exponential decay to thermoelastic systems over...
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Hindawi Publishing CorporationInternational Journal of Differential EquationsVolume 2011, Article ID 403264, 10 pagesdoi:10.1155/2011/403264
Research ArticleExponential Decay to Thermoelastic Systems overNoncylindrical Domains
Luci Harue Fatori and Michelle Klaiber
Department of Mathematics, State University of Londrina, Campus Universitario,86051-990 Londrina, PR, Brazil
Correspondence should be addressed to Luci Harue Fatori, [email protected]
Received 13 May 2011; Accepted 4 July 2011
Academic Editor: Alberto Cabada
Copyright q 2011 L. H. Fatori and M. Klaiber. This is an open access article distributed underthe Creative Commons Attribution License, which permits unrestricted use, distribution, andreproduction in any medium, provided the original work is properly cited.
This paper is concerned with linear thermoelastic systems defined in domains with movingboundary. The uniform rate of decay of the energy associated is proved.
1. Introduction
In the study of asymptotic behavior for thermoelastic systems, a pioneering work is theone by Dafermos [1] concerned with the classical linear thermoelasticity for inhomogeneousand anisotropic materials, where the existence of a unique global solution and asymptoticstability of the system were proved. The existence of solution and asymptotic behaviorto thermoelastic systems has been investigated extensively in the literature. For example,Munoz Rivera [2] showed that the energy of the linear thermoelastic system (on cylindricaldomain) decays to zero exponentially as t → ∞. In [3], Burns et al. proved the energydecay for a linear thermoelastic bar. The asymptotic behaviour of a semigroup of thethermoelasticity was established in [4]. Concerning nonlinear thermoelasticity we can cite[5–7].
In the last two decades, several well-known evolution partial differential equationswere extended to domains with moving boundary, which is also called noncylindricalproblems. See, for instance, [8–10] and the references therein. In this work we studied thelinear thermoelastic system in a noncylindrical domain with Dirichlet boundary conditions.This problem was early considered by Caldas et al. [11], which concluded that the energyassociated to the system decreases inversely proportional to the growth of the functions thatdescribes the noncylindrical domain. However they did not establish a rate of decay. The goalin the present work is to provide a uniform rate of decay for this noncylindrical problem.
2 International Journal of Differential Equations
Let us consider noncylindrical domains Q ⊂ R2 of the form
Q ={
(x, t) ∈ R2; x = K(t)y, y ∈ (−1, 1), t ∈ (0, T)
}
, (1.1)
with lateral boundary
Σ =⋃
0<t<T
{{−K(t) × {t}} ∪ {K(t) × {t}}}, (1.2)
where K : [0, T] → R+ is a given C2 function. Then our problem is
utt − uxx + αθx = 0 in Q, (1.3)
θt − kθxx + βuxt = 0 in Q, (1.4)
with initial conditions
u(x, 0) = u0(x), ut(x, 0) = u1(x), θ(x, 0) = θ0(x), −K(0) < x < K(0), (1.5)
and boundary conditions
u(−K(t), t) = u(K(t), t) = 0, θx(−K(t), t) = θ(K(t), t) = 0, 0 < t < T, (1.6)
where α, β, and k are positive real constants.The function K(t) and the constants α, β, and k satisfy the following conditions.(H1) K ∈ C 2([0, T],R+) and
K0 = min0≤t≤T
K(t) > 0. (1.7)
(H2) There exists a positive constant K1 such that
1 − (
K′(t)y)2
> K1. (1.8)
Problem (1.3)–(1.6) is slightly different from the one of [11] with respect to condition(1.6). Indeed, they assumed that θ(−K(t), t) = θ(K(t), t) = 0, for all t ∈ [0, T]. Because of thismixed boundary condition in (1.6), we are able to construct a suitable Liapunov functional toderive decay rates of the energy. This is sufficient to provide a uniform rate of decay for thisnoncylindrical problem.
The existence and uniqueness of global solutions are derived by the arguments of[11] step by step, that is, to prove that the result of existence and uniqueness is based ontransforming the system (1.3)–(1.6) into another initial boundary-value problem defined overa cylindrical domain whose sections are not time-dependent. This is done using a suitablechange of variable. Then to show the existence and uniqueness for this equivalent system
International Journal of Differential Equations 3
using Galerkin Methods and the existence result on noncylindrical domains will followsusing the inverse of the transformation.
Therefore, we have the following result.
Theorem 1.1. Let Ωt and Ω0 be the intervals (−K(t), K(t)), 0 < t < T , and (−K(0), K(0)),respectively. Then, given u0, θ0 ∈ H1
0(Ω0) ∩H2(Ω0) and u1 ∈ H10(Ω0), there exist unique functions
u : Q −→ R, θ : Q −→ R (1.9)
satisfying the following conditions:
u ∈ L∞(
0, T ;H10(Ωt) ∩H2(Ωt)
)
, ut ∈ L∞(
0, T ;H10(Ωt)
)
,
utt ∈ L∞(
0, T ;L2(Ωt))
, θ ∈ L2(
0, T,H2(Ωt))
, θt ∈ L2(
0, T ;H10(Ωt)
)
,
(1.10)
which are solutions of (1.3)–(1.6) in Q.
2. Energy Decay
In [11] the authors proved that the energy associated with (1.3)–(1.6) decays at the rate1/[K(t)]γ1 with γ1 > 0; that is, the energy is decreasing inverserly proportional to the increaseof sections of Q. We make a slightly difference from the one of [11] with respect to thehypotheses about K; we are able to construct a suitable Liapunov functional to derive decayrates of the energy. This is done with the thermal dissipation only. More specifically, in thissection we prove that the energy associated with (1.3)–(1.6) decays exponentially. Insteadconsidering an auxiliary problem, we work directly on the original problem (1.3)-(1.4) in itsnoncylindrical domain.
In order to decay rates of the energy let us suppose the following hypotheses.(H3) There exist positive constants δ0 and δ1 such that
0 < δ0 ≤ K′(t) ≤ δ1 < 1, t ≥ 0. (2.1)
(H4) There exists a positive constant δ2 such that
0 < K(t)K′(t) ≤ δ2, t ≥ 0. (2.2)
Let us introduce the energy functional
E(t) = E(t;u, θ) =12
∫K(t)
−K(t)
(
|ut|2 + |ux|2 + α
β|θ|2
)
dx. (2.3)
Our main result is the following.
4 International Journal of Differential Equations
Theorem 2.1. Under the hypotheses (H1)–(H4), there exist positive constants ˜C and γ such that
E(t;u, θ) ≤ ˜CE(0;u, θ)e−γt. (2.4)
The proof of Theorem 2.1 is given by using multipliers techniques. The notations andfunction spaces used here are standard and can be found, for instance, in the book by Lions[8].
Lemma 2.2. Let (u, θ) be solution of (1.3)–(1.5) given by Theorem 1.1; then one obtains
d
dtE(t;u, θ) ≤ −kα
β
∫K(t)
−K(t)|θx|2dx − C0
[
|ux(K(t), t)|2 + |ux(−K(t), t)|2]
, (2.5)
where C0 = (δ0/2)(1 − δ21) > 0.
Proof. From hypothesis u(K(t), t) = 0 = u(−K(t), t) it follows that
ut(K(t), t) = −K′(t)ux(K(t), t)eut(−K(t), t) = K′(t)ux(−K(t), t). (2.6)
Multiplying (1.3) by ut, integrating in the variable x, and from (2.6) we obtain
∫K(t)
−K(t)uttut dx =
12
[
d
dt
∫K(t)
−K(t)|ut|2dx −K′(t)|ut(K(t), t)|2 −K′(t)|ut(−K(t), t)|2
]
=12
[
d
dt
∫K(t)
−K(t)|ut|2dx −K′(t)3|ux(K(t), t)|2 −K′(t)3|ux(−K(t), t)|2
]
.
(2.7)
Now, applying integration by parts and using (2.6) it follows that
∫K(t)
−K(t)uxxut dx = −ux(K(t), t)ut(K(t), t) + ux(−K(t), t)ut(−K(t), t) +
∫K(t)
−K(t)uxutx dx
=K′(t)2
|ux(K(t), t)|2 + K′(t)2
|ux(−K(t), t)|2 + 12d
dt
∫K(t)
−K(t)|ux|2dx.
(2.8)
Thus, from inequalities (2.7) and (2.8)we have
12d
dt
∫K(t)
−K(t)
(
|ut|2 + |ux|2)
dx =12K′(t)3
[
|ux(K(t), t)|2 + |ux(−K(t), t)|2]
− K′(t)2
[
|ux(K(t), t)|2 + |ux(−K(t), t)|2]
− α
∫K(t)
−K(t)θxut dx.
(2.9)
International Journal of Differential Equations 5
Multiplying (1.4) by θ and integrating in the variable x and using (2.6)we obtain
12d
dt
∫K(t)
−K(t)|θ|2dx = −k
∫K(t)
−K(t)|θx|2dx + β
∫K(t)
−K(t)utθx dx. (2.10)
Multiplying (2.10) by α/β and summing with (2.9) it follows that
12d
dt
∫K(t)
−K(t)
[
|ut|2 + |ux|2 + α
β|θ|2
]
dx = −kαβ
∫K(t)
−K(t)|θx|2dx
+K′(t)3
2
[
|ux(K(t), t)|2 + |ux(−K(t), t)|2]
− K′(t)2
[
|ux(K(t), t)|2 + |ux(−K(t), t)|2]
.
(2.11)
Thus, following the hypothesis (H3),
12d
dt
∫K(t)
−K(t)
[
|ut|2 + |ux|2 + α
β|θ|2
]
dx ≤ −kαβ
∫K(t)
−K(t)|θx|2dx
− K′(t)2
(
1 − δ21
)[
|ux(K(t), t)|2 + |ux(−K(t), t)|2]
≤ −kαβ
∫K(t)
−K(t)|θx|2dx
− δ02
(
1 − δ21
)[
|ux(K(t), t)|2 + |ux(−K(t), t)|2]
,
(2.12)
which concludes the demonstration.
To estimate the term∫K(t)−K(t) |ux|2dx of the energy we use the following lemma.
Lemma 2.3. With the same hypothesis of Lemma 2.2, one gets
d
dt
∫K(t)
−K(t)utu dx ≤
∫K(t)
−K(t)|ut|2dx − 1
2
∫K(t)
−K(t)|ux|2dx +
Cpα2
2
∫K(t)
−K(t)|θx|2dx, (2.13)
where Cp is Poincare’s constant.
Proof. From the outline condition u(−K(t), t) = u(K(t), t) = 0 follows that
d
dt
∫K(t)
−K(t)utu dx =
∫K(t)
−K(t)|ut|2dx +
∫K(t)
−K(t)uutt dx. (2.14)
6 International Journal of Differential Equations
Replacing utt = uxx − αθx in the derivative above we get
d
dt
∫K(t)
−K(t)utu dx =
∫K(t)
−K(t)|ut|2dx −
∫K(t)
−K(t)|ux|2dx + α
∫K(t)
−K(t)uxθ dx. (2.15)
Applying Cauchy-Schwartz’s inequality, Young’s inequality, and Poincare’s inequalityin (2.15)we have
d
dt
∫K(t)
−K(t)utu dx ≤
∫K(t)
−K(t)|ut|2dx − 1
2
∫K(t)
−K(t)|ux|2dx +
Cpα2
2
∫K(t)
−K(t)|θx|2dx. (2.16)
Therefore our conclusion follows.
To estimate the term∫K(t)−K(t) |ut|2dx of the energy we introduce the function q =
∫x
−K(t) θ ds. By these conditions we have the following lemma.
Lemma 2.4. With the same hypothesis of Lemma 2.2, there are positive constants C1 and C2 such that
d
dt
∫K(t)
−K(t)utq dx ≤ C1
∫K(t)
−K(t)|θx|2dx +
β
32
∫K(t)
−K(t)|ux|2dx − β
4
∫K(t)
−K(t)|ut|2dx
+ εK(t)|ux(K(t), t)|2 + C2
[
|ux(K(t), t)|2 + |ux(−K(t), t)|2]
,
(2.17)
where C1 = ((Cp/2δ0) + αCp + (k2/2β) + (Cp/2) + (8/β)) and C2 = δ2(1 + 2βδ1 + δ31).
Proof. Calculate the derivative
d
dt
∫K(t)
−K(t)utq dx =
∫K(t)
−K(t)
∂
∂t
(
utq)
dx +K′(t)ut(K(t), t)q(K(t), t)
+K′(t)ut(−K(t), t)q(−K(t), t)
=∫K(t)
−K(t)uttq dx +
∫K(t)
−K(t)utqt dx +K′(t)ut(K(t), t)q(K(t), t).
(2.18)
From (1.3) and recording that q =∫x
−K(t) θ ds, we get
I1 =: ux(K(t), t)q(K(t), t) −∫K(t)
−K(t)uxqx dx +
∫K(t)
−K(t)αθ
[
d
dx
∫x
−K(t)θ ds
]
dx
+∫K(t)
−K(t)ut dx
[
∫x
−K(t)θt ds
]
+K′(t)ut(K(t), t)q(K(t), t).
(2.19)
International Journal of Differential Equations 7
As qx = θ and qt =∫x
−K(t) θt dswe obtain
I1 = ux(K(t), t)∫K(t)
−K(t)θ dx −
∫K(t)
−K(t)uxθ dx + α
∫K(t)
−K(t)|θ|2dx
+∫K(t)
−K(t)utqt dx +K′(t)ut(K(t), t)
∫K(t)
−K(t)θ dx.
(2.20)
Now, integrating (1.4) from −K(t) to x, multiplying by ut, and after integrating from−K(t) to K(t), it follows that
I2 =:∫K(t)
−K(t)utqt dx
= k
∫K(t)
−K(t)θxut dx − β
∫K(t)
−K(t)|ut|2dx + βut(−K(t), t)
∫K(t)
−K(t)ut dx.
(2.21)
Replacing (I2) in (I1) and from (2.6)we get
I1 =d
dt
∫K(t)
−K(t)utq dx
= ux(K(t), t)∫K(t)
−K(t)θ dx −
∫K(t)
−K(t)uxθ dx
+ α
∫K(t)
−K(t)|θ|2dx + k
∫K(t)
−K(t)θxut dx − β
∫K(t)
−K(t)|ut|2dx
+ βK′(t)ux(−K(t), t)∫K(t)
−K(t)ut dx − [
K′(t)]2ux(K(t), t)
∫K(t)
−K(t)θ dx.
(2.22)
Estimating some terms of (2.22) we obtain
d
dt
∫K(t)
−K(t)utq dx ≤ α
∫K(t)
−K(t)|θ|2dx +K′(t)K(t)|ux(K(t), t)|2 + Cp
2K′(t)
∫K(t)
−K(t)|θx|2dx
−∫K(t)
−K(t)uxθ dx − β
4
∫K(t)
−K(t)|ut|2dx +
(
k2
2β+Cp
2
)
∫K(t)
−K(t)|θx|2dx
+ 2βK(t)K′(t)2|ux(−K(t), t)|2 +K(t)K′(t)4|ux(K(t), t)|2.
(2.23)
8 International Journal of Differential Equations
Applying Poincare’s inequality in the first term of the previous inequality, using thehypothesis (H3), and grouping the common terms, we obtain
d
dt
∫K(t)
−K(t)utq dx ≤
(
αCp +Cp
2δ0+k2
2β+Cp
2
)
∫K(t)
−K(t)|θx|2dx −
∫K(t)
−K(t)uxθ dx − β
4
∫K(t)
−K(t)|ut|2dx
+K(t)K′(t)(
1 + 2βδ1 + δ31
)[
|ux(−K(t), t)|2 + |ux(K(t), t)|2]
.
(2.24)
From hypothesis (H4) we have
d
dt
∫K(t)
−K(t)utq dx ≤ C1
∫K(t)
−K(t)|θx|2dx +
β
32
∫K(t)
−K(t)|ux|2dx − β
4
∫K(t)
−K(t)|ut|2dx
+ C2
[
|ux(K(t), t)|2 + |ux(−K(t), t)|2]
.
(2.25)
where C1 and C2 are positive constants. This concludes the demonstration of the lemma.
Now we use the above auxiliary lemmas to conclude the proof of Theorem 2.1.
Proof of Theorem 2.1. Consider the functional
F(t) =∫K(t)
−K(t)
(
β
8utu + utq
)
dx. (2.26)
From Lemmas 2.3 and 2.4 we obtain
d
dtF(t) ≤ − β
32
∫K(t)
−K(t)|ux|2dx − β
8
∫K(t)
−K(t)|ut|2dx
+
(
C1 +α2βCp
16
)
∫K(t)
−K(t)|θx|2dx + C2
[
|ux(K(t), t)|2 + |ux(−K(t), t)|2]
.
(2.27)
Finally we introduce the functional
L(t) = F(t) +NE(t), (2.28)
where N ∈ N will be chosen later.
International Journal of Differential Equations 9
From Lemma 2.2 and from (2.27) it follows that
d
dtL(t) ≤ −
(
Nk − αC1
β− αβ2Cp
16
)
α
β
∫K(t)
−K(t)|θx|2dx
−(
Nδ02
− C2
)
[
|ux(K(t), t)|2 + |ux(−K(t), t)|2]
− β
32
∫K(t)
−K(t)|ux|2dx − β
8
∫K(t)
−K(t)|ut|2dx.
(2.29)
Taking N sufficiently large we find that there is a positive constant C3 such that
d
dtL(t) ≤ −C3
[
∫K(t)
−K(t)|ux|2dx +
∫K(t)
−K(t)|ut|2dx +
α
β
∫K(t)
−K(t)|θx|2dx
]
. (2.30)
Observe that L(t) and E(t) are equivalents, that is, there exists positive constant C4
satisfying
N
2E(t;u, θ) ≤ L(t) ≤ C4E(t;u, θ). (2.31)
Therefore,
d
dtL(t) ≤ −C3
C4L(t). (2.32)
Now, from equivalence (2.31) it follows that
E(t) ≤ ˜CE(0)e−γt, (2.33)
where ˜C = 2C4/N and γ = C3/C4. The proof is now complete.
References
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[3] J. A. Burns, Z. Liu, and S. M. Zheng, “On the energy decay of a linear thermoelastic bar,” Journal ofMathematical Analysis and Applications, vol. 179, no. 2, pp. 574–591, 1993.
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10 International Journal of Differential Equations
[7] M. Slemrod, “Global existence, uniqueness, and asymptotic stability of classical smooth solutions inone-dimensional nonlinear thermoelasticity,” Archive for Rational Mechanics and Analysis, vol. 76, no.2, pp. 97–133, 1981.
[8] J. L. Lions, Quelques Meethodes de Reesolution des Probleemes aux Limites Non Lineeaires., Dunod, Paris,France, 1969.
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