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Shallow Foundations – Bearing Capacity

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FLecture 4

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Page 1: FLecture 4

Shallow Foundations – Bearing Capacity

Page 2: FLecture 4

Introduction

2 /50

o Shallow foundations must satisfy various performance requirements and one of them is the bearing capacity (strength requirement)

o Since shallow foundations induce loads the near-surface soils, it induces both compressive and shear stresses in the soils

o The magnitudes of these stresses depend largely on the bearing pressure and the size of the footing

o If the bearing pressure is large enough, or the footing is small enough, the shear stresses may exceed the shear strength of the soil or rock that will result in a bearing capacity failure.

Page 3: FLecture 4

Bearing Capacity Failures

3 /50

o general shear failure

o local shear failure

o punching shear failure

Page 4: FLecture 4

General Shear Failure

o Most common mode of failure

o occurs in soils that are relatively incompressible and reasonably strong, in rock, and in saturated, normally consolidated clays that are loaded rapidly enough that the undrained condition prevails

o the failure surface is well defined and failure occurs quite suddenly

o a clearly formed bulge appears on the ground surface adjacent to the foundation

o Ultimate failure occurs on one side only and is often accompanied by rotation of the foundation

Load displacement curve for general shear failure

general shear failure

Page 5: FLecture 4

Local Shear Failure

o is an intermediate case

o shear surfaces are well defined under the foundation, but vague near the ground surface

o a small bulge may occur, but considerable settlement, perhaps on the order of half the foundation width, is necessary before a clear surface forms near the ground

o sudden failure does not occur

o The footing just continues to sink into the ground Load displacement curve for local shear failure

local shear failure

Page 6: FLecture 4

Punching Shear Failure

o opposite extreme

o occurs in very loose sands, in a thin crust of strong soil underlain by very weak soil, or in weak clays loaded under, slow drained conditions

o the high compressibility of the soil causes large settlements and poorly defined vertical shear surfaces

o little or no bulging occurs at the ground surface and failure develops gradually

Load displacement curve for

Punching shear failure

punching shear failure

Page 7: FLecture 4

Vesić’s investigation

o Vesic investigated these three modes of failure by conducting load tests on model circular foundations in sand

o shallow foundations (D/B < 2) can fail in any of the three modes

o deep foundations (D/B > 4) are always governed by punching shear

o The results show a general relationship between the mode of failure, relative density, and the D/B ratio.

Modes of failure of model circular foundations in Chattahoochee Sand

Page 8: FLecture 4

Bearing Capacity Failures

o The following guidelines are helpful to determine which of the three modes of failure will govern Shallow foundations in rock and undrained clays are governed by the

general shear case

Shallow foundations in dense sands are governed by the general shear case. In this context, a dense sand is one with a relative density, Dr, greater than about 67%

Shallow foundations on loose to medium sands (30% < Dr < 67%) are probably governed by local shear

Shallow foundations on very loose sand (Dr < 30%) are probably governed by punching shear

Page 9: FLecture 4

Bearing Capacity Analyses in Soil General Shear Case

o To be able to analyze and design spread footings, we must understand the relationship between bearing capacity, load, footing dimensions and soil properties

o The relationships have been studied using different approaches such as: assessments of the performance of real foundation, including full-scale

load tests

load tests on model footings

limit equilibrium analyses

detailed stress analyses, such as FEM analyses

Page 10: FLecture 4

Simple Bearing Capacity Formula

Bearing capacity analysis along a circular failure surface

Consider a continuous footing

a. assume this footing experiences a bearing capacity failure

b. failure occurs along a circular shear surface

c. soil is an undrained clay (f = 0)with a shear strength su

d. neglect the shear strength between the ground surface and a depth D

e. soil in this zone is considered to be only surcharge load that produces a vertical total stress of szD = gD at a depth D.

Page 11: FLecture 4

Simple Bearing Capacity Formula

Bearing capacity analysis along a circular failure surface

Take moments about Point A

Define a new parameter, called a bearing capacity factor, Nc

The above equation is known as the bearing capacity formula where Nc = 2p = 6.28.

Page 12: FLecture 4

Terzaghi’s Bearing Capacity Formulas

Assumptions of Terzaghi’s bearing capacity formulas

o the D B

o no sliding occurs between the foundation and the soil

o the soil beneath the foundation is a homogeneous semi-infinite mass

o s = c’ + s’tanf’

o the general shear mode of failure governs

o no consolidation of the soil occurs

o the foundation is very rigid in comparison to the soil

o the soil between the ground surface and a depth D has no shear strength, and serves only as a surcharge load

o applied load is compressive and applied vertically to the centroid of the foundation and no applied moment loads are present

Geometry of failure surface for Terzaghi’s bearing capacity formulas

Page 13: FLecture 4

Terzaghi’s Bearing Capacity Formulas

Assumptions of Terzaghi’s bearing capacity formulas

o three zones were considered

wedge zone – remains intact and moves downward with the foundation

radial shear zone – extends from each size of the wedge and the shape of the shear planes are logarithmic spirals

linear shear zone – the soil shears along planar surfaces

Geometry of failure surface for Terzaghi’s bearing capacity formulas

Page 14: FLecture 4

Terzaghi’s Bearing Capacity Formulas

o for square foundations

o for continuous foundations

o for circular foundations

qult = ultimate bearing capacity

c’ = effective cohesion for soil beneath foundation

f’ = friction angle for soil beneath foundation

szD‘ = vertical effective stress at depth D below the ground surface

g’ = effective unit weight of the soil if groundwater table is very deep

D = depth of foundation below ground surface

B = width (or diameter) of foundation

Nc , Nq , Ng = Terzaghi’s bearing capacity factors = f(f’)

Page 15: FLecture 4

Bearing Capacity Factors

f’

(deg)

TERZAGHI (Eq. 6.4 to 6.6)

VESIĆ (Eq. 6.13)

Nc Nq Ng Nc Nq Ng

0 5.7 1.0 0.0 5.1 1.0 0.0

1 6.0 1.1 0.1 5.4 1.1 0.1

2 6.3 1.2 0.1 5.6 1.2 0.2

3 6.6 1.3 0.2 5.9 1.3 0.2

4 7.0 1.5 0.3 6.2 1.4 0.3

5 7.3 1.6 0.4 6.5 1.6 0.4

6 7.7 1.8 0.5 6.8 1.7 0.6

7 8.2 2.0 0.6 7.2 1.9 0.7

8 8.6 2.2 0.7 7.5 2.1 0.9

9 9.1 2.4 0.9 7.9 2.3 1.0

10 9.6 2.7 1.0 8.3 2.5 1.2

Page 16: FLecture 4

Terzaghi bearing capacity factors

Page 17: FLecture 4

Example Problem

A square footing is to be constructed as shown. The groundwater table is at a depth of 50 ft. below the ground surface. Compute the ultimate bearing capacity and the column load required to produce a bearing capacity failure.

f’

(deg)

Terzaghi (Eq. 6.4 to 6.6)

Vesic (Eq. 6.13)

Nc Nq Ng Nc Nq Ng

30 37.2 22.5 20.1 30.1 18.4 22.4

31 40.4 25.3 23.7 32.7 20.6 26.0

32 44.0 28.5 28.0 35.5 23.2 30.2

Page 18: FLecture 4

Example Problem

The proposed continuous footing shown will support the exterior wall of a new industrial building. The underlying soil is an undrained clay, and the groundwater table is below the bottom of the footing. Compute the ultimate bearing capacity, and compute the wall load required to cause a bearing capacity failure.

f’

(deg)

TERZAGHI (Eq. 6.4 to 6.6)

VESIĆ (Eq. 6.13)

Nc Nq Ng Nc Nq Ng

0 5.7 1.0 0.0 5.1 1.0 0.0

1 6.0 1.1 0.1 5.4 1.1 0.1

2 6.3 1.2 0.1 5.6 1.2 0.2 0.2 m

0.2 m

Page 19: FLecture 4

Vesić’s Bearing Capacity Formulas

o Skempton (1951)

o Meyerhof (1953)

o Brinch Hansen (1961)

o DeBeer and Ladanyi (1961)

o Meyerhof (1963)

o Brinch Hansen (1970)

o Vesić (1973,1975)

developed formulas based on theoretical and experimental findings

excellent alternative to Terzaghi

produces more accurate bearing values

applies to a much broader range of loading and geometry conditions

Page 20: FLecture 4

Vesić’s Bearing Capacity Formulas

o Vesić retained Terzaghi’s basic format and added the following additional factors:

sc, sq, sg = shape factors

dc, dq, dg = depth factors

ic, iq, ig = load inclination factors

bc, bq, bg = base inclination factors

gc, gq, gg = ground inclination factors

o so that the bearing capacity formula is re-written as

Notation for Vesic’s load inclination, base inclination, and ground inclination factors. All angles are expressed in degrees

Page 21: FLecture 4

Vesić’s Shape Factors

For continuous footings, B/L 0, so sc, sq, sg = 1.

Page 22: FLecture 4

Vesić’s Depth Factors

o for relatively shallow foundations (D/B 1), use k = D/B.

o for deeper footings (D/B > 1), use k = tan-1(D/B)

Page 23: FLecture 4

Vesić’s Load Inclination Factors

o i factors are 1 if load acts perpendicular to the base of the footing

o i factors are 1 when f = 0

V = applied shear load

P = applied normal load

A = base area of footing

c’ = effective cohesion (use c = su for undrained analyses)

f’ = effective friction angle (use f = 0u for undrained analyses)

B = foundation width

L = foundation length

For loads inclined in the B direction:

For loads inclined in the L direction:

Page 24: FLecture 4

Vesić’s Base Inclination Factors

o if the base of the footing is level, which is the usual case, all b factors are equal to 1.

Page 25: FLecture 4

Vesić’s Ground Inclination Factors

𝑔𝑐 = 1−𝛽

1470

o if the ground surface is level (b= 0) the g factors are equal to 1.

𝑔𝑞 = 𝑔𝛾 = 1− 𝑡𝑎𝑛𝛽 2

Page 26: FLecture 4

Vesić’s Bearing Capacity Factors

𝑁𝑞 = 𝑒𝜋𝑡𝑎𝑛 𝜙 ′ tan 45+

𝜙 ′

2

𝑁𝑐 =𝑁𝑞 − 1

𝑡𝑎𝑛𝜙′

𝑁𝑐 = 5.14

For f’ > 0

For f’ = 0

𝑁𝛾 = 2 𝑁𝑞 + 1 𝑡𝑎𝑛𝜙′

o Vesic used the following formulas for computing the bearing capacity factors Nq and Nc:

Vesic recommended the following formula for Ng

Page 27: FLecture 4

Summary

o Bearing capacity failure occurs when the soil beneath the footing fails in shear

o There are three types of bearing capacity failures:

general shear failure

local shear failure

punching shear failure

o Most bearing capacity analyses for shallow foundations consider only the general shear case

Page 28: FLecture 4

Seatwork

A 1.2 m square, 0.4-m deep spread footing is underlain by a soil with the following properties:

g = 19.2 kN/m3

c’ = 5 kPa

f’ = 30o

The groundwater is at a great depth.

ID nos. ending in an ODD No.

Compute the ultimate bearing capacity using TERZAGHI’s method

ID nos. ending in an EVEN No.

Compute the ultimate bearing capacity using VESIĆ’s method

Page 29: FLecture 4

Seatwork

A 5-ft wide, 8 ft. long, 2 ft. deep spread footing is underlain by a soil with the following properties:

g = 120 lb/ft3

c’ = 100 lb/ft2

f’ = 28o

The groundwater is at a great depth. using VESIĆ’s method, compute the column load required to cause a bearing capacity failure.

Page 30: FLecture 4

Seatwork

A 1.5-m wide, 2.5 m. long, 0.6 m. deep spread footing is underlain by a soil with the following properties:

g = 19 kN/m3

c’ = 4.8 kN/m2

f’ = 28o

The groundwater is at a great depth. using VESIĆ’s method, compute the column load required to cause a bearing capacity failure.

Page 31: FLecture 4

Groundwater Effects

o The presence of shallow groundwater affects shear strength in two ways:

Reduction of apparent cohesion

Increase in pore water pressure

o Both of these affect bearing capacity, and thus need to be considered

Page 32: FLecture 4

Groundwater Effects

Three groundwater cases for bearing analyses

CASE I CASE 2 CASE 3

NOTE: If a total stress analysis is being performed, do not apply groundwater correction because the groundwater effects are supposedly implicit within the values of CT and fT.

Page 33: FLecture 4

Example Problem

A 30-m by 50-m foundation is to be built as shown in the figure. Compute the ultimate bearing capacity.

f’

(deg)

Terzaghi (Eq. 6.4 to 6.6)

Vesic (Eq. 6.13)

Nc Nq Ng Nc Nq Ng

30 37.2 22.5 20.1 30.1 18.4 22.4

31 40.4 25.3 23.7 32.7 20.6 26.0

32 44.0 28.5 28.0 35.5 23.2 30.2

Page 34: FLecture 4

Solution

f’

(deg)

Vesic (Eq. 6.13)

Nc Nq Ng

30 30.1 18.4 22.4

31 32.7 20.6 26.0

32 35.5 23.2 30.2

Page 35: FLecture 4

Allowable Bearing Capacity

To obtain the allowable bearing capacity, qa, the ultimate bearing capacity is divided by a factor of safety

where

qa = allowable bearing capacity

qult = ultimate bearing capacity

F = factor of safety

The foundation is then designed so that the bearing pressure, q, does not exceed the allowable bearing capacity, qa.

𝑞𝑎 =𝑞𝑢𝑙𝑡

𝐹

Page 36: FLecture 4

Allowable Bearing Capacity

o Soil Type

o Site characterization data

o Soil variability

o Importance of the structure and the consequences of a failure

o The likelihood of the design load ever actually occurring

Page 37: FLecture 4

Allowable Bearing Capacity

o Soil Type

o Site characterization data

o Soil variability

o Importance of the structure and the consequences of a failure

o The likelihood of the design load ever actually occurring

o Design F - Extreme Values

Typical Range

Sand Clay

Extensive Minimal

Uniform Erratic

Low High

Low High

2.0 4.0

2.5 3.5

Factors affecting the design factor of safety, and typical values of F.

Page 38: FLecture 4

Allowable Bearing Capacity

The true factor of safety is probably much greater than the design factor of safety, due to the following:

o The shear strength data are normally interpreted conservatively, so the design values of c and f implicitly contain another factor of safety.

o The service loads are probably less than the design loads

o Settlement, not bearing capacity, often controls the final design, so the footing will likely be larger than that required to satisfy bearing capacity criteria.

o Spread footings are commonly built somewhat larger than the plan dimensions.

Page 39: FLecture 4

Example Problem

A column has the following design vertical loads: PD = 300 k, PL = 140 k, PW = 160 k will be supported on a spread footing located 3 ft. below the ground surface. The underlying soil has an undrained shear strength of 2000 lb/ft2 and a unit weight of 109 lb/ft3. The groundwater table is at a depth of 4 ft. Determine the minimum required footing width to maintain a factor of safety of 3 against a bearing capacity failure (use Terzaghi’s method).

f’

(deg)

TERZAGHI (Eq. 6.4 to 6.6)

VESIĆ (Eq. 6.13)

Nc Nq Ng Nc Nq Ng

0 5.7 1.0 0.0 5.1 1.0 0.0

1 6.0 1.1 0.1 5.4 1.1 0.1

2 6.3 1.2 0.1 5.6 1.2 0.2

Page 40: FLecture 4

Design Loads

ASD design load combinations [ANSI/ASCE 2.4.1]

o D

o D + L + F + H + T + (Lr or S or R)

o D + L + (Lr or S or R) + (W or E)

o D + (W or E)

Alternate method of evaluating wind and seismic loads

o 0.75[D + L + (Lr or S or R) + (W or E)]

o 0.75[D + (W or E)]

Page 41: FLecture 4

Bearing Capacity on Layered Soils

Many soil profiles are not uniform. To compute the bearing capacity of foundation on soils where c, f and g vary with depth, we can use three methods:

o Evaluate the bearing capacity using the lowest values of c’, f’ and g in the zone between the bottom of the foundation and a depth B below the bottom.

this is the zone where bearing capacity failures occur

this method is conservative

however many design problems are controlled by settlement, so a conservative bearing capacity analysis may be the simplest and easiest solution

Page 42: FLecture 4

Bearing Capacity on Layered Soils

o use weighted average values of c’, f’ and g based on the relative thickness of each stratum in the zone between the bottom of the footing and a depth B below the bottom

this method could be both conservative and unconservative

provides acceptable results as long as the differences in the strength parameters are not too great

Page 43: FLecture 4

Bearing Capacity on Layered Soils

o consider a series of trial failure surfaces beneath the footing and evaluate the stresses on each surface using methods employed in slope stability analyses.

the surface that produces the lowest value of qult is the critical failure surface

most precise but also requires the most effort to implement

appropriate only for critical projects on complex soil profiles

Page 44: FLecture 4

Example Problem

Using the second method, compute the factor of safety against a bearing capacity failure in the square footing shown.

f’

(deg)

TERZAGHI (Eq. 6.4 to 6.6)

VESIĆ (Eq. 6.13)

Nc Nq Ng Nc Nq Ng

33 48.1 32.2 33.3 38.6 26.1 35.2

34 52.6 36.5 39.6 42.2 29.4 41.1

35 57.8 41.4 47.3 46.1 33.3 48.0

Page 45: FLecture 4

Evaluations of bearing capacity failures on saturated clays (Bishop and Bjerrum, 1960)

Locality Clay Properties

Computed Factor of Safety F Moisture

content, w

Liquid limit, wL

Plastic limit, wP

Plasticity index, IP

Liquidity index, IL

Loading test, Marmorera 10 35 15 20 -0.25 0.92

Kensal Green 1.02

Silo, Transcona 50 110 30 80 0.25 1.09

Kippen 50 70 28 42 0.52 0.95

Screw pile, Lock Ryan 1.05

Screw pile, Newport 1.07

Oil tank, Fredrikstad 45 55 25 30 0.67 1.08

Oil tank A, Shellhaven 70 87 25 62 0.73 1.03

Oil tank B, Shellhaven 1.05

Silo, US 40 20 35 1.37 0.98

Loading test, Moss 9 16 8 1.39 1.10

Loading test, Hagalund 68 55 19 18 1.44 0.93

Loading test, Torp 27 24 0.96

Loading test, Rygge 45 37 0.95

Page 46: FLecture 4

Evaluations of bearing capacity failures on saturated clays (Bishop and Bjerrum, 1960)

Results of static load tests on full-sized spread footings (Adapted from Briaud and Gibbens, 1994)

Page 47: FLecture 4

Seatwork

A column carrying a vertical downward dead load and live load of 150 k and 120 k, respectively, is to be supported on a 3-ft deep square spread footing.

The soil beneath this footing is an undrained clay with su = 3000 lb/ft2 and g = 117 lb/ft3. The groundwater table is below the bottom of the footing.

Compute the width B required to obtain a factor of safety of 3 against a bearing capacity failure.

Page 48: FLecture 4

Seatwork

A 120-ft diameter cylindrical tank with an empty weight of 1,900,000 lb. (including the weight of the cylindrical mat foundation) is to be built. The bottom of the mat will be at a depth of 2 ft. below the ground surface.

This tank is to be filled with water. The underlying soil is an undrained clay with su = 1000 lb/ft2 and g = 118 lb/ft3, and the groundwater table is at a depth of 5 ft.

Using Terzaghi’s equations, compute the maximum allowable depth of the water in the tank that will maintain a factor of safety of 3.0 against a bearing capacity failure. Assume the weight of the water and tank is spread uniformly across the bottom of the tank.

Page 49: FLecture 4

Summary

o there are several formulas to compute the ultimate bearing capacity, qult. These are Terzaghi and Vesic’s formulas.

o Shallow GWTs reduce the effective stress in the near-surface soils and can therefore adversely affect bearing capacity. Adjustment factors are available to account for this effect.

o The allowable bearing capacity, qa, is the ultimate bearing capacity divided by a factor of safety. The bearing pressure, q, must not exceed qa.

Page 50: FLecture 4

Summary

o Bearing capacity analyses should be based on the worst-case soil conditions that are likely to occur during the life of the structure.

o Bearing capacity analyses on sands and gravels are normally based on the effective stress parameters, c’ and f’. However, those on saturated clays are normally based on the undrained strength, su.

Page 51: FLecture 4

Summary

o Bearing capacity computations may be performed for local and punching shear cases. These analyses use reduced values of c’ and f’.

o Bearing capacity analyses on layered soils are more complex because the values of c’ and f’ for each layer should be considered.

o Evaluations of foundation failures and static load tests indicate the bearing capacity analysis methods in this chapter are suitable for the practical design of shallow foundations.