KERTAS 2

QUESTION 1

Section Mark Answer Note

(a) 1 Concave mirror

(b) 1 Reflection

(c) 1 Magnified // Upright // Virtual Reject : If answer morethan one and contradict

(d) 1 Decrease // same size as object

TOTAL 4

QUESTION 2

Section Mark Answer Note

(a) 1 Diffraction

(b) 1

1

[]

')J

)J

1 - Correct patteren2- Wavelength no

changed

(c) 1

1

20

1.5 cm

1- Correct substitution

2- Answer with correct

unit

TOTAL 4

QUESTION 3

Section Mark

(a)

(b)

(c)

TOTAL

Answer

Bourdon gaugeKinetic energy// velocity// speed of air moleculesincrease

Frequency collision between air molecules andwall of the flask increase // change of momentumincrease // force increase // pressure increase15+273//37+273//288//310

2.7xI05288

2.9063 xlO5 Pa

_5l310

Note

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QUESTION 4

Section Mark Answer Note

(a) 1 Beam of electron moving at high speed // fastmoving electron

(b)(i) 1

CaflaSine

ode ray\r Katod

(b)(ii) 1 Cathode ray has negatively charged // unlikecharges between cathode ray and plate producesforce of attraction

(b)(iii) Increase

The strength of electric field increase //forceincrease

(c)(ii) -x9xl0-31xv2=4.5xl0-162

v = 3.1623 jdO'ms"1TOTAL

QUESTION 5

Section

(a)

(b)(0

(ii)

(iii)

(c)(0

(ii)

(d)

(e)

1

Tot/Jum : 8

Answer

Theproperty of a material return to itsoriginal state after anapplied external force is removed.Spring N is thicker than spring M.Distanceofbouncingball in Diagram 5.2 is greater / higherthan in Diagram 5.1.Elastic potential energy stored in spring N is greater than inspring MThe greaterthe elastic potential energy, the greater thedistance of bouncing ball.Thegreater the thickness of a spring, thegreater theelasticpotential energy stored.As the thickness of the spring increases, the elastic potentialenergy stored in the spring increases // ... .directlyproportional // The greater.Elastic potential energy of the springs changes to kineticenergy of the balls.

Note

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QUESTION 6Section Mark

(a)

(b)(i)

(b)(ii)

(c)

(d)(i)

TOTAL

QUESTION 7

Answer

Ohm's law

Resistance

Gradient 6.2 > 6.3//Gradient 6.2 >

Diameter 6.2 < 6.3// Diameter 6.2

Cross sectional area 6.2 < 6.3// Cross sectional area6.2<

Inversely proportional // increases , decreases

Decrease//smaller/small//lower///low

Resistance decrease

Note

Accept: viceversa

Section Mark Answer Note

(a) 1 Angle of incidence when refrection angle is 90

(b) 1

1

Ray inside the glass block refracted towards thenormal

Ray in air again parallel to the AO

A ._.__.

(c)(i)

1

1

1

sin 42

1.49

(c)(ii) 1 Increase

(d)(i) 1

1

450-900-450//450-450-907/900-450-457/45°-900//90°-457/45°-457/ DiagramAngle of incidence > critical angle // the ray oflight canpassing through both of the prism // totalinternal reflection occur//ray of light does notrefract to the side ofprism

(d)(ii) 1

1

The prisms are replaced at the position of themirrors respectively // The prisms is located atupper corner and lower corner of the boxrespectively// The angle 90° of the prism at thecorner // diagramAngle of incidence > critical angle // the ray oflight can passing through both of the prism // totalinternal reflection occur//ray of light does notrefract to the side of prism

TOTAL 8

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QUESTION 8

Section mark Answer Note

(a) (0 1 Archimedes principle

(ii) 1

2

Sea water filled ballast tankThe weight of submarine bigger//Buoyant force < Weight of the submarine

(b) 1

2

V = 0.2 x 0.8

- 0.16 m3

(c) (i)

(c) (ii)

(c) (iii)

(c) (iv)

1,2

1,2

1,2

1

Characteristics Reason

More number of air

tanks cylinder carriedCan stay longer timeunder the water /

Can rise and

submerge manytimes / more air

supply forrespiration of crews

Can withstand highermaximum water

pressure

Safe when the

submarine submergevery deep in the sea /The body will notbreak due to highwater pressure

aerodynamicReduce water

Resistant

Submarine x

Total 12m

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QUESTION 9

Section Answer Note

(a) 1 Principle of thermal equilibrium of heat

(b) 1 - The amount of heat energy is the same1 - c of Diagram 9.1(a) is greater than Diagram 9.1(b)1 - Temperature in diagram 9.1 (a) is greater than in

Diagram 9.1(b)1 - the rate of heat loss in Diagram 9.1(b) is greater than in

Diagram 9.1(a)1 - the smaller the c ofcontainer, the greater the rate of

heat loss

(c) 1 - initially, more heat flow from water to the containerthan from container to the water

1 - nett heat flow is from water to the containers

1 - when thermal equilibrium is reached1 - nett heat flow is zero.

- the temperature of water = temperature ofcontainer

(d) Aspects Reasons

high specific capacity of small change in1,2 inner box temperature // keep hot

longer time.material X made of good prevent heat from flow out

3,4

5,67,89,10

heat insulator

Low density of material X Low mass // lightLow density of outer box Low mass // light

shiny colour of outer box Reflect heat from outside

20

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QUESTION 10

Section

(a)(b)

(c)

(d)

1,2

3,4

5,6

7,8

9,10

Tot/Jum : 20

Flemming left hand ruleThereading of ammeter in Diagram 10.2 > in Diagram 10.1Angle ofdeflection ofcopper wire coil in Diagram 10.2 > inDiagram 10.1The strength of magnetic field in Diagram 10. land Diagram10.2 is the sameThe bigger the reading of ammeter the bigger the deflectionof copper wire coilThe bigger the magnitude ofcurrent, the bigger the force oncurrent carrying conductor

Current flow in copper coil produce magnetic fieldAnd interact with magnetic field of permanent magnetProduce catapult fieldAnd force on copper coil

Suggestion / Modification Explanation /Reason

Many number of turns ofcoil

Increase the strength ofmagnetic field produced

Soft iron core To concentrate the magnetic

field line

Curve magnet To produce radial magneticfield

Lower stiffness The pointer easy to deflect

Strip mirror under thepointer // Has adjustmentscrew

Avoid parallax error // tocorrect the zero error

Note

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QUESTION 11

Section

(a)(i) 1

(a)(ii)

(b)

(c)(i)

(c)(ii)

Tot/Jum : 20

Answer

State the principle ofconservation ofmomentum correctlyTotal momentum of a system is always constant if there isno external force acting on the system.State the explanation correctlyCombustion fuel in compressed air, the hot gases is forcesout through blades of turbine.The exhaust gases emerge from the jet engine at highvelocity.The exhaust gases have been given high momentum.As total momentum conserved, equal amount of momentumacted in forward direction.The jet engine (and whole air craft) experiences a forwardforce / thrust.

State thecharacteristics and explanation correctlyFuel used is kerosene.Lighter and easy to increase acceleration //Easy to obtainhot gases in combustion chamber.High melting poinNot easily to melt // withstand high temperature.Large no of bladeRate of compression of air higherLarge sizeof combustion chamberHigh mass of exhaust gases can be emerged.State the choiceandgive thereason correctlyThe most suitable structure ofjet engine is RFuel used is kerosene, high melting, large no of blades andlarge sizeof combustion chamber

Show the calculation correctlyGreatest force provided by all engines working together,F= 4x250,000 // 1000,000 NSubstitute the value correctly

F 1000,000

3 ~ w 400,000Correct answer with unit

a - 2.5 m s""

Substitution of value correctlyv2 = tr + 2as852 = 0 + 2(2.5)*

Correct answer with unit

s = 1445 m

Note

Maximum : 4 marks

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QUESTION 12

Q12

12(a)

12(b)

12(c)(1)

12(c)(ii)

12(c)(iii)

12(d)

Total

Answer

Semiconductor is a material with electrical conductivity better thaninsulator but weaker than a conductor- Doping process/Silicon is doped with pentavalentatoms/Phosphorus/Antimony- To produce covalent bond- Increase the free electron inside the semiconductor- Majority charge-carriers is negative electron

Vx-z=6V

V X-Y = 6-1 =5V

VM =R M

KRM+*N\x6V

5 =R M

tftf+1000.x6V

5Rm± 5000 = 6RMRAf= 5000 Cl

Free

electron

- LDR is connected at base circuit- When intensity of light is low/ dark, resistance of LDR

increases / so Vbasc is large / transistor switched on- Terminal positive of batteries is connected to collector- So that the transistor is forward biased- Bulbs are arranged in parallel circuit- All bulbs are connected to voltage supply of 95V- Relay switch is used- So that the secondary circuit will switch on // So that theelectromagnet will switchon the secondary circuit

- Choose A- Because LDR is connected at base circuit, terminal positive ofbatteries is connected to collector; bulbs are arranged in parallelcircuit and relay switch is used.20 marks.

Mark

1

Note

Max

4

10

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