fluid flow in pipes - lecture 4
TRANSCRIPT
CIVE2400: Pipeflow - Lecture 4 09/04/2009
1
School of Civil EngineeringFACULTY OF ENGINEERING
Fluid Flow in Pipes: Lecture 4
Dr Andrew Sleigh
Dr Ian Goodwill
CIVE2400: Fluid Mechanics
www.efm.leeds.ac.uk/CIVE/FluidsLevel2Fluid Mechanics: Pipe Flow – Lecture 4 2
Local Head Losses
• Local head losses are the “loss” of energy at point where
the pipe changes dimension (and/or direction).
Pipe Expansion
Pipe Contraction
Entry to a pipe from a reservoir
Exit from a pipe to a reservoir
Valve (may change with time)
Orifice plate
Tight bends
• They are “velocity head losses” and are represented by
g
ukh LL
2
2
Fluid Mechanics: Pipe Flow – Lecture 4 3
Value of kL
• For junctions and bends we need
experimental measurements
• kL may be calculated analytically for
Expansion
Contraction
• By considering continuity and momentum
exchange and Bernoulli
Fluid Mechanics: Pipe Flow – Lecture 4 4
Losses at an Expansion
• As the velocity reduces (continuity)
• Then the pressure must increase
(Bernoulli)
• So turbulence is induced and head losses
occur
Turbulence and losses
Fluid Mechanics: Pipe Flow – Lecture 4 5
Value of kL for Expansion
• Apply the momentum equation from 1 to 2
• Using the continuity equation we can
eliminate Q
• From Bernoulli1 2
122211 uuQApAp
21212 uu
g
u
g
pp
g
pp
g
uuhL
12
2
2
2
1
2 Fluid Mechanics: Pipe Flow – Lecture 4 6
Value of kL for Expansion
• Combine and
• Using the continuity equation again
u1A1 = u2A2 u2=u1A1/A2
• A1 >> A2, kL = 1 exit loss
21212 uu
g
u
g
pp
g
pp
g
uuhL
12
2
2
2
1
2
g
uuhL
2
2
21
g
u
A
AhL
21
2
1
2
2
1
2
2
11A
AkL
CIVE2400: Pipeflow - Lecture 4 09/04/2009
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Fluid Mechanics: Pipe Flow – Lecture 4
• Flow converges as the pipe contracts
• Convergence is narrower than the pipe
Due to vena contractor
• Experiments show for common pipes
A1’ = 0.6A2
• Can ignore losses
bewteen 1 and 1’
As Convergent flow is very stable
7
Losses at an Contraction
1 1’ 2
Fluid Mechanics: Pipe Flow – Lecture 4
• Apply the general local head loss equation
between 1’ and 2
Using A1’ = 0.6A2
And Continuity
8
Losses at an Contraction
1 1’ 2
g
u
A
AhL
21
2
'1
2
2
'1
6.06.0
2
2
22
'1
22'1
u
A
uA
A
uAu
g
uhL
244.0
2
2
Fluid Mechanics: Pipe Flow – Lecture 4
• Whenever there is expansion
• Pressure increases down stream
• Danger of boundary layer separation as the fluid
near the walls had little momentum
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Other Losses
Fluid Mechanics: Pipe Flow – Lecture 4
Losses: Junctions
Reduced velocity
Increased pressureReduced velocity
Increased pressure
Fluid Mechanics: Pipe Flow – Lecture 4
Losses: Sharp bends
Reduced velocity
Increased pressure
Fluid Mechanics: Pipe Flow – Lecture 4
kL values
kL
valu
e
Bellmouth entry 0.10
Sharp entry 0.5
Sharp exit 0.5
90 bend 0.4
90 tees
In-line
flow
0.4
Branch
to line
1.5
Gate value (open) 0.25
kL = 0.1
Bell mouth Entry
kL = 0.5
Sharp Entry/Exit
T-inline
kL = 0.4
T-branch
kL = 1.5
CIVE2400: Pipeflow - Lecture 4 09/04/2009
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Fluid Mechanics: Pipe Flow – Lecture 4
Pipeline Analysis
• Bernoulli Equation
equal to a constant: Total Head, H
• Applied from one point to another (A to B)
With head losses
Hzg
u
g
pA
AA
2
2
fLBBB
AAA hhz
g
u
g
pHz
g
u
g
p
22
22
Fluid Mechanics: Pipe Flow – Lecture 4
• Reservoir
• Pipe of Constant diameter
• No Flow
Bernoulli Graphically
Datum line
zA= HH
z
p/ g
Pressure head
Elevation
p/ g
z
z
p/ g
Hzg
u
g
pA
AA
2
2
Total Head Line
Fluid Mechanics: Pipe Flow – Lecture 4
• Constant Flow
• Constant Velocity
• No Friction
Bernoulli Graphically
Datum line
zA= HH
z
p/ g
Pressure head
Elevation
Hzg
u
g
pA
AA
2
2
Total Head Line
Hydraulic Grade
Line
u2/ g
Velocity head
Fluid Mechanics: Pipe Flow – Lecture 4
• Constant Flow
• Constant Velocity
• No Friction
Bernoulli Graphically
Datum line
zA= HH
z
p/ g
Pressure head
Elevation
Hzg
u
g
pA
AA
2
2
Total Head Line
Hydraulic Grade
Line
u2/ g
Velocity head
u22/ g
Wider Pipe
Change of Pipe
Diameter
Fluid Mechanics: Pipe Flow – Lecture 4
• Constant Flow
• Constant Velocity
• With Friction
Bernoulli Graphically
Datum line
zA= HH-hf
z
p/ g
Total Head Line
Hydraulic Grade
Line
u2/ g
fLBBB
AAA hhz
g
u
g
pHz
g
u
g
p
22
22
u2/ g u2/ g
Fluid Mechanics: Pipe Flow – Lecture 4
Reservoir Feeding Pipe Example
• d = 0.1m
• Length A-C = L = 15m
• Length A-B = L = 1.5m
• f = 0.08
• kL entry = 0.5 Sharp
• kL exit = 0 Opens to atmosphereB
A
CzA zB
zCpc = Atmospheric
zB-zA = 1.5m
zA-zC = 4m
Find
a) Velocity in pipe
b) Pressure at B
CIVE2400: Pipeflow - Lecture 4 09/04/2009
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Fluid Mechanics: Pipe Flow – Lecture 4
Reservoir Feeding Pipe Example
• Apply Bernoulli with head losses
fLCCC
AAA hhz
g
u
g
pz
g
u
g
p
22
22
B
A
CzA zB
zCpc = Atmospheric
d
fL
g
u
gd
fLu
g
u
g
uzz C
CA
45.00.1
22
4
25.0
2
2222
1.0
1508.045.1
81.924
2usmu /26.1
pA= pc = Atmospheric
uA= negligible
Fluid Mechanics: Pipe Flow – Lecture 4
Reservoir Feeding Pipe Example
• Find pressure at B: Apply Bernoulli A-B
fLBBB
AAA hhz
g
u
g
pz
g
u
g
p
22
22
B
A
CzA zB
zCpc = Atmospheric
smuu B /26.1
pA= Atmospheric = treat as 0
uA= negligible
ABABBB zzgd
ufL
g
u
g
u
g
p
2
4
25.0
2
222
5.11.0
0.508.045.1
81.92
26.1
81.91000
2
Bp 23 / 1058.28 mNpB
Negative
i.e. less than Atmospheric pressure
21
Today’s lecture:
• Local head losses
Expansion loss
Contraction loss
Junction
+ other minor losses
• Graphical representation of Bernoulli
Total Head Line
Hydraulic Grade Line
• Analysis of pipeline, including losses
g
ukh LL
2
2
g
u
A
AhL
21
2
1
2
2
1