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Page 1: Electronic structure

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7-1

Chapter 4

Quantum Theory and Atomic Structure

Page 2: Electronic structure

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7-2

Quantum Theory and Atomic Structure

7.1 The Nature of Light

7.2 Atomic Spectra

7.3 The Wave-Particle Duality of Matter and Energy

7.4 The Quantum-Mechanical Model of the Atom

Page 3: Electronic structure

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7-3

Figure 7.1

Frequency and Wavelength

c =

The Wave Nature The Wave Nature ofof

LightLight

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7-4

Figure 7.2 Amplitude (intensity) of a wave.

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7-5

Figure 7.3 Regions of the electromagnetic spectrum.

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7-6

Sample Problem 7.1

SOLUTION:PLAN:

Interconverting Wavelength and Frequency

wavelength in units given

wavelength in m

frequency (s-1 or Hz)

= c/

Use c =

10-2 m1 cm

10-9 m1 nm

= 1.00x10-10 m

= 325x10-2 m

= 473x10-9 m

=3x108 m/s

1.00x10-10 m= 3x1018 s-1

=

=

3x108 m/s

325x10-2 m= 9.23x107 s-1

3x108 m/s

473x10-9 m= 6.34x1014 s-1

PROBLEM: A dental hygienist uses x-rays (= 1.00A) to take a series of dental radiographs while the patient listens to a radio station ( = 325 cm) and looks out the window at the blue sky (= 473 nm). What is the frequency (in s-1) of the electromagnetic radiation from each source? (Assume that the radiation travels at the speed of light, 3.00x108 m/s.)

o

1 A = 10-10 m1 cm = 10-2 m1 nm = 10-9 m

o

325 cm

473nm

1.00Ao 10-10 m

1Ao

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7-7

Figure 7.4

Different behaviors of waves and particles.

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7-8

Figure 7.5

The diffraction pattern caused by light passing through two adjacent slits.

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7-9

Figure 7.6 Blackbody radiationE = n h

E = n h

E = h when n = 1

smoldering coal

electric heating element light bulb filament

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7-10

Figure 7.7

Demonstration of the photoelectric effect.

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7-11

Sample Problem 7.2

SOLUTION:

PLAN:

Calculating the Energy of Radiation from Its Wavelength

PROBLEM: A cook uses a microwave oven to heat a meal. The wavelength of the radiation is 1.20cm. What is the energy of one photon of this microwave radiation?

After converting cm to m, we can use the energy equation, E = h combined with = c/ to find the energy.

E = hc/

E =6.626X10-34J*s 3x108m/s

1.20cm 10-2m

cm

x= 1.66x10-23J

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7-12

Figure 7.8

The line spectra of

several elements.

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7-13

Figure 7.10

Quantum staircase.

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7-14

Figure 7.11

The Bohr explanation of the three series of spectral lines.

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7-15

Figure 7.14

Comparing the diffraction patterns of x-rays and electrons.

x-ray diffraction of aluminum foil electron diffraction of aluminum foil

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7-16

Figure B7.2

Figure B7.1

Emission and absorption spectra of sodium atoms.

Flame tests.

strontium 38Sr copper 29Cu

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7-17

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7-18

Figure 7.13

Wave motion in restricted systems.

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7-19

The Dual Property of Matter

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7-20

Table 7.1 The de Broglie Wavelengths of Several Objects

Substance Mass (g) Speed (m/s) (m)

slow electron

fast electron

alpha particle

one-gram mass

baseball

Earth

9x10-28

9x10-28

6.6x10-24

1.0

142

6.0x1027

1.0

5.9x106

1.5x107

0.01

25.0

3.0x104

7x10-4

1x10-10

7x10-15

7x10-29

2x10-34

4x10-63

h /mu

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7-21

Sample Problem 7.3

SOLUTION:

PLAN:

Calculating the de Broglie Wavelength of an Electron

PROBLEM: Find the deBroglie wavelength of an electron with a speed of 1.00x106m/s (electron mass = 9.11x10-31kg; h = 6.626x10-34 kg*m2/s).

Knowing the mass and the speed of the electron allows to use the equation = h/mu to find the wavelength.

= 6.626x10-34kg*m2/s

9.11x10-31kg x 1.00x106m/s= 7.27x10-10m

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7-22

Bohr’s Model of The Hydrogen Atom

• Ground state• Excited state• When an electron falls

back to the lower level, it emits a definite amount of energy in the form of a quantum of light.

• Ex. X-rays

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Limitations of the Bohr Model → Quantum Mechanical Model

• Unfortunately, the Bohr Model failed for all other elements that had more than one proton and one electron. (The multiple electron-nuclear attractions, electron–electron repulsions, and nuclear repulsions make other atoms much more complicated than hydrogen.)

• In 1920s, a new discipline, quantum mechanics, was developed to describe the motion of submicroscopic particles confined to tiny regions of space.

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7-24

CLASSICAL THEORYCLASSICAL THEORY

Matter particulate,

massive

Energy continuous,

wavelike

Since matter is discontinuous and particulate perhaps energy is discontinuous and particulate.

Observation Theory

Planck: Energy is quantized; only certain values allowed

blackbody radiation

Einstein: Light has particulate behavior (photons)photoelectric effect

Bohr: Energy of atoms is quantized; photon emitted when electron changes orbit.

atomic line spectra

Figure 7.15

Summary of the major observations and theories leading from classical theory to quantum theory.

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7-25

Since energy is wavelike perhaps matter is wavelike

Observation Theory

deBroglie: All matter travels in waves; energy of atom is quantized due to wave motion of electrons

Davisson/Germer: electron diffraction by metal crystal

Since matter has mass perhaps energy has mass

Observation Theory

Einstein/deBroglie: Mass and energy are equivalent; particles have wavelength and photons have momentum.

Compton: photon wavelength increases (momentum decreases) after colliding with electron

Figure 7.15 continued

QUANTUM THEORY

Energy same as Matterparticulate, massive, wavelike

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7-26

The Heisenberg Uncertainty Principle

x * m u ≥

h

4

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7-27

The Schrödinger Equation

H = E

d2dy2

d2dx2

d2dz2

+ +82m

h2(E-V(x,y,z)(x,y,z) = 0+

how changes in space

mass of electron

total quantized energy of the atomic system

potential energy at x,y,zwave function

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7-28

Quantum Numbers and Atomic Orbitals

An atomic orbital is specified by three quantum numbers.

n the principal quantum number - a positive integer

l the angular momentum quantum number - an integer from 0 to n-1

ml the magnetic moment quantum number - an integer from -l to +l

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Quantum Numbers

Energies

n 1 < 2 < 3 < 4…

l s < p < d < f

ml Orbitals in the same subshell have equal energies

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7-30

Azimuthat quantum number, l

Subshell designation Maximum number of electrons per subshell

0 s 2

1 p 6

2 d 10

3 f 14

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7-31

Table 7.2 The Hierarchy of Quantum Numbers for Atomic Orbitals

Name, Symbol(Property) Allowed Values Quantum Numbers

Principal, n(size, energy)

Angular momentum, l

(shape)

Magnetic, ml

(orientation)

Positive integer(1, 2, 3, ...)

0 to n-1

-l,…,0,…,+l

1

0

0

2

0 1

0

3

0 1 2

0

0-1 +1 -1 0 +1

0 +1 +2-1-2

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7-32

Sample Problem 7.5

SOLUTION:

PLAN:

Determining Quantum Numbers for an Energy Level

PROBLEM: What values of the angular momentum (l) and magnetic (ml) quantum numbers are allowed for a principal quantum number (n) of 3? How many orbitals are allowed for n = 3?

Follow the rules for allowable quantum numbers found in the text.

l values can be integers from 0 to n-1; ml can be integers from -l through 0 to + l.

For n = 3, l = 0, 1, 2

For l = 0 ml = 0

For l = 1 ml = -1, 0, or +1

For l = 2 ml = -2, -1, 0, +1, or +2

There are 9 ml values and therefore 9 orbitals with n = 3.

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Sample Problem 7.6

SOLUTION:

PLAN:

Determining Sublevel Names and Orbital Quantum Numbers

PROBLEM: Give the name, magnetic quantum numbers, and number of orbitals for each sublevel with the following quantum numbers:

(a) n = 3, l = 2 (b) n = 2, l = 0 (c) n = 5, l = 1 (d) n = 4, l = 3

Combine the n value and l designation to name the sublevel. Knowing l, we can find ml and the number of orbitals.

n l sublevel name possible ml values # of orbitals

(a)

(b)

(c)

(d)

3

2

5

4

2

0

1

3

3d

2s

5p

4f

-2, -1, 0, 1, 2

0

-1, 0, 1

-3, -2, -1, 0, 1, 2, 3

5

1

3

7

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Figure 7.18

The 2p orbitals.

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7-35

Figure 7.19 The 3d orbitals.

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7-36

Figure 7.19 continued

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Figure 7.20 One of the seven possible 4f orbitals.