fiam exercitii

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caz 1 20 25 25 36 26 45 26 33 39 34 55 56 45 55 46 36 39 35 25 22 34 44 42 49 46 35 55 33 40 41 Numar esantioane (n)= 30 Suma esantioanelor (SUM)= 1142 Maximul (MAX) (Xmax) = 56 Minimul (MIN) (Xmin)= 20 Media (MEAN AVERAGE)= 38.06667 Mediana (MEDIAN)= 37.5 Moda (Mode)= 25 Varianta (VARIANCE)= 220.5 Deviatia standard (STDEV)= 10.31883 Coeficient de simetrie (SKEW)= 0.097126 Coeficient de aplatizare (KURT)= -0.77965 Cuantila (ordin 0)= 20 Cuantila (ordin 1)= 33 Cuantila (ordin 2)= 37.5

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Page 1: FIAM Exercitii

caz 1202525362645263339345556455546363935252234444249463555334041

Numar esantioane (n)= 30Suma esantioanelor (SUM)= 1142Maximul (MAX) (Xmax) = 56Minimul (MIN) (Xmin)= 20Media (MEAN AVERAGE)= 38.06667Mediana (MEDIAN)= 37.5Moda (Mode)= 25Varianta (VARIANCE)= 220.5Deviatia standard (STDEV)= 10.31883Coeficient de simetrie (SKEW)= 0.097126Coeficient de aplatizare (KURT)= -0.779651Cuantila (ordin 0)= 20Cuantila (ordin 1)= 33Cuantila (ordin 2)= 37.5

Page 2: FIAM Exercitii

Cuantila (ordin 3)= 45Cuantila (ordin 4)= 56

3087.867Abaterea medie standard (σ)= 55.56858

-128.6391x+3*σ= 204.7724intervalul normal de variatie IVN=6*σ= 333.4115Limita superioara Ls=[(x+3*σ)+x]/2= 121.4195Limita inferioara Li=[(x-3*σ)+x]/2= -45.2862Intervalul de confidenta -95% 34.37419(pentru α=0.05) -95% 41.75914

Cuantila inferioara Zi=(Li-x)/σ= -1.5Cuantila superioara Zs=(Ls-x)/σ= 1.5Probabilitatea de rebut la partea inferioara i=F(-Zi)=1-F(Zi) 0.566807Probabilitatea de rebut la partea superioara αs=F(Zi)= 0.433193Procentul estimat al rebutului la partea inferioara pi=100*αi= 56.6807Procentul estimat al rebutului la partea superioara ps=100*αs= 43.3193Procent estimat al rebutului total pt(%)=pi(%)+ps(%)= 100Lungime interval I=(Xmax-Xmin)/(1+3.322*lg(n)= 3Nr clase= (Xmax-Xmin)/I= 12

Dispersia (s²)=

x-3*s=

Page 3: FIAM Exercitii

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Page 4: FIAM Exercitii

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Page 5: FIAM Exercitii

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