ee138 chapter 8_slides - annotated 11-05

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Chapter 8 1 Outline Reading: Livingston, Chapter 8.1-8.7 Planck’s Constant Wave-Particle Duality of Light Wave-Particle Duality of Electrons Wave-Particle Duality: Momentum and Energy Schrodinger’s Equation Probability Density Case 1: Free Electron Heisenberg’s Uncertainty Principle Case 2: Potential Barrier (E<V) Case 3: Potential Barrier (E>V) Case 4: Tunneling Case 5: Infinite Potential Well Case 6: Finite Potential Well

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UCR EE138

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  • Chapter 8 1

    OutlineReading: Livingston, Chapter 8.1-8.7

    Plancks Constant Wave-Particle Duality of Light Wave-Particle Duality of Electrons Wave-Particle Duality: Momentum and Energy Schrodingers Equation Probability Density Case 1: Free Electron Heisenbergs Uncertainty Principle Case 2: Potential Barrier (EV) Case 4: Tunneling Case 5: Infinite Potential Well Case 6: Finite Potential Well

  • Chapter 8 22

    DiffractionWhat if wavelength of light ~ periodic atomic spacing?

  • Chapter 8 3

    Planck: Energy of Electromagnetic Wave

    hchE ==

    =EPlancks Constant: 6.626 x 10-34 J-s

    ""2

    barhh ==

    Relationship between energy and frequency:

  • Chapter 8 4

    Wave-Particle Duality of Light

    http://phet.colorado.edu/en/simulation/photoelectric

    1. Photoelectric Effect: e- ejected from matl surface when exposed to light

    2. Compton Scattering: increase in the wavelength of light scattered by an e-

    Effects which are NOT explained by wave properties:

    particle-particle collision:electron and photon (light particle)

    increase , decrease in E hcE =

    hp =

  • Chapter 8 5

    Wave-Particle Duality of ElectronsIf light can act as particles, can electrons act as waves?

    de Broglies Hypothesis: e- can have wave-like nature defined by p = mvand p = h/Davisson and Germer Experiment:

    sin2dn =Braggs Law of Diffraction: If e- is a wave and ~d, diffraction should be observed.

    For an e- with an applied V, the energy is E= eV.

    Need to apply correct V.

  • Chapter 8 6

    Wave-Particle Duality: Momentum and Energy

  • Chapter 8 7

    Example: Wave-Particle Duality

    Calculate the wavelength of a 50 g golf ball traveling at a velocity of 20 m/s.

  • Chapter 8 8

    Schrodingers Equation: Electron Wave Equation

    dtdiV

    m

    =+ 22

    2z

    ky

    jx

    i

    +

    +

    =

    )(),,(),,,( tzyxtzyx =Manipulate equation so that it is easier to use:

    Remember:

    Separate variables:

    dtdiV

    m =+ 2

    2

    2

    Divide by :dtdiV

    m

    =+ 22

    2

    LHS and RHS must equal constant, E:dtdiE

    =

    = diEdt ti

    iEt

    eet

    ==)(

    =E

    EVm

    =+ 22

    2 Time-independent Schrodingers Equation

    (stationary states)

    Multiply by :

    m = mass of electronV = potential energy of electron

    function waveelectron

  • Chapter 8 9

    Schrodingers Equation: Electron Wave Equation (cont.)

    EVm

    =+ 22

    2 Time-independent Schrodingers Equation

    (stationary states)

    EEPEK =+ ....

    mpEK2

    ..2

    =

    = ipMomentum operator:

    Please just believe for now

  • Chapter 8 10

    Probability DensityElectron is BOTH particle AND wave = fuzzy in time and space

    z

    *

  • Chapter 8 11

    Case 1: Free ElectronE

    V(z)=0

    z

    *

    1 Dimension

    EVm

    =+ 22

    2

    )(),,(),,,( tzyxtzyx = Time-dependent Scrodingers Equation)()(),( kztikzti BeAetx + +=

    22* BA +=

  • Chapter 8 12

    Heisenbergs Uncertainty Principle

    z

    *infinite uncertainty in position

    hzp

    Electron is BOTH particle AND wave = fuzzy in time and space

    mkE

    2

    22=kp =

    Other forms of uncertainty principle:

    zp

    htE

  • Chapter 8 13

    Example

    Laser light is normally monochromatic. However, when the pulse time becomes sufficiently short, the energy range can broaden to cover the entire range of visible light (and a laser beam becomes white). Below what pulse time will this phenomenon occur?

  • Chapter 8 14

    Case 2: Potential Barrier (E

  • Chapter 8 1515

    Case 2: Potential Barrier (E

  • Chapter 8 16

    Case 3: Potential Barrier (E>V)

    16

    1 Dimension

    EVm

    =+ 22

    2

    EV=Vo

    z=0

    Region 1 Region 2

    Region 1:zikzik BeAez 11)(1

    += mEk 21 =

    Solutions to time-independent Schrodingers Equation

    Region 2:zikzik DeCez 22)(2

    += ( )oVEmk

    =

    22

    Boundary conditions: E>Vo , no reflected wave from right side, D=0zikCez 2)(2 =

    K2 is REAL!!!

  • Chapter 8 17

    Case 3: Potential Barrier (E>V)

    17

    1 Dimension

    EVm

    =+ 22

    2

    EV=Vo

    z=0

    Region 1 Region 2

    Interface Continuity

    @ z = 0, 1=2 CBA =+

    @ z = 0, dzd

    dzd 21

    = ( ) CkBAk 21 =

    VEEVEE

    kkkk

    AB

    +

    =

    +

    =

    21

    21

    VEEE

    kkk

    AC

    +=

    +=

    22

    21

    1

    )*()*(

    1

    1

    AAkBBkR =

    )*()*(

    1

    2

    AAkCCkT =

    zikzikzik CeBeAe 211 =+

    zikzikzik eCikeBikeAik 211 211 =

    Ratio of reflected toincident amp

    Reflection Coeff

    Transmission CoeffRatio of transmitted toincident amp

  • Chapter 8 18

    Example What do you expect

    classically? What do you expect based

    on quantum mechanics? Calculate the reflection

    coefficient for the matter wave.

  • Chapter 8 19

    Example (cont.) What do you expect

    classically? What do you expect based

    on quantum mechanics? Calculate the reflection

    coefficient for the matter wave.

  • Chapter 8 20

    Case 4: Tunneling (E

  • Chapter 8 21

    Review

    E

    V(z)=0

    EV=Vo

    z=0

    Region 1 Region 2

    EV=Vo

    z=0

    Region 1 Region 2

    1. What would you expect to happen classically?2. What happens quantum mechanically?

  • Chapter 8 22

    Case 5: Infinite Potential Well

    22

    z=0 z=L

    V=infinity V=infinityV=0

    EVm

    =+ 22

    2

    Solutions to time-independent Schrodingers Equation

  • Chapter 8 23

    Case 5: Infinite Potential Well (cont.)

    2

    22

    8mLhnEn =

  • Chapter 8 24

    Example

    1. Sketch a plot of n versus E for an infinite potential well.2. If the width of the well increases by a factor of 2, how

    does the energy change?

  • Chapter 8 25

    Paulis Exclusion PrincipleRule of quantum mechanics that allows only two electrons (one spin up and one spin down) to fill each energy level

  • Chapter 8 26

    Case 6: Finite Potential Well (Quantum Well) How do energy wavelength and energy levels change qualitatively if potential barriers are not infinite?

  • Chapter 8 27

    Review Questions

    1. Name and explain two experiments that showed photons are particles.

    2. Name and explain an experiment that showed electrons are waves.3. What relationship did Planck find between frequency and energy?

    Momentum and wavelength?4. How are momentum and energy treated differently for particles and

    waves?5. What is the physical meaning of wave function?6. What is Schrodingers Equation (S.E.)? What does each term

    represent?7. What are general solutions to the time-dependent and time-

    independent S.E.? What is the relationship between E and k?8. Give the general procedure for solving S.E. for a potential profile.9. What is Heisenbergs Uncertainty Principle tell us?

  • Chapter 8 28

    More Review Questions

    1. What are the allowed energies for an infinite potential well?

    2. What is the ground state energy?3. What are the excited energy levels?4. How many electrons per energy level?5. How to electrons move and down in energy levels?6. If the potential barriers are made finite, how do the

    energy levels and wavelength change?

  • Chapter 8 29

    Important Equations

    hchE ===E

    Plancks Constant: 6.626 x 10-34 J-s

    2h

    =

    hp = vmp =

    2v2mE =

    sin2dn =

    dtdiV

    m

    =+ 22

    2 EV

    m=+ 2

    2

    2

    tiiEt

    eet

    ==)(

    mE

    2p2

    =

    *_ =distribprob

    kp =

    mkE

    2

    22=

    hzp htE

    zikzik BeAex 11)(1+=

    VEEVEE

    kkkk

    AB

    +

    =

    +

    =

    21

    21

    VEEE

    kkk

    AC

    +=

    +=

    22

    21

    1

    )*()*(

    1

    1

    AAkBBkR =

    )*()*(

    1

    2

    AAkCCkT =

    mLhnEn 8

    22

    =

    = z

    LnAnn sin ( )2228 fiif nnmL

    hhE

    =

    =...3,2,1=n