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Example Solutions

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Example Solutions. Example 1. Random backoff = r A = 0. DIFS =2. Packet length = 10. A. 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25. ACK=1. ACK=1. SIFS=1. SIFS=1. Answer: T = 24. B. 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25. DIFS =2. - PowerPoint PPT Presentation

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Page 1: Example Solutions

Example Solutions

Page 2: Example Solutions

Example 1

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25

A

B

C

t =0

DIFS =2

Random backoff = rA = 0

Random backoff = rC = 1

Packet length = 10

DIFS =2

SIFS=1

ACK=1

DIFS =2

Frozen Random backoff = rC = 1

Random backoff decremented, rC = 0

Packet length = 5

SIFS=1

ACK=1

Answer: T = 24

Page 3: Example Solutions

Example 2

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40

A

B

C

t =0

DIFS =2

Random backoff = rA = 1

Random backoff = rC = 1

Packet length = 10

DIFS =2

SIFS=1

ACK=1

DIFS =2 Packet length = 5

SIFS=1

ACK=1

Packet length = 5

Packet collision

Packet collision

DIFS =2

New Random backoff = rA = 0

New Random backoff = rC = 1

Packet length = 10

DIFS =2

Frozen Random backoff = rC = 1 Random backoff decremented, rC = 0

Answer: T = 37