fantacy foot ball introduction

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Week one introduction to determining points for fantasy football.

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Page 1: Fantacy foot ball introduction

Introduction to Orders of Operations and Linear Equations

Page 2: Fantacy foot ball introduction

Order Of Operations

Rule 1: First perform any calculations inside parentheses.

Rule 2: Next perform all multiplications and divisions, working from left to right.

Rule 3: Lastly, perform all additions and subtractions, working from left to right.

Page 3: Fantacy foot ball introduction

Example 3: Evaluate 9 - 5 ÷(8 - 3) x 2 + 6 using the order of operations.

Solution:

Step 1: 9 - 5 ÷ (8 - 3) x 2 + 6

= 9 - 5 ÷ 5 x 2 + 6 Parentheses

Step 2: 9 - 5 ÷ 5 x 2 + 6 = 9 - 1 x 2 + 6 Division

Step 3: 9 - 1 x 2 + 6 = 9 - 2 + 6 Multiplication

Step 4: 9 - 2 + 6 = 7 + 6 Subtraction

Step 5: 7 + 6 = 13 Addition

In Examples 2 and 3, you will notice that multiplication and division were evaluated from left to right according to Rule 2. Similarly, addition and subtraction were evaluated from left to right, according to Rule 3.

Page 4: Fantacy foot ball introduction

Example 2: Evaluate 3 + 6 x (5 + 4) ÷ 3 - 7 using the order of operations.

Solution:

Step 1: 3 + 6 x (5 + 4) ÷ 3 - 7

= 3 + 6 x 9 ÷ 3 - 7 Parentheses

Step 2: 3 + 6 x 9 ÷ 3 - 7 = 3 + 54 ÷ 3 - 7 Multiplication

Step 3: 3 + 54 ÷ 3 - 7 = 3 + 18 - 7 Division

Step 4: 3 + 18 - 7 = 21 - 7 Addition

Step 5: 21 - 7 = 14 Subtraction

Page 5: Fantacy foot ball introduction

When two or more operations occur inside a set of parentheses, these operations should be evaluated according to Rules 2 and 3. This is done in Example 4 below.

Example 4:

Evaluate 150 ÷ (6 + 3 x 8) -5 using the order of operations.

Solution:

Step 1: 150 ÷ (6 + 3 x 8) - 5

= 150 ÷ (6 + 24) - 5 Multiplication inside Parentheses

Step 2: 150 ÷ (6 + 24) - 5

= 150 ÷ 30 - 5 Addition inside Parentheses

Step 3: 150 ÷30 - 5

= 5 - 5 Division

Step 4: 5 - 5 = 0 Subtracti

Page 6: Fantacy foot ball introduction

Example 5: Evaluate the arithmetic expression below:

Solution:

This problem includes a fraction bar (also called a vinculum), which means we must divide the numerator by the denominator. However, we must first perform all calculations above and below the fraction bar BEFORE dividing.

Thus

Evaluating this expression, we get:

Page 7: Fantacy foot ball introduction
Page 8: Fantacy foot ball introduction

Multiplying a Fraction and a Whole Number

4 X 2/3 =

4/1 X 2/3 = 2/3 + 2/3 +2/3+ 2/3 = 8/3

Page 9: Fantacy foot ball introduction

Multiplying a Fraction and a Whole Number

4 X 2/3 =

4/1 X 2/3 = 2/3 + 2/3 +2/3+ 2/3 = 8/3

Page 10: Fantacy foot ball introduction

Multiplying a Fraction and a Whole Number

4 X 2/3 =

4/1 X 2/3 = 2/3 + 2/3 +2/3+ 2/3 = 8/3

Page 11: Fantacy foot ball introduction

Multiplying a Fraction and a Whole Number

4 X 2/3 =

4/1 X 2/3 = 2/3 + 2/3 +2/3+ 2/3 = 8/3

Page 12: Fantacy foot ball introduction

Multiplying a Fraction and a Whole Number

4 X 2/3 =

4/1 X 2/3 = 2/3 + 2/3 +2/3+ 2/3 = 8/3

Page 13: Fantacy foot ball introduction

T= 2V= 1P=14R=3C=0I=2F=0

Problem One

Page 14: Fantacy foot ball introduction

T= 3V= 0P=1R=17C=7I=4F=1

Problem Two