electrochemistry mechanical work g = electrical work w = n = w = w max # moles e - f =charge on 1...
TRANSCRIPT
Electrochemistry
Mechanical work
G =
Electrical work
w =
n =
w =
wmax
# moles e-
F = charge on 1 mol e-
=electrical potential
- Pext V - n F
Electrochemistry
electrons
ose lectronsxidation
ain lectronseduction
reduction oxidation
LEO
GER Ger
Electrochemistry
silver Ag(s)
aluminum Al(s)
Ag(s)
Al(s)
G =
Gof =
Ag+(aq)
Al3+(aq)
77 kJ mol-1
-481 kJ mol-1
Ag+(aq) + e-of
Al3+(aq) + 3e-
Ag(s) Ag+(aq) + e-
Al(s) Al3+(aq) + 3e-
Gof = 77 kJ mol-1
Gof = -481 kJ mol-1
Al(s) Al3+(aq) + 3e- Gof = -481 kJ mol-1
Ag+(aq) + e- Ag(s) Go = -77 kJ mol-13( ) 3( )__________________ ________________
3Ag+ Go =
spontaneous
+ Al 3Ag + Al3+ -712 kJ/mol
1 molecule Al3+
3Ag++ Al Al3+ + 3Ag
1M AgNO31M Al(NO3)3
AgAl
Ag+ + e- AgAl Al3+ + 3e-
3e-
oxidation reduction
K+ Cl-
anode cathode
1 mol Al3+ + 3 mol NO3-
1M AgNO31M Al(NO3)3
AgAlK+ Cl-
anode cathode
Ag+ +e- AgAl Al3+ + 3e-
oxidation reduction
Al(s)Al3+(1 M)Ag+(1 M)Ag(s)
Reduction Potential
Al(s) Al3+(aq) (1M) Ag+(aq) (1M) Ag(s)
3Ag+ + Al 3Ag + Al3+
Go =
o =
Go = -712 kJ/mol
wmax =
Al(s) Al3+ + 3e- Ag+ + e- Ag
standard reduction potentialstandard = 1M, 1 atmreduction potential = tendency to gain e-
wmax-n F o
half-reaction o (V)
o = 0 Standard Hydrogenelectrode
spontaneous reduction
spontaneous oxidation
(SHE)
F2 + 2e- 2F- 2.87Ag+ + e- Ag 0.80
Cu2+ + 2e- Cu 0.342H+ + 2e- H2 0.00Sn2+ + 2e- Sn -0.13
Li+ + e- Li -3.05Al3+ + 3e- Al -1.66
half-reaction o (V)F2 + 2e- 2F- 2.87Ag+ + e- Ag 0.80Cu2+ + 2e- Cu 0.342H+ + 2e- H2 0.00Sn2+ + 2e- Sn -0.13Al3+ + 3e- Al -1.66Li+ + e- Li -3.05
Al half-cell and Ag half-cell
reduction reaction: oxidation reaction:
ocell
ocell = o
red - oox
Ag+ (aq) + e- Ag(s)
Al3+ (aq) + 3e- Al(s)
o = 0.80 V
o = -1.66 V
ocell = 0.80 - (-1.66) = 2.46 V
ocell > 0
ocell < 0
voltaic or galvanic cell spontaneous
electrolytic cell non-spontaneous
Electrochemical work
3Ag+ + Al 3Ag + Al3+ ocell = 2.46 V
Go = wmax = -n = mol of e-
Go =
= -712170 CV
n
F = faraday = 96,500 C / mol e-
F
o = standard reduction potential V (J/C)
o
-(3 mol e-) (96,500 C/mol e-)(2.46V)
= -712170 J = -712 kJ