etank full report
DESCRIPTION
tankTRANSCRIPT
ETANK FULL REPORT - JGC
ETank2000 Full 1.9.14 (26 Oct 2010)
TABLE OF CONTENTS PAGE 1
ETANK SETTINGS SUMMARY PAGE 2
SUMMARY OF DESIGN DATA AND REMARKS PAGE 3
SUMMARY OF RESULTS PAGE 5
BOTTOM DESIGN PAGE 37
SEISMIC MOMENT PAGE 42
ANCHOR BOLT DESIGN PAGE 44
CAPACITIES AND WEIGHTS PAGE 51
MAWP & MAWV SUMMARY PAGE 52
ETANK SETTINGS SUMMARY
To Change These ETank Settings, Go To Tools->Options, Behavior Tab.
----------------------------------------------------------------------
No 650 Appendix F Calcs when Tank P = 0 -> Default : False
Show MAWP / MAWV Calcs : True
Enforce API Minimum thicknesses : True
Enforce API Maximum Roof thickness : True
Enforce Minimum Self Supp. Cone Pitch (2 in 12) : True
Force Non-Annular Btm. to Meet API-650 5.5.1 : False
Set t.actual to t.required Values : False
Maximum 650 App. S or App. M Multiplier is 1 : True
Enforce API Maximum Nozzle Sizes : True
Max. Self Supported Roof thickness : 0.5 in.
Max. Tank Corr. Allowance : 0.5 in.
External pressure calcs subtract C.A. per V.5 : False
Use Gauge Material for min thicknesses : False
Enforce API Minimum Live Load : True
Enforce API Minimum Anchor Chair Design Load
= Bolt Yield Load : True
SUMMARY OF DESIGN DATA and REMARKS
Job : JGC
Date of Calcs. : 7/15/2013 , 01:39 PM
Mfg. or Insp. Date : 7/15/2013
Designer : Faizal
Project : Global Toyo
Plant : Marunda
Site : Indonesia
Design Basis : API-653 4th Edition, April 2009,
& API-620 10th Edition, Feb 2002
----------------------------------------------------------------------
- TANK NAMEPLATE INFORMATION
----------------------------------------------------------------------
- Operating Ratio: 0.4
- Design Standard:
- API-620 10th Edition, Feb 2002 -
- API-650 Appendices Used: E -
- Roof : A-285 Gr C: 0.375in. -
- Shell (10): A-283 Gr C: 0.25in. -
- Shell (9): A-36: 0.25in. -
- Shell (8): A-36: 0.25in. -
- Shell (7): A-36: 0.25in. -
- Shell (6): A-36: 0.25in. -
- Shell (5): A-36: 0.25in. -
- Shell (4): A-36: 0.25in. -
- Shell (3): A-36: 0.25in. -
- Shell (2): A-36: 0.25in. -
- Shell (1): A-36: 0.25in. -
- Bottom : A-36: 0.25in. -
- Annular Ring : A-283 Gr C: 0.25in. -
----------------------------------------------------------------------
Design Internal Pressure = 0.142 PSI or 3.94 IN. H2O
Design External Pressure = 0 PSI or 0 IN. H2O
MAWP = 3.0130 PSI or 83.50 IN. H2O
MAWV = 0 PSI or 0 IN. H2O
OD of Tank = 57.1193 ft
Shell Height = 54.0353 ft
S.G. of Contents = 1
Max. Liq. Level = 20 ft
Re-Rate Temperature = 70 °F
Tank Joint Efficiency = 1
Ground Snow Load = 0 lbf/ft^2
Roof Live Load = 20 lbf/ft^2
Design Roof Dead Load = 0 lbf/ft^2
Basic Wind Velocity = 100 mph
Wind Importance Factor = 1
Using Seismic Method: API-650 10th Ed.
Seismic Zone = 1
Site Amplification Factor = 1.5
Importance Factor = 1
DESIGN NOTES
NOTE 1 : There are tank calculation warnings.
Search for * * Warning * * notes.
NOTE 2 : Tank is not subject to API-650 Appendix F.7
SUMMARY OF RESULTS
Shell Material Summary (Bottom is 1)
------------------------------------------------------------------------
Shell Width Material Sts Sca Weight CA
# (ft) (psi) (psi) (lbf) (in)
------------------------------------------------------------------------
Ratio = (t-CA)/R
= (0.25 - 0)/342.7155
= 0.0007
10 5.403 A-283 Gr C 15,200 729 9,886 0
Ratio = (t-CA)/R
= (0.25 - 0)/342.7155
= 0.0007
9 5.403 A-36 16,000 729 9,885 0
Ratio = (t-CA)/R
= (0.25 - 0)/342.7155
= 0.0007
8 5.403 A-36 16,000 729 9,885 0
Ratio = (t-CA)/R
= (0.25 - 0)/342.7155
= 0.0007
7 5.403 A-36 16,000 729 9,885 0
Ratio = (t-CA)/R
= (0.25 - 0)/342.7155
= 0.0007
6 5.403 A-36 16,000 729 9,885 0
Ratio = (t-CA)/R
= (0.25 - 0)/342.7155
= 0.0007
5 5.403 A-36 16,000 729 9,885 0
Ratio = (t-CA)/R
= (0.25 - 0)/342.7155
= 0.0007
4 5.403 A-36 16,000 729 9,885 0
Ratio = (t-CA)/R
= (0.25 - 0)/342.7155
= 0.0007
3 5.403 A-36 16,000 729 9,885 0
Ratio = (t-CA)/R
= (0.25 - 0)/342.7155
= 0.0007
2 5.403 A-36 16,000 729 9,885 0
Ratio = (t-CA)/R
= (0.25 - 0)/342.7155
= 0.0007
1 5.403 A-36 16,000 729 9,885 0
------------------------------------------------------------------------
Total Weight 98,851
Shell API 653 Summary (Bottom is 1)
-----------------------------------------------------------------
Shell t.design(Sd) t.test(St) t.external t.required t.actual
# (in.) (in.) (in.) (in.) (in.)
-----------------------------------------------------------------
10 0.0032 0 0 0.1 0.25
9 0.003 0 0 0.1 0.25
8 0.003 0 0 0.1 0.25
7 0.003 0 0 0.1 0.25
6 0.003 0 0 0.1 0.25
5 0.2462 0 0 0.2462 0.25
4 0.0382 0 0 0.1 0.25
3 0.0883 0 0 0.1 0.25
2 0.1384 0 0 0.1384 0.25
1 0.1885 0 0 0.1885 0.25
-----------------------------------------------------------------
Structurally Supported Conical Roof
Plate Material = A-285 Gr C,
Struct. Material = A-36
t.required = 0.1933 in.
t.actual = 0.375 in.
Roof Joint Efficiency = 0.85
Plate Weight = 39,234 lbf
Rafters:
26 Rafters at Rad. 28.559 ft.: 3 X 3 X 1/4 ANGLE
Rafters Weight = 3,646 lbf
Girders:
Girders Weight = 0 lbf
Columns:
1 Column at Center: 6 INCH SCH 40 PIEP
Columns Weight = 1,005 lbf
Bottom Type: Flat Bottom: Annular
Bottom Floor Material = A-36
t.required = 0.1049 in.
t.actual = 0.25 in.
Bottom Joint Efficiency = 1
Annular Bottom Plate Material : A-283 Gr C
Minimum Annular Ring Thickness = 0.236 in.
t_Annular_Ring = 0.25 in.
Minimum Annular Ring Width = 24 in.
W_Annular_Ring = 24 in.
Total Weight of Bottom = 26,440 lbf
ANCHOR BOLTS: (20) 1in. UNC Bolts, A-307
BOTTOM END STIFFENER: BAR 2x1/4, , 0 lbf
SUPPORTED CONICAL ROOF (from Brownell & Young)
Roof Plate Material: A-285 Gr C, Sd = 16,500 PSI, Fy = 30,000 PSI (API-620 «
Table 5-1)
Structural Material: A-36, Sd = 18,000 PSI, Fy = 36,000 PSI (API-620 Table «
5-3)
R = 28.5596 ft
pt = 0.75 in/ft (Cone Roof Pitch)
Theta = ATAN(pt/12) = ATAN(0.0625) = 3.5763 degrees
Ap_Vert = Vertical Projected Area of Roof
= pt*OD^2/48
= 0.75*57.1193^2/48
= 50.978 ft^2
Horizontal Projected Area of Roof (Per API-650 5.2.1.f)
Xw = Moment Arm of UPLIFT wind force on roof
= 0.5*OD
= 0.5*57.1193
= 28.5596 ft
Ap = Projected Area of roof for wind moment
= PI*R^2
= PI*28.5596^2
= 2,562 ft^2
Dead_Load = Ground_Snow_Load + Added_Dead_Load
= 0 + 0
= 0 lbf/ft^2
P = Design Load
= Snow Load + Live Load + Insulation + Roof Plates + P_external
= 0 + 20 + (8)(0/12) + 15.2982 + (0)(144)
= 35.2982 lbf/ft^2
= 0.2451 PSI
l = Maximum Rafter Spacing (Per API-650 5.10.4.4)
= (t - ca) * SQRT(1.5 * Fy / P)
= (0.375 - 0)*SQRT(1.5*30,000/0.2451)
= 160.67 in.
MINIMUM # OF RAFTERS
< FOR OUTER SHELL RING >
l = 84 in. since calculated l > 84 in. (7 ft)
N_min = 2*PI*R/l = 2*PI*(28.5596)(12)/84 = 25.64
N_min = 26
Actual # of Rafters = 26
Minimum roof thickness based on actual rafter spacing
l = 82.82 in. (actual rafter spacing)
t-Calc = l/SQRT(1.5*Fy/p) + CA
= 82.82/SQRT(1.5*30,000/0.2451) + 0
= 0.1933 in.
NOTE: Governs for roof plate thickness.
RLoad_Max = Maximum Roof Load based on actual rafter spacing
RLoad_Max = 216(Fy)/(l/(t - ca))^2
= 216(30,000)/(82.82/(0.375 - 0))^2
= 177.14 lb/ft^2
Pa_rafter_1 = Max. External Pressure due to rafter ring 1
= (Roof_Plates + Lr + Dead_Load +
Insulation - RLoad_Max) / 144
= (15.3 + 20 + 0 +
0 - 177.14)/144
= -0.985 PSI or -27.30 IN H2O.
t.required Must be >= 0.09 in. (per API-653)
t.required = MAX( 0.09 , t-Calc )
= 0.1933 in.
RAFTER DESIGN
Maximum Rafter Span = 28.56 ft
Average Rafter Spacing on Shell = 6.885 ft
Average Plate Width = (6.885)/2 = 3.443 ft
Mmax = Maximum Bending Moment
Mmax = wl^2/8
where, w = (0.2451)(3.443)*12 + 4.91/12 = 10.54 lbf/in
l = (28.56)(12) = 342.72 in.
Mmax = (10.54)(342.72)^2/8 = 154750. in-lbf
Z req'd = Mmax/18,000 = 154750./18,000 = 8.6 in^3
Actual Z = 0.58 in^3 using 3 X 3 X 1/4 ANGLE
W_Max (Max. stress allowed for each rafter in ring 1)
= Z * Sd * 8 / l^2
= 0.58 * 18,000 * 8 / 342.72^2
= 0.7111 lbf/in.
Max_P (Max. Load allowed for each rafter in ring 1)
= (W_Max - W_Rafter/12)/(Average Plate Width*12)
= (0.7111 - 4.91/12)/(3.443*12)
= 0.0073 PSI
P_max_ext = 0 PSI
(limited by Rafter Type)
* * Warning * * Rafters Inadequate.
* * Warning * * Shell Ring:
Rafter Z Actual = 0.58 in^3,
Rafter Z Req'd = 8.6 in^3
COLUMN DESIGN
CENTER COLUMN
l = Column Length
= 670 in = 55.83 ft (as computed)
r = Radius of gyration
if l/r must be less than 180, then
r req'd = l/180 = 670/180 = 3.72 in.
Actual r = 2.246 in. using 6 INCH SCH 40 PIPE
* * Warning * * Center Column:
Actual r = 2.246 in.,
Req'd r = 3.72 in.
P = Total load supported by center column
= [(rafter length)(rafter load)(# of inner rafters)]/2
= [(28.56 ft)(12 in/ft)(10.54 lbf/in)(26)]/2
= 46,959 lbf
Fa = Allowable Compressive Stress (Per API-620 Table 5-3)
R = L/r = 298.3 (actual)
Fa = 18,000/(1 + R^2/18,000)
= 18,000/(1 + 298.3^2/18,000)
= 3,029 PSI
Fa is not modified Since Design Temp. <= 200 °F.
(API-650 M.3.5 N.A.)
Fa = 3,029 * 1
= 3,029 PSI
A_reqd = P/Fa
= [46,959 + (670/12)(18)]/3,029
= 15.83 in^2
F = actual induced stress for the column
= P/A = [ 46,959 + (670/12)(18) ] / 5.58
= 8,596 PSI
W_Max (Max. weight allowed for each column in ring 1)
= 15,897 lbf
Max_P (Max. Load allowed for each column in ring 1)
P_max_ext = 0 PSI
(limited by Column Type)
Roof_Area = 36*PI*OD^2/COS(Theta)
= 36*PI*(57.1193)^2/COS()
= 369,712 in^2
ROOF WEIGHT
Weight of Roof Plates
= (density)(t)(PI/4)(12*OD - t)^2/COS(Theta)
= (0.2833)(0.375)(PI/4)(685.431 - 0.375)^2/COS(3.5763)
= 39,234 lbf (New)
= 39,234 lbf (Corroded)
Weight of Roof Plates supported by shell
= 39,234 lbf (New)
= 39,234 lbf (Corroded)
Weight of Rafters = 3,646 lbf (New)
Weight of Girders = 0 lbf (New)
Weight of Columns = 1,005 lbf (New)
Total Weight of Roof = 43,885 lbf (New)
= 43,885 lbf (Corroded)
<Actual Participating Area of Roof-to-Shell Juncture>
(From API-620 5.12.4.2 Eqn. 25)
Wc = 0.6 * SQRT[Rc * (t-CA)] (Top Shell Course)
= 0.6 * SQRT[342.4655 * (0.25 - 0)]
= 5.5517 in.
(From API-620 5.12.4.2 Eqn. 24)
Wh = 0.6 * SQRT[R2 * (t-CA)] (Roof Plate)
= 0.6 * SQRT[5,494 * (0.375 - 0)]
= MIN(27.2344, 12)
= 12 in.
Top End Stiffener: NONE
Aa = (Cross-sectional Area of Top End Stiffener)
= 0 in^2
Ashell = Contributing Area due to shell plates
= Wc*(t_shell - CA)
= 5.5517 * (0.25 - 0)
= 1.388 in^2
Aroof = Contributing Area due to roof plates
= Wh*(t_roof - CA)
= 12 * (0.375 - 0)
= 4.5 in^2
A = Actual Part. Area of Roof-to-Shell Juncture (per API-620)
= Aa + Aroof + Ashell
= 0 + 4.5 + 1.388
= 5.888 in^2
W/At = (-39,234 / 368,992)
= -0.1063 PSI
<Meridional and Latitudinal Forces>
T1 = R3/[2*COS(Alpha)]*(P + W/At)
= 342.7155/[2*COS(86.4237)]*(0 + -0.1063)
= -292.01 lbf/in
T2 = R3/COS(Alpha)*(P + W/At)
= 342.7155/COS(86.4237)*(0 + -0.1063)
= -584.03 lbf/in
Sts = 16,500 PSI (Allowable Tensile Stress per API-620 Table 5-1)
<Minimum Participating Area>
T2s = P*R3 = (0)(342.7155) = 0 lbf/in
Q = (T2)(Wh) + (T2s)(Wc) - (T1)(Rc)(SIN(Alpha))
= (-584.03)(12)+(0)(5.5517)-(-292.01)(342.4655)(SIN(86.4237))
= 92,800 lbf
A_min = Minimum Participating Area ( per API-620 5.12.4.3 Eq. 27)
= Q/Sts
= 92,800/16,500
= 5.624 in^2
P_max_external = 0 PSI or 0 IN. H2O
SHELL COURSE RE-RATING (Bottom Course is #1)
Course # 1; Material: A-36; Width = 5.4035ft
< API-620 >
R = R2 = Rc = 342.7155 in.
At = 368,992 in^2
< Internal Pressure - Full >
W = - (shell) = -98,891 lbf
W/At = (-98,891 / 368,992)
= -0.268 PSI
Px = P + P_liquid = 0.142 + 8.66 = 8.802 PSI
<Meridional and Latitudinal Forces>
T1 = Rc/2*(P + W/At)
= 342.7155/2*(8.802 + -0.268)
= 1,462 lbf/in
T2 = P*Rc
= 8.802*342.7155
= 3,017 lbf/in
< API-620 >
Minimum thickness (t) requirement:
(Per 5.10.3.2)
T = MAX(T1, T2) = 3,017 lb./in.
Sts = 16,000 PSI (Allowable Tensile Stress per API-620 Table 5-1)
t-Calc = T/(Sts*E) + CA = 3,017/(16,000*1) + 0 = 0.1885 in.
t-Calc = 0.1885 in.
Since t.actual > T620,
Back-Calculating Pmax using t.actual as target, and T620 routine...
Entry Condition: P_x = 8.803, t-620 = 0.1886
Exit Condition: P_x = 11.673, t-620 = 0.25
P_shell_int = 3.013 PSI (due to Shell Course, without Liquid Head)
< External Pressure - Empty >
W = - (shell) = -98,891 lbf
W/At = (-98,891 / 368,992)
= -0.268 PSI
PV = 0 PSI
<Meridional and Latitudinal Forces>
T1 = Rc/2*(P + W/At)
= 342.7155/2*(0 + -0.268)
= -45.92 lbf/in
T2 = P*Rc
= 0*342.7155
= 0 lbf/in
< API-620 >
Minimum thickness (t) requirement:
Tp = MAX(ABS(T1),ABS(T2))
= 45.9 lb/in.
Tpp = MIN(ABS(T1),ABS(T2))
= 0 lb/in.
Rp = R2 = 342.7155 in.
Rpp = R1 = 342.7155 in.
t_18 = SQRT[(Tp + 0.8*Tpp)*Rp]/1342 + CA
= 0.0935 in.
t_19 = SQRT[Tpp*Rpp]/1000 + CA
= 0 in.
(t_18 - CA)/Rp = 0.0003
(t_19 - CA)/Rpp = 0
t-Calc = MAX(t_18,t_19)
Ratio = (t-CA)/R
= (0.25 - 0)/342.7155
= 0.0007
Sca = 10^6*Ratio (Per 5.5.4.3)
= 729 PSI (Allowable Compressive Stress)
t-Calc = 0.0935 in.
Since t.actual > T620,
Back-Calculating Pmax using t-Calc as target, and T620 routine...
Entry Condition: V_x = 0 PSI, t-620 = 0.0935
Exit Condition: V_x = -0.608, t-620 = 0.25
P_shell_ext = -0.608 PSI (due to Shell Course)
Course # 2; Material: A-36; Width = 5.4035ft
< API-620 >
R = R2 = Rc = 342.7155 in.
At = 368,992 in^2
< Internal Pressure - Full >
W = - (shell) = -89,002 lbf
W/At = (-89,002 / 368,992)
= -0.2412 PSI
Px = P + P_liquid = 0.142 + 6.3203 = 6.4623 PSI
<Meridional and Latitudinal Forces>
T1 = Rc/2*(P + W/At)
= 342.7155/2*(6.4623 + -0.2412)
= 1,066 lbf/in
T2 = P*Rc
= 6.4623*342.7155
= 2,215 lbf/in
< API-620 >
Minimum thickness (t) requirement:
(Per 5.10.3.2)
T = MAX(T1, T2) = 2,215 lb./in.
Sts = 16,000 PSI (Allowable Tensile Stress per API-620 Table 5-1)
t-Calc = T/(Sts*E) + CA = 2,215/(16,000*1) + 0 = 0.1384 in.
t-Calc = 0.1384 in.
Since t.actual > T620,
Back-Calculating Pmax using t.actual as target, and T620 routine...
Entry Condition: P_x = 6.4633, t-620 = 0.1384
Exit Condition: P_x = 11.673, t-620 = 0.25
P_shell_int = 5.3527 PSI (due to Shell Course, without Liquid Head)
< External Pressure - Empty >
W = - (shell) = -89,002 lbf
W/At = (-89,002 / 368,992)
= -0.2412 PSI
PV = 0 PSI
<Meridional and Latitudinal Forces>
T1 = Rc/2*(P + W/At)
= 342.7155/2*(0 + -0.2412)
= -41.33 lbf/in
T2 = P*Rc
= 0*342.7155
= 0 lbf/in
< API-620 >
Minimum thickness (t) requirement:
Tp = MAX(ABS(T1),ABS(T2))
= 41.3 lb/in.
Tpp = MIN(ABS(T1),ABS(T2))
= 0 lb/in.
Rp = R2 = 342.7155 in.
Rpp = R1 = 342.7155 in.
t_18 = SQRT[(Tp + 0.8*Tpp)*Rp]/1342 + CA
= 0.0887 in.
t_19 = SQRT[Tpp*Rpp]/1000 + CA
= 0 in.
(t_18 - CA)/Rp = 0.0003
(t_19 - CA)/Rpp = 0
t-Calc = MAX(t_18,t_19)
Ratio = (t-CA)/R
= (0.25 - 0)/342.7155
= 0.0007
Sca = 10^6*Ratio (Per 5.5.4.3)
= 729 PSI (Allowable Compressive Stress)
t-Calc = 0.0887 in.
Since t.actual > T620,
Back-Calculating Pmax using t-Calc as target, and T620 routine...
Entry Condition: V_x = 0 PSI, t-620 = 0.0887
Exit Condition: V_x = -0.615, t-620 = 0.2499
P_shell_ext = -0.615 PSI (due to Shell Course)
Course # 3; Material: A-36; Width = 5.4035ft
< API-620 >
R = R2 = Rc = 342.7155 in.
At = 368,992 in^2
< Internal Pressure - Full >
W = - (shell) = -79,113 lbf
W/At = (-79,113 / 368,992)
= -0.2144 PSI
Px = P + P_liquid = 0.142 + 3.9806 = 4.1226 PSI
<Meridional and Latitudinal Forces>
T1 = Rc/2*(P + W/At)
= 342.7155/2*(4.1226 + -0.2144)
= 669.7 lbf/in
T2 = P*Rc
= 4.1226*342.7155
= 1,413 lbf/in
< API-620 >
Minimum thickness (t) requirement:
(Per 5.10.3.2)
T = MAX(T1, T2) = 1,413 lb./in.
Sts = 16,000 PSI (Allowable Tensile Stress per API-620 Table 5-1)
t-Calc = T/(Sts*E) + CA = 1,413/(16,000*1) + 0 = 0.0883 in.
t-Calc = 0.0883 in.
Since t.actual > T620,
Back-Calculating Pmax using t.actual as target, and T620 routine...
Entry Condition: P_x = 4.1236, t-620 = 0.0883
Exit Condition: P_x = 11.673, t-620 = 0.25
P_shell_int = 7.6924 PSI (due to Shell Course, without Liquid Head)
< External Pressure - Empty >
W = - (shell) = -79,113 lbf
W/At = (-79,113 / 368,992)
= -0.2144 PSI
PV = 0 PSI
<Meridional and Latitudinal Forces>
T1 = Rc/2*(P + W/At)
= 342.7155/2*(0 + -0.2144)
= -36.74 lbf/in
T2 = P*Rc
= 0*342.7155
= 0 lbf/in
< API-620 >
Minimum thickness (t) requirement:
Tp = MAX(ABS(T1),ABS(T2))
= 36.7 lb/in.
Tpp = MIN(ABS(T1),ABS(T2))
= 0 lb/in.
Rp = R2 = 342.7155 in.
Rpp = R1 = 342.7155 in.
t_18 = SQRT[(Tp + 0.8*Tpp)*Rp]/1342 + CA
= 0.0836 in.
t_19 = SQRT[Tpp*Rpp]/1000 + CA
= 0 in.
(t_18 - CA)/Rp = 0.0002
(t_19 - CA)/Rpp = 0
t-Calc = MAX(t_18,t_19)
Ratio = (t-CA)/R
= (0.25 - 0)/342.7155
= 0.0007
Sca = 10^6*Ratio (Per 5.5.4.3)
= 729 PSI (Allowable Compressive Stress)
t-Calc = 0.0836 in.
Since t.actual > T620,
Back-Calculating Pmax using t-Calc as target, and T620 routine...
Entry Condition: V_x = 0 PSI, t-620 = 0.0836
Exit Condition: V_x = -0.623, t-620 = 0.2499
P_shell_ext = -0.623 PSI (due to Shell Course)
Course # 4; Material: A-36; Width = 5.4035ft
< API-620 >
R = R2 = Rc = 342.7155 in.
At = 368,992 in^2
< Internal Pressure - Full >
W = - (shell) = -69,224 lbf
W/At = (-69,224 / 368,992)
= -0.1876 PSI
Px = P + P_liquid = 0.142 + 1.6409 = 1.7829 PSI
<Meridional and Latitudinal Forces>
T1 = Rc/2*(P + W/At)
= 342.7155/2*(1.7829 + -0.1876)
= 273.37 lbf/in
T2 = P*Rc
= 1.7829*342.7155
= 611.03 lbf/in
< API-620 >
Minimum thickness (t) requirement:
(Per 5.10.3.2)
T = MAX(T1, T2) = 611 lb./in.
Sts = 16,000 PSI (Allowable Tensile Stress per API-620 Table 5-1)
t-Calc = T/(Sts*E) + CA = 611/(16,000*1) + 0 = 0.0382 in.
t-Calc = 0.0382 in.
Since t.actual > T620,
Back-Calculating Pmax using t.actual as target, and T620 routine...
Entry Condition: P_x = 1.7839, t-620 = 0.0382
Exit Condition: P_x = 11.673, t-620 = 0.25
P_shell_int = 10.0321 PSI (due to Shell Course, without Liquid Head)
< External Pressure - Empty >
W = - (shell) = -69,224 lbf
W/At = (-69,224 / 368,992)
= -0.1876 PSI
PV = 0 PSI
<Meridional and Latitudinal Forces>
T1 = Rc/2*(P + W/At)
= 342.7155/2*(0 + -0.1876)
= -32.15 lbf/in
T2 = P*Rc
= 0*342.7155
= 0 lbf/in
< API-620 >
Minimum thickness (t) requirement:
Tp = MAX(ABS(T1),ABS(T2))
= 32.2 lb/in.
Tpp = MIN(ABS(T1),ABS(T2))
= 0 lb/in.
Rp = R2 = 342.7155 in.
Rpp = R1 = 342.7155 in.
t_18 = SQRT[(Tp + 0.8*Tpp)*Rp]/1342 + CA
= 0.0783 in.
t_19 = SQRT[Tpp*Rpp]/1000 + CA
= 0 in.
(t_18 - CA)/Rp = 0.0002
(t_19 - CA)/Rpp = 0
t-Calc = MAX(t_18,t_19)
Ratio = (t-CA)/R
= (0.25 - 0)/342.7155
= 0.0007
Sca = 10^6*Ratio (Per 5.5.4.3)
= 729 PSI (Allowable Compressive Stress)
t-Calc = 0.0783 in.
Since t.actual > T620,
Back-Calculating Pmax using t-Calc as target, and T620 routine...
Entry Condition: V_x = 0 PSI, t-620 = 0.0783
Exit Condition: V_x = -0.631, t-620 = 0.25
P_shell_ext = -0.631 PSI (due to Shell Course)
Course # 5; Material: A-36; Width = 5.4035ft
< API-620 >
R = R2 = Rc = 342.7155 in.
At = 368,992 in^2
< Internal Pressure - Full >
W = - (shell) = -59,335 lbf
W/At = (-59,335 / 368,992)
= -0.1608 PSI
Px = P + P_liquid = 0.142 + 0 = 0.142 PSI
<Meridional and Latitudinal Forces>
T1 = Rc/2*(P + W/At)
= 342.7155/2*(0.142 + -0.1608)
= -3.22 lbf/in
T2 = P*Rc
= 0.142*342.7155
= 48.67 lbf/in
< API-620 >
Minimum thickness (t) requirement:
(Per 5.10.3.3)
T_tens = 48.7 (Tension Load),
Sts = 16,000 PSI (Allowable Tensile Stress per API-620 Table 5-1)
N = 0.9995 (N from API-620 Fig. 5-1)
Sta = Sts*N = (16,000)(0.9995) = 15,992 PSI
tmin1 = T_tens / (Sta*E) + CA
= 48.7/(15,992*1) + 0 = 0.003 in.
T_comp = 3.2 (Compressive Load),
N = 0.0122 (actual N, using compressive stress)
M = 0.9939 (calculated M from API-620 Fig. F-1)
Sca = T_comp / M = 13 PSI
tmin2 = T_comp / Sca + CA = 3.2/13 + 0 = 0.2462 in.
t-Calc = MAX(tmin1, tmin2) = 0.2462 in.
t-Calc = 0.2462 in.
Since t.actual > T620,
Back-Calculating Pmax using t.actual as target, and T620 routine...
Entry Condition: P_x = 0.1618, t-620 = 0.0035
Exit Condition: P_x = 11.673, t-620 = 0.25
P_shell_int = 11.673 PSI (due to Shell Course)
< External Pressure - Empty >
W = - (shell) = -59,335 lbf
W/At = (-59,335 / 368,992)
= -0.1608 PSI
PV = 0 PSI
<Meridional and Latitudinal Forces>
T1 = Rc/2*(P + W/At)
= 342.7155/2*(0 + -0.1608)
= -27.55 lbf/in
T2 = P*Rc
= 0*342.7155
= 0 lbf/in
< API-620 >
Minimum thickness (t) requirement:
Tp = MAX(ABS(T1),ABS(T2))
= 27.6 lb/in.
Tpp = MIN(ABS(T1),ABS(T2))
= 0 lb/in.
Rp = R2 = 342.7155 in.
Rpp = R1 = 342.7155 in.
t_18 = SQRT[(Tp + 0.8*Tpp)*Rp]/1342 + CA
= 0.0725 in.
t_19 = SQRT[Tpp*Rpp]/1000 + CA
= 0 in.
(t_18 - CA)/Rp = 0.0002
(t_19 - CA)/Rpp = 0
t-Calc = MAX(t_18,t_19)
Ratio = (t-CA)/R
= (0.25 - 0)/342.7155
= 0.0007
Sca = 10^6*Ratio (Per 5.5.4.3)
= 729 PSI (Allowable Compressive Stress)
t-Calc = 0.0725 in.
Since t.actual > T620,
Back-Calculating Pmax using t-Calc as target, and T620 routine...
Entry Condition: V_x = 0 PSI, t-620 = 0.0725
Exit Condition: V_x = -0.638, t-620 = 0.2499
P_shell_ext = -0.638 PSI (due to Shell Course)
Course # 6; Material: A-36; Width = 5.4035ft
< API-620 >
R = R2 = Rc = 342.7155 in.
At = 368,992 in^2
< Internal Pressure - Full >
W = - (shell) = -49,446 lbf
W/At = (-49,446 / 368,992)
= -0.134 PSI
Px = P + P_liquid = 0.142 + 0 = 0.142 PSI
<Meridional and Latitudinal Forces>
T1 = Rc/2*(P + W/At)
= 342.7155/2*(0.142 + -0.134)
= 1.37 lbf/in
T2 = P*Rc
= 0.142*342.7155
= 48.67 lbf/in
< API-620 >
Minimum thickness (t) requirement:
(Per 5.10.3.2)
T = MAX(T1, T2) = 48.7 lb./in.
Sts = 16,000 PSI (Allowable Tensile Stress per API-620 Table 5-1)
t-Calc = T/(Sts*E) + CA = 48.7/(16,000*1) + 0 = 0.003 in.
t-Calc = 0.003 in.
Since t.actual > T620,
Back-Calculating Pmax using t.actual as target, and T620 routine...
Entry Condition: P_x = 0.143, t-620 = 0.0031
Exit Condition: P_x = 11.673, t-620 = 0.25
P_shell_int = 11.673 PSI (due to Shell Course)
< External Pressure - Empty >
W = - (shell) = -49,446 lbf
W/At = (-49,446 / 368,992)
= -0.134 PSI
PV = 0 PSI
<Meridional and Latitudinal Forces>
T1 = Rc/2*(P + W/At)
= 342.7155/2*(0 + -0.134)
= -22.96 lbf/in
T2 = P*Rc
= 0*342.7155
= 0 lbf/in
< API-620 >
Minimum thickness (t) requirement:
Tp = MAX(ABS(T1),ABS(T2))
= 23 lb/in.
Tpp = MIN(ABS(T1),ABS(T2))
= 0 lb/in.
Rp = R2 = 342.7155 in.
Rpp = R1 = 342.7155 in.
t_18 = SQRT[(Tp + 0.8*Tpp)*Rp]/1342 + CA
= 0.0662 in.
t_19 = SQRT[Tpp*Rpp]/1000 + CA
= 0 in.
(t_18 - CA)/Rp = 0.0002
(t_19 - CA)/Rpp = 0
t-Calc = MAX(t_18,t_19)
Ratio = (t-CA)/R
= (0.25 - 0)/342.7155
= 0.0007
Sca = 10^6*Ratio (Per 5.5.4.3)
= 729 PSI (Allowable Compressive Stress)
t-Calc = 0.0662 in.
Since t.actual > T620,
Back-Calculating Pmax using t-Calc as target, and T620 routine...
Entry Condition: V_x = 0 PSI, t-620 = 0.0662
Exit Condition: V_x = -0.646, t-620 = 0.25
P_shell_ext = -0.646 PSI (due to Shell Course)
Course # 7; Material: A-36; Width = 5.4035ft
< API-620 >
R = R2 = Rc = 342.7155 in.
At = 368,992 in^2
< Internal Pressure - Full >
W = - (shell) = -39,557 lbf
W/At = (-39,557 / 368,992)
= -0.1072 PSI
Px = P + P_liquid = 0.142 + 0 = 0.142 PSI
<Meridional and Latitudinal Forces>
T1 = Rc/2*(P + W/At)
= 342.7155/2*(0.142 + -0.1072)
= 5.96 lbf/in
T2 = P*Rc
= 0.142*342.7155
= 48.67 lbf/in
< API-620 >
Minimum thickness (t) requirement:
(Per 5.10.3.2)
T = MAX(T1, T2) = 48.7 lb./in.
Sts = 16,000 PSI (Allowable Tensile Stress per API-620 Table 5-1)
t-Calc = T/(Sts*E) + CA = 48.7/(16,000*1) + 0 = 0.003 in.
t-Calc = 0.003 in.
Since t.actual > T620,
Back-Calculating Pmax using t.actual as target, and T620 routine...
Entry Condition: P_x = 0.143, t-620 = 0.0031
Exit Condition: P_x = 11.673, t-620 = 0.25
P_shell_int = 11.673 PSI (due to Shell Course)
< External Pressure - Empty >
W = - (shell) = -39,557 lbf
W/At = (-39,557 / 368,992)
= -0.1072 PSI
PV = 0 PSI
<Meridional and Latitudinal Forces>
T1 = Rc/2*(P + W/At)
= 342.7155/2*(0 + -0.1072)
= -18.37 lbf/in
T2 = P*Rc
= 0*342.7155
= 0 lbf/in
< API-620 >
Minimum thickness (t) requirement:
Tp = MAX(ABS(T1),ABS(T2))
= 18.4 lb/in.
Tpp = MIN(ABS(T1),ABS(T2))
= 0 lb/in.
Rp = R2 = 342.7155 in.
Rpp = R1 = 342.7155 in.
t_18 = SQRT[(Tp + 0.8*Tpp)*Rp]/1342 + CA
= 0.0592 in.
t_19 = SQRT[Tpp*Rpp]/1000 + CA
= 0 in.
(t_18 - CA)/Rp = 0.0002
(t_19 - CA)/Rpp = 0
t-Calc = MAX(t_18,t_19)
Ratio = (t-CA)/R
= (0.25 - 0)/342.7155
= 0.0007
Sca = 10^6*Ratio (Per 5.5.4.3)
= 729 PSI (Allowable Compressive Stress)
t-Calc = 0.0592 in.
Since t.actual > T620,
Back-Calculating Pmax using t-Calc as target, and T620 routine...
Entry Condition: V_x = 0 PSI, t-620 = 0.0592
Exit Condition: V_x = -0.654, t-620 = 0.25
P_shell_ext = -0.654 PSI (due to Shell Course)
Course # 8; Material: A-36; Width = 5.4035ft
< API-620 >
R = R2 = Rc = 342.7155 in.
At = 368,992 in^2
< Internal Pressure - Full >
W = - (shell) = -29,668 lbf
W/At = (-29,668 / 368,992)
= -0.0804 PSI
Px = P + P_liquid = 0.142 + 0 = 0.142 PSI
<Meridional and Latitudinal Forces>
T1 = Rc/2*(P + W/At)
= 342.7155/2*(0.142 + -0.0804)
= 10.56 lbf/in
T2 = P*Rc
= 0.142*342.7155
= 48.67 lbf/in
< API-620 >
Minimum thickness (t) requirement:
(Per 5.10.3.2)
T = MAX(T1, T2) = 48.7 lb./in.
Sts = 16,000 PSI (Allowable Tensile Stress per API-620 Table 5-1)
t-Calc = T/(Sts*E) + CA = 48.7/(16,000*1) + 0 = 0.003 in.
t-Calc = 0.003 in.
Since t.actual > T620,
Back-Calculating Pmax using t.actual as target, and T620 routine...
Entry Condition: P_x = 0.143, t-620 = 0.0031
Exit Condition: P_x = 11.673, t-620 = 0.25
P_shell_int = 11.673 PSI (due to Shell Course)
< External Pressure - Empty >
W = - (shell) = -29,668 lbf
W/At = (-29,668 / 368,992)
= -0.0804 PSI
PV = 0 PSI
<Meridional and Latitudinal Forces>
T1 = Rc/2*(P + W/At)
= 342.7155/2*(0 + -0.0804)
= -13.78 lbf/in
T2 = P*Rc
= 0*342.7155
= 0 lbf/in
< API-620 >
Minimum thickness (t) requirement:
Tp = MAX(ABS(T1),ABS(T2))
= 13.8 lb/in.
Tpp = MIN(ABS(T1),ABS(T2))
= 0 lb/in.
Rp = R2 = 342.7155 in.
Rpp = R1 = 342.7155 in.
t_18 = SQRT[(Tp + 0.8*Tpp)*Rp]/1342 + CA
= 0.0512 in.
t_19 = SQRT[Tpp*Rpp]/1000 + CA
= 0 in.
(t_18 - CA)/Rp = 0.0001
(t_19 - CA)/Rpp = 0
t-Calc = MAX(t_18,t_19)
Ratio = (t-CA)/R
= (0.25 - 0)/342.7155
= 0.0007
Sca = 10^6*Ratio (Per 5.5.4.3)
= 729 PSI (Allowable Compressive Stress)
t-Calc = 0.0512 in.
Since t.actual > T620,
Back-Calculating Pmax using t-Calc as target, and T620 routine...
Entry Condition: V_x = 0 PSI, t-620 = 0.0512
Exit Condition: V_x = -0.661, t-620 = 0.2499
P_shell_ext = -0.661 PSI (due to Shell Course)
Course # 9; Material: A-36; Width = 5.4035ft
< API-620 >
R = R2 = Rc = 342.7155 in.
At = 368,992 in^2
< Internal Pressure - Full >
W = - (shell) = -19,779 lbf
W/At = (-19,779 / 368,992)
= -0.0536 PSI
Px = P + P_liquid = 0.142 + 0 = 0.142 PSI
<Meridional and Latitudinal Forces>
T1 = Rc/2*(P + W/At)
= 342.7155/2*(0.142 + -0.0536)
= 15.15 lbf/in
T2 = P*Rc
= 0.142*342.7155
= 48.67 lbf/in
< API-620 >
Minimum thickness (t) requirement:
(Per 5.10.3.2)
T = MAX(T1, T2) = 48.7 lb./in.
Sts = 16,000 PSI (Allowable Tensile Stress per API-620 Table 5-1)
t-Calc = T/(Sts*E) + CA = 48.7/(16,000*1) + 0 = 0.003 in.
t-Calc = 0.003 in.
Since t.actual > T620,
Back-Calculating Pmax using t.actual as target, and T620 routine...
Entry Condition: P_x = 0.143, t-620 = 0.0031
Exit Condition: P_x = 11.673, t-620 = 0.25
P_shell_int = 11.673 PSI (due to Shell Course)
< External Pressure - Empty >
W = - (shell) = -19,779 lbf
W/At = (-19,779 / 368,992)
= -0.0536 PSI
PV = 0 PSI
<Meridional and Latitudinal Forces>
T1 = Rc/2*(P + W/At)
= 342.7155/2*(0 + -0.0536)
= -9.18 lbf/in
T2 = P*Rc
= 0*342.7155
= 0 lbf/in
< API-620 >
Minimum thickness (t) requirement:
Tp = MAX(ABS(T1),ABS(T2))
= 9.2 lb/in.
Tpp = MIN(ABS(T1),ABS(T2))
= 0 lb/in.
Rp = R2 = 342.7155 in.
Rpp = R1 = 342.7155 in.
t_18 = SQRT[(Tp + 0.8*Tpp)*Rp]/1342 + CA
= 0.0418 in.
t_19 = SQRT[Tpp*Rpp]/1000 + CA
= 0 in.
(t_18 - CA)/Rp = 0.0001
(t_19 - CA)/Rpp = 0
t-Calc = MAX(t_18,t_19)
Ratio = (t-CA)/R
= (0.25 - 0)/342.7155
= 0.0007
Sca = 10^6*Ratio (Per 5.5.4.3)
= 729 PSI (Allowable Compressive Stress)
t-Calc = 0.0418 in.
Since t.actual > T620,
Back-Calculating Pmax using t-Calc as target, and T620 routine...
Entry Condition: V_x = 0 PSI, t-620 = 0.0418
Exit Condition: V_x = -0.669, t-620 = 0.25
P_shell_ext = -0.669 PSI (due to Shell Course)
Course # 10; Material: A-283 Gr C; Width = 5.4038ft
< API-620 >
R = R2 = Rc = 342.7155 in.
At = 368,992 in^2
< Internal Pressure - Full >
W = - (shell) = -9,890 lbf
W/At = (-9,890 / 368,992)
= -0.0268 PSI
Px = P + P_liquid = 0.142 + 0 = 0.142 PSI
<Meridional and Latitudinal Forces>
T1 = Rc/2*(P + W/At)
= 342.7155/2*(0.142 + -0.0268)
= 19.74 lbf/in
T2 = P*Rc
= 0.142*342.7155
= 48.67 lbf/in
< API-620 >
Minimum thickness (t) requirement:
(Per 5.10.3.2)
T = MAX(T1, T2) = 48.7 lb./in.
Sts = 15,200 PSI (Allowable Tensile Stress per API-620 Table 5-1)
t-Calc = T/(Sts*E) + CA = 48.7/(15,200*1) + 0 = 0.0032 in.
t-Calc = 0.0032 in.
Since t.actual > T620,
Back-Calculating Pmax using t.actual as target, and T620 routine...
Entry Condition: P_x = 0.143, t-620 = 0.0032
Exit Condition: P_x = 11.086, t-620 = 0.25
P_shell_int = 11.086 PSI (due to Shell Course)
< External Pressure - Empty >
W = - (shell) = -9,890 lbf
W/At = (-9,890 / 368,992)
= -0.0268 PSI
PV = 0 PSI
<Meridional and Latitudinal Forces>
T1 = Rc/2*(P + W/At)
= 342.7155/2*(0 + -0.0268)
= -4.59 lbf/in
T2 = P*Rc
= 0*342.7155
= 0 lbf/in
< API-620 >
Minimum thickness (t) requirement:
Tp = MAX(ABS(T1),ABS(T2))
= 4.6 lb/in.
Tpp = MIN(ABS(T1),ABS(T2))
= 0 lb/in.
Rp = R2 = 342.7155 in.
Rpp = R1 = 342.7155 in.
t_18 = SQRT[(Tp + 0.8*Tpp)*Rp]/1342 + CA
= 0.0296 in.
t_19 = SQRT[Tpp*Rpp]/1000 + CA
= 0 in.
(t_18 - CA)/Rp = 0.0000864
(t_19 - CA)/Rpp = 0
t-Calc = MAX(t_18,t_19)
Ratio = (t-CA)/R
= (0.25 - 0)/342.7155
= 0.0007
Sca = 10^6*Ratio (Per 5.5.4.3)
= 729 PSI (Allowable Compressive Stress)
t-Calc = 0.0296 in.
Since t.actual > T620,
Back-Calculating Pmax using t-Calc as target, and T620 routine...
Entry Condition: V_x = 0 PSI, t-620 = 0.0296
Exit Condition: V_x = -0.677, t-620 = 0.25
P_shell_ext = -0.677 PSI (due to Shell Course)
Wtr = Transposed Width of each Shell Course
= Width*[ t_thinnest / t_course ]^2.5
Transforming Courses (1) to (10)
Wtr(1) = 5.4035*[ 0.25/0.25 ]^2.5 = 5.4035 ft
Wtr(2) = 5.4035*[ 0.25/0.25 ]^2.5 = 5.4035 ft
Wtr(3) = 5.4035*[ 0.25/0.25 ]^2.5 = 5.4035 ft
Wtr(4) = 5.4035*[ 0.25/0.25 ]^2.5 = 5.4035 ft
Wtr(5) = 5.4035*[ 0.25/0.25 ]^2.5 = 5.4035 ft
Wtr(6) = 5.4035*[ 0.25/0.25 ]^2.5 = 5.4035 ft
Wtr(7) = 5.4035*[ 0.25/0.25 ]^2.5 = 5.4035 ft
Wtr(8) = 5.4035*[ 0.25/0.25 ]^2.5 = 5.4035 ft
Wtr(9) = 5.4035*[ 0.25/0.25 ]^2.5 = 5.4035 ft
Wtr(10) = 5.4038*[ 0.25/0.25 ]^2.5 = 5.4038 ft
Hts (Height of the Transformed Shell)
= SUM{Wtr} = 54.0353 ft
INTERMEDIATE WIND GIRDERS (API 620 Section 5.10.6)
V (Wind Speed) = 100 mph
Ve = vf = Velocity Factor = (vs/100)^2 = (100/100)^2 = 1
Re-Rate PV = 0 PSI, OR 0 In. H2O
<TOP END STIFFENER CALCULATIONS>
Z = Required Top Comp Ring Section Modulus (per API-650 5.1.5.9.e)
= 0.35 in^3,
For Structural Roof and OD <= 60 ft,
Minimum Required Angle is 2 x 2 x 1/4 in.
<INTERMEDIATE STIFFENER CALCULATIONS> (PER API-620 Section 5.10.6)
* * * NOTE: Using the thinnest shell course, t_thinnest,
instead of top shell course.
* * * NOTE: Not subtracting corrosion allowance per user setting.
ME = 28,799,999/28,799,999
= 1
Hu = Maximum Height of Unstiffened Shell
= {ME*600,000*t_thinnest*SQRT[t_thinnest/OD]^3} / Ve)
= {1*600,000*0.25*SQRT[0.25/57.1193]^3} / 1
= 43.4338 ft
Wtr = Transposed Width of each Shell Course
= Width*[ t_thinnest / t_course ]^2.5
Transforming Courses (1) to (10)
Wtr(1) = 5.4035*[ 0.25/0.25 ]^2.5 = 5.4035 ft
Wtr(2) = 5.4035*[ 0.25/0.25 ]^2.5 = 5.4035 ft
Wtr(3) = 5.4035*[ 0.25/0.25 ]^2.5 = 5.4035 ft
Wtr(4) = 5.4035*[ 0.25/0.25 ]^2.5 = 5.4035 ft
Wtr(5) = 5.4035*[ 0.25/0.25 ]^2.5 = 5.4035 ft
Wtr(6) = 5.4035*[ 0.25/0.25 ]^2.5 = 5.4035 ft
Wtr(7) = 5.4035*[ 0.25/0.25 ]^2.5 = 5.4035 ft
Wtr(8) = 5.4035*[ 0.25/0.25 ]^2.5 = 5.4035 ft
Wtr(9) = 5.4035*[ 0.25/0.25 ]^2.5 = 5.4035 ft
Wtr(10) = 5.4038*[ 0.25/0.25 ]^2.5 = 5.4038 ft
Hts (Height of the Transformed Shell)
= SUM{Wtr} = 54.0353 ft
L_0 = Hts/# of Stiffeners + 1
= 54.0353/1 = 54.04 ft.
Req'd Number of Intermediate Wind Girders = 1, Rounded to 1
Actual Number of Intermediate Wind Girders = 0
Zi (Req. Wind Gird. Z)
= (0.0001)(Ve)(L0)(OD^2)
= (0.0001)(1)(54.04)(57.1193^2) = 17.63 in^3
Actual Zi = 0 (No Wind Girder Selected, but One Required)
Parameter Still Required: Int Wind Girder Type,
since Required Number of Int. Wind Girders > 0.
SHELL COURSE #1 SUMMARY
-------------------------------------------
t-Calc = MAX(t-Calc_620, t_min_ext, t.seismic)
= MAX(0.1885, 0, 0)
= 0.1885 in.
Course Minimum t shall not be less than 0.1" + CA
(per API-653 Section 4.3.3.1)
t-653min = 0.1 in.
t.required = MAX(t.design, t.min653)
= MAX(0.1885,0.1) = 0.1885 in.
< API-653 4.3.2.1 >
t1 (lowest average thickness in the shell course)
t1 must be >= t.required = 0.1885 in.
t2 (least min. thickness in an area of shell course)
t2 must be >= 0.6*(t.required - CA) + CA = 0.113100 in.
t.actual = 0.25 in.
Weight = Density*PI*[(12*OD) - t]*12*Width*t
= 0.2833*PI*[(12*57.1193)-0.25]*12*5.4035*0.25
= 9,885 lbf (New)
= 9,885 lbf (Corroded)
SHELL COURSE #2 SUMMARY
-------------------------------------------
t-Calc = MAX(t-Calc_620, t_min_ext, t.seismic)
= MAX(0.1384, 0, 0)
= 0.1384 in.
Course Minimum t shall not be less than 0.1" + CA
(per API-653 Section 4.3.3.1)
t-653min = 0.1 in.
t.required = MAX(t.design, t.min653)
= MAX(0.1384,0.1) = 0.1384 in.
< API-653 4.3.2.1 >
t1 (lowest average thickness in the shell course)
t1 must be >= t.required = 0.1384 in.
t2 (least min. thickness in an area of shell course)
t2 must be >= 0.6*(t.required - CA) + CA = 0.083040 in.
t.actual = 0.25 in.
Weight = Density*PI*[(12*OD) - t]*12*Width*t
= 0.2833*PI*[(12*57.1193)-0.25]*12*5.4035*0.25
= 9,885 lbf (New)
= 9,885 lbf (Corroded)
SHELL COURSE #3 SUMMARY
-------------------------------------------
t-Calc = MAX(t-Calc_620, t_min_ext, t.seismic)
= MAX(0.0883, 0, 0)
= 0.0883 in.
Course Minimum t shall not be less than 0.1" + CA
(per API-653 Section 4.3.3.1)
t-653min = 0.1 in.
t.required = MAX(t.design, t.min653)
= MAX(0.0883,0.1) = 0.1 in.
< API-653 4.3.2.1 >
t1 (lowest average thickness in the shell course)
t1 must be >= t.required = 0.1 in.
t2 (least min. thickness in an area of shell course)
t2 must be >= 0.6*(t.required - CA) + CA = 0.060000 in.
t.actual = 0.25 in.
Weight = Density*PI*[(12*OD) - t]*12*Width*t
= 0.2833*PI*[(12*57.1193)-0.25]*12*5.4035*0.25
= 9,885 lbf (New)
= 9,885 lbf (Corroded)
SHELL COURSE #4 SUMMARY
-------------------------------------------
t-Calc = MAX(t-Calc_620, t_min_ext, t.seismic)
= MAX(0.0783, 0, 0)
= 0.0783 in.
Course Minimum t shall not be less than 0.1" + CA
(per API-653 Section 4.3.3.1)
t-653min = 0.1 in.
t.required = MAX(t.design, t.min653)
= MAX(0.0783,0.1) = 0.1 in.
< API-653 4.3.2.1 >
t1 (lowest average thickness in the shell course)
t1 must be >= t.required = 0.1 in.
t2 (least min. thickness in an area of shell course)
t2 must be >= 0.6*(t.required - CA) + CA = 0.060000 in.
t.actual = 0.25 in.
Weight = Density*PI*[(12*OD) - t]*12*Width*t
= 0.2833*PI*[(12*57.1193)-0.25]*12*5.4035*0.25
= 9,885 lbf (New)
= 9,885 lbf (Corroded)
SHELL COURSE #5 SUMMARY
-------------------------------------------
t-Calc = MAX(t-Calc_620, t_min_ext, t.seismic)
= MAX(0.2462, 0, 0)
= 0.2462 in.
Per 5.6.1.3, this course t-Calc cannot exceed the lower course t-Calc.
reset t-Calc_4 = 0.2462 in.
Course Minimum t shall not be less than 0.1" + CA
(per API-653 Section 4.3.3.1)
t-653min = 0.1 in.
t.required = MAX(t.design, t.min653)
= MAX(0.2462,0.1) = 0.2462 in.
< API-653 4.3.2.1 >
t1 (lowest average thickness in the shell course)
t1 must be >= t.required = 0.2462 in.
t2 (least min. thickness in an area of shell course)
t2 must be >= 0.6*(t.required - CA) + CA = 0.147720 in.
t.actual = 0.25 in.
Weight = Density*PI*[(12*OD) - t]*12*Width*t
= 0.2833*PI*[(12*57.1193)-0.25]*12*5.4035*0.25
= 9,885 lbf (New)
= 9,885 lbf (Corroded)
SHELL COURSE #6 SUMMARY
-------------------------------------------
t-Calc = MAX(t-Calc_620, t_min_ext, t.seismic)
= MAX(0.0662, 0, 0)
= 0.0662 in.
Course Minimum t shall not be less than 0.1" + CA
(per API-653 Section 4.3.3.1)
t-653min = 0.1 in.
t.required = MAX(t.design, t.min653)
= MAX(0.0662,0.1) = 0.1 in.
< API-653 4.3.2.1 >
t1 (lowest average thickness in the shell course)
t1 must be >= t.required = 0.1 in.
t2 (least min. thickness in an area of shell course)
t2 must be >= 0.6*(t.required - CA) + CA = 0.060000 in.
t.actual = 0.25 in.
Weight = Density*PI*[(12*OD) - t]*12*Width*t
= 0.2833*PI*[(12*57.1193)-0.25]*12*5.4035*0.25
= 9,885 lbf (New)
= 9,885 lbf (Corroded)
SHELL COURSE #7 SUMMARY
-------------------------------------------
t-Calc = MAX(t-Calc_620, t_min_ext, t.seismic)
= MAX(0.0592, 0, 0)
= 0.0592 in.
Course Minimum t shall not be less than 0.1" + CA
(per API-653 Section 4.3.3.1)
t-653min = 0.1 in.
t.required = MAX(t.design, t.min653)
= MAX(0.0592,0.1) = 0.1 in.
< API-653 4.3.2.1 >
t1 (lowest average thickness in the shell course)
t1 must be >= t.required = 0.1 in.
t2 (least min. thickness in an area of shell course)
t2 must be >= 0.6*(t.required - CA) + CA = 0.060000 in.
t.actual = 0.25 in.
Weight = Density*PI*[(12*OD) - t]*12*Width*t
= 0.2833*PI*[(12*57.1193)-0.25]*12*5.4035*0.25
= 9,885 lbf (New)
= 9,885 lbf (Corroded)
SHELL COURSE #8 SUMMARY
-------------------------------------------
t-Calc = MAX(t-Calc_620, t_min_ext, t.seismic)
= MAX(0.0512, 0, 0)
= 0.0512 in.
Course Minimum t shall not be less than 0.1" + CA
(per API-653 Section 4.3.3.1)
t-653min = 0.1 in.
t.required = MAX(t.design, t.min653)
= MAX(0.0512,0.1) = 0.1 in.
< API-653 4.3.2.1 >
t1 (lowest average thickness in the shell course)
t1 must be >= t.required = 0.1 in.
t2 (least min. thickness in an area of shell course)
t2 must be >= 0.6*(t.required - CA) + CA = 0.060000 in.
t.actual = 0.25 in.
Weight = Density*PI*[(12*OD) - t]*12*Width*t
= 0.2833*PI*[(12*57.1193)-0.25]*12*5.4035*0.25
= 9,885 lbf (New)
= 9,885 lbf (Corroded)
SHELL COURSE #9 SUMMARY
-------------------------------------------
t-Calc = MAX(t-Calc_620, t_min_ext, t.seismic)
= MAX(0.0418, 0, 0)
= 0.0418 in.
Course Minimum t shall not be less than 0.1" + CA
(per API-653 Section 4.3.3.1)
t-653min = 0.1 in.
t.required = MAX(t.design, t.min653)
= MAX(0.0418,0.1) = 0.1 in.
< API-653 4.3.2.1 >
t1 (lowest average thickness in the shell course)
t1 must be >= t.required = 0.1 in.
t2 (least min. thickness in an area of shell course)
t2 must be >= 0.6*(t.required - CA) + CA = 0.060000 in.
t.actual = 0.25 in.
Weight = Density*PI*[(12*OD) - t]*12*Width*t
= 0.2833*PI*[(12*57.1193)-0.25]*12*5.4035*0.25
= 9,885 lbf (New)
= 9,885 lbf (Corroded)
SHELL COURSE #10 SUMMARY
-------------------------------------------
t-Calc = MAX(t-Calc_620, t_min_ext, t.seismic)
= MAX(0.0296, 0, 0)
= 0.0296 in.
Course Minimum t shall not be less than 0.1" + CA
(per API-653 Section 4.3.3.1)
t-653min = 0.1 in.
t.required = MAX(t.design, t.min653)
= MAX(0.0296,0.1) = 0.1 in.
< API-653 4.3.2.1 >
t1 (lowest average thickness in the shell course)
t1 must be >= t.required = 0.1 in.
t2 (least min. thickness in an area of shell course)
t2 must be >= 0.6*(t.required - CA) + CA = 0.060000 in.
t.actual = 0.25 in.
Weight = Density*PI*[(12*OD) - t]*12*Width*t
= 0.2833*PI*[(12*57.1193)-0.25]*12*5.4038*0.25
= 9,886 lbf (New)
= 9,886 lbf (Corroded)
FLAT BOTTOM: ANNULAR PLATE DESIGN
Bottom Plate Material : A-36
Annular Bottom Plate Material : A-283 Gr C
<Weight of Bottom Plate>
Bottom_Area = PI/4*(OD - 2*t_course_1 - 2*AnnRing_Width)^2
= PI/4*(685.431 - 2*0.25 - 2*24)^2
= 318,621 in^2
Annular_Area = PI/4*(Bottom_OD)^2 - Bottom_Area
= PI/4*(689.431)^2 - 318,621
= 54,691 in^2
Weight = Btm_Density * t.actual * Bottom_Area + Ann_Density * t-AnnRing * «
Annular_Area)
= 0.2833 * 0.25*318,621 + 0.2833 * 0.25*54,691
= 26,440 lbf (New)
= 25,996 lbf (Corroded)
< API-653 >
Calculation of Hydrostatic Test Stress & Product Design Stress
(per API-653 Table 4-5 footnote b)
t_1 : Original Bottom (1st) Shell Course thickness.
H'= Max. Liq. Level + P(psi)/(0.433)
= 20 + (0.142)/(0.433) = 20.3279 ft
St = Hydrostatic Test Stress in Bottom (1st) Shell Course
= (2.6)(OD)(H' - 1)/t_1
= (2.6)(57.1193)(20.3279 - 1)/(0.1875)
= 15,309 PSI
Sd = Product Design Stress in Bottom (1st) Shell Course
= (2.6)(OD)(H' - 1)(G)/(t_1 - ca_1)
= (2.6)(57.1193)(20.3279 - 1)(1)/(0.1875)
= 15,309 PSI
--------------------------
<Non-Annular Bottom Plates>
t_min = 0.1 + 0.0049 = 0.1049 in. (per API-653 Table 4-4)
t-Calc = t_min = 0.1049 in.
t-Actual = 0.25 in.
<Annular Bottom Plates> (Per API-653 Section 4.4.8),
t_Min_Annular_Ring = 0.236 + 0 = 0.236 in. (per API-650 Table 5-1)
t_Annular_Ring = Actual Annular Ring Thickness
= 0.25 in.
W_Annular_Ring = Actual Annular Ring Width
= 24 in.
<Annular Bottom Plates> (per API-650 Section 5.5.2),
W_int = Minimum Annular Ring Width
(from Shell ID to Any Lap-Welded Joint)
(t_Min_Annular_Ring exclusive of corrosion)
= 390*t_Min_Annular_Ring/SQRT(H*G)
= 390(0.236)/SQRT(20.3279*1)
= 20.41 in.
W_int = 24 in.
< FLAT BOTTOM: ANNULAR SUMMARY >
t.required = t-Calc = 0.1049 in.
t.actual = 0.25 in.
Annular Bottom Plate Material : A-283 Gr C
Minimum Annular Ring Thickness = 0.236 in.
t_Annular_Ring = 0.25 in.
Minimum Annular Ring Width = 24 in.
W_Annular_Ring = 24 in.
NET UPLIFT DUE TO INTERNAL PRESSURE
(See roof report for calculations)
Net_Uplift = -138,085 lbf
Anchorage NOT required for internal pressure.
WIND MOMENT (Using API-650 SECTION 5.11)
vs = Wind Velocity = 100 mph
vf = Velocity Factor = (vs/100)^2 = (100/100)^2 = 1
Wind_Uplift = Iw * 30 * vf
= 1 * 30 * 1
= 30 lbf/ft^2
API-650 5.2.1.k Uplift Check
P_F41 = WCtoPSI(0.962*Fy*A*TAN(Theta)/D^2 + 8*t_h)
P_F41 = WCtoPSI(0.962*30,000*5.888*0.0625/57.1193^2 + 8*0.375)
= 0.2259 PSI
Limit Wind_Uplift/144+P to 1.6*P_F41
Wind_Uplift/144 + P = 0.3503 PSI
1.6*P_F41 = 0.3614 PSI
Wind_Uplift/144 + P = MIN(Wind_Uplift/144 + P, 1.6*P_F41)
Wind_Uplift/144 = MIN(Wind_Uplift/144, 1.6*P_F41 - P)
Wind_Uplift = MIN(Wind_Uplift, (1.6*P_F41 - P) * 144)
= MIN(30,31.5994)
= 30 lbf/ft^2
Ap_Vert = Vertical Projected Area of Roof
= pt*OD^2/48
= 0.75*57.1193^2/48
= 50.978 ft^2
Horizontal Projected Area of Roof (Per API-650 5.2.1.f)
Xw = Moment Arm of UPLIFT wind force on roof
= 0.5*OD
= 0.5*57.1193
= 28.5596 ft
Ap = Projected Area of roof for wind moment
= PI*R^2
= PI*28.5596^2
= 2,562 ft^2
M_roof (Moment Due to Wind Force on Roof)
= (Wind_Uplift)(Ap)(Xw)
= (30)(2,562)(28.5596) = 2,195,476 ft-lbf
Xs (Moment Arm of Wind Force on Shell)
= H/2 = (54.0353)/2 = 27.0176 ft
As (Projected Area of Shell)
= H*(OD + t_ins / 6)
= (54.0353)(57.1193 + 0/6) = 3,086 ft^2
M_shell (Moment Due to Wind Force on Shell)
= (Iw)(vf)(18)(As)(Xs)
= (1)(1)(18)(3,086)(27.0176) = 1,500,996 ft-lbf
Mw (Wind moment)
= M_roof + M_shell = 2,195,476 + 1,500,996
= 3,696,472 ft-lbf
W = Net weight (PER API-650 5.11.3)
(Force due to corroded weight of shell and
shell-supported roof plates less
40% of F.1.2 Uplift force.)
= W_shell + W_roof - 0.4*P*(PI/4)(144)(OD^2)
= 98,851 + 39,234 - 0.142*(PI/4)(144)(57.1193^2)
= 117,126 lbf
RESISTANCE TO OVERTURNING (per API-650 5.11.2)
An unanchored Tank must meet these two criteria:
1) 0.6*Mw + MPi < (MDL + MF_min_liq)/1.5
2) Mw + 0.4MPi < (MDL + MF)/2
Mw = Destabilizing Wind Moment = 3,696,472 ft-lbf
MPi = Destabilizing Moment about the Shell-to-Bottom Joint from Design «
Pressure.
= P*(PI*OD^2/4)*(144)*(OD/2)
= 0.142*(3.1416*57.1193^2/4)*(144)*(28.5596)
= 1,496,436 ft-lbf
MDL = Stabilizing Moment about the Shell-to-Bottom Joint from the Shell and «
Roof weight supported by the Shell.
= (W_shell + W_roof)*OD/2
= (98,851 + 39,234)*28.5596
= 3,943,656 ft-lbf
tb = Annular Bottom Ring thickness less C.A. = 0.25 in.
Lb = Minimum bottom annular ring width
Lb = greater of 18 in. or 0.365*tb*SQRT(Sy_btm/H_liq)
= 18 in.
wl = Circumferential loading of contents along Shell-To-Bottom Joint.
= 4.67*tb*SQRT(Sy_btm*H_liq)
= 4.67*0.25*SQRT(36,000*20)
= 990.66 lbf/ft
wl_min_liq = Circumferential loading of Minimum-Level contents along «
Shell-To-Bottom Joint.
= 4.67*ta*SQRT(Sy_btm*H_min_liq)
= 4.67*0.25*SQRT(36,000*0)
= 0 lbf/ft
MF_min_liq = wa_min_liq*PI*OD
= 0*3.1416*57.1193
= 0 lbf
MF = Stabilizing Moment due to Bottom Plate and Liquid Weight.
= (OD/2)*wl*PI*OD
= (28.5596)(990.66)(3.1416)(57.1193)
= 5,077,027 ft-lbf
Criteria 1
0.6*(3,696,472) + 1,496,436 < (3,943,656 + 0)/1.5
Since 3,714,319 >= 2,629,104, Tank must be anchored.
Criteria 2
3,696,472 + 0.4 * 1,496,436 < (3,943,656 + 5,077,027)/2
Since 4,295,047 < 4,510,342, Tank is stable.
RESISTANCE TO SLIDING (per API-650 5.11.4)
F_wind = vF * 18 * As
= 1 * 18 * 3,086
= 55,556 lbf
F_friction = Maximum of 40% of Weight of Tank
= 0.4 * (W_Roof_Corroded + W_Shell_Corroded +
W_Btm_Corroded + RoofStruct + W_min_Liquid)
= 0.4 * (39,234 + 98,851 + 25,996 + 4,651 + 0)
= 67,493 lbf
No anchorage needed to resist sliding since
F_friction > F_wind
<Anchorage Requirement>
Anchorage required since Criteria 1, Criteria 2, or Sliding
are NOT acceptable.
Bolt Spacing = 10 ft, Min # Anchor Bolts = 18
SEISMIC MOMENT (API-650 APPENDIX E & API-620 APPENDIX L)
Ms (Seismic Moment)
Ms = Z*I*(C1*Ws*Xs + C1*Wr*Ht + C1*W1*X1 + C2*W2*X2)
Z = 0.075 Zone coefficient for zone 1 (from Table E-2)
I = 1 Importance Factor
S = 1.5 Site amplification factor (from Table E-3)
C1 = 0.6 = Lateral earthquake force coefficient
k = 0.6319 (factor for D/H = 2.856 from figure E-4)
T = Natural Period of First Sloshing Mode
= k*SQRT(OD) = 0.6319*SQRT(57.1193) = 4.776
C2 = Lateral Earthquake Force Coefficient
= 3.375(S)/T^2 = 3.375(1.5)/(4.776)^2 = 0.2219
From Figures E-2 & E-3
X1_H = X1/H chart factor
X2_H = X2/H chart factor
W1_Wt = W1/Wt chart factor
W2_Wt = W2/Wt chart factor
Wt = Weight of tank contents @ Max. Liquid Level
X1 = (X1_H)*H = (0.375)*20 = 7.5
X2 = (X2_H)*H = (0.5578)*20 = 11.1565
W1 = (W1_Wt)*Wt = (0.4081)*3,191,735 = 1,302,586
W2 = (W2_Wt)*Wt = (0.5451)*3,191,735 = 1,739,817
Ws = W_shell + W_Insulation (New Condition)
= 98,851 + 0 = 98,851
Wr = W_roof + Snow Load + W_Insulation (New Condition)
= 39,234 + 0 + 0 = 39,234
C1*Ws*Xs = 0.6*(98,851)(27.0176) = 1,602,432
C1*Wr*Ht = 0.6*(39,234)(54.0353) = 1,272,012
C1*W1*X1 = 0.6*(1,302,586)(7.5) = 5,861,635
C2*W2*X2 = (0.2219)(1,739,817)(11.1565) = 4,307,914
Ms = Z*I*(C1*Ws*Xs + C1*Wr*Ht + C1*W1*X1 + C2*W2*X2)
= (0.075)(1)(1,602,432 + 1,272,012 + 5,861,635 + 4,307,914)
= 978,300 ft-lbf
W_shell = Weight of Shell (New Condition)
W_roof2 = Weight of Roof Plates Supported By Shell (New)
wt = (W_shell + W_roof2)/(PI*OD) (New Condition)
= (98,851 + 39,234)/(PI*57.1193)
= 770. lbf/ft
RESISTANCE TO OVERTURNING (per Section E.4.1, E.4.2,
assuming no anchors)
wl = 7.9*(tb1)*SQRT(Sy*G*H)
= 7.9*(0.2451)*SQRT(30,000*1*20)
= 1,500 lbf/ft
where tb1 = t - CA = 0.2451 in. (for Bottom Plate)
1.25*G*H*OD = 1.25(1)(20)(57.1193)
= 1,428 lbf/ft
since wl > 1.25*G*H*OD, wl = 1.25G*H*OD
wl = 1,428 lbf/ft
UNANCHORED TANKS (Section E.5.1)
Ms/[OD^2(wt+wl)] = 978,300/[(57.1193^2)(770. + 1,428)] = 0.1365
b = wt + 1.273(Ms)/OD^2 = max longitudinal compressive force
= 770. + 1.273(978,300)/(57.1193)^2 = 1,151 lbf/ft
MAXIMUM ALLOWABLE SHELL COMPRESSION (Section E.5.3)
b/(12t) = Max Longitudinal Compressive Stress
= 1,151/(12*(0.25 - 0)) = 384 PSI
G*H*OD^2/t^2 = (1)(20)(57.1193^2)/(0.25 - 0)^2 = 1,044,035
Fa = 10^6*t/OD = (10^6)(0.25 - 0)/57.1193 = 4,377 PSI
t = 0.25 - 0 = 0.25 in. (OK since b/(12t) <= Fa)
ANCHORED TANKS (Section E.5.2)
b = wt + 1.273(Ms)/OD^2 = Max Longitudinal Compressive Force
= 770. + 1.273(978,300)/(57.1193)^2 = 1,151 lbf/ft
MAXIMUM ALLOWABLE SHELL COMPRESSION (Section E.5.3)
b/(12t) = Max Longitudinal Compressive Stress
= 1,151/(12*(0.25 - 0)) = 384 PSI
G*H*OD^2/t^2 = (1)(20)(57.1193^2)/(0.25 - 0)^2 = 1,044,035
Fa = 10^6*t/OD = (10^6)(0.25 - 0)/57.1193 = 4,377 PSI
t = 0.25 - 0 = 0.25 in. (OK since b/(12t) <= Fa)
ANCHORAGE OF TANKS (Section E.6.1)
N = 20 Number of Anchors
D = 57.3623 ft Diameter of Anchor Circle
W = Minus Corroded weight of shell and roof plates.
MAR = minimum anchorage resistance due to seismic moment
= 1.273(Ms)/OD^2 - W/Circumference
= 1.273(978,300)/57.1193^2 + -138,085/(PI*57.1193)
= -388 lbf/ft circumference
btseis = anchor tension req'd to resist seismic moment
= MAR*D*PI/(N)
= (-388)(57.3623)(PI)/(20) = -3,496 lbf
ANCHOR BOLT DESIGN
Bolt Material : A-307
Sy = 36,000 PSI
< Uplift Load Cases, per API-650 Table 5-21b >
D (tank OD) = 57.1193 ft
P (design pressure) = 3.94 INCHES H2O
Pt (test pressure per F.4.4) = P = 3.94 INCHES H2O
Pf (failure pressure per F.6) = N.A. (see Uplift Case 3 below)
t_h (roof plate thickness) = 0.375 in.
Mw (Wind Moment) = 3,696,472 ft-lbf
Mrw (Seismic Ringwall Moment) = 978,300 ft-lbf
W1 (Dead Load of Shell minus C.A. and Any
Dead Load minus C.A. other than Roof
Plate Acting on Shell)
W2 (Dead Load of Shell minus C.A. and Any
Dead Load minus C.A. including Roof
Plate minus C.A. Acting on Shell)
W3 (Dead Load of New Shell and Any
Dead Load other than Roof
Plate Acting on Shell)
For Tank with Structural Supported Roof,
W1 = Corroded Shell + Shell Insulation
= 98,851 + 0
= 98,851 lbf
W2 = Corroded Shell + Shell Insulation + Corroded Roof Plates
Supported by Shell + Roof Dead Load Supported by Shell
= 98,851 + 0
+ 39,234 * [1 + 369,308*0/(144 * 39,234)]
= 138,085 lbf
W3 = New Shell + Shell Insulation
= 98,851 + 0
= 98,851 lbf
Uplift Case 1: Design Pressure Only
U = [(P - 8*t_h) * D^2 * 4.08] - W1
U = [(3.94 - 8*0.375) * 57.1193^2 * 4.08] - 98,851
= -86,338 lbf
bt = U / N = -4,317 lbf
Sd = 15,000 PSI
A_s_r = Bolt Root Area Req'd
A_s_r = N.A., since Load per Bolt is zero.
Uplift Case 2: Test Pressure Only
U = [(Pt - 8*t_h) * D^2 * 4.08] - W1
U = [(3.94 - 8*0.375) * 57.1193^2 * 4.08] - 98,851
= -86,338 lbf
bt = U / N = -4,317 lbf
Sd = 20,000 PSI
A_s_r = Bolt Root Area Req'd
A_s_r = N.A., since Load per Bolt is zero.
Uplift Case 3: Failure Pressure Only
Not applicable since if there is a knuckle on tank roof,
or tank roof is not frangible.
Pf (failure pressure per F.6) = N.A.
Uplift Case 4: Wind Load Only
PWR = Wind_Uplift/5.208
= 30/5.208
= 5.7604 IN. H2O
PWS = vF * 18
= 1 * 18
= 18 lbf/ft^2
MWH = PWS*(D+t_ins/6)*H^2/2
= 18*(57.1193+0/6)*54.0353^2/2
= 1,500,997 ft-lbf
U = PWR * D^2 * 4.08 + [4 * MWH/D] - W2
= 5.7604*57.1193^2*4.08+[4*1,500,997/57.1193]-138,085
= 43,707 lbf
bt = U / N = 2,185 lbf
Sd = 0.8 * 36,000 = 28,800 PSI
A_s_r = Bolt Root Area Req'd
A_s_r = bt/Sd
= 2,185/28,800 = 0.076 in^2
Uplift Case 5: Seismic Load Only
U = [4 * Mrw / D] - W2*(1-0.4*Av)
U = [4 * 978,300 / 57.1193] - 138,085*(1-0.4*0)
= -69,576 lbf
bt = U / N = -3,479 lbf
Sd = 0.8 * 36,000 = 28,800 PSI
A_s_r = Bolt Root Area Req'd
A_s_r = N.A., since Load per Bolt is zero.
Uplift Case 6: Design Pressure + Wind Load
U = [(0.4*P + PWR - 8*t_h) * D^2 * 4.08] + [4 * MWH / D] - W1
= [(0.4*3.94+5.7604-8*0.375)*57.1193^2 * 4.08]+[4*1,500,997 / 57.1193] «
- 98,851
= 63,986 lbf
bt = U / N = 3,199 lbf
Sd = 20,000 = 20,000 PSI
A_s_r = Bolt Root Area Req'd
A_s_r = bt/Sd
= 3,199/20,000 = 0.16 in^2
Uplift Case 7: Design Pressure + Seismic Load
U = [(0.4*P - 8*t_h)*D^2 * 4.08] + [4*Mrw/D] - W1*(1-0.4*Av)
= -49,297 lbf
bt = U / N = -2,465 lbf
Sd = 0.8 * 36,000 = 28,800 PSI
A_s_r = Bolt Root Area Req'd
A_s_r = N.A., since Load per Bolt is zero.
Uplift Case 8: Frangibility Pressure
Not applicable since if there is a knuckle on tank roof,
or tank roof is not frangible.
Pf (failure pressure per F.6) = N.A.
< ANCHOR BOLT SUMMARY >
Bolt Root Area Req'd = 0.16 in^2
d = Bolt Diameter = 1 in.
n = Threads per inch = 8
A_s = Actual Bolt Root Area
= 0.7854 * (d - 1.3 / n)^2
= 0.7854 * (1 - 1.3 / 8)^2
= 0.5509 in^2
Exclusive of Corrosion,
Bolt Diameter Req'd = 0.56 in. (per ANSI B1.1)
Actual Bolt Diameter = 1.000 in.
Bolt Diameter Meets Requirements.
<ANCHORAGE REQUIREMENTS>
Minimum # Anchor Bolts = 18
NOTE: API-620 has no minimum spacing requirement, but
per API-650 5.12.3, maximum spacing is 10 ft if anchorage required.
Actual # Anchor Bolts = 20
Anchorage Meets Spacing Requirements.
ANCHOR CHAIR DESIGN
(from AISI 'Steel Plate Engr Data' Dec. 92, Vol. 2, Part VII)
Entered Parameters
Chair Material: A-283 Gr C
Top Plate Type: DISCRETE
Chair Style: VERT. STRAIGHT
a : Top Plate Width = 4.000 in.
b : Top Plate Length = 2.708 in.
k : Verical Plate Width = 2.500 in.
m : Bottom Plate Thickness = 0.2500 in.
t : Shell Course + Repad Thickness = 0.2500 in.
r : Nominal Radius to Tank Centerline = 342.591 in.
Design Load per Bolt: P = 4.8 KIPS (1.5 * Maximum from Uplift Cases)
d = Bolt Diameter = 1 in.
n = Threads per unit length = 8 TPI
A_s = Computed Bolt Root Area
= 0.7854 * (d - 1.3 / n)^2
= 0.7854 * (1 - 1.3 / 8)^2
= 0.551 in^2
Bolt Yield Load = A*Sy/1000 (KIPS)
= 0.551*36,000/1000
= 19.836 KIPS
Anchor Chairs will be designed to withstand
Bolt Yield Load (per API-650 App. E.6.2.1.2)
Anchor Chair Design Load, P = 19.836 KIPS
Sts = 15,200 PSI (Allowable Tensile Stress per API-620 Table 5-1)
For Anchor Chair material: A-283 Gr C
Sd_Chair = 15.2 KSI
Since bottom t <= 3/8 in., Seismic Zone is a Factor,
and Wind Speed is >= 100 mph,
h_min is 12 in.
For Discrete Top Plate,
Max. Chair Height Recommended : h <= 3 * a
h_max = 3 * 4 = 12 in.
h = 12 in.
e_min = 0.886 * d + 0.572 = 1.458 in.
e = e_min = 1.458 in.
g_min = d + 1 = 2 in.
g = g_min = 2 in.
f_min = d/2 + 0.125 = 0.625 in.
f = f_min = 0.625 in.
c_min = SQRT[P / Sd_Chair / f * (0.375 * g - 0.22 * d)]
= SQRT[19.836 / 15.2 / 0.625 * (0.375 * 2 - 0.22 * 1)]
= 1.052 in.
c >= c_min = 1.052 in.
j_min = MAX(0.5, [0.04 * (h - c)])
= MAX(0.5, [0.04 * (12.000 - 1.052)])
= 0.5 in.
j = j_min = 0.5 in.
b_min = e_min + d + 1/4
= 1.458 + 1 + 1/4
= 2.708 in.
Checking Requirement: b - k > 0.5 in.
<Stress due to Top Plate Thickness>
S_actual_TopPlate = P / f / c^2 * (0.375 * g - 0.22 * d)
= 19.84/0.625/1.052^2 * (0.375 * 2 - 0.22 * 1)
= 15.2 KSI
<Shell Stress due to Chair Height> (For Discrete Top Plate)
S_actual_ChairHeight = P * e / t^2 * F3
where F3 = F1 + F2,
now F1 = (1.32 * z) / (F6 + F7)
where F6 = (1.43 * a * h^2) / (r * t)
and F7 = (4 * a * h^2)^(1/3)
and z = 1 / (F4 * F5 + 1)
where F4 = (0.177 * a * m) / SQRT(r * t)
and F5 = (m / t)^2
yields F5 = (0.25 / 0.25)^2
= 1.
yields F4 = (0.177 * 4. * 0.25) / SQRT(342.5905 * 0.25)
= 0.0191
yields z = 1 / (0.0191 * 1. + 1)
= 0.9812
yields F7 = (4 * 4. * 12.^2)^(1/3)
= 13.2077
yields F6 = (1.43 * 4. * 12.^2) / (342.5905 * 0.25)
= 9.6171
yields F1 = (1.32 * z) / (9.6171 + 13.2077)
= 0.0567
now F2 = 0.031 / SQRT(r * t)
yields F2 = 0.031 / SQRT(342.5905 * 0.25)
= 0.0033
yields F3 = 0.0567 + 0.0033
= 0.0601
yields S_actual_ChairHeight = 19.836 * 1.458 / 0.25^2 * 0.0601
= 27.8086 KSI
Sts = 16,000 PSI (Allowable Tensile Stress per API-620 Table 5-1)
For Shell Course material: A-36,
Sd_ChairHeight = Sd_shell1 = 16 KSI
< ANCHOR CHAIR SUMMARY >
S_actual_TopPlate Meets Design Calculations
(within 105% of Sd_Chair)
S_actual_TopPlate/Sd_Chair
= 15.2/34.58 = 44.0%
S_actual_ChairHeight/Sd_ChairHeight
= 27.8086/16 = 173.8%
* * Warning * * S_actual_ChairHeight Exceeds 105% of Sd_ChairHeight
Use Anchor Chair Repad ( t = 0.100).
NORMAL & EMERGENCY VENTING (API-2000)
Contents : Base Oil
Tank OD = 57.11925 ft
Tank Shell Height = 54.03527 ft
Tank Design Temp. = 70 °F
<INBREATHING - VACUUM RELIEF>
Q1 (Maximum Movement Out of Tank) (per Section 4.3.2.1.1)
= 5.6 CFH Air per 42 GPH outflow
= (5.6/42)*220*60
= 1,760 CFH, or 29 CFM free air
Q2 (Thermal Inbreathing) (per Section 4.3.2.1.2)
= 24,598 CFH, or 410. CFM free air (Table 2A Column 2)
Total Vacuum Relief Required = Q1 + Q2 = 26,358 CFH, or 439. CFM
<OUTBREATHING - PRESSURE RELIEF>
Q1 (Maximum Movement Into Tank) (per Section 4.3.2.2.1)
= 6 CFH Air per 42 GPH inflow
= (6/42)*1,321*60 = 11,323 CFH, or 189. CFM free air
Q2 (Thermal Outbreathing) (per Section 4.3.2.2.2)
= 15,299 CFH, or 255 CFM free air (Table 2A Column 3)
Total Pressure Relief Required = Q1 + Q2 = 26,622 CFH, or 444. CFM
<EMERGENCY VENTING>
Max W = 30 ft.
For flat bottom tanks, only shell is considered for Wetted Area.
Wetted Area = 5,383 ft^2
(Section 4.3.3.2.2, Design Pressure <= 1 PSI)
Qe = 742,000 CFH, or 12367. CFM free air (Table 3A Column 2)
x1 = 0.5 (Environment Factor for Drainage)
x2 = 1 (Environment Factor for Insulation)
Qe = x1*x2*Qe = (0.5)(1)(742,000)
= 371,000 CFH
CAPACITIES and WEIGHTS
Maximum Capacity (to upper TL) : 1,034,265 gal
Design Capacity (to Max Liquid Level) : 382,810 gal
Minimum Capacity (to Min Liquid Level) : 0 gal
NetWorking Capacity (Design - Min.) : 382,810 gal
New Condition Corroded
-----------------------------------------------------------
Shell 98,851 lbf 98,851 lbf
Roof
Plates 39,234 lbf 39,234 lbf
Rafters 3,646 lbf 3,646 lbf
Girders 0 lbf 0 lbf
Columns 1,005 lbf 1,005 lbf
Bottom 26,440 lbf 25,996 lbf
Stiffeners 0 lbf 0 lbf
Nozzle Wgt 0 lbf 0 lbf
Misc Roof Wgt 0 lbf 0 lbf
Misc Shell Wgt 0 lbf 0 lbf
Insulation 0 lbf 0 lbf
-----------------------------------------------------------
Total 169,176 lbf 168,732 lbf
Weight of Tank, Empty : 169,176 lbf
Weight of Tank, Full of Product (SG=1): 8,800,531 lbf
Weight of Tank, Full of Water : 8,800,531 lbf
Net Working Weight, Full of Product : 3,363,879 lbf
Net Working Weight, Full of Water : 3,363,879 lbf
Foundation Area Req'd : 2,562 ft^2
Foundation Loading, Empty : 66.03 lbf/ft^2
Foundation Loading, Full of Product (SG=1) : 3,435 lbf/ft^2
Foundation Loading, Full of Water : 3,435 lbf/ft^2
SURFACE AREAS
Roof 2,565 ft^2
Shell 9,696 ft^2
Bottom 2,562 ft^2
Wind Moment 3,696,472 ft-lbf
Seismic Moment 978,300 ft-lbf
MISCELLANEOUS ATTACHED ROOF ITEMS
MISCELLANEOUS ATTACHED SHELL ITEMS
MAWP & MAWV SUMMARY FOR JGC
MAXIMUM CALCULATED INTERNAL PRESSURE
MAWP = 15 PSI or 415.7 IN. H2O (per API-620)
MAWP = Maximum Calculated Internal Pressure (due to shell)
= 3.013 PSI or 83.5 IN. H2O
MAWP = Maximum Calculated Internal Pressure (due to roof)
= 36.0473 PSI or 999 IN. H2O
TANK MAWP = 3.013 PSI or 83.5 IN. H2O
MAXIMUM CALCULATED EXTERNAL PRESSURE
MAWV = Maximum Calculated External Pressure (due to shell)
= -0.0536 PSI or -1.49 IN. H2O
MAWV = Maximum Calculated External Pressure (due to roof)
= 0 PSI or 0 IN. H2O
MAWV = N.A. (not calculated due to columns)
TANK MAWV = 0 PSI or 0 IN. H2O