SAP2000 Advanced Version 12.0.0.0 (Analysis Build 8757/32) File: D:\SAP Result\etabs\SAP Model\6 Story Final.LOG B E G I N A N A L Y S I S 2013/07/18 14:56:45 RUNNING ANALYSIS WITHIN THE MAIN SAP2000 PROCESS USING THE STANDARD SOLVER (PROVIDES COMPLETE INSTABILITY INFORMATION) E L E M E N T F O R M A T I O N 14:56:45 REDUCTION OF CONSTRAINTS AND RESTRAINTS: NUMBER OF CONSTRAINT MASTER DOF BEFORE REDUCTION = 1266 COUPLED CONSTRAINT/RESTRAINT MASTER DOF = 936 CONSTRAINT MASTER DOF AFTER REDUCTION = 330 L I N E A R E Q U A T I O N S O L U T I O N 14:56:46 FORMING STIFFNESS AT ZERO (UNSTRESSED) INITIAL CONDITIONS TOTAL NUMBER OF EQUILIBRIUM EQUATIONS = 1596 APPROXIMATE "EFFECTIVE" BAND WIDTH = 155 NUMBER OF EQUATION STORAGE BLOCKS = 1 MAXIMUM BLOCK SIZE (8-BYTE TERMS) = 237721 SIZE OF STIFFNESS FILE(S) (BYTES) = 1.820 MB NUMBER OF EQUATIONS TO SOLVE = 1596 * * * W A R N I N G * * * NUMERICAL PROBLEMS ENCOUNTERED DURING EQUATION ASSEMBLY: TYPE LABEL DOF X-COORD Y-COORD Z-COORD PROBLEM VALUE ----- ------- -- ----------- ----------- ----------- ------------- ----------- Joint ~318 U3 11.442308 16.500000 18.500000 Diag = 0 --> 1.00E-10 Joint ~318 R1 11.442308 16.500000 18.500000 Diag = 0 --> 1.00E-10 Joint ~318 R2 11.442308 16.500000 18.500000 Diag = 0 --> 1.00E-10 Joint ~317 U3 11.442308 16.500000 15.500000 Diag = 0 --> 1.00E-10 Joint ~317 R1 11.442308 16.500000 15.500000 Diag = 0 --> 1.00E-10 Joint ~317 R2 11.442308 16.500000 15.500000 Diag = 0 --> 1.00E-10 Joint ~316 U3 11.442308 16.500000 12.500000 Diag = 0 --> 1.00E-10 Joint ~316 R1 11.442308 16.500000 12.500000 Diag = 0 --> 1.00E-10 Joint ~316 R2 11.442308 16.500000 12.500000 Diag = 0 --> 1.00E-10 Joint ~315 U3 11.442308 16.500000 9.500000 Diag = 0 --> 1.00E-10 Joint ~315 R1 11.442308 16.500000 9.500000 Diag = 0 --> 1.00E-10 Joint ~315 R2 11.442308 16.500000 9.500000 Diag = 0 --> 1.00E-10 Joint ~314 U3 11.442308 16.500000 6.500000 Diag = 0 --> 1.00E-10 Joint ~314 R1 11.442308 16.500000 6.500000 Diag = 0 --> 1.00E-10 Joint ~314 R2 11.442308 16.500000 6.500000 Diag = 0 --> 1.00E-10 Joint ~313 U3 11.442308 16.500000 3.500000 Diag = 0 --> 1.00E-10 Joint ~313 R1 11.442308 16.500000 3.500000 Diag = 0 --> 1.00E-10 Joint ~313 R2 11.442308 16.500000 3.500000 Diag = 0 --> 1.00E-10 NUMBER OF EIGENVALUES BELOW SHIFT = 0 L I N E A R S T A T I C C A S E S 14:56:48 USING STIFFNESS AT ZERO (UNSTRESSED) INITIAL CONDITIONS TOTAL NUMBER OF CASES TO SOLVE = 9 NUMBER OF CASES TO SOLVE PER BLOCK = 9 LINEAR STATIC CASES TO BE SOLVED: CASE: DEAD CASE: DL_FINISH CASE: DL_PROOF CASE: DL_EXTWALL CASE: DL_INTWALL CASE: DL_PARAPET CASE: LL_FLOOR CASE: LL_TERRACE CASE: EQ E I G E N M O D A L A N A L Y S I S 14:56:48 CASE: MODAL USING STIFFNESS AT ZERO (UNSTRESSED) INITIAL CONDITIONS NUMBER OF STIFFNESS DEGREES OF FREEDOM = 1596 NUMBER OF MASS DEGREES OF FREEDOM = 330 MAXIMUM NUMBER OF EIGEN MODES SOUGHT = 6 MINIMUM NUMBER OF EIGEN MODES SOUGHT = 1 NUMBER OF RESIDUAL-MASS MODES SOUGHT = 0 NUMBER OF SUBSPACE VECTORS USED = 24 RELATIVE CONVERGENCE TOLERANCE = 1.00E-09 FREQUENCY SHIFT (CENTER) (CYC/TIME) = .000000 FREQUENCY CUTOFF (RADIUS) (CYC/TIME) = -INFINITY- ALLOW AUTOMATIC FREQUENCY SHIFTING = YES Original stiffness at shift : EV= 0.0000000E+00, f= .000000, T= -INFINITY- Number of eigenvalues below shift = 0 Found mode 1 of 6: EV= 6.1779344E+01, f= 1.250955, T= 0.799389 Found mode 2 of 6: EV= 6.3585277E+01, f= 1.269108, T= 0.787955 Found mode 3 of 6: EV= 6.9135571E+01, f= 1.323338, T= 0.755665 Found mode 4 of 6: EV= 6.1104008E+02, f= 3.934187, T= 0.254182 Found mode 5 of 6: EV= 6.2569601E+02, f= 3.981088, T= 0.251188 Found mode 6 of 6: EV= 6.8933368E+02, f= 4.178639, T= 0.239312 NUMBER OF EIGEN MODES FOUND = 6 NUMBER OF ITERATIONS PERFORMED = 5 NUMBER OF STIFFNESS SHIFTS = 0 A N A L Y S I S C O M P L E T E 2013/07/18 14:56:49 SAP2000 Advanced Version 12.0.0.0 (Analysis Build 8757/32) File: D:\SAP Result\etabs\SAP Model\6 Story Final.LOG B E G I N A N A L Y S I S 2013/07/18 14:56:56 RUNNING ANALYSIS WITHIN THE MAIN SAP2000 PROCESS USING THE STANDARD SOLVER (PROVIDES COMPLETE INSTABILITY INFORMATION) PREVIOUS STIFFNESS IS STILL AVAILABLE AT ZERO (UNSTRESSED) INITIAL CONDITIONS L I N E A R S T A T I C C A S E S 14:56:56 USING STIFFNESS AT ZERO (UNSTRESSED) INITIAL CONDITIONS TOTAL NUMBER OF CASES TO SOLVE = 1 NUMBER OF CASES TO SOLVE PER BLOCK = 1 LINEAR STATIC CASES TO BE SOLVED: CASE: EQ A N A L Y S I S C O M P L E T E 2013/07/18 14:56:56