mol% on dry basismethane-ch4 96.52%ethane-c2h6 1.95%propane-c3h8 0.42%iso-butane-c4h10 0.116%n-butane-c4h10 0.061%iso-pentane-c5h12 0.028%n-pentane-c5h12 0.015%hexane plus-c6h14 0.332%water vapour-h20 saturatednitrogen-n2 0.35%carbon dioxide-co2 0.21%

relative humidity 60% - 90%suction temperature 40 deg C to 35 deg Csuction pressure 384.136303058283 psig 27 kg/cm2grequired capac 17.655 mmscfd 20832.9 scmh

Basis and definition:

*1 hours of steady state operation*100 mol of dry gas*wet gas is gas with water vapour included in while dry gas is gas without water vapour*wet basis is gas composition with water content included while dry basis is gas composition without water vapour included in it*This means that the gas composition on wet basis has to be determined

*But gas composition under saturation at 20 and 35 deg C can be determined

Step 1) Find total mole of wet gas

a)Let standard condition beT 15 deg C 288.15 KP 14.7 psia 1.013 bar

b) Use ideal gas to find volume at normal condition

PoVo=

ToP1V1 T1

@ 20 deg C @ 35 deg CV1 834.46 m3 821.14 m3

b) Use ideal gas to find total no of moles of wet gas

*If water content is saturated,it means that partial pressure of water vapour is the same as vapour pressure of water at a specific temperature (means relative humidity is 100%).But to have relative humidity data is contradicting the "saturated" statement

@ 20 deg C @ 35 deg Ctotal no of moles of wet gas 8.809 mol 8.809

Step 2) Find mole of water

a) Use antoine equation to find vapor pressure of water

A 8.07131B 1730.63C 233.426

@ 20 deg C @ 35 deg Cvapor pressure of water P*w 55.193 mmHg 42.071 mmHg

0.074 bar 0.056 bar

b) If we know what is the relative humidity definition, partial pressure of water can be found

relative humidity(R.H)=partial pressure of water

vapor pressure of water @ specific temperature

relative humidity 60%@ 20 deg C relative humidity 90%@ 35 deg CPw 0.044 bar 0.050 bar

c)Use ideal gas to find out moles of water

relative humidity 60%@ 20 deg C relative humidity 90%@ 35 deg Cmols of water 0.014147 mol 0.0161758024892288 mol

Step 3) Find the relation between dry gas and wet gas via ratio

relative humidity 60%@ 20 deg C relative humidity 90%@ 35 deg Ctotal moles of wet gas 8.809 mol 8.809 molmoles of water vapour 0.014147 mol 0.0161758024892288 mol

relative humidity 60%@ 20 deg C

0.014147 moles of waterX

8.809 moles of wet gas

0.014147 moles of water=

8.795 moles of dry gas

relative humidity 90%@ 35 deg C

0.016176 moles of waterX

8.809 moles of wet gas

0.016176 moles of water=

8.793 moles of dry gas

Step 4) Final step is to find gas composition on wet basis at 20 deg C and 35 deg C

a) Use basis of 100 mol of dry gas to find no of moles

100 moles of dry gas

60% relative humidity@ 20 deg C 90% relative humidity@ 35 deg Cno of moles mol% no of moles mol%

methane-ch4 96.52 96.36% 96.52 96.34%ethane-c2h6 1.952 1.95% 1.952 1.95%propane-c3h8 0.421 0.42% 0.421 0.42%iso-butane-c4h10 0.116 0.1158% 0.116 0.1158%n-butane-c4h10 0.061 0.0609% 0.061 0.0609%iso-pentane-c5h12 0.028 0.0280% 0.028 0.0279%n-pentane-c5h12 0.015 0.0150% 0.015 0.0150%hexane plus-c6h14 0.332 0.3315% 0.332 0.3314%water vapour-h20 0.161 0.16% 0.184 0.18%nitrogen-n2 0.348 0.35% 0.348 0.35%carbon dioxide-co2 0.207 0.21% 0.207 0.21%total no of moles(wet basis) 100.160857384851 100.183964285361

0.5 mmscmd

Basis and definition:

*wet basis is gas composition with water content included while dry basis is gas composition without water vapour included in it

Step 1) Find total mole of wet gas

*If water content is saturated,it means that partial pressure of water vapour is the same as vapour pressure of water at aspecific temperature (means relative humidity is 100%).But to have relative humidity data is contradicting the "saturated" statement

mol

Step 2) Find mole of water

@saturation at 20 degC @saturation at 35 degC0.074 bar 0.056 bar

@saturation at 20 degC @saturation at 35 degC0.02358 mol 0.01797311388 mol

Step 3) Find the relation between dry gas and wet gas via ratio

@saturation at 20 degC @saturation at 35 degC8.809 mol 8.809 mol

0.02358 mol 0.01797311388 mol

@saturation at 20 degC

8.809 moles of wet gas 0.023579 moles of water8.795 moles of dry gas 8.809 moles of wet gas

0.00160857384851moles of water 0.023579 moles of watermoles of dry gas 8.786 moles of dry gas

@saturation at 35 degC

8.809 moles of wet gas 0.017973 moles of water8.793 moles of dry gas 8.809 moles of wet gas

0.00183964285361moles of water 0.017973 moles of watermoles of dry gas 8.791 moles of dry gas

Step 4) Final step is to find gas composition on wet basis at 20 deg C and 35 deg C

@saturation at 20 degC @saturation at 35 degCno of moles mol% no of moles mol%

96.52 96.26% 96.52 96.32% 0.9626165 methane-ch41.952 1.95% 1.952 1.95% 0.0194678 ethane-c2h60.421 0.42% 0.421 0.42% 0.0041987 propane-c3h80.116 0.1157% 0.116 0.1158% 0.0011569 iso-butane-c4h100.061 0.0608% 0.061 0.0609% 0.0006084 n-butane-c4h100.028 0.0279% 0.028 0.0279% 0.0002793 iso-pentane-c5h120.015 0.0150% 0.015 0.0150% 0.0001496 n-pentane-c5h120.332 0.3311% 0.332 0.3313% 0.0033111 hexane plus-c6h140.268 0.27% 0.204 0.20% 0.0026767 water vapour-h200.348 0.35% 0.348 0.35% 0.0034707 nitrogen-n20.207 0.21% 0.207 0.21% 0.0020645 carbon dioxide-co2

100.268383451152 100.204446551361

moles of waterX

8.809 moles of wet gasmoles of wet gas 8.786 moles of dry gas

moles of water= 0.002684

moles of watermoles of dry gas moles of dry gas

moles of waterX

8.809 moles of wet gasmoles of wet gas 8.791 moles of dry gas

moles of water= 0.002044

moles of watermoles of dry gas moles of dry gas

methane-ch4ethane-c2h6propane-c3h8iso-butane-c4h10n-butane-c4h10iso-pentane-c5h12n-pentane-c5h12hexane plus-c6h14water vapour-h20nitrogen-n2carbon dioxide-co2