family feud review - armstrong feud review math 2200: elementary statistics april 28, 2011 moore...
Embed Size (px)
TRANSCRIPT
-
Family Feud Review
Math 2200: Elementary Statistics
April 28, 2011
Moore Family Feud
-
Question 1
What is an equivalence relation?
Moore Family Feud
-
Answer 1
Answer
A relation R is an equivalence relation if R is reflexive, symmetric,and transitive.
Moore Family Feud
-
Question 2
Does there exist an equivalence relation R such that R is afunction? Give an example coinciding with your claim?
Moore Family Feud
-
Answer 2
Answer
Let R be a relation on the set A = {a, b} given byR = {(a, a), (b, b)}. Then R is an equivalence relation and R is afunction. This implies there does exist an equivalence relation thatis a function.
Moore Family Feud
-
Question 3
For the compound statement If P, then Q what truth valuesmust occur for statements P and Q in order for the implication tobe false.
Moore Family Feud
-
Answer 3
Answer
The statement P must be true and Q must be false.
Moore Family Feud
-
Question 4
Prove or disprove: If n N, then n2 n + 41 is prime.
Moore Family Feud
-
Answer 4
Answer
This statement is false since 412 41 + 41 = 412 is divisible by 41.
Moore Family Feud
-
Question 5
Give an indexed collection {Sr}rN of distinct sets (that is no twosets are equal) satisfying the conditions
rN
Sr = [0, 1] andrN
Sr = {0}.
Moore Family Feud
-
Answer 5
AnswerSr = [0,
1r ]
Moore Family Feud
-
Question 6
Determine if A B = A B. Give an example supporting yourclaim.
Moore Family Feud
-
Answer 6
Answer
Let U = {a, b}, A = {a}, B = {b}. Then A B = {(b, a)} andA B = {(a, a), (b, a), (b, b)}, which implies the two sets are notequal.
Moore Family Feud
-
Question 7
What does it mean for a function to be a bijection?
Moore Family Feud
-
Answer 7
AnswerA function is a bijection if the function is onto and an injection.
Moore Family Feud
-
Question 8
Give an example of infinite sets A and B along with a functionf : A B such that f is injective, but f is not onto.
Moore Family Feud
-
Answer 8
Answer
Let A = N and B = Z with f : N Z given by f (x) = x .
Moore Family Feud
-
Question 9
Let R be a relation on the set A = {a, b, c , d , e} given byR = {(a, c), (c , d), (d , c), (b, d), (e, c)}. Is R a function? Justifyyour answer.
Moore Family Feud
-
Answer 9
Answer
Yes, R is a function since every input has exactly one output.
Moore Family Feud
-
Question 10
Give an example of a relation R on the set A = {a, b, c , d , e} suchthat R is reflexive and transitive, but not symmetric.
Moore Family Feud
-
Answer 10
Answer
R ={(a, a), (b, b), (c, c), (d , d), (e, e), (a, d), (d , e), (a, e), (d , c), (a, c)}
Moore Family Feud