (1) 3)

    .

    (2) 1(

    3

    (3) 9

    () 2/

    2

    Q.5 If 1 and 2 are the wavelengths of the first mem'ers of the Lyman and as"hen series res!e"tively, then 12is 4(1) 13 (2) 13 (3) /. () /15

    Q.6 6le"trons in a "ertain energy level n n 1, "an emit 3 s!e"tral lines$ +hen they are in another energy level,n n2$ %hey "an emit s!e"tral lines$ %he s!eed of the ele"trons in the two or'its are in the ratio4(1) 3 (2) 3 (3) 2 1 () 1 2

    Q.7 0or an atom of ion having single ele"tron, the following wavelengths are o'served$ +hat is the val#e ofmissing wavelength, x

    (1) 2 mm (2) mm (3) mm () 12 mm

    Q.8 %he a""eleration of ele"tron in the first or'it of hydrogen atom is4

    (1)3

    2

    h

    m(2)

    mr

    h

    2

    2

    (3)

    322

    2

    rm

    h

    ()

    32

    22

    r

    hm

    CAREER POINT, CP Tower, IPIA, Road No.1, Kota (Raj.), Ph: 0744-3040000 1

    CP Live Enthuse Class XII -2015

    PRE

    "PPS #$ - 0% 7is"#ssion on 3-6-214

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    Q.! 8 !arti"le of mass m moves aro#nd in a "ir"#lar or'it in a "entro symmetri" !otential field ( )2

    2Kr

    ru = $

    sing Bohr:s ;#anti

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    mmR

    11912

    19/5

    ===

    912

    2. ,2

    =

    22

    21

    111

    nnR

    0or shortest wavelength in Balmer series$

    n1 2, n2

    =

    1

    11R or

    R

    =

    =

    221

    1

    :

    1R F ===

    1:

    RR

    3.,2 1

    *

    9 *

    22

    14

    1

    n

    4. ,4 1

    *

    223

    14

    2

    13(

    .R

    :

    1

    *

    22

    1421

    1(12R F

    :

    3(.R

    R12

    1(

    5. ,4 0or Lyman series, n1 1 and n2 2 for firstline

    3

    1

    1

    1

    2

    1

    1

    1122

    1

    RRR =

    =

    =

    0or as"hen series n1 3 and n2 for firstline

    1

    /

    1

    1

    9

    1

    1

    3

    11

    222

    RRR =

    =

    =

    15

    /

    /?1

    3?

    2

    1 ==

    R

    R

    6. ,1 =#m'er of emission s!e"tral lines

    2

    )1( =

    nnN

    2

    )1(3 11

    =

    nn (in first

    "ase)

    or 121 =nn or (n14 3) (n1G 2)

    %a&e !ositive root n1 3

    8gain, 2

    )1(

    22 =

    nn

    (in se"ond "ase)

    or 12222 = nn or (n24 ) (n2G 3)

    %a&e !ositive root, or n2 =ow, velo"ity of ele"tron

    nh

    KZev

    22=

    3

    1

    2

    1

    1==

    n

    n

    v

    v

    7. ,4 0rom *its "om'ination !rin"i!le

    122313

    111

    nnnnnn +

    =

    Hr

    11

    1+=

    x or x 12 mm

    8. ,3

    !. ,1r

    mvKrru

    dr

    dF

    2

    )( ===

    or mKrmv 2= and mvr 2nh

    =2

    2 nhmkrr or

    2

    1

    =Km

    nhr

    and

    mv2 Kr2

    Km

    nhK

    %6 6 G 6

    m

    Knh

    Km

    nhK

    Km

    nhK

    =

    +

    2221

    1.,3 m$v$ c

    E

    =22 1

    1

    .

    1$13E

    2$1 1415J

    v 52/

    15

    131/$1

    11$2

    =

    mc

    EF v $19

    m?s

    11.,1 1 red'#rg 13$ eK o, the energy needed to deta"h the ele"tron

    is 13$ eK$%he energy in the gro#nd state

    1 4 13$eK%he energy in first eA"ited state

    2

    1 4 13$ eK

    5$

    122=

    = hc

    3

    12.,1 D i8 r

    ev

    2 r2 ef r2

    13.,3 8!!ly "on"e!t of red#"ed mass

    = emar F em2

    2

    ar =

    14.,4 mto 'e re!la"ed 'y red#"ed mass s#"h that

    mM

    111+=

    15.,3 0or "entre of mass at Oele"tron at Aand n#"le#satB, the !osition of "entre of mass OfromAis

    CAREER POINT, CP Tower, IPIA, Road No.1, Kota (Raj.), Ph: 0744-3040000 3

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    mM

    Mr

    mM

    rMomr

    +=

    ++

    =1

    16.,2 r3 r1 n2x 32 9x 2r n,

    x

    x

    n

    r

    =

    =

    = 3922

    CAREER POINT, CP Tower, IPIA, Road No.1, Kota (Raj.), Ph: 0744-3040000