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    John A. SchreifelsChemistry 212

    Chapter 20-1

    Chapter 20

    Electrochemistry

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    John A. SchreifelsChemistry 212

    Chapter 20-2

    Overview

    Half-Reactions Balancing oxidation reduction in acidic and basic solutions

    Voltaic cells

    Construction of voltaic cells

    Notation for voltaic cells

    Electromotive force (EMF)

    Standard cell potentials

    Equilibrium constants from EMFs

    Concentration dependence of EMF

    Electrolytic cells Aqueous electrolysis

    Stoichiometry of electrolysis

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    John A. SchreifelsChemistry 212

    Chapter 20-3

    Electrochemistry

    Electrochemistry - Field of

    Chemistry dealing with transfer of

    electrons from one species to

    another.

    E.g. Zn in CuSO4(aq).

    Electrochemical cell - combination of

    two half reactions to produce

    electricity from reaction.

    E.g. Danielle cell: Zn and Cu

    electrodes in salts of these ions.

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    John A. SchreifelsChemistry 212

    Chapter 20-4

    Balancing Redox Reactions: Oxidation Number

    Method

    Determine oxidation # for each atom- both sides of equation.

    Determine change in oxidation state for each atom.

    Left side: make loss of electrons = gain.

    Balance on other side.

    Insert coefficients for atoms that don't change oxidation state.

    E.g. Balance

    FeS(s)+CaC2(s)+CaO(s)Fe(s)+CO(g)+CaS(s)

    In acidic or basic solution balance as above, then balance

    charge with H+ or OH on one side and water on other side.

    Cancel waters that appear on both sides at end.

    E.g. Balance which occurs in acidic solution:

    242 CrOClCrOClO

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    John A. SchreifelsChemistry 212

    Chapter 20-5

    Balancing: Half-Reaction Method

    Write unbalanced half reactions for the oxidation and the

    reduction Balance the number of elements except O and H for each.

    Balance O's with H2O to the deficient side.

    Balance H's with H+ to the hydrogen deficient side

    Acidic: add H+

    Basic: add H2O to the deficient side and OH to the other side.

    Balance charge by adding e to the side that needs it.

    Multiply each half-reaction by integers to make electronscancel.

    Add the two half-reactions and simplify.

    E.g. Balance: Acidic: Zn(s) + VO2+(aq) Zn2+(aq) + V3+(aq).

    Basic: Ag(s) + HS(aq) + (aq) Ag2S(s) + Cr(OH)3(s).2

    4CrO

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    John A. SchreifelsChemistry 212

    Chapter 20-6

    Galvanic (Voltaic) and Electrolytic Cells

    Cell reaction Redox reaction involved inelectrochemical cell.

    Voltaic (galvanic) cell reaction is spontaneous and

    generates electrical current.

    Electrolytic non-spontaneous reaction occurs dueto passage of current from external power source.

    E.g. charging of batteries.

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    John A. SchreifelsChemistry 212

    Chapter 20-7

    Galvanic Cell 2

    anode electrode whereoxidation occurs.

    cathode electrode wherereduction occurs. salt bridge ionic solution connecting two half-

    cells (half-reactions) to prevent solutions frommixing.

    E.g. Which is the anode and cathode in the cellto the right? Write the halfreactions.

    Cd(s) + 2Ag+(aq) 2Ag(s) + Cd2+(aq)

    Sign of electrodes (current flows from anode tocathode):

    E.g. determine direction of electron flow for thereaction for a galvanic cell made from Ni(s) andFe(s). The reaction is:

    2Fe3+(aq) + 3Ni 2Fe(s) + 3Ni2+(aq)

    Electrode Sign Description1. Cathode: + cations migrate to it.

    cations reduced2. Anode: anions migrate to it.

    cations made.

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    John A. SchreifelsChemistry 212

    Chapter 20-8

    Shorthand Notation for Galvanic Cells

    Shorthand way of portraying electrodes in a voltaic

    electrochemical cell. Redox couple-oxidized and reduced forms of same element

    when it is involved in electrochemical reaction. Shorthand:Ox/Red

    E.g. Cu2+/Cu, Zn2+/Zn. 2 couples required for electrochemical reaction.

    Shorthand rules: Anode reaction-left; reduced form first.

    Cathode-right; oxidized form first.

    Vertical line drawn between different phases including reaction ofgases at metal electrode.

    Double vertical drawn where salt bridge separates two half-

    reactions.E.g. draw cell diagram for

    Zn(s) + Cu2+(aq) Zn2+(aq) + Cu(s).

    Fe3+(aq) + H2(g) Fe2+(aq) + 2H+(aq).

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    John A. SchreifelsChemistry 212

    Chapter 20-9

    Electrical Work

    Earlier w =

    P

    V In electrochemistry electrical pressure = potential

    difference; w = Eq or charge times the electrical

    pressure.

    Units: Coulomb

    Volts = Joules (SI Units 1J = 1C

    V) ;

    Also want to relate to # moles.

    1 mole e = 1 Faraday = 1 F

    F = qeN = 1.602x1019

    C6.022x1023

    /mol =9.65x104C/mol e.

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    John A. SchreifelsChemistry 212

    Chapter 20-10

    Cell Potentials for Cell Reactions: Spontaneity of

    Redox Reactions

    G vs E:

    G E G = nFE. Use this to calculate G forelectrochemical reaction when cell voltage known.

    E.g. Determine G for Zn/Cu cell if E = 1.100V

    G E

    At Equilibrium 0 0Spontaneous +

    Not spontaneous +

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    John A. SchreifelsChemistry 212

    Chapter 20-11

    Standard Reduction Potentials

    As with thermodynamic quantities, we list cell potentials at standard state = 1M

    at 1 atm and usually 25C. Cell potential is the sum of half-cell potentials using Hess law.

    Half-cell reactions for Daniell cell were

    Potential at each electrode initially determined relative to SHE = Standardhydrogen electrode.

    2H+(aq)+2e H2(g); [H+] = 1M and PH2=1atm.

    Other reaction run to determine if the SHE reaction proceeds spontaneously indirection written when connected to other half-cells.

    E.g. the cell potential of copper at standard state conditions relative toSHE(acting as the anode) was 0.340 V; determine the halfcell potential for Zn Zn2+ if the potential for the Daniell cell (standard state conditions) was 1.100V.

    Half-cell reactions reported as reductions.

    Zn(s) Zn2+

    (aq) + 2e Anode

    Cu

    2+

    (aq) + 2e

    Cu(s) Cathode

    Zn(s) +Cu2+

    (aq) Zn2+

    (aq) + Cu(s)

    oanode

    ocathode

    ocell

    EEE

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    John A. SchreifelsChemistry 212

    Chapter 20-12

    Using Standard Reduction Potentials

    Largenegative value meansoxidation strongly favored; strong reducing

    agent. Largepositive value meansreduction strongly favored; strong oxidizingagent.

    Relative values in table give an indication that one half-reaction favored overother. Summing half-cell reactions allow determination of standard cell potential.

    Half-cell potential intensive property independent of amount of material wedont use stoichiometric coefficients for determining standard cellpotentials.

    E.g. determine the cell potential ofBr2(l) + 2I

    (aq) I2(l) + 2Br(aq)

    E.g.2 determine the cell potential of

    2Ag+(aq) + Cu(s) 2Ag(s) + Cu2+(aq)

    E.g.3 Determine cell potential:

    (aq) + Fe(s) Fe2+(aq) + Mn2+(aq) (balanced?).

    when it is operated galvanically. Which is the oxidizing agent? reducing agent? E.g. 4 Determine if the reaction below is spontaneous in the direction written.

    Fe3+(aq) + Ag(s) ?

    4MnO

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    John A. SchreifelsChemistry 212

    Chapter 20-13

    Spontaneity of Redox Reactions

    G vs E:

    G E G = nFE. Use this to calculate G forelectrochemical reaction when cell voltage known.

    E.g. Determine G for Zn/Cu cell if E = 1.100V

    G E

    At Equilibrium 0 0Spontaneous +

    Not spontaneous +

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    John A. SchreifelsChemistry 212

    Chapter 20-14

    Effect of Concentration on Cell EMF: The Nernst

    Equation

    Recall that G = Go + RTlnQ where

    or at 25C

    which is called Nernst Equation.

    E.g. Determine potential of Daniell cell at 25C if

    [Zn2+] = 0.100 M and [Cu2+] = 0.00100 M.

    ba

    nm

    ]B[]A[

    ]N[]M[Q

    QlnnF

    RTEE o

    Qlogn

    0592.0EE o

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    John A. SchreifelsChemistry 212

    Chapter 20-15

    Electrochemical Determination of pH

    Electrodes can be used to determine acidity ofsolution by using hydrogen electrode with anotherone e.g. Hg2Cl2 half-cell.

    E.g. determine the pH of a solution that develops acell potential of 0.280 V (at 25C) given the cell below

    Pt(s) | H2(g) (1atm) | H+(? M) || Pb2+(1 M) | Pb(s)

    E.g. 2 determine the pH of a solution that develops a

    cell potential of0.200 V (at 25C) given the cellbelow (called a concentration cell).

    Pt(s)|H2(g)(1atm)|H+(1.00M)||H+(?M)|H2(g)(1atm)|Pt(s)

    pH.

    05920E'

    ]log[H0.0592'EE

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    John A. SchreifelsChemistry 212

    Chapter 20-16

    Standard Cell Potentials and Equilibrium

    Constants

    Free energy and equilibrium constant for reaction studied can

    be determined from cell voltage.

    Cell potential can be determined from G or from equilibrium

    constant.

    Recall: G = nFE = RTlnK.

    E.g. Determine free energy and equilibrium constant for reaction

    below (unbalanced).

    (aq) + Fe(s) Fe2+(aq) + Mn2+(aq)

    E.g.2 Determine cell potential and equilibrium constant of Cl2/Br2

    cell.

    E.g.3 The following cell has a potential of 0.578 V at 25C;determine Ksp.

    Ag(s)|AgCl(s)|Cl(1.0 M)||Ag+(1.0 M)|Ag(s).

    4MnO

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    John A. SchreifelsChemistry 212

    Chapter 20-17

    Quantitative Aspects of Electrolysis

    Current, i, measured units: 1 ampere = 1 coulomb per s (1 A = 1 Cs1).

    Time of electrolysis, t (s), also measured. Total charge, Q, calculated from the product:

    Q = it

    Charge on 1 mol of e:

    mol of e in an electrolysis obtained from balanced cell reaction:

    E.g. determine # mol of electron involved in the electrolysis of the following: Ag+(aq) + e Ag(s)

    2Cl(aq) + 2e Cl2(g)

    Amount deposited given by:

    E.g. Determine amount of Cu2+ electrolyzed from solution at constant current of6.00 A for period of 1.00 hour.

    eofmolC96500

    e

    C10x602.1

    eofmol

    e10x02.6

    eNF

    1923

    nF

    ti=

    nF

    Q=moles

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    John A. SchreifelsChemistry 212

    Chapter 20-18

    Electrical Work

    Maximum electrical work: G = wmax = nFE

    n = mol of electrons

    F = Faradays constant

    E = cell potential

    Units Joules

    Electrical Power: 1 watt = 1 J/s. Energy often expressed as kilowatthr

    1 kW*hr = 1000 W*3600 s = 3.6x106 J

    E.g. determine the maximum work in kW*hr required to produce

    1.00 kg of Zn from Zn2+ in a Daniell cell where the cell potential

    is 1.100 V for the production of Zn metal.Strategy:

    Determine n: mol of Zn2+ times 2.

    Calculate work.