final exam review · 1, 7p 4) 0 p 6 p 3 p 2p2 3 5p 6 p 7p 6 4p 3p 2 5p 3 11p 6 1234 142) (2, 225°)...
TRANSCRIPT
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Precalculus
Final Exam Review
Name___________________________________ ID: 1
Date________________ Period____©c X2p0w1o8c FK_uRtLaZ fS_oPfYtDwlavrAeI WLFLCC[.e y UAQl[lE ar_iWgCh]t^sH tr[eeshemruvyendh.
-1-
Use identities to find the value of each expression.
1) If sin (q - p
2 ) = 0.52, find cos q . 2) If sin (-q ) = 0.16, find cos (q - p
2 ).
3) Find csc q and tan q
if cot q = 9
5 and sec q > 0.
4) Find tan q and sec q
if sin q = 3
4 and cot q > 0.
Verify each identity.
5) sec2 x + cot2 x = tan2 x + csc2 x 6)
csc2 x
tan2 x =
cot2 x
sin2 x
7) sec x + cos x = cos2 x + 1
cos x
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-2-
8) cot2 xsin x
= csc x
tan2 x 9)
cot x
sec2 x =
cos3 xsin x
10) tan x
sec3 x = cos2 xsin x
11) 2cos2 x(1 - cos 2x) = sin2 2x
12) 2sin2 xcos x = sin 2xcsc x
13) cos xtan 2x
= cos 2x2sin x
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-3-
14) tan x + sec2 x = 2(sin xcos x + 1)
1 + cos 2x
Use the half-angle identities to find the exact value of each.
15) cos 22.5° 16) sin 67.5°
Find the exact value of each.
17) tan q = -4
3 where
7p
2 £ q < 4p
Find sinq
2
18) cos q = 4
5 where 0 £ q <
p
2
Find sinq
2
Find the exact value of each expression.
19) tan-1 020) tan-1 3
3
21) tan-1 322) tan-1 -
3
3
23) cos-1 0 24) cos-1 1
2
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-4-
25) tan-1 126) cos-1 2
2
27) sin-1 -3
2
28) cos-1 1
29) cos-1 3
2
30) sin-1 1
31) cot sin-1 3 34
3432) tan-1 (cos
p
2 )
33) csc sin-1 57
1134) sin-1 (cot
3p
4 )
35) cos-1 (cotp
4 ) 36) tan sin-1 6 2
11
37) cos-1 (sec 0)38) sin cos-1 3 11
11
39) sin-1 (tan 0)40) csc sin-1 13
7
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-5-
41) tan-1 (sec p)42) sec sin-1 4
5
Write each trigonometric expression as an algebraic expression.
43) cot cos-1 x 44) csc sin-1 x
45) sin cos-1 x 46) csc tan-1 x
47) cot sin-1 x 48) sec sin-1 x
Find the exact value of each.
49) sin2p
9cos
p
18 - cos
2p
9sin
p
1850)
tan43p
18 - tan
5p
9
1 + tan43p
18tan
5p
9
51) sin 159cos 24 - cos 159sin 24 52) sin 104cos 46 + cos 104sin 46
Simplify.
53) cos 2q cos -q + sin 2q sin -q54)
tan 5q + tan -6q
1 - tan 5q tan -6q
55) cos 5vcos 6v - sin 5vsin 6v56)
tan -2x - tan 6x1 + tan -2xtan 6x
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-6-
Write each trigonometric expression as an algebraic expression.
57) cos (tan-1 x + tan-1 0)58) tan (tan-1 x - sin-1 2
2 )
Verify each identity.
59) sin (q - 3p
2 ) = cos q 60) sin (p
2 + q ) = cos q
State the number of possible triangles that can be formed using the given measurements.
61) In ZXY, Zm = 63°, y = 30, z = 6 62) In TRS, Tm = 138°, s = 26, t = 20
63) In HPK, Hm = 66°, k = 28, h = 8 64) In FDE, Em = 55°, e = 21, d = 4
Find each measurement indicated. Round your answers to the nearest tenth.
65) In DEF, Dm = 151°, Em = 9°, d = 34Find e
66) In BCA, Bm = 57°, a = 22, b = 5Find c
67) In DEF, Dm = 31°, f = 27, d = 20Find e
68) In STR, Tm = 36°, Rm = 30°, s = 42Find r
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-7-
69) In KHP, Km = 139°, p = 23, k = 27Find Pm
70) In ZXY, Ym = 89°, y = 16, x = 8Find Xm
71) In ABC, Cm = 73°, c = 20, b = 14Find Bm
72) In BCA, Bm = 16°, a = 29, b = 8Find Cm
Solve each triangle. Round your answers to the nearest tenth.
73) In YZX, Ym = 75°, x = 21, y = 8 74) In STR, Sm = 137°, Rm = 23°, r = 8
75)
30 m
13 m
AB
C
73°
76)
29 mi
13 mi
21 miB
C
A
77)
28.7 in29.5 in
B
CA
89°
78)
24 in
21 in
CA
B
89°
79) a = 24 mi, b = 15 mi, Cm = 107° 80) a = 21 in, b = 23 in, c = 8 in
81) a = 28 km, c = 18 km, b = 12 km 82) b = 24.5 m, c = 25.8 m, a = 23.4 m
Find each measurement indicated. Round your answers to the nearest tenth.
83) c = 16.6 in, b = 20.1 in, Am = 119.1°Find a
84) Cm = 128°, a = 28 mi, b = 19 miFind c
85) c = 10 yd, b = 17 yd, Am = 25°Find a
86) b = 15 in, Am = 31°, c = 28 inFind a
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-8-
Find the area of each triangle to the nearest tenth.
87)
9 in AB
C
112°22°
88)
10 m TR
S
84°65°
89)
5 cm RS
T
137°21°
90) 10 m
A
BC
59°
58°
91)
11 yd
15 yd
B
CA
34°
92)
4 in 5.3 in
T
R
S39°
93)
6 yd
9 yd
B
C
A127°
94)
5 km
8 km
F
DE
62°
Find the component form of the resultant vector.
95) u = 2, 4g = 0, 4Find: u - g
96) u = -4, -10Find the vector opposite u
97) f = -2, -5Find: -4f
98) Given: T = (9, 0) X = (-1, -4) Y = (-1, 0) Z = (-7, 4)Find: TX + 4YZ
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-9-
99) Given: A = (5, -5) B = (7, 3)Find: 7AB
100) Given: A = (-3, 0) B = (-9, -10)Find the vector opposite AB
Express the resultant vector as a linear combination of unit vectors i and j.
101) Given: A = (-5, -7) B = (0, 4) C = (3, 8) D = (8, -6)Find: 7AB - 9CD
102) u = -5i + 7jFind the vector opposite u
103) f = -8i + 2jFind the vector opposite f
104) f = -8i - 8jUnit vector in the opposite direction of f
105) f = 30i - 1309 jFind the vector opposite f
106) Given: A = (9, 7) B = (2, -10)Find: 3 × AB
107) u = -6i + 2jUnit vector in the direction of u
Find the component form of the resultant vector.
108) u = 1, 3 2Unit vector in the direction of u
Find the magnitude and direction angle of the resultant vector.
109) f = -4, -12Unit vector in the direction of f
110) u = -9, 40Unit vector in the direction of u
111) u = -12, 11Unit vector in the opposite direction of u
112) a = 15, 36Unit vector in the opposite direction of a
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-10-
113) f = -2, 7g = 10, -6Find: -7f - 7g
114) f = -9, -8b = 0, -11Find: -2f - 5b
115) u = -5, -4Unit vector in the direction of u
116) f = 12, -10b = -2, 6Find: -10f + 6b
Find the component form, magnitude, and direction angle of the resultant vector.
117) f = 12, 7g = 5, 3Find: -6f + 2g
118) a = 12, -4g = 12, 12Find: 4a + 8g
Express the resultant vector as a linear combination of unit vectors i and j, and find themagnitude and direction angle.
119) f = 4ig = 8i - jFind: -8f + 4g
120) u = -8i + 11jv = -i - 12jFind: -10u + 5v
Draw a diagram to illustrate the horizontal and vertical components of the vector. Then find themagnitude of each component.
121) a = 11, 280° 122) m = 29, 37°
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-11-
Draw a vector diagram to find the resultant of each pair of vectors using the triangle method. Then state the magnitude and direction angle of the resultant.
123) t = -5, 12 u = 8, 15 124) t = 8, 15 u = 5, -12
Draw a vector diagram to find the resultant of each set of vectors. Then state the magnitudeand direction angle of the resultant.
125) a = -14, 12 b = 5, 13 c = 5, -12 126) t = 5, -12 u = -8, 6 v = -8, 15
Use the given vectors to draw a vector diagram for each expression using the triangle method. Then state the magnitude and direction angle of the resultant.
127) a = -8, 15 b = 19, 29a + b
128) m = 12, 16 n = 1, -10-8m - 3n
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-12-
Use the given vectors to draw a vector diagram for each expression using the parallelogrammethod. Then state the magnitude and direction angle of the resultant.
129) a = -10, 1 b = 6, -5-7a - 9b
130) a = 12, 16 b = 3, -142a + 3b
Find the dot product of the given vectors.
131) u = 2, -4v = -3, 5
132) u = 9, 2v = -5, -7
133) u = 2i + 9jv = -7i + j
134) u = 3i - 4jv = -3i - 9j
State if the two vectors are parallel, orthogonal, or neither.
135) u = 7i + 2jv = 2i + 7j
136) u = -3i + 3jv = 16i - 12j
Find the measure of the angle between the two vectors.
137) u = 8i + 5jv = 6i + 8j
138) u = -9i - 7jv = -8i + 7j
139) u = -8i - 3jv = -8i + 5j
140) u = 6i - 5jv = i + j
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-13-
Find all pairs of polar coordinates that describe the same point as the provided polarcoordinates.
141) (1, 7p
4 )
0
p
6
p
3
p
22p
3
5p
6
p
7p
6
4p
3 3p
2
5p
3
11p
6
1 2 3 4
142) (2, 225°)
0°
30°
60°90°
120°
150°
180°
210°
240°
270°
300°
330°
1 2 3 4
Convert each pair of polar coordinates to rectangular coordinates.
143) (3, 300°)144) (3,
7p
4 )
Convert each pair of rectangular coordinates to polar coordinates where r > > 00 and 00 £ £ qq < < 22pp .
145) ( 2
2, -
2
2 ) 146) (1
2,
3
2 )
Two points are specified using polar coordinates. Find the distance between the points.
147) (2, 11p
6 ), (2, 7p
12 ) 148) (1, 3p
2 ), (3, p
4 )
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-14-
Convert each equation from polar to rectangular form. Then graph the polar equation.
149) tan q = 5
0
p
6
p
3
p
22p
3
5p
6
p
7p
6
4p
3 3p
2
5p
3
11p
6
1 2 3 4 5 6 7
150) cot q = 5
0
p
6
p
3
p
22p
3
5p
6
p
7p
6
4p
3 3p
2
5p
3
11p
6
1 2 3 4 5 6 7
151) tan q = 4
0
p
6
p
3
p
22p
3
5p
6
p
7p
6
4p
3 3p
2
5p
3
11p
6
1 2 3 4 5 6 7
152) q = p
6
0
p
6
p
3
p
22p
3
5p
6
p
7p
6
4p
3 3p
2
5p
3
11p
6
1 2 3 4 5 6 7
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-15-
Consider each polar equation over the given interval. Classify the curve; determine if the graphis symmetric with respect to the origin, polar axis, and line qq =pp /22; find the values of qq where r is zero; find the maximum r value and the values of qq where this occurs; and sketch thegraph.
153) r2 = 25sin (2q ), 0 ≤ q < 2p
0
p
6
p
3
p
22p
3
5p
6
p
7p
6
4p
3 3p
2
5p
3
11p
6
1 2 3 4 5 6 7
154) r2 = 4sin (2q ), 0 ≤ q < 2p
0
p
6
p
3
p
22p
3
5p
6
p
7p
6
4p
3 3p
2
5p
3
11p
6
1 2 3 4 5 6 7
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-16-
155) r2 = 16cos (2q ), 0 ≤ q < 2p
0
p
6
p
3
p
22p
3
5p
6
p
7p
6
4p
3 3p
2
5p
3
11p
6
1 2 3 4 5 6 7
156) r2 = 49sin (2q ), 0 ≤ q < 2p
0
p
6
p
3
p
22p
3
5p
6
p
7p
6
4p
3 3p
2
5p
3
11p
6
1 2 3 4 5 6 7
Convert numbers in rectangular form to polar form and numbers in polar form to rectangularform.
157) 4(cosp
4 + isin
p
4 ) 158) 3(cos 45 + isin 45)
Simplify. Write your answer in rectangular form when rectangular form is given and in polarform when polar form is given.
159) 4(cos 210 + isin 210) × 5(cos 120 + isin 120)
160) (6 + 6i)(-2 + 4i)161)
6(cos 60 + isin 60)3(cos 225 + isin 225)
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-17-
162) 15(cos 300 + isin 300)
2 5(cos 240 + isin 240)163) (5(cos 60 + isin 60))3
164) (2(cos 60 + isin 60))4
Find the absolute value.
165) 6(cos 90 + isin 90) 166) 2 2 - 2i 2
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-18-
Answers to Final Exam Review (ID: 1)
1) -0.52 2) -0.163)
106
5 and
5
94)
3 7
7 and
4 7
7
5) sec2 x + cot2 x Use tan2 x + 1 = sec2 x
tan2 x + 1 + cot2 x Use cot2 x + 1 = csc2 x
tan2 x + csc2 x ■
6) csc2 x
tan2 xUse cot x =
1
tan x
csc2 xcot2 x Use csc x = 1
sin x
cot2 x
sin2 x■
7) sec x + cos x Decompose into sine and cosine
1
cos x + cos x Simplify
cos2 x + 1
cos x■
8) cot2 xsin x
Use cot x = 1
tan x
1
tan2 xsin xUse csc x =
1
sin x
csc x
tan2 x■
9) cot x
sec2 xUse cot x =
cos xsin x
cos x
sec2 xsin xUse sec x =
1
cos x
cos3 xsin x
■
10) tan x
sec3 xDecompose into sine and cosine
sin xcos x
( 1
cos x)3Simplify
cos2 xsin x ■
11) 2cos2 x(1 - cos 2x) Use cos 2x = 1 - 2sin2 x
4cos2 xsin2 x Use sin 2x = 2sin xcos x
sin2 2x ■
12) 2sin2 xcos x Use sin 2x = 2sin xcos x
sin xsin 2x Use csc x = 1
sin x
sin 2xcsc x
■
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-19-
13) cos xtan 2x
Use tan 2x = sin 2xcos 2x
cos xcos 2xsin 2x
Use sin 2x = 2sin xcos x
cos xcos 2x2sin xcos x
Cancel common factors
cos 2x2sin x
■
14) tan x + sec2 x Decompose into sine and cosine
sin xcos x
+ ( 1
cos x)2
Simplify
sin xcos x + 1
cos2 xUse cos2 x =
1 + cos 2x2
2(sin xcos x + 1)1 + cos 2x
■
15) 2 + 2
216)
2 + 2
217) -
5
518)
10
10
19) 020)
p
621)
p
322) -
p
6
23) p
224)
p
325)
p
426)
p
4
27) -p
3
28) 029)
p
630)
p
2
31) 5
3
32) 033)
11 57
5734) -
p
2
35) 036)
6 2
7
37) 038)
22
1139) 0
40) 7 13
1341) -
p
442)
5
3
43) x
1 - x244)
1
x45) 1 - x2
46) 1 + x2
x
47) 1 - x2
x48)
1
1 - x249)
1
250) -
3
3
51) 2
252)
1
2
53) cos 3q 54) tan -q
55) cos 11v 56) tan -8x57)
x2 + 1
x2 + 158)
x - 1
1 + x
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-20-
59) sin (q - 3p
2 )= sin q cos
3p
2 - cos q sin
3p
2= sin q × 0 - cos q × -1= cos q
60) sin (p
2 + q )
= sinp
2cos q + cos
p
2sin q
= cos q + 0sin q= cos q
61) None
62) None 63) None 64) One triangle 65) 1166) Not a triangle 67) 37.5 or 8.8 68) 23 69) 34°70) 30° 71) 42° 72) 76.3° or 71.7° 73) Not a triangle74) Tm = 20°, s = 14, t = 7 75) Bm = 25.4°, Cm = 81.6°, a = 29 m76) Bm = 24°, Cm = 41°, Am = 115° 77) Cm = 46.3°, Am = 44.7°, b = 40.8 in78) Am = 41.6°, Bm = 49.4°, c = 31.6 in 79) Am = 46.2°, Bm = 26.8°, c = 31.8 mi80) Am = 65.6°, Bm = 94.1°, Cm = 20.3° 81) Cm = 26°, Am = 137°, Bm = 17°82) Bm = 59.5°, Cm = 65.1°, Am = 55.4° 83) 31.7 in 84) 42.4 mi85) 9 yd 86) 17 in 87) 19.6 in² 88) 87.5 m²89) 8.2 cm² 90) 44.1 m² 91) 70.1 yd² 92) 9.8 in²93) 9.6 yd² 94) 19.9 km² 95) 2, 0 96) 4, 1097) 8, 20 98) -34, 12 99) 14, 56 100) 6, 10101) -10i + 203j 102) 5i - 7j 103) 8i - 2j
104) 2 × i2
+ 2 × j2
105) -30i + 1309 × j 106) -7 3 × i - 17 3 × j107) -
3 10 × i10
+ 10 × j10
108) 19
19,
3 38
19
109) 251.57° 110) 102.68° 111) 317.49°
112) 247.38° 113) 7 65 » 56.436; 187.13° 114) 5365 » 73.246; 75.77°115) 218.66° 116) 4 2245 » 189.526; 134.14°117) -62, -36
2 1285 » 71.694; 210.14°118) 144, 80
16 106 » 164.73; 29.05°119) -4j
4; 270°120) 75i - 170j
5 1381 » 185.809; 293.81°121)
a y
x
Horizontal: 1.91Vertical: -10.83
122)
my
x
Horizontal: 23.16Vertical: 17.45
123)
t
u
t + u
27.17; 83.66°
124)
tu
t + u
13.34; 12.99°
125)
a
b c
a + b + c
13.6; 107.1°
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Worksheet by Kuta Software LLC
-21-
126)
t
u
v
t + u + v
14.21; 140.71°
127)
9a
b
9a + b
146.89; 111.15°
128)
-8m
-3n
-8m - 3n
139.3; 224.71°
129)
-7a
-9b-7a - 9b
41.23; 67.17°
130)
2a
3b
2a + 3b
34.48; 343.14°
131) -26
132) -59 133) -5 134) 27 135) Neither136) Neither 137) 21.12° 138) 79.06° 139) 52.56°140) 84.81°
141) (1, 7p
4 + 2np) and (-1,
7p
4 + (2n + 1)p)
where n is an integer142) (2, 225° + 360n°) and (-2, 45° + 360n°)
where n is an integer 143) (3
2, -
3 3
2 ) 144) (3 2
2, -
3 2
2 )145) (1,
7p
4 ) 146) (1, p
3 ) 147) 2 2 + 2 » 3.696
148) 10 + 3 2 » 3.774 149)
0
p
6
p
3
p
22p
35p
6
p
7p
64p
33p
2
5p
3
11p
6
2 4 6
y = 5x150)
0
p
6
p
3
p
22p
35p
6
p
7p
64p
33p
2
5p
3
11p
6
2 4 6
y = x5
151)
0
p
6
p
3
p
22p
35p
6
p
7p
64p
33p
2
5p
3
11p
6
2 4 6
y = 4x152)
0
p
6
p
3
p
22p
35p
6
p
7p
64p
33p
2
5p
3
11p
6
2 4 6
y = x 3
3
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Worksheet by Kuta Software LLC
-22-
153)
0
p
6
p
3
p
22p
35p
6
p
7p
64p
33p
2
5p
3
11p
6
2 4 6
LemniscateSymmetric about the origin
r = 0 when q = {0, p
2, p,
3p
2 }r = 5 when q = {p
4,
5p
4 }
154)
0
p
6
p
3
p
22p
35p
6
p
7p
64p
33p
2
5p
3
11p
6
2 4 6
LemniscateSymmetric about the origin
r = 0 when q = {0, p
2, p,
3p
2 }r = 2 when q = {p
4,
5p
4 }
155)
0
p
6
p
3
p
22p
35p
6
p
7p
64p
33p
2
5p
3
11p
6
2 4 6
LemniscateSymmetric about the origin,
polar axis, and line q = p
2
r = 0 when q = {p
4,
3p
4,
5p
4,
7p
4 }r = 4 when q = {0, p}
156)
0
p
6
p
3
p
22p
35p
6
p
7p
64p
33p
2
5p
3
11p
6
2 4 6
LemniscateSymmetric about the origin
r = 0 when q = {0, p
2, p,
3p
2 }r = 7 when q = {p
4,
5p
4 }
157) 2 2 + 2i 2158)
3 2
2 +
3 2
2i
159) 20(cos 330 + isin 330)
160) -36 + 12i 161) 2(cos -165 + isin -165)162)
3
2(cos 60 + isin 60)
163) 125(cos 180 + isin 180) 164) 16(cos 240 + isin 240) 165) 6166) 4