ELECTROLYSIS OF MOLTEN COMPOUNDAt cathode:

- Each lead (II) ion is discharged by accepting 2 electron to form lead atom, Pb

Pb2+(l) + 2e ( Pb(s) - Lead metal is formed

At anode :

- each bromide ion is discharged by donating an electron to form

a neutral bromine atom, Br

Br-(l) ( Br(l) + e

- two bromine atoms combine to form a bromine molecule, Br2

Br(l) + Br(l) ( Br2(g)

- half-equation: 2Br-(l) ( Br2(g) + 2e

- Bromine gas is formed

Overall equation: Pb 2+(l) + 2Br-(l) ( Pb(s) + Br2(g)

THINKING1. Based on above electrolysis,

a. state the ions present. b. Which ion will go to anode, and which ion will go to cathode?c. anode is the positively charge electrodes or negatively charged electrodes? how about cathode?d. what is the product form at anode and cathode?.e. where is the electron flow?2. try to analysis the electrolysis of molten lead(II) oxide and molten sodium chloride.

a. state the ions present.

b. Which ion will go to anode, and which ion will go to cathode?

c. write the half-equation at anode and cathode, also the overall equation.

d. what is the product form at anode and cathode