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0 NORTHERN CAPE DEPARTMENT OF EDUCATION NOORD- KAAP DEPARTEMENT VAN ONDERWYS PHYSICAL SCIENCES/ FISIESE WETENSKAPPE PHYSICS/FISIKA Grade 11 /graad 11 ELECTRIC CIRCUITS ELEKTRIESE STROOMBANE memorandum COMPILED BY/SAAMGESTEL DEUR: G. Izquierdo Rodriguez 2020

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    NORTHERN CAPE DEPARTMENT OF EDUCATION NOORD- KAAP DEPARTEMENT VAN ONDERWYS

    PHYSICAL SCIENCES/ FISIESE WETENSKAPPE PHYSICS/FISIKA

    Grade 11 /graad 11

    ELECTRIC CIRCUITS

    ELEKTRIESE STROOMBANE

    memorandum

    COMPILED BY/SAAMGESTEL DEUR: G. Izquierdo Rodriguez

    2020

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    PHYSICS/FISIKA

    SOLUTIONS/OPLOSSINGS:

    QUESTION 1/VRAAG 1 (2)

    1.1 D (2)

    1.2 B (2)

    1.3 A (2)

    1.4 D (2)

    1.5 A (2)

    1.6 D (2)

    1.7 C (2)

    1.8 C (2)

    1.9 D (2)

    1.10 D (2)

    [20]

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    QUESTION 2/VRAAG 2

    2.1 The potential difference across a conductor is directly proportional to the

    current in the conductor at constant temperature. Die potensiaalverskiloor 'n geleier is direkeweredigaan die stroom in die geleier by konstantetemperatuur.

    (2)

    2.2.1 𝑅 =

    𝑉

    𝐼

    𝑅 =12

    2

    𝑅 = 6 𝛺

    (3)

    2.2.2 POSITIVE MARKING FROM QUESTIONS 2.2.1

    POSITIEWE NASIE VANAF VRAE2.2.1 OPTION 1/OPSIE 1

    RT = Rp + Rs

    Rp =R1×R2R1+R2

    Rp =4 × 44 + 4

    Rs = 6 − 2

    Rs = 4 Ω

    V = IR

    V = 2 × 4

    V = 8 V

    OPTION 2/OPSIE2

    𝑅𝑇 = 𝑅𝑝 + 𝑅𝑠

    1

    Pp= 1

    R1+ 1

    R2

    1Pp

    =14

    +14

    𝑅𝑝 = 2 Ω

    Any one/Enige een

    Any one/Enige een

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    6 = 2 + Rs

    V = IR

    V = 2 × 4

    V = 8 V OPTION 3/OPSIE 3

    Rp =R1×R2R1+R2

    Rp =4 × 44 + 4

    𝑅𝑝 = 2 Ω

    Vp = IRp

    V = 2 × 2

    V = 4 V 𝑉 = 𝜀 − 𝑉𝑝

    𝑉 = 12 − 4

    V = 8 V

    (6)

    2.3.1 INCREASES/TOENEEM

    Total resistance decreases,emf is constant and total current is inversely proportional to resistance. Totale weerstand afneem, emf is konstant en totale stroom is omgekeerd eweredig aan weerstand.

    (4)

    2.3.2 INCREASES/ TOENEEM

    Total current increases, resistance is constant and potential difference is directly proportional to current. Totale stroom neem toe, weerstand is konstant en potensiaalverskil is direk eweredig aan stroom.

    (4)

    [19]

    Any one/Enige een

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    QUESTION 3/VRAAG 3

    3.1 The potential difference across a conductor is directly proportional to the current in the conductor at constant temperature. Die potensiaalverskil oor 'n geleier is direk eweredig aan die stroom in die geleier by konstante temperatuur.

    (2)

    3.2 Option 1/Opsie 1

    321

    1111

    RRRRparallel

    6

    1

    6

    1

    6

    11

    parallelR

    Rparallel= 2 Ω

    Requivalent/total= Rparallel + Rseries

    Requivalent/total= 2 + 3

    Requivalent/total= 5 Ω

    R

    VI

    5

    12I

    AI 4.2

    Option 2/Opsie 2

    Requivalent/total= Rparallel + Rseries

    R1= R2= R3= R

    Requivalent/total= n

    R+ Rseries

    Requivalent/total= 3

    6 + 3

    Requivalent/total= 5 Ω

    R

    VI

    (either one/enigeen)

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    5

    12I

    AI 4.2 (6)

    3.3 Increases/ Vermeerder

    Potential difference (Voltage)/emf remais constant (is the same) and total resistance

    decreases.

    Potensiaalverskil /emk bly konstant (is dieselfde) en totale weerstand neem af (3)

    [11]

    QUESTION 4/VRAAG 4

    4.1 Rt= R1+ R23

    R23=32

    11

    RR =

    2

    1

    2

    1 =

    2

    2= 1Ω

    Rt= 4 +1= 5 Ω

    (4)

    4.2 OPTION N1/OPSIE 1

    Ammeter 1

    I=TR

    V=

    5

    12 = 2.4 A

    Ammeter 2

    I= I2+I3

    I2=I3

    I2= 2

    4,2= 1,2 A

    OPTION 2/OPSIE 2

    V23= ε – V1 = 12 – (2,4X4) = 2.4 V

    I= 2

    4,2= 1.2 A

    (4)

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    OPTION 3/OPSIE 3

    V1= IR1= 2.4 x 4 = 9,6 V

    V23= ε – V1 = 12 – 9,6 = 2.4 V

    I= 2

    4,2= 1.2 A

    4.3 OPTION 1/OPSIE 1

    RIP 2

    4)4.2( 2P

    04.23P W

    OPTION2/OPSIE 2

    P= IV

    P=I(ε-I2R2)

    P=2.4 [12-(1,2 x 2)]

    P=23.04 W

    (3)

    4.4 Yes/Ja

    Resistance in the circuit increases /Weerstand in die stroomban vermeerder

    Current decreases/Stroom verminder

    For a constant resistance power is directly proportional to the square root of current

    (P α I2/Vir ‘n konstante weerstand, is drywing direk eweredig aan die kwadraat van

    stroom (P α I2)

    (4)

    [15]

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    QUESTION 5/VRAAG 5

    5.1.1 OPTION 1/OPSIE1

    21

    111

    RRRP OR/OF

    4

    1

    2

    1

    33,1PR

    TR = 1 ,33+3

    =4,33

    OPTION 2/ OPSIE 2

    Rp = 21

    21

    RR

    RR

    =42

    42

    x = 1,33Ω

    TR = 1 ,33+3

    =4,33

    (5)

    5.1.2 POSITIVE MARKING FROM 5.1/ POSITIEWE NASIEN VANAF 5.1

    I

    VR

    4,33 = I

    12

    I = 2,77 A

    (4)

    5.1.3 POSITIVE MARKING FROM 5.1.2/ POSITIEWE NASIEN VANAF 5.1.2

    V3Ω =IR OR V// = I T R//

    =2,77 x3 = 8,31 V = 2,77 x 1,33

    V = 12-8,31 = 3,69 V V// = 3,68 V

    (4)

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    5.2 Decreases The total resistance increases. According to I =

    R

    V, when R

    increases I decreases as potential difference is constant.

    Afneem. Die totale weerstand neem toe Na aanleiding van I =R

    V,

    wanneer R toeneem sal I afneem.

    (3)

    5.3.1 ANY TWO/ ENIGE TWEE

    Temperature/ Temperatuur

    Length/Lengte

    Cross sectional area(thickness) of material/ Dikte (deursnee) van die

    materiaal

    (2)

    5.3.2. Conductor Q / Geleier Q

    Option 1/Opsie 1

    For the same potential difference, wire Q has a higher current than

    wire P. Therefore wire Q has a lower resistance than wire P.

    Vir dieselfde potensiaalverskil het draad Q ‘n hoër stroom as draad P.

    Daarom het draad Q ‘n laer weerstand as draad P.

    Option 2/Opsie 2

    The gradient of the graph for wire Q is bigger than that of wire P.

    Gradient =V

    1 is bigger, thus R

    I

    V is smaller.

    Die gradient van die grafiek vir draad Q is groter as die van draad P.

    Gradient =V

    1 is groter, daarom R

    I

    V is kleiner.

    (3)

    [21]

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    QUESTION 6/VRAAG 6

    6.1 The potential difference across a conductor is directly proportional to the current in the conductor at constant temperature. Die potensiaalverskil oor 'n geleier is direk eweredig aan die stroom in die geleier by konstante temperatuur.

    (2)

    6.2.1 V= IR OR/OF R =

    I

    V

    R = A

    V

    2

    12

    R = 6 Ω

    (3)

    6. 2.2 POSITIVE MARKING FROM 6.2.1 /POSITIEWE NASIEN VANAF 6.2.1

    RT = Rx + RAB OR/OF Rx = Rt - RAB

    BA RR

    11

    R

    1

    AB

    OR/OF BA

    BA

    RR

    RRR

    2

    1

    3

    1

    R

    1

    AB

    OR/OF 23

    23

    R

    Rparallel= 1,2 Ω

    R= 6- 1,2

    R= 4,8 Ω

    (4)

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    6.2.3 POSITIVE MARKING FROM 6.2.2 /POSITIEWE NASIEN VANAF 6.2.2 OPTION 1/OPSIE 1

    VAB = I R

    VAB = 2 x 1,2

    VAB = 2,4 V

    IA =R

    VAB

    IA =3

    4,2

    IA = 0,8 A

    OPTION 2/OPSIE 2

    IAB= IA + IB

    BBAA RIRI 23 BA II

    AA II2

    32

    IA = 0,8 A

    (3)

    6.3 OPTION 1/OPSIE 1

    RIP 2

    8,422 P

    WP 2,19

    OPTION 2/OPSIE 2

    IVP

    IRV

    8,42V

    VV 6,9

    6,92P

    (3)

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    WP 2,19

    OPTION 2/OPSIE 2

    R

    VP

    2

    ABVV

    2,1212 V =

    VV 6,9

    8,4

    )6,9( 2P

    WP 2,19

    6.4 DECREASES/ VERMINDER

    Total resistance increases emf/ Terminal voltage/terminal potential

    difference is constant current decreases.

    Totale weerstand verhoog emk / terminaalpotensiaalverskil / terminale

    potensiaalverskil konstant stroom afneem.

    OR/OF

    Total resistance increases and current is inversely proportional to

    resistance when emf/terminal voltage/terminal potential difference is

    constant.

    Totale weerstand verhoog en stroom is omgekeerd eweredig aan weerstand

    wanneer emk / klemspanning / terminale potensiaalverskil konstante is.

    (3)

    [18]

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    QUESTION 7 / VRAAG 7

    7.1

    21

    111

    RRRparallel

    12

    1

    4

    11

    Rparallel

    Rparallel = 3 Ω

    (3)

    7.2 V// = IR//

    = (2)(3)

    = 6 V

    (3)

    7.3 I4Ω = V//

    R

    = 6

    4

    = 1,5 A

    (3)

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    7.4

    tR

    VE

    2

    6012

    )6( 2E

    E = 180 J

    OR/OF OR / OF

    I12 = V/R E = IVt

    = 6/12

    = 0,5 A = (0,5)(6)(60)

    E = I2Rt

    = (0,5)2(12)(60) = 180 J

    = 180 J

    (3)

    [12]

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    QUESTION 8/ VRAAG 8

    8.1 Current / Stroom (2)

    8.2

    8.2.1 (4,0 : 0,64) (2)

    8.2.2 Temperature was not kept constant / Die temperatuur is nie konstant gehou

    nie.

    (2)

    8.3 Gradient / Gradiënt =

    04

    064,0

    = 0,16

    R= 16,0

    1 = 6,25 Ω

    (4)

    [10]

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    QUESTION 9/VRAAG 9

    9.1. What is the relationship between potential difference and current in a circuit with a resistor

    with constant resistance?

    Wat is die verband tussen die potensiaalverskil en die elektriese stroom in ‘n stroombaan met ‘n weerstand met ‘n konstante weestand? (2) 9.2. When current increases potential difference also increases.

    Wanneer die stroom verhoog, verhoog die potensiaalverskil ook as die weerstand konstant bly. (2)

    9.3. 9.3.1 Potential difference/ Potensiaalverskil

    9.3.2 Current /Stroom (2)

    9.4.

    1mark straight line (shape)

    1 mark both axes lables and unit

    1 mark both axes scale

    1 mark for estarting at 0.02 (4)

    9.5 Gradient/ Gradiënt = I

    V

    Gradient/ Gradiënt = 02,008,0

    624

    Gradient/ Gradiënt = 300 (3)

    9.6. Resistance of the resistor/ Weerstand van die resistor.. (1)

    9.7. The hypothesis is correct the potential difference is directly proportional to current when

    the resistant is constant.

    Die hipotese is korrek, want die potensiaalverskil is direk eweredig aan die sterkte van die elektriese stroom wanneer die weerstand van die resistor konstant gehou word. (2)

    [16]

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