false position method

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FALSE POSITION METHOD F(x)=x 3 +x-3 Initial Values / Boundaries: x l = 1 , x u = 2 Tolerance Value: 10 -3 (0.001) xl xu f(xl) f(xu) xr F(xr) error Tol.va lue 1 2 -1 7 1.125 - 0.4511 7 0.1111 11 FALSE 1.125 2 - 0.4511 7 7 1.1779 82 - 0.1874 0.0449 77 FALSE 1.1779 82 2 - 0.1874 7 1.1994 15 - 0.0751 1 0.0178 7 FALSE 1.1994 15 2 - 0.0751 1 7 1.2079 14 - 0.0296 7 0.0070 36 FALSE 1.2079 14 2 - 0.0296 7 7 1.2112 57 - 0.0116 5 0.0027 6 FALSE 1.2112 57 2 - 0.0116 5 7 1.2125 68 - 0.0045 7 0.0010 81 FALSE 1.2125 68 2 - 0.0045 7 7 1.2130 82 - 0.0017 9 0.0004 23 FALSE 1.2130 82 2 - 0.0017 9 7 1.2132 82 - 0.0007 0.0001 66 TRUE Formula: =B6^3+B6-3 =C6^3+C6-3 =(B6*(E6)-(C6)*D6)/(E6-D6) =(F6^3+F6-3) 1

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False-position method

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FALSE POSITION METHODF(x)=x3+x-3

Initial Values / Boundaries:xl = 1,xu = 2 Tolerance Value:10-3 (0.001)

xlxuf(xl)f(xu)xrF(xr)errorTol.value

12-171.125-0.451170.111111FALSE

1.1252-0.4511771.177982-0.18740.044977FALSE

1.1779822-0.187471.199415-0.075110.01787FALSE

1.1994152-0.0751171.207914-0.029670.007036FALSE

1.2079142-0.0296771.211257-0.011650.00276FALSE

1.2112572-0.0116571.212568-0.004570.001081FALSE

1.2125682-0.0045771.213082-0.001790.000423FALSE

1.2130822-0.0017971.213282-0.00070.000166TRUE

Formula:=B6^3+B6-3=C6^3+C6-3=(B6*(E6)-(C6)*D6)/(E6-D6)=(F6^3+F6-3)=(F6-B6)/F6=IF(D6*G6