example solutions
DESCRIPTION
Example Solutions. Example 1. Random backoff = r A = 0. DIFS =2. Packet length = 10. A. 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25. ACK=1. ACK=1. SIFS=1. SIFS=1. Answer: T = 24. B. 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25. DIFS =2. - PowerPoint PPT PresentationTRANSCRIPT
Example Solutions
Example 1
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
A
B
C
t =0
DIFS =2
Random backoff = rA = 0
Random backoff = rC = 1
Packet length = 10
DIFS =2
SIFS=1
ACK=1
DIFS =2
Frozen Random backoff = rC = 1
Random backoff decremented, rC = 0
Packet length = 5
SIFS=1
ACK=1
Answer: T = 24
Example 2
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40
A
B
C
t =0
DIFS =2
Random backoff = rA = 1
Random backoff = rC = 1
Packet length = 10
DIFS =2
SIFS=1
ACK=1
DIFS =2 Packet length = 5
SIFS=1
ACK=1
Packet length = 5
Packet collision
Packet collision
DIFS =2
New Random backoff = rA = 0
New Random backoff = rC = 1
Packet length = 10
DIFS =2
Frozen Random backoff = rC = 1 Random backoff decremented, rC = 0
Answer: T = 37