fire water tank foundation
TRANSCRIPT
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. Gr&/e n$#r!&%#n
,inished ground level = E; 100.00 m
. C&,u,&%#n $#r "e%#n&, 2r#2er%e" #$ rn* +&,, $#un/&%#n
%rea at &ase = % = 11.
"ection modulus at &ase = ? = 4
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. C&"e () - DL 6 LL 6 WL
!otal vertical load = 6 =
= 112
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C3ECK FOR O8ERTURNING
C&"e (1) - T&n' E!2% #n/%#n - DL 6 WL
7verturning moment due to wind = =
= 4. 2.5 + 2520
= 5< 9.m
3estoring moment = =
= os h
$istance from &ottom of ring wall at which the force 6s
acts
e
!1 s & e1
!2
6e e
2
!
6s e
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!otal torsional moment = =
= 2.< 9.m
,actored torsional moment = ! = 5.4 9.m
"hear stress due torsion = = 2!
= 0.05
= = 0.42
TORSION REINFORCEMENT NOT RE9UIRED
$=18.m
;=0.5m
! 6s
= 2. m
6e
hw2
t=0.8m
L#n*%u/n&, ren$#re!en% /ue %# &//%#n&, !#!en%
@ = !- $2;+t2
= 5.4285--18. 2 0.5 + -0.8 2
= 20.
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=
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!otal #ressure at &ottom = =
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F#re" &% ;&"e #$ rn* +&,,
%ial load = 6 = 112
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FOOTING
'earing #ressure for $esign -Ultimate state
$esign maimum &earing #ressure = = 15.4
15.4
Conservativel( assuming maimum &earing #ressure
-@ = 28.
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DESIGN FOR TEMPERED WATER TANK FOUNDATION - RING WALL Rev.0
MATERIAL DATA
Characteristic strength of concrete = 40
Characteristic strength of steel = 4
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. Gr&/e n$#r!&%#n
,inished ground level = E; .000 m
. C&,u,&%#n $#r "e%#n&, 2r#2er%e" #$ rn* +&,, $#un/&%#n
%rea at &ase = % = 2.<
"ection modulus at &ase = ? = 1.0
6erimeter of !an9 = 7 = 5.
LOAD DATA
-3eference $ocument o.
Em#t( weight of tan9 = 14.00 9
!est eight of !an9 = 244.10 9
7#erating weight of !an9 = 251.10 9
=
1. De&/ ,#&/"
eight of !an9 shell + roof = = 12.00 9
eight of ring wall = = 9
eight of ring wall footing = = 2< 9
eight of soil over the footing on innerside = = 0 9
eight of soil over the footing on outerside = = 0 9eight of liuid #ortion on wall = = 2 9
eight of liuid #ortion on footing = = 0 9
!otal dead load at &ase = =
= 14 9
. Lve ,#&/
-1.29m2 is considered
;ive load from tan9 roof = = .10 9
. Wn/ L#&/ (WL)
-3eference $ocument o.
:oriAontal shear at to# of ring wall = = 4. 9
@oment at to# of ring wall = =
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. C&"e () - DL 6 LL 6 WL
!otal vertical load = 6 =
= 150 9
@oment = @ = 15 9.m
6ressure due to aial load = = 6%
= 58
6ressure due to moment = = @?
= 15
@a. u#ward soil #ressure = =
=
B 18 OKA5
@in. u#ward soil #ressure = =
= 4 OKA5
. C&"e () - 0.7 DL 6 WL
"ince the main resisting load is dead load/ the &earing ca#acit( needs to &e
chec9ed under minimum dead load condition with a load factor of 0. to
ensure that there will &e no tension develo#s &eneath the &ase of ring wall.
@inimum dead load =
= 15 9@oment = @ = 15 9.m
6ressure due to aial load = = 6%
= 5
B 18 OKA5
6ressure due to moment = = @?
= 15
@in. soil #ressure = f =
= OKA5
C3ECK FOR SLIDING
C&"e (1) - T&n' e!2% #n/%#n - DL 6 WL
:oriAontal force causing sliding =
= 4 9
3esisting force =
=
= 40
,actor of safet( against sliding =3esisting force
"liding force
=40
4
= .24 1.5 OKA5
Note : Conservatively passive resistance of soil is ignored
6$ + 6
;
#1
9m2
#2
9m2
f 1
#1 + #
2
9m2
9m2
f 2
#1 #
2
9m2
0. -61+ 6
2+6+64+65+6<
#1
9m2
9m2
#2
9m2
#1 #
2
9m2
:1
D !otal self weight
D -61+ 62+6+64+65
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C3ECK FOR O8ERTURNING
C&"e (1) - T&n' E!2% #n/%#n - DL 6 WL
7verturning moment due to wind = =
= 4. 1.2 + os h
$istance from &ottom of ring wall at which the force 6s
acts
e
!1 s & e1
!2
6e e
2
!
6s e
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!otal torsional moment = =
= . 9.m
,actored torsional moment = ! = 5.8 9.m
"hear stress due torsion = = 2!
= 0.05
= = 0.42
TORSION REINFORCEMENT NOT RE9UIRED
$=1.8m
;=0.2125m
! 6s
= 1.< m
6e
hw2
t=0.45m
L#n*%u/n&, ren$#re!en% /ue %# &//%#n&, !#!en%
@ = !- $2;+t2
= 5.04
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= 15.0 9m2
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!otal #ressure at &ottom = = 15 + 14.4
= 2.4
!otal #ressure at !o# = = 15.0
%ve 6ressure = = -6ma+6min 2
= 22.2
:oo# tension = =
= 18.0 9m
$=1.8m
,actored hoo# tension = ! = 1.5 18
= 2 9m
%rea of steel reuired =
=2 1000
0.0 4
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F#re" &% ;&"e #$ rn* +&,,
%ial load = 6 = 150 9 DL 6 LL
@oment = @ = 15 9 m
!he annular section is chec9ed with the use of charts given in 3e(noldLs hand &oo9
-wor9ing stress method
@odular ratio = = .1
= = 1.
@ean radius of the ring wall = r = 0.125 m
!hic9ness of ring wall = h = 450 mm
3atio = 0.00
3atio = 0.0
3atio h / r = 0.4
3eferring to the chart given in ta&le 1
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FOOTING
'earing #ressure for $esign -Ultimate state
$esign maimum &earing #ressure = = 110.02
110.02
Conservativel( assuming maimum &earing #ressure
-@ = 0 9 m
Calculation for reinforcement.
,or moment
Effective de#th = d = 1 mm
!he ratio = 9 =
= 0
;ever arm = A = .4.4.4= 1 mm 6art 1
;ever arm = = 0.5d
= 01.15 mm
!herefore the design FAF value = A = 1 mm
3einforcement reuired = =
= 0
= = 0.001
= 520
12 K 150 = 54
@a clear s#acing of &ars in tension =
= 222.22 mm
%ctual clear s#acing #rovided = 18 mm
B 222.22 mm OKA5
Pun