february 3, 2015
TRANSCRIPT
Notes
All Khan Due @ end of the dayFinal Exam Grades Posted @ v6 Math
Khan for this Week PostedAlt.Khan Available Now
Notebooks: 1st leave today, 2nd Tuesday, 3rd
Wed., 4th Thursday.
Warm Up:
1. Solve the inequality: -1 < π βππ
π< 3
4 > x and x > -6; write as one inequality -6 < x < 4
2. Solve for x: 1 -π
π βπ
1 + π
π βπ
Eliminate both denominators. Hint: There are 2 terms in both the numerator and the denominator.
π β π 1 -π
π βππ β π β π
π β π + π
π β π
π
A quick look at the 3rd quarter
Warm Up:
5. Graph the inequality: 2x + 3y > 12
x
y
2-2
(0,4)
(6,0)
3. Write an equation for a horizontal line
6. Write an equation for a line perpendicular to: βπ
πx = 2y + 12.
4. Write an equation with an undefined slope
a. (4, 5); y < x + 1
Tell whether the ordered pair is a solution of the inequality.
y < x + 1
Substitute (4, 5) for (x, y).Substitute (1, 1) for (x, y).
b. (1, 1); y > x β 7
y > x β 7
5 4 + 1
5 5 <
1 1 β 7
>1 β6
(4, 5) is not a solution. (1, 1) is a solution.
The boundary line also represents the related linear equation....what is the related equation?
What is the Inequality?
y > x + 4
Graphing Linear Inequalities
Step 1Solve the inequality for y (solved EXACTLY like an equation; slope-intercept form).
Step 2Graph the solution (the boundary line). Use a solid line for β€ or β₯. Use a dashed line for < or >.
Step 3Shade the half-plane above the line for y > or β₯. Shade the half-plane below the line for y < or y β€. Check your answer.
Graph y > -3x + 2 on the coordinate plane.
x
y
Boundary Line
y = -3x + 2m = -3 b = 2
Test a point not on the line
test (0,0)
0 > -3(0) + 2
Not true!
Graph y -3x + 2 on the coordinate plane.
x
y
Instead of testing a point
If in y = mx + b form...
Shadeup
Shadedown
Solidline
Dashedline
> <
Graphing Linear Inequalities
Graph the solution of the linear inequality.5x + 2y > β8
Step 1 Solve the inequality for y.Step 2 Graph the boundary line and Use a dashed line for >.
y = βπ
πx β 4
Step 3: Test a point not on the line. Use (0,0) when you can.
5(0) + 2(0) > -8, True or False?
If true, include that point in your shading.
Graph the inequality.
3x - 4y > 12-3x -3x
-4y > -3x + 12
-4 -4
y < x - 3
m = b = -3
Boundary Line
x
y
3
4
π
π
π
π
Problem
You have less than $5.00 in nickels and dimes, find an inequality and sketch a graph to describe how many of each coin you have.
Let n = # of nickels
Let d = # of dimes
0.05 n + 0.10 d < 5.00
or 5 n + 10 d < 500
Graphing Linear Inequalities
When dealing with angled lines,If the inequality is > or > ,then you shade above
If the inequality is < or < ,then you shade below
Finding a point not on the line is still the safest and
surest method to determine where to shade.
Graph y -3x + 2 on the coordinate plane.
x
y
Instead of testing a point
Arrange the equation in y = mx + b form...
Shadeup
Shadedown
Solidline
Dashedline
> <
Graphing Linear Inequalities
Graph on the coordinate plane.
3x - 4y > 12-3x -3x
-4y > -3x + 12
-4 -4
y < x - 33
4
m = b = -33
4
Boundary Line
x
y
Graphing Linear Inequalities
If the point makes the inequality true, shade that side of the line.
If the point does not make the inequality true, shade the opposite side of the line.Use (0,0) as a test if this point is not on the line.
Quadrilateral ABCD has diagonals AC and BD. Determine whether segment AC is perpendicular to BD
AC, m = 7
BD, m = βπ
π
The lines are perpendicular.